期末考題目-Question 3

1 like 0 dislike
4.7k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 4.7k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
* *  *  *      *      *    ** **       *  **     * * * **  ***
*  * * * *** **       * **    **** 
 * ** *** * ** *  ***  
**   ** * ** *      *     *******     ** *   ** *  *
 *   * * ** *  **  *  *  ** 
************  **** * *   *** **   * * *
*           *   *  ** ****   
 *** * *** *  * * *   ***** *   *   * * ****

*  *     * * ** ***  *    0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
**     * * *  **  *  **** *** *  *  ** **  **    *  *  *** * **** 
 **  *** ****  ***   *** **  *
** ***** *****  * *   *  *      *
  ** *      **** ** *  * * ***   **** *** *  ***   *  * *** * *  **** * 
***   *    ***  * *       *   if(s==1)
  *** ***       **     ***** ****  *  *   *   * * *** * **  ***  *** ***  * 
** *  *  *  * *** ** *** ** ** if(s==2)
  *  ** *  * * * * *****  *  *   *   ** * *  ** *     ***  *** *** **    
***    * *  ****  **** *    *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 * ****** * *** ******* M,D,S;
    
 ****   ** *       *   ** ** * * * %d",&M,&D);
    
 *  *   * ******  *****  ***   **** **
   *** * *  * * *   *** * *
      * **   * * **   **      **
 *  *   * **    **** * *
* ** * ** ** ***   *  ***  ****   * * **  * * *   * * *** *  * * *    ** **  ***** 
*****   * * ***  *  *  * 
 * ** *     ****  *  ** ** if(S==1)
  *    *     ***    * * ** *  
   **  **  **  *  * * ***  *  **   **    * * * ** ***** *** * ***   *  ***  *  *  *    
** ***    * ****** * * *** 
*** ***** * * **   *  *  **    **  if(S==2)
 ** ******  ** ***** **   *   **
***** *  *** **   *   * *  **  **   * *  *** ***  * *** ***** *  ***   ** *****  
    **  **   *   *   * * *** 
  *   * * ***  *******  * * *  * **    0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
* **  *  ******* *** **    **** m,d,s;
 * * ** *      ****    * 
    * *  **  *  **    **  *    ****  ****   %d",&m,&d);
    
**  ***      ***       ** *  * + d)%3;
****     *    *  * *** *  *   
 * **  ***** **   ***** ** **  **
* ** *  *** *    *     *   *
** **    **** *     ** * *      ** **** *  * *  * ****   *   **
*** * * *   ** *      * * **
 *    **   *  *  *     ***** if(s==1)
 **      *       *  * * 
          ** * *       **     *  * **    * ** * * ******* ***  ** * *   *  *      
* *   **    * * **   *** *
   *** ** **  *  *******    * if(s==2)
** ** ***  ***** * ** *  *** * *  * 
 * ** *   ** * *    ** * *** *  ******* ** **** * **   * * *** *  *    * ** * ** *  * 
  * *  **** ** *** * * **
  ***   ***  ** **   ** * **    
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
    **** *** ** 
int main()
{
int M,D,S;
 * ***  ** * **       ** ** **** ******  
scanf("%d *** * * * ** * **  *   
S=(M*2+D)%3;
if(S==0)
*    ** * * **    *  * **  *    * * * *** *
*  ** ** *  *   * *** **  *  ***  if(S==1)
*    *     *** *** *** ** *** *   *  *  **  *  * * *** *  ** *** * 
* *    ** * *  ****  * * *    * ** ** ***  * ** * ** **     
*  ***  * **** *** **** *  *      ****  * *  **** ** * *****  *   * *  *  ****          * *** * *  *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
      *  ***  * * *  ** * m,d,s;
   ****      * *   *   ** ****         * *   ** ****** *   * * 
 * *  * ****  *   * *   ***** = (m*2+d)%3;
**  * ***** *** *  ** *   (s == 0)
 * **     **      *  **       ** *** ** * *      * **   *  
*** * **   ** *     *   * **** if (s == 1)
  *   *** ** **       * *   **  * ***  *** ** ***  
  * ***   **  **   ** ** *     if (s == 2)
 * **        * ***** *** *   *  *     **  * **  ***
    *** **  *** * *   **  
   * ******* ****  *   ** *** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
**   *     *  *  * ** * * M,D,S;
       ****     *** *  ***     **    **** %d",&M,&D);
 *  *** ** * *  * ** **  *  
  *  ** ** *** *  * * *       **  **
 ** *   ***  **   ***    *     *   ****  *  * * **
  *      * * * **  ** **  *   * *** 
* *  ** * * ** *     ** * * * *** ** *       
 *   *   *** ** *    * ***  
*    ** *   ** *  * ***  ****  *   *    *   *  *  **
 *      ***     **** *** ***  *** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *** * ****  * *  * * ** * *** * m,d,s;
**  * *    ** ** *    *   **  *    * ** **    * * ***      *
 ** *   * * ***  *   = (m*2+d)%3;
  * * * **** *   *  ** * * * (s == 0)
  * ** ***** *   *** **  ** *  *  * *   * **** * *
     *****  **  * ***  * ** if (s == 1)
 ***** *  * ** *** *******       *  *****      * **
* ***  *  **    ** * ******** if (s == 2)
**** * * ****  **    *** ***   * * *  *     * 
* ** *****   ** **  ***   
**      *** **  * ** **   *     0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 *     * ** ***  **  *       * **** %d",&m,&d)!=EOF)
    {
*     * *     *** ***   *   ** * * *** **  **  *  * **** **   
* *** *  ** ****  ***** **    ***   *  * ** * ***   *  *  ******* 
 ** *  * * * **** * *   *     * * *  **** * *  *    *      * * ***   ** ****   * ** * ***   ** *  *  *  * 
**** ********* * ****    * *  * ****  * **  * ** ***  ** if(s==1)
*** ****  *****     **    *    ** *** *****     * * *   * ***** **       * ******  ** ****  * *****   
* ** *  ** ****** *   ******* * ** **  *** *     **  *  * ** * if(s==2)
*** *     ** *    * * ***  *     *      ***      *** *****    *   *** ****     **** *  ***   ** **      *
 *  *    ** **  ***       * * **  **      *       * *  ** *  
***  * ** ** * * *     *     *** *  ** * * *  *   ******** ****     ********  * *  * 
    }
      **  * *  * *  **** * *** **  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  *      ** *******  *

int main()
{
int M,D,S;

* ***     *      **** **  ** ***     
 * * *  
* *****
{
* ******  *  *    * **  * 
}
     *
{
**  ***** ** *  *  * ** *  * 
}
* *   *
{
 **** ***   **  * ** ****    
}
**    **** *   **     * *    

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.141
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users