期末考題目-Question 3

1 like 0 dislike
14.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 14.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
**** ***  **  * *   *** ** **** *     * ** * **   **** * 
  **  **       * *** * **** * **
    * * * * * *  * ***  *  * *
        * ****  **  ****** *  *  ** ** *   *
   **  ***   *   *    * *** 
 *** * **** ****  * *      *   *  ** * ******
     *  * * **   * **** 
  ******   **     *  *** * *****    *** *  

 ***      **    ** *** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 *        * **** *******     * ** * **  *  * *  * *** 
* **   *    *  ***  ***   
*  *** **    **  **** * * *  *  **
** **  *  ***** ***  **  **   * ** *  *  * *    **   ** * *    **   ** *     *** 
*  **     **** ******* ***  ** * if(s==1)
** **** *  *  **  * **  **   * ***   ***        *   **  * * ********** 
**   **  **** *  **  **  **     if(s==2)
* *****  ** *    ** ** **    *     *  *  *  **    * *    * ******  ******  * 
 ** * **** ****   **** **    *   0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 **   *** ** *  **       * ***** M,D,S;
    
**    *****   * * * **** **    * ** ****   %d",&M,&D);
    
  **   *  ****   * *  *  ***** *    **
 ** * *  * ***** *** * *  * ***   
*  * *   ******    *  **** **  ** ** *
   **  *     ***    *** ****
  *  * ***  **     *  *** ***   *   *******  *  **  *  * ***** * **   *    **  
* ***   * * *   *  * ******
 * ** *    ** *** ** * ** *  *   * * if(S==1)
  * *  *    *** *   ***  
*  * * ** * *  ** ********       *   *  **** ** *      * *  *        *  ** *   * ** *
 ** *   **   ********  *   * ** *
  * **** * ** ** *** **** * if(S==2)
*   * *  **** ***  * ***  ***
    ****   **  ****    * *** ** * * *     *** *   **  *  * * *     *     *   * *  *  
  ** ** *    * * **   *
  *** * **    ** **       ** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
** *******     ***  * **   m,d,s;
**  * **   * *  **** *  *
*  ** * ***     ** * ***  *** *  *** **  * %d",&m,&d);
    
***        ** * * ** *  * + d)%3;
 *  **** **   * **   
* * **   * *     ** * *  ** ******
** * ** *** **  * ** *    * *
*** *  *** * ** ***      * * * ** *****  * * **    * *****  *  
 ***  * *** * **** * ** *** ** *
* **** ** * * ***  *  ****  *** if(s==1)
 * ** * *     *   ***
*****  * *  * ****    **  ****    ** ** * **  ****** *    * **   * *  ** *   * 
   ****       **   **   *******
 ****** ***** ** *     ** *** if(s==2)
    *   ***   ** ** *  *** *
* * * * *** ****    *** *  ****   * *** * ** *  *** * *  * *** * ** **  *   ** *   *  
 *** **  *   *  *   *  ** * 
 *** **   *   ******  ** ** * 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
     * *      ***  *
int main()
{
int M,D,S;
  ** *** *  *** * * ***     **   *  *
scanf("%d      **  ** *** * **** **
S=(M*2+D)%3;
if(S==0)
*  * * * *  *  **  *     ****  * **  *  * * *   
**  * *         **   * *  *** * *   if(S==1)
**  *      *** * * * *           ** * **     *   * *  *  ** * * *** *
***    *  ***    * ****  *       *     *   *  *   ** *    *** 
 * * ****** ** *  *** * *** *    **  * *  ***  *   ** *         *   * *     * **  *** * ** * ** * * ** *  *   



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  ***  *** *  *****  *****   m,d,s;
  *  * * ** ****   ****       *   **  *  ***  * 
     **** *      **  *   *** = (m*2+d)%3;
 ** * ********* ** ** *** (s == 0)
 * *  ***    **   *** * * ***  *** *   *  *  *   * ** 
 ** ****    * ******** *  **** if (s == 1)
* ****  *  * **  **  *  *** ** *  *   **   *********   *  
*** *     *** *   * *** if (s == 2)
 * ***   ****** * ** *** ****  * *** **  **
 *  ** *       *  *      ****  
 ** ****  *      * **    * **  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  * * * * *  *  ****   *  ** ** M,D,S;
   ***     *   ** *   ***  * *  **       %d",&M,&D);
*   * ****  *    * **  * * *
  *           *  *** * ****
 *** **  * *   ** ********    ***     * **  *** *    
   ** * * ** * * ****** *** ** * 
** * *   *  * * ***   * *          ** **  * * * * *  
*       ** *       * **** * * 
 ***  *   ***   *  **  *** * **  *     *** * 
  ** *  * **   ****  * *  ****  *  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
**    * ** *  ***  *****   m,d,s;
   * *   *  *  **   ** *     **   * *    *** * *  ***   * **
*  *  *  **  * * *****  = (m*2+d)%3;
***       ** * * * * * (s == 0)
*  *   ** * ** * **      * ***    * * ***   * **  
 ** *    **     * * **  if (s == 1)
 *  *  **  **** *  *    *** *    *     * ****   * *
  *   * *   *  ***** * * **  if (s == 2)
   ***  *  * ***  ****  ***** * *  * ** *   **     
* ** *** ** ** **  ** * * * * 
*     *      **     ***  * *** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
*   *    *     *  *****  **     * * **  ***** %d",&m,&d)!=EOF)
    {
* *   ****  * ** **     **  **    *  *   **  *  * * ****   * *** * 
  *   * * *  * ** *  * * * ***  **    * **   **  ** *   * * **  
*   **  ***** *   ***       *****  * *  * **   ** * * **** * *      *  *    **    *  *****    **    * **  * * 
 ****      *  * * ******* ** ** * *    *  ** *    * *  if(s==1)
*     **** *   *  **** *  *  * ***  ** ******     * ************ ***  * ** ****** *    *  * ** ***
**  * *     ***  *     **  *  ***    **   * ** * *** if(s==2)
 * *    *****  *       *** **  * **** *** ***       **    **  *  *  *******  ***    *    * ** *** 
 ***  ** * * ***** ** *** ***  ******** ********** * * * *** 
** ****** * **  *   ***** * *  ** **  **   *   ***  *  * * * ***** *** **   ** ** *     * ** 
    }
  *   ************ **** * *  *** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  *** *** *** **

int main()
{
int M,D,S;

 *  * ***  * * * *    *  * *    *
 *** **  *
   *  
{
* **** ** * *      * 
}
 * ***
{
******    *** *** * * *** *  
}
  ***  
{
 * ****   ** **        
}
 ***** **  **  ****  * **  

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.51
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.1k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.7k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 5.2k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.9k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users