期末考題目-Question 3

1 like 0 dislike
10k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 10k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
  *** *** **   ****** ** **  *  * *     ***** *  ***** ***
*******   * ****** **  **   * 
 ** ** *  * * *****  *
 *  ** *  *** ** ** * *****   **  ** ****
 ***   *  * *  **** *  ** 
***  **     *   * * **   ** *******   **     
*  ** *   ***  ******
   *   ** ****  ** ** *  * *  * * ** 

**   * *****   *** *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 ******  * *     ** ****  ** **** ** *** ***    ***   ***     *  
*  * **** ****   * **     ** ** 
* ** ****  * *  *  ** **  **     ** ****
* *  *     *   *  ****    **  ** ** ******  **   *  * *  *  ***** * *  
 *   * **  **  *** **      if(s==1)
 * *******   * *   *      ***** *** * *     * *     *    * * ** *** *  ****  
   **   *  ** **  ****  *** *    if(s==2)
  * *  * ****  ***    **   ** *    * * *  *** * *** *** ***   *   ** *  * * 
**  ** ** *          ** * **  **  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
    * **  *** *   **   *   *** M,D,S;
    
   ** ** **  *   **  *  ****** *** **** * **  %d",&M,&D);
    
* * ***    * **         *   ****
 *  ****  *  * **  *    
  *  **** ***    **  **    ** 
*  * *   ** *  *** *   ***** 
****   ** * ****  *** * *** * ***** *  ******  **** *  *** **      * *** * **  ** *
 * ***  *  * ****   **  ** 
    ** *  * *** * ** * *  *  *  ** if(S==1)
   **   *** * *  *     * *     
    * ****** * * * ***    ** * *    *    *    * *    *   *  *** * **     * **  ** ** ***   
   *   ** ***   *    *     
 **** *  ***   * * *  if(S==2)
***** *  * ***      **
 ** * *  * *  *   ** *      *   **  *  *    *     **   ** ***** **  **    *  **  * ** 
    *  ** *   **   *   * 
 * *  *  *   *       * ***  ***    0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
* *       *   ** *   ** ** m,d,s;
****  * * *  ** * **    *** *
 ******    **  * * * * ********* ***    %d",&m,&d);
    
  * * *    **** *    * **  *     + d)%3;
*** * *         **** * *  
* **     * ** * * **   *  * *  ** 
*  ***   *** *** ** **     *
 ********  ** * **  ** ** ****    *   *    ** ** *   * ** ***** * **  **
**** *      ** *** *** *** 
***  * **** *      *****    *  ** if(s==1)
*  *****    **  * ** *  ** * 
 ** **  * *   *      *   * ** *** * * **   *  *   ***   ** ****  **   **** *  *** * *
** *  * * *** ** **** ***   
*  * * *    ** **  * **      *  if(s==2)
 *****  **     *** ****  *  ***  *  
*  *   *   ** ***   *   *      * **** *  ** * ** ** * * ******* *    **   * **** *
  *  **** * * * ***  * * * 
 **    *  * *  *** * *  
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ***   *  * * **** *
int main()
{
int M,D,S;
  ** * * *    *    ***** * * **
scanf("%d   **  ** * * *  **  **  * *
S=(M*2+D)%3;
if(S==0)
* ** **     * ************ * *          ****   **
**     ** ** **  *  * * **   ***  if(S==1)
* * ***** ***  * **** ** * *    *  **** **** ** *  * *   * ****
    * ** **  * *  * *  ***** * * * *   ** ***     * 
 *  ***** ** *  *    ** *  ** * **      * **** * *  * * * * ***  * * *** ***    *   *    *** *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 ** ** *   * **  * ***  * ** m,d,s;
     **  **  **  * ** * * * ****  ** *   *      * **  *   *   
  **** * * ** * ** ** * = (m*2+d)%3;
* * * * ** ** *  **   *  *** (s == 0)
   * *  *** *** ** * * *  *   ***   ***     *  **  * 
  ** ** *  ***       *   *  *      if (s == 1)
  **  ***  * ** *   *  * * *        ***    ** ** *****   **
 ***** *****  ****** ******* * if (s == 2)
  *    *  *  * ** ** * *   * *  ***  ****    *
***  **    *  ****  ******
**    *  **    ** **    **  ***    0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
**** ******    **  * **** ** M,D,S;
 *  ******  *   ******* ** ****  ***** *  %d",&M,&D);
* **  * ****   *   * *   *   ***
** * ***   *    ***  * ** *  *
 ** **  ******  *   **   **      ** *   ***
*   * ** * * *   * ** * *       **
**     ****** *  *** ** ** ** * ***  * * ** ****
**** ***      ** ** **  *   
** *  **  ****  ****  *** * *      ** *******
 *   *  **  **   ** * *** ****    0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** * * **** * ** * * * * *****  *  m,d,s;
 * * *    * *   *** ***    *   *  * ***   *** * *        **   **
**  * ***  *    **   *    **  ** = (m*2+d)%3;
   *** * ****  ***  * *  (s == 0)
* * * *       ** *** ** * **** *** *  * *** *  
   **  ****   * ***  *  *   * if (s == 1)
*   ** * *  *  **   ** *  ******* **    *   *    * * * 
** *   *  ** ** * **  *** **** if (s == 2)
   **** * * ** ** **  *  *  * *********   ***  ***   
   * * * * * ** * **   * *
 * ****    *    **   ***  ** * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 *    ******  *** ** * *  * * ** * **** ** %d",&m,&d)!=EOF)
    {
**** * *   * * * ********   ** **   * **** ** * *    * *
*   * ** * ***  * *** * * *** **   * * *    * ***  *  *** 
**  *   * * *      * * *   ** ***** * ** **** *   ***  * *    * *  * **       *           * *     **   *    *  
**  * ******* *  ******    * ***  *       * *  *  *   **   ** if(s==1)
** ****** ** ** *  * **  *    * ** *  *    ******* **  **  **   ** *  *  *    *  ****  ***  ** ** ** ****     *
*    * ***  *   ****** **  * * ******   * *   **     * ***     if(s==2)
 **  * * **    * *** * ***   ** *   * *  **   ** *    *  * *    **  **  ***    ** ** *  *
 **** *     * *       *   *  *** * * * ****  *****  * *  * 
 *** *** *  *    * *   * * *   * **** **  ** ***** ***  *  *   * *  **  *  ****   *  
    }
** *  * *     * ** **     *  * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * * **** * *  *  

int main()
{
int M,D,S;

     ****      * ** ***   *** *    *  
**  *  * *
 ** **
{
*  * *   * *** **  **
}
 **    
{
 * *   **   **** **** * 
}
* * * * 
{
**   *  *   ** **  * 
}
* **    * * *   * * ***   *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.139
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.7k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users