期末考題目-Question 3

1 like 0 dislike
1.7k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 1.7k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
  **** * *  ** *** *  **   * ****  * * *   *  *******  *** 
* * *  *** ***  * ** *    *
   ******  * *  ***     *
 **  **   * * *** ** * *    **** ** **  
* *** * *   * ** * ** * ** 
*    **  *     ***    **  * *     ** ***  *
*  ***  *   * * *** *
  **  ****   ****  **** **  ** *   ** * *

   ********  *  * * *   *** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
  **   * * ******  ** * ***   *   * **** *    *   * * *  * 
  ******    *** ** ******** 
    * **   ** * ** ****** **  ** 
* ***  * * ** ***  ****     ** * ***   *   * *******  * *      **  ** ** 
 * ****    ***  *** **  ** *** *    if(s==1)
** * *  ***  * * *  *  **   * *  * * *  *****   *  ******   *    **** *   *
**  *  ****     *** *******  *  if(s==2)
*** * ***  * *   ****   * *   *** * ** *    *   *    *****  * **** *     * **
 * *  **  ***   *** *** ** *  * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
     *   *   **  * *** * *****  M,D,S;
    
 * ***    * **     * * ******  **  %d",&M,&D);
    
* ******** * * * **    * **    *
      ** **        ** *  *** *
*   ** * ***  * *  *  **     * ** * 
  ** ***  ** *  ** ***    *** *
******  *  *  *   *  * *     *    * **  **** * *********   *****  *****   ****
  ** ** ** * *   * * * *   *** 
*  * *** ** *   *   *  *  **  * **  if(S==1)
  *  * ** **    **   * *** *   * *
** ***** *    * ** ** *   ** **  **** * *** *  *   *          ** ***  * * **   **
* * **** ** ****   ****
  ******* * ***    *   * *  *** **** if(S==2)
  * ***      ** *   * *** ****
*** *      **** *  *   * *  * *   ***** ***  *  * **  * **** ** * * *  * **
  **** *  * *   ** ** * 
** *    **   *** **  ** ** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
   * **  *** ** **    ** * *  m,d,s;
  ***  **  ** ****** * *
   ** **** ****    * ** ***   * ***** * *    %d",&m,&d);
    
 **  *   **     *  *   *    * + d)%3;
*    ****  **      * ***     *
** * *** ***  *** * *** *    *  *
* ***  *     * *** **  ** 
 ** ****  *  ** *  ***   **  **  **  *   * *     ***  *   *  *  ** * *  
*    ** * * ***** * ***  **   *
  *** *****  **  **** * * *   if(s==1)
 **  *   * ***   *  *** 
        *** * ** * * * * *   * * **  **  *  *    ***  *   * **  *  *** ** ***      ** 
** * *  ** * *  * ** *  * ***
   * **** **   *****  *  *** *     if(s==2)
* ******     ** *   *      *** 
*   **  ****** ** *  * ***  ** ** * *  * **  **    *******  *****    **   **     *
    *  ** * *  ** *  **  *   **
*  *** ***   ***   ** ** 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** ***   * *   ***   
int main()
{
int M,D,S;
   * *****    ****   * * ***       
scanf("%d    * **    * **  ***** *
S=(M*2+D)%3;
if(S==0)
   * ** ** ** * *  **   ***  *    *  *    **
    *    ***        **     ** if(S==1)
*   * ****  *** * ** * * * * **    * *  *** ***   ***   ** *   
* ** ** ** **  *  *  *   * ** ** *  ** ****   *    *    * *  * *
*** *** * *    ** *   ** *     **  * ****  * *  * * **  * ** ** **  *  *   ****   *** **    *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*** *   *****  *    * * * *  m,d,s;
  *   ** *     *   **  *   *** ** **** * * *** *  **   *** **  * *  *
* **** * * * * **  * * ** *   = (m*2+d)%3;
***  * **** ********** *        (s == 0)
 *******  **    *  ***  *** *  **   *  *  *  **
**    * * *  *** *   *** * if (s == 1)
 ** *       **  * **        **** **  *  *** ***
*    * * **** *  *  **    **  if (s == 2)
*  ****   *  * ****    ** ** *  *  *    ****
*  **  * *        ******* * *
   ***   * * *   * **   ** ***   ** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
** *     *** * *  ****   M,D,S;
***** * *   * *   * *****    ***     *** *  ** %d",&M,&D);
   *  **     * *  * *** * *    **  *
* ** * * ******   *  **** 
*** ** *  ** ** **       ** * *   **      *    ***  *
  * **** *** **** ****** ** 
***    ****   ****  * * ***       *****   * ** *  ****
 ** ****   *  **   * ** *****  *  *
* *  ** *   **** *** *****  ***      *   *** *** ** * *
 ****** ** * * * **  *****   ** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   *    **  *  *   *** **  * *  m,d,s;
  ***  **  ** *** * ** *   **  ** **  *** **  * * *  ***  ** *
 *** * **     ******* * *  * = (m*2+d)%3;
 *       ***   ** ******  *   *  (s == 0)
* * *** *  ****     ******** * **   *    ***** *  
****   **** **  *** **  *** ** ***  if (s == 1)
**   * *  *** * * **  ** ** *    ** **** ***
     *  *** *** * ***     * *   if (s == 2)
* ** *  * ****   * **    * *   ***** *         **  ** *
 *      * ***   ****  * *  *
  *    * ****   **  *  *** ***  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 ** *  * *   **  * *  * * *   *   *  * ** %d",&m,&d)!=EOF)
    {
* ** ** *** *       * ****    *     * ********  **** ****    
 ** *    *** ** *   * * **** ****    *     **** * *   
**** * * * ******  *   ** **** * *  **     **  *  ** *  ** *  ** ***  *    *   *   * * *** **  * * **     
** * * ** **  **   ** * ***  * **   ** *  ***       ** if(s==1)
**  * * ****   * * *  *      *   ** **   *  * *  ****     *   **   ***** *  ** *    * ****  *** * *
 * *  *    * * *   * ** ****     *****  **  * ** ** **** if(s==2)
*    *   * * * **** * *  **  ** * *   * **   * **   *   *** * * *****   **** *  *  ** **** **   *** ** *** *
  * *    ** *** * * *** *  **              ****** * *  *
   * **  ********  ** *****  * ** *  * *   * ****  * * ****     ***** * * * ** ****  *
    }
* ** **  *** * * **  *******  ***** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ***     * *    *** 

int main()
{
int M,D,S;

 * *  * * ***** *   *    *   *    ** **   
*  * 
  *** 
{
 *   * *   ***** * * *** *  **
}
   ** 
{
* * *  * ** **  ** ** ***  
}
*   *
{
   *** *  **         * **
}
*     * * * * * *** * 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.219
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 804 views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 735 views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 775 views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 688 views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 621 views
12,783 questions
183,443 answers
172,219 comments
4,824 users