期末考題目-Question 3

1 like 0 dislike
12.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 12.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*  * *   **     ***  *  * ** **     * *** **** * *   *** * 
 ****** *    *     ** **    
**           * ** *   ****  
******** **  **** * * ***  * * ***     
  ****  ***   * * * ** *  * 
 ** * * *   * ** *  * **** *     * ***** * ** *    *  
  *    **    * *****   * *** 
*    * ***** * ** *  **    * ***** *** *

      * *  *   *      0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*   ***  *** * * ****** * *     *    *  *    *   * **** 
   ** *****       ** ** * 
  *  ***   *   ****   * **  *  *
* * *    ***  * **** *  ***** *  *     *  *** ****  ***  ** **   ** ***   **
**  ****  *     ** ** * ** * *  ** if(s==1)
* **    **         * *   *  ** *  ***    *** **** * **  * ****    **** *** **  
 *** * ** *****  **** *   *  *  *  if(s==2)
**** **   * * * *    ***** *     **    ** ****  *****       * * *   ** * 
** *** * *  * *  *     ***** * * * * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
   ** **  *** ***    * *    M,D,S;
    
*  **   **    * ** * * ***  * * *** **  %d",&M,&D);
    
 *  * *     ********* * *    *  *
    * * * *** *     ****  
       * *  * *** ** *  * ******   
 *    **     **** *** **** 
  ** *   ****  *     **  *  * *  * *   * *  *   **** ** *    *** ***** **  * *  ****  ** 
  **   *** **    *  * *  * 
*      **** *** ** **   * ****   if(S==1)
  **     *     ***  * *** *
 * * * ***  *  ********  ** *  * ****** *    *   *** * *    *        ***** ** *** * 
**  ** * **  **** ** *  ** 
  *** **   * * *  * **  **   **** if(S==2)
 * * **** ** *     * **    *  *
  * **  **  * *  * **  *  *** **  * ******** * * **  * * *** ****    **   *    
 *** * **  ****    ***
* **  **  *  *** ** * **   *** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
       **  * ****** *      * **  *  m,d,s;
 * ****  * *  **** * 
** *   **** * * ****   *  **   *  * ***  %d",&m,&d);
    
** **    **   **   ** ***** ** + d)%3;
 * * ** * **   *****  ** *  ***** 
 *  ****       ** * * *** *  
  **   * *  **   * * * * * *
  * **     ***  * *  *   **** *   *** *  ** *  * *  ** ******* 
 ***** * * **   ** * **  * *  
***   * **    * ** * * *  * ***** if(s==1)
   ***  *** ******  *   * **
  ** *  *   **     * *      **   * *   *  *** * ** ***    * ** * **  *  ****  **  *  *** 
*  **   * ** **    *  *** *  ** 
  *** ** *     *   *  * *     * *   if(s==2)
 *   *** * ** *** * * ****
* **  *   * * *     ******** *****   * ***   **    **   *** **  **     **    ** **
*     * * *  *    ***** *
     ** * ****  *** **  ***    *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  *******  *   **   **
int main()
{
int M,D,S;
   *** **  * **    *    ***  **
scanf("%d ** *  *    ** *   *        *
S=(M*2+D)%3;
if(S==0)
* *  ***   *  ***  * **     ****** * * 
 ****  **  **       * *   * ** if(S==1)
*  *  ** ** ** ***** * ***    *  ***  ** **** * * *   *** *   *** **
*** **    * * ** ** ******* * **  **  **** ****  *  
** ** **  *   *   **  *** ** ** * * * *  **      *   *  * **    **  *** *****  * * **    **    * *  



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  ******* * * ********* *    ** *  m,d,s;
   **** ** *  * ** ***** ** *    ***** *  * *  **     ****     * 
  ******   ** *** ***  *** = (m*2+d)%3;
 * * *    **  ** *  * **** ** (s == 0)
*** *  * * **       *   * * **** *  **      *      **    
   * **     * *** * *      * if (s == 1)
*   *  ****   * **** *   *  ****** ****   ****     ***
** * ***** * * *   *** **  if (s == 2)
 *  ****   * *** **   **   ****  * *  * *   *  *   *
* ******  **** ******* * * 
  *****    *** ** *    ****   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 * * *   *** * * *    ****  M,D,S;
     ****  **** * ***   * ***   **   * *  *   %d",&M,&D);
*  ******        *  ***       *
  **    *   *  *  ** ****** *****
   * *** * *  *  ** ****     *  **   *       * ***  *
** **** *  *  * **  *** * *** 
 ** * *******  * ** **      ** *  *   **** ** *** **
  * * **** * *  * * ** * **  *** *   
* *  ***  *   *  ****   *** *   * * ****   ***  *   *  ****  
*    ***    ** *   * *   *  *    * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  ****    *            * *** m,d,s;
    *  ****  *  * *  *** *   *** * * **    * *   ***  
 ************* ** *   **  * ** = (m*2+d)%3;
 ****  ***   *     * **    (s == 0)
 *****   **    **  *   ******  ***  * **  * * *
*   **  ** * * * * *      *  *   if (s == 1)
    * **   *   ** * ** ** ** **** * * ** * *** ***   
* *   ********  * **    * if (s == 2)
*  * * * **  *  *        **  **  * * * **  * ****
** **   ** *   *  * *  *
 * * * *    * * **  * **** *  *  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
******** *   **** ***  * *  *   *  ** ***   %d",&m,&d)!=EOF)
    {
*  ** **** *  * * *  * ****  *  * ** *  ***** ** **    ***   *
  ********   * ** * * * ***** * * *  **   *  *********     
* *   ** ** ** ******   ** ** * ** *  *** ***  ** *    *    ***  *** *   ** **   *  * *** * * ** ***  ** ***
* **   *   * **   ** *  * *     *    *** *******  *   ** if(s==1)
* ** **    ** ***   **** ****     ***  **** * **** * *  *       * **     * **  ** * ***** ****  *** *     * *   
    **  ** * ** ***    **   **** *   * ** ** **   * * *  *  *   if(s==2)
***   *    ***        *    **  ** ****  *  *   **  * ***      *   ****  *   *  * * *** ******     *
* *   *  *** ** ** **  ** ***   *  *  *** * **  *** * * *
  * ** * *  * **   **** * * * *      *****  *** * *   ***   * * **** **  **   *  * * ** **
    }
 ** **   * **  **     *  *  * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *  *** *   * * *  * 

int main()
{
int M,D,S;

*  ** ** * **  ** * **    * **  *   **
***  *
 ***
{
  *    **    *   * ****
}
** 
{
 * ** * * **  *   *  * *
}
  ** 
{
  ** *   ** *     *** ***  
}
 *** **  **     *  *   *** *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.97
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.3k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users