期末考題目-Question 3

1 like 0 dislike
12.5k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 12.5k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*  *  * *    ***  * *** *   *  ** *  **    **** **  *****  **
 * ** *******   *** * ****
      ***  **    ****   *  *
***** *  *  * **     ***  * *   ** *   ***   * *  *
    * **** **     *
  * *** *    *  *  **** *** ** ** *       **
* * *   **** *  ******** 
  * * *   *  ****  ** ***  **  * ** *    *** 

* * ** * ****   *** *** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 **    ****** *** * *   ***  *** ***  *****      *  *** *  ** *  
** * ***        **   ** ***  ***  
**   * * **    *  *       * *  *  * 
** *  *     *  ****    * **   *     ** *** * *   ***** * *** *******  ***
   *  *  *  **  *****  * if(s==1)
 *  ** *  *** * *****  **** * * * ** *  **  * * * **** **  * * **  *
**   *   * * *    * ******* **  *  if(s==2)
*       ***  ** *****  *  ** ****  **  * **       * *** **  ** ** *   ** **** 
 *    ***** *  *  *  *   ***** **    0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
  **   *  **  ****  *  * *      M,D,S;
    
*  **  **    *  * ** **    * ** *** **  %d",&M,&D);
    
***  **    *  * *** **  *  *  ** * **
    *    *** * * * ****** *
**  ****** ** *****  ** **  * ** 
  *** *   * *  **  **  
 ** *   * **  ** *   * * ***** *  ***  **   *   *** *  * ** *  *  * * **   *  ******* 
  *** ****  * * *  * ***  * *
** ** ** * ******     ****    if(S==1)
*  ** *  *     **    *  ***
 ***    **    **  *   ** ****   * **   **   **  * **** **     *      ** *     *** * *    
 **  * *   ****** **   * *  
 *** ** **  **** **   *   * ** *  if(S==2)
* * **  **    *  * * * * * 
* ****  **    *  ***** * *   ***    *  * *  **   *  * ** **  * ****  **   * ****
*  ** *** *  *** *  ** ***
 *****   * *    *** * *  *  ***  * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
   ******* ******* * * ** ** m,d,s;
  *****   *  * ** *  **** **** 
***    ** *  ***   *   **** **  **  ***** %d",&m,&d);
    
* *   ***     ***  *   **  *** ** + d)%3;
****  *  ** ** ** * ** **
* * * *** *     *** ** **** * **
   ****  *   ***  * * *    
     *** *** ***  ****   ****  * *      **** **     *** * *     
*    *  **   ** *  ****      * 
 *  ***     *   *  *  *** * if(s==1)
*  **   *  **  **    **  ****   * 
 *  *  * *   ***  **   **** *  *  ** *   **  **   *    *   * *    *** **  * ** ***    *  *
  * *   **** *  *** * **  **
 * **    *   * *  * *  * *   * if(s==2)
  *    *** *  *       ***
*  **  * * *      ** **** *    * *** **  *  *****    *  *  *  *  ***    *   ***** *
   ***  ** ***  *   ** *
  *  ** *** **** ** *  * *  *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
************* **     
int main()
{
int M,D,S;
* ** *   * ** **  *  * ** ***   
scanf("%d  *** *  * *    ****   *
S=(M*2+D)%3;
if(S==0)
***** *  * **  *    **  *  *** *  ** ******* *
* *  ** *      *  ** * if(S==1)
*   * **       *       **   *  ** *** ** * ** **  *    * **
   **    **** * ***  ***** ** * ******* *   **** ******    
*  *  * ** *    * *    *  * *   ** ** * **  *   * *   * * *  * ** * ***  ** *** **  * ***  ***      *  *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*   *** * **   *  * *   ***** m,d,s;
* **    **   *    ***  **   *  *  * *** ***  **** ** ***    * 
 *   * ** *   *  * * ** ***  = (m*2+d)%3;
* ** ** **** * * *  ** * ***  * (s == 0)
***  *   *****        **  * * ***** * **  * * ***
   ****  *  ***    ***  *  **  if (s == 1)
 ** *   *  ******    *** * ***  * **  ** **** ****
*** ***** * * *    * *  ** **    if (s == 2)
 ***   *** *  **        ** ***  * *** ***** **  
*****     ****   * * ****
* * **   *   *****  * *  ***  *   ** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
*  ** *  ***   *       *** **** M,D,S;
  *****   *      ** ** * * *****  **     * %d",&M,&D);
      ***          * *    ****  *  
*  *  **      **  *   *   ***  *** 
 * * *** ***** **      *      **  *    *  * * *  *
*  * *   ********** *  ***** * *   *
        ** *   ***  * **** *** ** ** ***  **** *  
     *   **********         *  ** 
 ****   *  * ** *  *   * *** *    *** ***   **   ** 
*   *  ** * *  *  ***** * **  *   **  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   **** *   *    *   *   ***  * m,d,s;
 *  * ****  * **    ** ****  *  *     * * * * *   *   ***** *  *   * ***
***  *** ***  * *  ** * *** * = (m*2+d)%3;
**** *** **       *       ** ** (s == 0)
  *  *  **  *     *  * * *  *** *  *** *** * * ***   
*** * **          **   if (s == 1)
 * * * *    *  *    **  ***** * *    *   **** *   ***
*** ****    *****  ** ** **  if (s == 2)
* * *  ** * **** * *  **      **     * **** ****  ***  
 ***  * ** ** *  *  * **   
   *  ** * *  *** *** * * *  * *  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
* * ** * ** *******    **   *   ***    %d",&m,&d)!=EOF)
    {
 *  **    * * **  *** ** *  * ******  * *  *   *    ** ***  ** 
* * * * * **  ** ** ***** * * ***    * ** * * * *  
  * **     * * * * ***  * ***     **  ****  ***   ** ** ** * *  ****  * ***   **  * ** **        **  *   **
   ****** **   * * * * ***  ** * *  * * *** * * ***   * *** if(s==1)
** **    ** *   * *   * * *   *     *  **** *** *    **** ***      * ***  **   **    * **   ** ** * *    
  *   * *   * **** *****  ***   **** ** ***  ** **    *  ** if(s==2)
   * ** *  ** ****    **  * *          ***   ** ** ****   ****     ***** ***    *  * ** *  * ** *** 
******* **        * ***   ** * **   *********    * ** * *****
 ***  *** ****** ******      * *   **** ** * *      **  * **  *  ** *** * *    *  ***
    }
 **      ***** * *  * **     *  **   0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***    *    *    ***

int main()
{
int M,D,S;

** *** ** *  **  * *  ****   **** **   
    * *
*    
{
  ** *  *** ***     **** 
}
  ** *  
{
***   ***** **  **  *  *     
}
**** 
{
* **     * ******* *
}
 * * *   ** ** * ********  *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.170
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.6k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.3k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.3k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users