期末考題目-Question 3

1 like 0 dislike
10k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 10k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*  * ** ** ***   *  * * * **** *   * ** * *  *******   *  *** 
 ** * *    * *  * **   ** 
 * * *** *  ** ** ****   *
   *** *  **   * **** *  *  *  ***  * * **       
*  ** **  * *** *  *** * 
** * ***   *** *    *   **    * ** **** *   * * 
* * **  * *    ****   ******
  * * *** *    * *   * * *      *   ****** 

  * *** *  **    **   ** **  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
      ** **  *  * **  * * *   **   *  * ** * * * ***   * ** * ** ****** 
*   **    * *** **  * *    *** *   *
*     ** ** * *  *    *******  ** 
  **  ** *   * * * *  *        * ******* * **  **   *    * * *   ****   * **** *
* * ****     *** **  ** if(s==1)
***  **** **    *  ** ** ** **     *  * *   **** *** **  ******
  ** **  *** ****    **  *       if(s==2)
      **   ***  ***  *  *    **   * *  *  *  ** **  *  * **     * *    
 * ** * ** *  **    *    **** ** *   0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 * ** ** ****  *  *  * *  ** *  ** *    M,D,S;
    
    **     ***  **      ***  *** %d",&M,&D);
    
*  **    *  * * * *** * *    ** **  ***  
**    * ** *   ****    *    
* * *   ****   **  ** * *   * * * *
* **  ****** ***  ***  ** **
*   *** *     * *** ** *    *******  ****  ****      ** ** *  * ** ******  ****   * ***
   * **  * *****  * *   ** ****
 * *  **    ****   *** ** * if(S==1)
  *     * * * *    *** ***** 
**     ***   * ** *  ************  *    * **** **    **** * ** * **  * * * **   *    **
  *** ** *** *  *** ** **  ** 
  *     **  *  * * ****   *  ***  if(S==2)
 * ***** *  *  ** * * ***** 
*** *** *      * **    **   *    *    ***  *  ***    * * * ** *** ********    *  *  
 ** *  *  *    ****  * *  
  * **     **  *   ***    *   0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
*  * ***   *  * *       *   m,d,s;
**** *  * **   *  * ****
 ***** ****   * *** *** ******      *   * * %d",&m,&d);
    
 ** ** *  ***  *** ** **** * **  + d)%3;
  *   * *  ** **  *   ****
*  *   *   *  *  ***      **   *  *
 ** *  * * *   **     * 
 * * *** *    * * **  * ** ** * * *  * ** ** *   *   *** ** 
*      *   * * * ***  * *** * *
  ****** *    ****  *** *   * if(s==1)
***   * **** *   ******  * **    
* * ** *  *  *    ** **  * ******   **** * * ** * *** *   * *** * **  ****    
   *  *    * * *  *   * *
*  ** *   ***  **   **    * * if(s==2)
*   ** ******   * **** *  *
    *   *  *****  ****  ** ***    * *  *  *  ** * ** * ***   ** * ** * ***  **
 **   **  *  *  ***    *  * * 
*****    ** * ** * *  *  
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *  *  ** ** *** ** 
int main()
{
int M,D,S;
* * * *   * * * **  ***  ***     
scanf("%d    *  ***  * **  * *
S=(M*2+D)%3;
if(S==0)
  * *     ********* *  *   * * *** * *  * * 
* *   *** ** * **  ***  **    **    if(S==1)
** ****    ** ***** * **  ** *  * ****     ****  ***** ** 
*** **** **  **  *   *  *  *  *   *  * * * *  *** *
   **  *  * ** *** * * *** *   *** **  **** *  * *         ****  ** ****   *    ***      *    *  * * 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 * **  **** *  ** * * **  *  m,d,s;
*  * ** * * *  * **  *  * **** ** *  *   * *    *     **    ** *
 * ***   *  ***   * * *** = (m*2+d)%3;
  *  * ****    ** *** ****    (s == 0)
  ** **  *** *  **    ** *****     *** **   **** ** *
 * ** * **    ** ** *** * ** *** if (s == 1)
 *****   **  ***   **** * * **   *  **   ***  * * **  
   *  * ** ***      *   *  ** if (s == 2)
  *   *   *      ****  *  ** ***   *   *   ***  **       **
   *       * ** * **** *  *  *
*    ** * *  *   * *  ****  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
* *  * * **      **    ** ** M,D,S;
 **** * * ** ***  * ***** *  * ***   *** %d",&M,&D);
*  * *   ***    * *  ***  * ****
  *  ****   * * *** *  * * **    *
***** ** ** * *   ** **  * ***  * *   * *   *   * * * 
**       *** * *    *   ** * ***  
*** ** *   * ****  ***  * ***   *    ****  ***
 ****** *   *  *  ******  **** * **
   * * ****       * *****   *** *** **** **  **  ** 
*   **   ***     *    * ***     0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** ** ******* *  ***   m,d,s;
** * ***   *   **  ** ****** ***  *  * ***  *** ** * ***** ****
*    *** *    ** * ****** = (m*2+d)%3;
  * *  *    * ***   *  (s == 0)
 *  ** *   ***** **  ****** **** *     ** **  * * **
* ** *** *   **   ** ** * ** * *  if (s == 1)
    **  **  **   * * * *  * *    **    ** * **   * * *
 ** *** * ***     * **  ** *** if (s == 2)
 *** *** ** *       ***   * *  * *** *********** 
 * * **    * ** ***** *
 * *   *  *   * *    *  *     0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
  *     * *****         * ** **  **** ** **** %d",&m,&d)!=EOF)
    {
 ***   *     ***********   ***  *   **  *  ** ******* * **** ***
 ** * *** * *     **     * * ** *   * ***   *** *  ***** * * *
   ******  ***** * * ** ***  **      *  **** *    **  * * ****  **  *  *** * **  **  * ** ****    ****  *
 *   ***  *     * *  *   **  *** *   ** ***   ** if(s==1)
    **** ** * ** *   *** ***** * *   **** *  *    *** * ***** **   * * *******  **** ** *  * **    **********
* * * ** *  *      **    *   * *  ** **  *  ** **   *       ** * if(s==2)
* * * ** * * ** * * ***   **  * *  * *** * * *** ** * * * * *   *  *  *  * * * *  ** **  **** *   * * **  
 * ** ** ***         * * ** **    * *  * ** * *   * ** 
      * **** *** ** * * ***    **     *  **  ****    * *     * *  *    **     * * 
    }
  *** * ***  ***** ***   0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * ** * ** *  ** ****

int main()
{
int M,D,S;

 * *  * *  ***   ** **      *  * ** **  *
 * ** *
  ** 
{
  * *  *   * *  ***   * * 
}
 *    *  
{
*  *  **  *   ***    *** 
}
**    *
{
***** ** ****   * * **
}
**  * * **** *   **      * 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.223
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.7k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users