期末考題目-Question 3

1 like 0 dislike
1.7k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 1.7k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 ***** ** * *   *    *     *    * **** ***   * * *  *  
* **   * *** *** ***   
        *   ** ****     **   
  **   ** ** * ** ******  *  ***  *** * ** **** 
* * **** * ** * * ******* **
  ****    *** * * *   * * ** *   *  ****** *
 * * *** **** ***     
** ** **  * * *****   *   * *  * *      * *

** ***** * *** ** ***  * * 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
* *   *** * **** ** *       ** ** ** ****** ** * *  ****    ***  * *** 
****  *  * *** **  ** * *  **  *   ****
** *  *****   * *  * *** * **   *  
* * * **   **  *   **   ***** *  **** ****    *** ***** *  **     **
 * ***  **     **  * ** ***  *   if(s==1)
  * ***  ****   * *******   *****   ****  *  **  ****** * *  *    **** ***** **
**   * **** **   **   *   *** if(s==2)
 * ** *  *    * * **   *   ** **   ******* * * *  ******          ** **** **
**** *** ****** *   * ** ** * *  * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 * *   *   ****  *   * * ***  M,D,S;
    
 ** * **   ** *   ***  * *  * ** * %d",&M,&D);
    
      *  * *  *    ** ** *** *** **   
* * * *   ** ***** * * * **
**** ****  ***  * *     **   ** 
*** * **     * * *  **  * 
** * *** ***  *      **      * *** ***  *** ** ***  *  *** *    * *  **  **
 * ** **    *  *  ****    
* *      *** ****  ***** *      * if(S==1)
*    ** *   *  ** **  * *  
 *  * * *** * * *  *  **  * * *  * *   ****  *  **   * **    *  **        * ** ** *
*   *      ***  *   *   * **  *
** *  **  *     ** *  *  *  ** *  if(S==2)
**  * *** *     * * ****
   *   * *        ***   *** **   *  *  *** *  *** ***  * ******* ***********  * ** *
    * ** *  **  * **   *  ** *
 *  *****  *        *  **** *****  0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
    * * ***  * **  ** ****   m,d,s;
   **** **  ** *** ****  **  **
* * *   ** *  * ** ***    *** *** * %d",&m,&d);
    
 ** ******* * ** *    *  * **   + d)%3;
    * * ** *    *** ****  *   
******** ** * * **  ******   
  ** **   **     *  * ***  
  **  **     *  **** * ** ** * ***  *   ** ** ****  ** *      *     **
*****  **  ***** *** * *  
** **** * * ** *** * *    * if(s==1)
 *     * *  ****  * * ** *
******   **  *  *  * *   *  ***  ** * ***** * *   **      *  * *   **  *         *
  ******** *  ** *  *  ***
***  *   **   * *  *** ** if(s==2)
 * * **  ** * *** * **  * ** * 
*** * * * *   * ******  *****       ** ** ** **  *** *    * ** **  * ******** ****
  ** * ***** **  * * **
*  * * ***** *   **  *  *  *** 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   *   * ***  ***  * **
int main()
{
int M,D,S;
 ***** * **  ** *  ***  ***  ** ****    *
scanf("%d *****  ********** ***  *
S=(M*2+D)%3;
if(S==0)
*  * * * ** * ***   **  *****   * *   **  * *  *
 *  *  * **       ** * * *   * * ** if(S==1)
  *    *  *    ***** *  *   ** *** ** ***  **** *  *** *  *
 ***    * * ** * * *    ******  * * ********* * ***     
 **   *  **   **  ***** ***  *    *  **    ** * * ** **  * **  * *** **  ** ** *****          * 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* *   * ***   ****  * * m,d,s;
**** *** *   *** * ** *  **** **   *   *   *   **  ***   
  *   *** *   * ** * *** * = (m*2+d)%3;
 * *  *   * * ******* ***  *   (s == 0)
** **     **      * **  **  **  * * ****   
     * *** * * **  * * * *****   if (s == 1)
***  ** ** * *  * *       *** **   * * **********   *   
*********    ** ***     **  ** if (s == 2)
 **** *     ** *  ** *      * **   * **  * *  ********
*  **  *  **     ***** *   *  *
**  ** **  **  *    * *        0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  *** * *  **  *** *   ** ** M,D,S;
 * **  * ** ***  **  **  * *****  ***   %d",&M,&D);
*   *  * * *  *  ***  ** **   *     
 **  **  * * * ****  ******  *  * 
 ** ****** *** **  * *  ***  ******* ** **
     **    **  * * *  *  *****   *** 
 **   *  **   *** **     ***** *   *** *   **   **      
*  * * ***  *** * ***  ****   **  *  
 *   **  * *** *** * * *****     **  * **
     ****  **   *    *** * * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** * * * ***   * *  *  ***   m,d,s;
   *  **     *  * ** * *  *****    *** * ****** ****  * 
*       **     *** *  = (m*2+d)%3;
*    **    **** *  * **  ****   (s == 0)
 **   * *  ********* * *   **  * * *** **   * **  
     ***   *   * ***    * *   * if (s == 1)
* * ***    * *  * **** *  ***    ** * * * **  *     
 * ** ****** *    * ***       * * if (s == 2)
*     * ****    **    *** *     ***  *  **    ***   
**  **   ******  * * ** *** 
    **  **   ** * *   * ****** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 * *  ***** * ***   *   ** *** *  ** **  * %d",&m,&d)!=EOF)
    {
 *** *  *   ** **  *  *** * *    * *   *  *  * *** *  
 ***  *  * * *     ***** *    ** **   * ** **  *** * *    
 **    * *  * * ***  **   * * *** ****      ***   **  * *  *  * * *** ** * * **** * *  * ****** *  *
  *** ******* * * *** *  *    **** ***     ** * ** *   *    if(s==1)
   ** ***  *   *   *** *   * * *   ** *** *  * * *  ** * ** * * **  * *  **** *   *** *  ***** * *  ****
*      **   *   *********** ** *   * **** ** *  *  ********  *  if(s==2)
 *          ** **    * ** *  ***  ***   ** * * ** *  ** *    **  * *    ** ****      * * **  * ** * *** *
     *  **   * ** *  * * **   ** **  *  * *** *****     **
 * **   ******* **  ** **** * * *      * * * **  *  *  **** *** ***    * **       *** * *
    }
 ** * * * *  ** ***     *  * * * ** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *  *   ** ** * *

int main()
{
int M,D,S;

 *  *   ** *  *  * *      **   *  
 **  **  
 *     
{
    * * ** *  ** *  **   *
}
 * **
{
** * * *    **  ***  ***  
}
* * **
{
*  *   ***  * * * *** 
}
 * * ** * * *    * *** *  * 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.70
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 807 views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 735 views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 776 views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 689 views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 622 views
12,783 questions
183,443 answers
172,219 comments
4,824 users