期末考題目-Question 3

1 like 0 dislike
15.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 15.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 *    ******   ****  ***    * *    *** ** *      *     * 
    **  * *   * ***** * * *  ** *
 *** **   **** * **    * 
 *  **** *   * * *****  *** *   * **  *    ** *
  * * ** * ****  * *  
    *     *  *   ***  ** ** **** ***    *
*  **    * *  *** **   ** 
* *  ** ** * *** **   *** * **    ***** ***   * 

** ** **  ** *    **   * *** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
***  **  * **   *  * **  *** * *  *   **  *  *   **  *   ****   
   *  *** * ** *  ** *****   ***  * **
* **  * ** ***  ***    ***  *
** * **    ** **  ***    ** ***        **   ***     * ** **    
 * *  *** ***    **  * * **    ** if(s==1)
 *  * *   *   ** ** * ****         ***  *  ** ** * *   *    *   * **  **
*    ** ** ** * *    **  * * if(s==2)
***** **  **** ****** ** * ***    * *  **   ** *       *   ***  *  ** 
*     ** ** *    ** ** ***  ** *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*  *** * * * * *****  * * **  M,D,S;
    
*  ** *           ** *   *** ** **   * %d",&M,&D);
    
* ******   ***  *  *  ********     ***
 * **   ***    ** * *    
*  *  **  *      * * **  * **  **  * **
    ***  **  *     ***** ***
** *   **  *    **  * ** * ***   * * ***     ** * *** **   * ********** * **   *   *  * **
**      ****   **** ** **
    **** *  * *    **   ** * if(S==1)
* *     **     ***    *** **
*     *  **   ***  *** * ***     ** *  * *  **  *  **   ** ***** * * *** **    *  *  *
    *        * * *  * **** ***
 *  * * **     * *** *  *  if(S==2)
 ***    ***  *  **  *  * *
  ***** ** **  ** * * ** ** *****  *   ** ** ****     * * *  ***  * *      * **    **  * 
***   ***  * * ** *  *  **   
** ** *** * *   * * * **  *  0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
  **** *   * **** **    *** *** m,d,s;
**    *** * * *** *    
*  *  **   *  **  *** ******* *     *   * %d",&m,&d);
    
* * ***  * * **** * ***  *** * *  ** + d)%3;
 * *      ** *** *  **  
**   *** ***        * * *  * *** ****
* *  **   ***  *       *  *
 *** **   *  **     *  * *  * *  *    ** * **   ** * **** ** ***** 
 **  **** *   *   ** ** ***
** **** * * *** *   ** ** * *  *** if(s==1)
**  ** ****** ***  *    **  
*  * *****   **   * *      * *  ** ******  * *** *   *  ***    ****  *    ** *   
** *   ** * ** **    ** ***
*** * ***   * ***** * *  ** *   if(s==2)
*     *  * * * *   * *** **
  *****    ******* *  ****  ***  *  ***   * *** *  ** * ** ** * *  * **** *  * * ******
****   *    **  ***     **
   ****     * ***  ***  *  
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* **** * ****  ** * *
int main()
{
int M,D,S;
* ** ****     *  * ** * ***  **
scanf("%d  * ***  * *  *  ***    *  
S=(M*2+D)%3;
if(S==0)
*** **** *  *  ****** * *  *    *    **    
**** **   *****   *   *   **   *** if(S==1)
** ** *  *****   **   **   ***  *  ***  * *  **  ******    * ** *** 
*****  ** *** * ***   *  *        * * **  **    * *     
 ** *  ** ****   **   *  **     * * **  ** *  * ** * ***   **   *  * *  ****    **   * *  *  * *  *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** *       **    *       **  m,d,s;
 **    **   *  ***** *  * * *  *      *  **   *         * **   * *  * 
  *  *    * * ***   *      **** = (m*2+d)%3;
 *** *  * *  **   * ** ***  (s == 0)
 * *** **   ***     * ***   * *** * **  ** *****  ***  *
  ** * ** ** * *   *     *  if (s == 1)
*  * * * ** *****   * *** ** *** *** * *  *     *  
 *        * ** ***  ** *** if (s == 2)
**     **** * ***** * *** **   ***  *   *   * *    *
 *** * ****** **** *     ***
   *    ***** ***** ** *   * 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
** *** **** *    *    ***   **** M,D,S;
*  *  **     * ** * *    **  * * * ** ** %d",&M,&D);
  **   ** * * *** *  * *    *
*  * **  ***  * * * ** *   ** 
  ** *   *** ****** ***    * **  * *** * **   * ** *
** * ** *    **   *     *  * 
 *  ***  *   ** **  *  **   ** *   **  *  **      *  
*  ***    **** **** ** ** *  ***  
     ***** **   *** *    * ** ***      *   * ***      
 ****** ***** *          **** * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
**  *     *  **  *  *   ***    m,d,s;
 ***** *  **   ***   * **    **    ** **  **  *  * *** *  *     *  
**   *  * **  ****  **   ** * = (m*2+d)%3;
*** *** * * * ******* ** * ** (s == 0)
 ***  ** * * ****  *****  **   ****   *    *   *** * *
* * ** ** ***   *** **    * if (s == 1)
 * ***  **  * *** * *   ***** * ** **** **  ** ****** *
******* *    * ****** **  **** if (s == 2)
 ***** **** *   ***** *  * ***    *****    **
     ** ** *      *   * 
 ***   **** *  *** *** *   0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 ****  **  * **  * * **  **** ** * * * * ***  %d",&m,&d)!=EOF)
    {
  *   *    *  ***** ***** *  **** * *  * *  **** ***** *  *** 
***** * *****  ** ** * * *   ****** *** * ** **  *****   *     * * 
*  *  * ***** ** * ****   * * * ****** *   ** * **   * ** **  *  *    ***   **  ***    *  ** *  ** *   *
**   ***   ***** *** * * *   *   **** * ** * ** *   if(s==1)
* ** ***     *  *  * **   **** * *    *  *  ** * *    ***** **   **  * **    * * *  * *    **
** *  *  ** ***   * ** *  *   **  *  * *     * *         *   if(s==2)
  * ** * *** * **   ** *   ******   *   **  * ** *   *  **  *      *  **  * **    *   * **     *   **
 ** *  ** *  *****  * **        *    ** *    *   **   ****
*      ** *   *   * *  * ***  **** *** **     * **  *  *** ***     **     * ***   **** 
    }
 * * **      *** **  ** * **  ** **   0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ******  *** *   * 

int main()
{
int M,D,S;

 **   ** *       **  * ******* **  * * 
*      
**    **
{
**  *   *** * ** ** **
}
****   
{
 *** *  **  * ** * *  *
}
**   *
{
 *   * * *  * * *   
}
*  *  *** * ***   *   ** 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.103
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.8k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 5.4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users