期末考題目-Question 3

1 like 0 dislike
7.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 7.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
****  *   **    *   *  ** ** **  *    **      ***** *** ***
  ** * * ***    ** ***  * * **
*  ** ***  ** ***  * ** *   
  ** ** *  ***  **   *    *  *  *  ***  *  *
*   **  **   *  **     ***    
** *  ***    **  *    * **  ** *** *  *** *** *  
 * * ***** **** *   *      *  *
******  * * ***** *    **   * *  * ***  *     

** **    ** * *  ***   0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
    **  *  ** ** *     *** *** * * *     ** *   *  ** 
** *  * *    **  *  ** *  * **  
  *      *   *******    * * *** **  *
   *  *** ***  ******* **     * *   *   ****** ***  **  * * * ****   
   **    ******  * ** * * if(s==1)
 *   ** *     * * * ** **** *   *  ** *  *  *** *   * *** **  *  * ****   * 
   *   ** *  *        *    if(s==2)
***** ****** ** *     * * * * **    * *****     *    *  *** ** *    ** * 
  * *** *  *   * * **  *  *    *   0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 * **     * * **  * * * *** M,D,S;
    
* *** **** *****   ****** ********  *  ***  ** %d",&M,&D);
    
* **  ** * ** *   *  *  *   *   
   *   *     **   ** **    
 **  *    *   ***     **  ** *
** * * *   **    **    * ** ** *
 ** *  ***  **  *   *    *   ** *    * *     *  * ****  ** ** *  ***   ** **  *  ** *** *** 
 *  ***  *** *   ** *    ** *** 
** *  **   * *    *** *** * if(S==1)
***    *   ***  *  **   * 
*   *  ***  ** *********   ** ** * *  *  *    **   * * * *       *   *   *****  ******* *** 
*   * **** * * **     ** * *   
* * ****** **     * * ***    ** if(S==2)
 *  * ** *      *** ** ** *
* ** *    **  **** ***   **    **  **  * *  **  * ** *** *  **** *   **** * *  *   *   *  *
 ** * * * ** ***  * *
      *    *     **  **  *    0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
   *  ***     *   ***  *  ***** m,d,s;
** * * *** *  *  ****  *   *
 **  * ** * *   *   *   ***    * * *  **** *  %d",&m,&d);
    
* ** *    *   ***  * ******* **   ***  + d)%3;
  **** *   *  **   **** * * **
* * * **  * * ** *   **      * 
 *******   ***    *    **
** * ********  **   *  *    **  **    **    **    * * *  **  * *
*  ** * * *** **  *  * *   ***
*  **   * *  *      *      if(s==1)
  * ****  * *   * **   **    
 * * **    *** ****     ******* **** ****** ** ****** * *   * * ***   * *    **     *   
   **  **  ******  ****** ** 
 ***  **     *** *** ** **  ***  if(s==2)
  ** *     * * * * *** * 
*  ***  * *  * *****  *******        **   *** ****  *  **    **   *  *******  ****  *
* *** ** *  * ***  * * * 
*****   *   *  *  ** *  * 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * * ** *  ***  ** *
int main()
{
int M,D,S;
*  *    ** **** *  ****** **** *****
scanf("%d   * ********  ***  
S=(M*2+D)%3;
if(S==0)
 * ** * *  **  **    *****  * * *   **   ****
*  *  ***** ** * *    **  **    if(S==1)
*   * *  *  * ***** ****   **  *******    **   **  *    
  *      *  ***  ***   * *  ****  *** **       ** 
 * *****  *** *  ** *  ** *  * * ** *  *  *   **** * *  **   ** * **** ****    *   *****    *  *  **    *   * 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
    *    * * * **       *  * m,d,s;
* * *   *  * ** ** *  **   **  *  * * *  * ***   *  *** *   
**    ** **** * * ** * = (m*2+d)%3;
  * **  *   * ** ***  **  *** (s == 0)
***** *   *   * **     * ****    ** ** * ***  **
   **  ***    * * * **    * **  if (s == 1)
*** *  *  *   *  * *  * *  *  *   **   *  * ***    
 *  **   *   *      *   *       if (s == 2)
* *    *  **     *  *   * *   ** ****** * * ** *
*  ******   *   **  * **  **  
   * ***   *  * **  **   **  *  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 **  * ** **  **      *  * * M,D,S;
 *    *** *  **   *   ***** *  ***  *** %d",&M,&D);
  ** *   *** * ****  *   * * *  
***  * * * ** *** *    * *   
***  **   ** ********  *** *  **  * ** **      *  *
*** *  *****  * **** **   **** ** *
 ** *    ******  **  ***    **** *  **  **  * * * 
*** ** *     *      *  **   * 
   ** *   * * * *   **  *   **  ***       *  *  
 * *** *  *  *  ** *    *   *   * ** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *     * ******     *** ** ** m,d,s;
  ******* *  **** ** **  *     ** * *  **  ***  ********  *
***  * *      *** **         = (m*2+d)%3;
 **     ** * ****    ** *** ** (s == 0)
 * **  *   ** * **  *  *******      * ***  * **  * *** ** 
 *** *  * *** ** **** * ** *  **  * if (s == 1)
 *  * *  * *  * ** *  ****  ** ** *      * *   **   *
 **   * * **  * * * * *   *  * if (s == 2)
 * *** ***  **  * * * * * **    *   ** * * *** *
 *** * ***** *** * *  *** 
*** **  * ** * * *  *    ***  ** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
****   * * *   **    *** *********  * *     *  %d",&m,&d)!=EOF)
    {
***** * * *  ***** **    **** ****      *** * ***  * *  
 *** ** * * * ** * ** ** *****  **   * ****       ***  *** *  *
     *  *    **   ** *  **** ** * *** *  *  ***** *  * **    * *** ****  *  **   ** **   *   * **  
****  * ***** *  ** *    ** ** * **          *   *  *  * ***   if(s==1)
*** *** *** *****  * *  ******  *   * * * ***     **  * **  ****  *   *  ** ** **   **    *   **  ** *
*** ****   * ***   ** * *      *  ** *** * **    *    * **  if(s==2)
    *  *      * *     *** **   ***** **  *  **    *  * * *   *** **  ****   * * **   *  ****   ** *
  ***  * *** * *** *        * * * *     **  **   ****
****   *** ****    *    ***   * ***  **  * * *  * *****  *  * * ****    ** *** **  *  * *
    }
 *    *   *  ** * **  ** *  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  * **   ****  ***  

int main()
{
int M,D,S;

*** * * ***  ** ****       *  ******   *  * *
 * *** * 
** *
{
 *  * ****       *     ****
}
  *
{
*****   ** ******* * ** ** *
}
* ***   
{
  * *      **  * *** 
}
 * * *   **   **  ****** **** 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.179
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.2k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.9k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users