期末考題目-Question 3

1 like 0 dislike
12.6k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 12.6k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
  * *   * ***  *  ****  **   * **  ***** *   * *   *  ** *  ** 
* * *  * ** ***  * *     * *
** * *** *    **  *  
 *    ***** ** *  **         * *** **     *
* *  * **   *   ****  *  *
* ****** ***   ** ***** **  * ** *  *   *   *  
*** ****  * **  *   **  * ** 
*  *  *    * ** *  **   * ** *   **  **  *  

    ** * *  ****   * *   0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
  ******    * *    * * ** **  * * * * *    ***** * **** * 
**  *** * *  **  *  ***** ** *    
*  *  * *   *** *  **  * **   *
*  *  ** **  * * **    *** ***  * ***  *  * ** **** ***  * **  * *** ** *
**  * * ** * * * **** *   if(s==1)
 * *  **   ** * **    * * ****** ***   **** *   * ** *   * *  
**  *  * **** * ** **  **     * * * if(s==2)
 ****   ****** **** **   ***     ** **  *******  *  * *   * *   ** * **    
**       * **** *    ********* * ** * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
** *   * * **** ***** *  ***  * M,D,S;
    
  **  ** *  ** * **  ****  **     **      %d",&M,&D);
    
 * *   ***    ******* ***  * * **** * 
* ** *      * * *    ***    
*  **  * ** *****  ****  *   
    ** **  **  **  * * **** **  
  ****** ***** **** * *  ***** * * *** *****   * *******  ** * **  *    * *** *** *  ***  **
** **  ***** *   *  **    
*    *    **     ** * ** **** if(S==1)
**  ** **   *      ***
*** **  *   *   ****  * *    * **   ***** * * ** **     *** ** *   *** * ** *  * * 
*****  * * *  *   ** * * 
****  ** *** ** ** *  *  **  *    if(S==2)
 * *** *    *  *       ***
 * *****    ** * *   *   * * *  ***  **    ****** *** *    ** *  ** *   * * **  **
 ** **  * * *  * ****  **
*   ** * *** *   ** ** *        * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
  **    *****       *** *   *    m,d,s;
   * *       *  ** * *  *     
 *   *  ***    **   **  ** **  *  * ** * %d",&m,&d);
    
   * ********** *  ** *  **  *  *     **  + d)%3;
 *      *** * **  ** *  ***  
*****   *  ****  * *    * *   ** *
* *   *****    *****   ** 
  * *      **  ** *  ** *  *  * *****    ** *** **** **** 
***** *** ***  *   *  * *
 *   ** ***  *  * **  * *   **  if(s==1)
**    *  * *** ** *  * * * * 
*  *  * ***  ****   * *  *  * *  * *  *  ***    * ***    ** ***** ** *  *      * * **  
    * **  *  * ** *** **  * * * 
 * *    * * * **  *   *****  if(s==2)
** *   ***        ** * **
 * * **   *   ** **  * ***     **  * * ****** *   * **** ***  *** *   ** *   *  *  ***** * *
  ** *  **  * **   **** 
*      *  **      * * *  
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * * * *     ** * **
int main()
{
int M,D,S;
** * *****  *   * *  **   * * ****  *  
scanf("%d * * ** **** *   ****    *  
S=(M*2+D)%3;
if(S==0)
 ***          *     ****  *** *   **  *    *
* *    ****   * ***** ** ***  *** * if(S==1)
*  **  *****  ** *   ***  ***** * * * **** * *  *   *   **    
 * ***    *    *   ** *  ** *   **** ** *  *  *  *    *
** *   ***  ***     *** *********** ***** *****   *     * *** ***** * ***** *  ** ****      *   * ****



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
****      *  ******   **     ** *  m,d,s;
*  ******   ** *   * * *  **   *    **  *    ***  *   *** *  **
 ** ** *  * ******* ***   = (m*2+d)%3;
* * **** ***** ** * ********* (s == 0)
** ***  * * ** ** ** ** * *** * ***    ** **  
  ***   *   *   * * ***   *** if (s == 1)
  *  *   *   * *** ***  ** *  ***  * * ** *   *  * **** *
 **   *  *** *   ***   ***    if (s == 2)
 *    * **** ***   **  * ***     **   ****
  ***   *  *  * ****** **  * * 
**   **   * ** * **** ** ** * * 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
**  ****   *     *   **** *  *  M,D,S;
  **  **  ** *       **  **  *  * %d",&M,&D);
  *  * *** ** ** ** ***  *  * *  *   ***
  *  **  * *   *   * * * *  ** 
*  ***  *  *   *  **** **** ***** ***   *  *  
   *****  * *       ** *** * * 
 **   **  ***   * *      * *  ** ***    **** *      *
*   ** ****** * ***  * * * *** **  *
 ** ** * **  *      *** **    **     ** * ** * **  * ** 
   * **  ***   *    * ** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* ** *  * * *       **    ** ** * m,d,s;
 **      *  * * **  *    ***     *  ** *** * *   * **     *
* * *  **** *        ***     * = (m*2+d)%3;
  ***  **  *** ** * ** ****   * (s == 0)
  * *  *  *   **    **    **   *   **  * ** *  ****  *
** *   **** *** *    *****  if (s == 1)
**   *** * * * * ***  * * * *  *  *  *   *      ***** *
  * **   ******** *** **  * *   if (s == 2)
**         * **  ******  * **   ** ***  **  * **** 
 * * ** **** *** *  ****
**** * **** ** ***** * *  *********** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
***  *  *  *        *     ** ** **       %d",&m,&d)!=EOF)
    {
* *  * **   ** **  * * ****  *   *  * *  ** * ** *   ***   
*   ***   *** * ** * *  ** **** ***   *** *** * ** * ** ***  *   
 **  *  ** ******     **  ****   **  * **  ** ** *****  * * *  ** * * *** *  *  **  ****  * *****  
*   ***   **     * * * *  ** **  *   * * **    *      ** if(s==1)
 *** *   ***  * **   *  *    ** *  * * * ** ***  ** * ** **  * * *****  * ** ***   ****  *  ** * * ** **   *  
* * *  ***    *   *** ***   * **   * **     * ** **  * if(s==2)
 * ******  *  ******* * *  * * ** *  **  * * *  ** * **  * ****    *   * * *** *****      **   * *    **  ** 
 **** *  ** *    *  **** **   *  * ** **   ** ****   
**** ** *  ** *  ****** ** * **    * ** **      ** * *   ** * **  ** *** *  **  
    }
*  ** * * ** *    *  ****     *  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
    * ** ***   ***

int main()
{
int M,D,S;

*    ****  *  *   ** **        * **
*   ***
*****
{
  * *   * *** * * * * ***  
}
**   
{
 **   *     *   *** **    *  *
}
 ** 
{
 *      *      **** *
}
 *  * *  *   ** **** * ***   

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.150
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.6k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.2k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.3k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users