期末考題目-Question 3

1 like 0 dislike
4.7k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 4.7k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*  *  *  ****  * ******      *  * **  * ***** ***** * *** 
** **    *****   **    *** * 
 ** *    *******   * *** *
   * *   *** ** *    * * *** ** * *********   *  *
 * * *    * *  ***  *   * 
*  * **** *      *  ****  * *  ** * *  **   *
*   ***** *** **  * *  * ** **
 *    *     *  * * **** **    ** * **   * *  

** **  ***    * *  ***  *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
**  *  **   *  * *  *     * ** **  *   *** **  *    *  *   
 *  ***  * * ** ** ******    *    **
   ****** * **    * ** **
 *  *  **  * *** *  ** *  *** * * * ****  *   *   * ** **** * ** **  **
* ** * ** * **** * *      if(s==1)
 * *  ***    **   * * ** *  *** **** ***     * **** *** *    ***** * *  
 **  ** *** ***** * **   ***  if(s==2)
    ***  *   ** **** *****    *   * **  *  *    ***    *  * ** *   *  * **
*  * **  *** * **   **   *  *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* ** ** *** ** ****  *  * M,D,S;
    
**    **  **  **       *  ** **     *** * %d",&M,&D);
    
*  *  *         ** * *****    *  
**   * **     ** *   * ** 
* *  * ***   * *** * *** 
*  ****   *** *       *
 **   *   ****** *  * *****  * * **** *     *** *    ***    *  *** * * *   ** ** * ** * **
 * *  * ***** **     *      *
* **** **   * *    *  ** *  * *   if(S==1)
* *   *  *  **   * **     * 
  *****     ****    ** ***   **** * ****  *   * *** *  ** **** * **    ** ***  ***   ** 
 *  * *   ***  * **     *  ***
 *** *** ****    *  *   * * if(S==2)
* **   ** ** *    **   *  *  * 
* ***  ** **  *******   * ** ** * * *   *** *  *    ***    ***** **            *  * * ***
** *** *** * *  * **  ***  
**    **** *    *** * * *  * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
  **  **   **   ***      **  m,d,s;
  **   *** ****  *   ** 
 **** **  ** *  * ***    *   *** ******* ** %d",&m,&d);
    
***    * ** **** ** *    *     *  + d)%3;
* ***  ** **  * **  *  * * *
* **   **  * ** *      * *  * 
   *  * ** *  *  *    * *
  *** * ** ***** ****     *  * *** *     *** *   ***  *      *   *
*     * *****     *  * 
* * **   *  *  **  **** ***  * if(s==1)
* *   *   *  *  *   * **** 
* *  ****   * *  * *       * *  *** ** **  ********  *  * * *  *  **     ** * *
** **** *** *    ** *  **  *
** *  * * ***   **  * *  ** **    *** if(s==2)
  *** * ***  * * * * ** **   **  *
 *  ** **  ***** *********    **    ** * ** **  **** *  ***  *  * ** ** ***
  **      * * *  * **        **
 **  ***  * *  *    *  * *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * *   *  *  * ***
int main()
{
int M,D,S;
*** ** *****  **   ******* ** **** **
scanf("%d   * ** *  ** *** *    
S=(M*2+D)%3;
if(S==0)
 *    ** * ** **     *   **    * * **   * 
*** *******  * ** * **  *  * if(S==1)
 ****      * * *     * *  * *   * *****   *****  *   ** *** **  *
 *** ****    *  ** *  * ** ***** *   * ** *   *   
***  *****  *    * ** ***  **** **** ***    ** ** **     **  * * * ** * *   *  *    *****  *    



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   *  ******  *   * **   ** ** m,d,s;
      ****  ** *   * ***  ** ** *       *   ***   *  *  ** ** * 
     *  **** *  ** ***** *** = (m*2+d)%3;
****  *    ******  * *  * * * (s == 0)
** * **  **    * ****        ***  * *** *  **   * **  
* ** *  * * * * ** *  * *  ***  if (s == 1)
  * * ** *     *  *  **   *   ***  ****   * *** * *  
****** ** *** *    *  ******** if (s == 2)
   *******  **********   **  *  **   *      **
*   *   ***  * ***   **    
 *  ***  ** *  ** **   ***   ** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
***  *   ** * ** **  * * **   M,D,S;
 * *    **   **** *     * * ****  %d",&M,&D);
***** *   ******  *     **  * **  * 
  * ** *   **  **   *** *  * **  
  *   *     *  * *  ****    **    *  ***     ** *  * **
 *  *  *  *** *  **  * * * **
 * ***    ***  *    *   ** *  *       **** ****   **
*  *    * * *** * * ***** *
*  **       * *  * *   *****  ***  * *** * **** *
* *    **** **  *** **** *    ** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  * **     * *  **    **  ** m,d,s;
 * *** ** ******* * **** *   ***** *** ***  *   * *      ***  **  *
  *  * ***  **     * * **  = (m*2+d)%3;
* ** ** *      * *    *  *  (s == 0)
  **      *****  **** **  * *  * *  * * ** ** * 
 * *      ********   *****  * * *    if (s == 1)
  *   *** ** ** *       *  ****   *  **  ****  ** 
  * **** * *  ****  * *   * ** if (s == 2)
****       ****   **     * * *  *    * * ****
**   ** *    *  *** * *
***  **  * ****      **  **  * *  * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
* ***  ** *      ** * * * ***   * **   %d",&m,&d)!=EOF)
    {
  * * * *****  * *  **   ***  * ***  * *  **   * *   *** ** * *
*  * *  **      *  *  ** **  *     * ** * *** * * *  **
***** ****  **      **  *  ***   ** *** * *  *  **** * **** **  *  ***** ** * *  *  *    **    * **  *  
****  ***   ** *   *  *****  ****   **   *  *  ***** ******  ** if(s==1)
******* ** *** *     ***** *  *  **  *  * * ******** *** *  * * ***  * * * ** *** ******   
   * ** * ****** *  *   ***   ****** *** **      * *     if(s==2)
  * ****   * *  * ***** *  * *  * ****    * ** * ** *** * * *  ****   ****  *   *   *    **    *  *
  *****  ** **** * **  ****** *  **  *** ** * ** *   *
*  * ***** ****    ** *****  *  *       * * * **  ** * ***  * *****     * ***       
    }
****** * * * ***   ** * * *  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   ***** **  * ***   * *

int main()
{
int M,D,S;

**  *   * *** *     ****     ****** ** * * 
** ** ***
*   *  
{
**   **** ****** *  ** * * 
}
 * * 
{
 ******    *   ****  * 
}
 *   
{
* *  *   **** ** ** **  
}
* ********** ***    * * *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.114
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users