期末考題目-Question 3

1 like 0 dislike
14.8k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 14.8k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 ** * *** **** * * **   *    ***    **     *  * *** * *    
  *** *      * *     * *****
* *** ***          ***      
 * *** **  *** *** **   * *  ***** *  ** **
**    * *  *  * **  ***
 * *  * *** **   ******* *  *** **   
 ** ******* * *  **  *   
*** **** * **** **********  **** * *    

 **  *** *       *  ***  * 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
   ****  *** ***     * ** *****  ****  *       **  ** *  ** * 
    ** * ***** **   *   *  *  *   ** *  
****    * *  *********      * * **
*   *   * ** **  * * *** ***  **   * ***   **  * ** *  * *  ****   ***
         ***** *     *  * ***   if(s==1)
 *  *  ** ** * * *    *     *     ******  * *  *   **   *      *  **  
* *   *** *   *** ***  ***   if(s==2)
**    *  * *** **    * * ******  ***** * *  *** **  ***    ****** 
* ****     *** * * ***   ** * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*** *   ***** *    * *  * ** M,D,S;
    
**  * *  *** * *******      *  * * %d",&M,&D);
    
** ** ** *  **  ** ***   ** **
***   *  *  ****  * **  **** 
   ** ***** ** * ****  **** * *
**  ****  ***        ** *** *
   ** * * **   ****  * **   ***    **  * ** *** * * *    ** * **** *** **  **  ** *   *    
*** * **  ***  * *  *  *
 *** *  **  ** * **   * *  if(S==1)
** ** ***** **  **  * ** *
* ***  ** * *   * *   * * **   ***  ****  ** *       *   * **   *    *  *    *  ***  **
   * **** *    ****  *  * 
 **** ***  *** ****  * **** * if(S==2)
***** *  *  *****  * *
 *   ** *  * *  * * * *   * * * * *   **  * * **** * *  *  * ** *  *  ***** ***** * **
  *****   *****   *** **    * * 
 *   **** ** *    ** * **   **  *  * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
 *  * **   **** * *  * * **   m,d,s;
*  ***  ****   ** ***
*** * **   *   * * * * * * * *   *** **  ** %d",&m,&d);
    
    *  * * * ***  * ****  *  + d)%3;
   **  *** *  *   *   ****  *
*   **    ** ***    * *** *  ***
*   * **   *  ** *  *
   ****   * **   ****    *   * *  * ***  * *  * * *  *  *     **** *
***   **     * *  ***  *    ** ****
 ***   * *  **  **  *    **** * ** if(s==1)
*  ***** ****** **  * * ** * 
   ***   **   * ***** * * *****  ****     * *    *  ******* ** * *  ** *** **  **
* * ** *  * *      *   *****
** *    ** *****   * ****** **   if(s==2)
**  * * ***** **** * * *****
* ** * *     *  * * ** *  *    ***   *  ** **  **  ******   *  **   ** ***   
*    *      *  ** ** *  *
 **   *** ****   * *   **  *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  *   ** * **    * ** 
int main()
{
int M,D,S;
**** ** **  * *    ****** *  **     * 
scanf("%d  ** ** * *     *  ** ****  
S=(M*2+D)%3;
if(S==0)
**  **** ** **** *****  *   ***   *** ** ** 
     ** * * **  * ******* ** if(S==1)
  *   ** * * * *   *      * ***** **      *     ****  ** *
     **  ** **   * ** * ** *  ****   ** ** **** ** * *  
  * ***    *  * ** *  * *   ** *  * *    *   * ** * * *    * *   **** ** * *** *** **    ***   * *  *  *** *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 * *****  *** **     *   *   m,d,s;
 *  **   **       *  *    **  ** **    ** **   *    *  **  ***
*  *  *     * * * *   *  ** = (m*2+d)%3;
*  * *   *      ********* *  ** (s == 0)
  * **         *******  * * * *  * * **   *    * 
  * ** **** ***** *** * * *  if (s == 1)
* *** *  **  * ***** * ***   ** **      ****    ** 
***  *** ** *  *** *  * * * if (s == 2)
** ****   * *    *  *  **  * ***** * ** 
 * ** * ** ****  **    * **   *
 *              *** * *****   *  ** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
**   ** * *  *   **  ** **   ** M,D,S;
 ***          ** *  ** **  * *  *** **  %d",&M,&D);
*  *     * * * *** ***  **  ****   **
 ****    *   *   ****     **** ** **
  ** ** * * *        **     **   * * *  ** *** * *
  **   *  ***  **** *** ********  
 * ** * *  ****    *  ***  ** *   *   *   * * * * * ** ****
* *     ** * *     *     ** 
* *     *  ***     ****  * *  * ** **    *  ***  *    
****   *   * **   * ** *   * ** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *****  ** ** *  * ** ** * m,d,s;
  *   **  * * * **   * * * **   * *     *******  *  * ** *
*  ** ** ** ****  * ** ****    = (m*2+d)%3;
* **    *   *** ****  *  (s == 0)
  ** ** *     *  **  **** * **** ** ** * * **  * * *  
     * ***   * ****** *  *  * **   if (s == 1)
** ***  *  ** *  ****  ** *** * ***** *     ** **** *
  * *    *  *  * *  * *  * * **    if (s == 2)
****** ****** *  *****   *  ** *  * ****** ** * * *  *  **
 * ** ** *  ** * * *  
  ** *** ****   ***    **   ***   0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 ** *  ******  * *  ** * * **  ***   ** ** ** %d",&m,&d)!=EOF)
    {
  ***** ** ***   **** *****  **   * * *    * * *  * * ** **
**  ***  ** * **** *   *  *** **  * ** ***   *    *  *    *      * 
 * **  *       ***** ** **  **   *     *    ** *  * * ** *     *****    *  **   * *   * ****** ***    ** * 
*** ************ * **** ***   * *****  *  * * *  * ** if(s==1)
**** ****      * *  *** ** *** ** * *   *** ** * **     ****  * ** ***  ****     * ** *** ***  * * * **  **
* *  * **  **   * **  * * **   ******  ****  **     *** *  * if(s==2)
 *  * *** *  *****  * ***  ** ******   ** *** *       **    **   ***** **  * **  *    * *      *   **  *  ** ****
*   ** *    ***** ***  ** *** *       ***  * * * **     * **
* ***  ******  *  ** *** ***  ** *        * **     **** * * ****** ** *    ***    **  **  
    }
*   *  * *   ** ** *****  *** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  ** * * ***  *  *   

int main()
{
int M,D,S;

***   **   * *   **  *** ** *** *  *
  *** 
  *   
{
 *  *** ** **  *    *** **
}
** ***
{
  *  *  * ** * ***      
}
     
{
* * ***  *     * ** *
}
*   *** *******       *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.58
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.7k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 5.3k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.9k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users