期末考題目-Question 3

1 like 0 dislike
1.6k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 1.6k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
**  ***  ** *  ***   *    *    ***      **  ***  ** * 
   * ** **** **  ****  *   
 *** * *  **** * *  *** *******
***   **  ***  * *        *  * *     * ***  
*   * * ** *** ** ** ** 
  ** * *** ***** ** ** ** ** * **** * * *
* ** *   ***  **** * *** ** *
*   *    ** *  ** *  ***  *  *     *  *    *

**** ** * **   ** **  * 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*  ***** ** ** **   *   *   * ** * ** *  *****  *    *  * * 
****   * * ** *  **** ****  *
* *    ** ****  * *   *  **** ** *  
 * *    ****   ** * ** ****  ** *** * **  * ** *  *  **** *****   * * * *  *
 *    ***    *        ******  * if(s==1)
*  ** **   ****** * **  * **  * **   * ** ***  *  ** **   * * * *  ***  
 *  ***** ***    *  **   if(s==2)
* * * ****  **  *       **** *******   ***  *   * *   ****  * *  *  **** *
  *** ***** ****   **  * **   0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
     * ******* * *  * ****  **   M,D,S;
    
    ******  *** *  *    ***** *     %d",&M,&D);
    
*     *  *   ***  *  * ****     *** **
 * *  * *** ** * * **  *
*** *   * **  ** *** *  ***
*** * *** **  * * ***  * *
*   *  *  **** *  **     ** *      * ****** * ****    *  *  * ** *   *   *  ******
   *    *   * * ***  * ***  
  *  ****    ** **** * *   * *** if(S==1)
* *  * **** *** * *  *      *   *
 * ***  **   ** ***  *      *  ***  ****   *** ** *** ****  * ******    * *  *
**** ********   *  **
***    * * ****        **  if(S==2)
 *  ***** **    *  *  * **
 *  *    ***   *   * ******  *  ***   * ** * *** *  ** ****    *  *   * * *** *  *** *
 * * *    *    **   *** * * *
*  **  * **     **     *   * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
   ** **** * ******** *    ** m,d,s;
******* *  ***  *   * ** *** **
*   **   *** *  *  * **** **  ** ***  * %d",&m,&d);
    
 ** * *  * * *  **  ***   + d)%3;
*  *******  *** *  * * *
** * ****** ****     *  * * * *
**   **  ** *   * *   *** *   
* * * ** *** *** *   * **     *****   **** **   **  * 
* * ** * * **** *** *  * 
* * **  *   ***** **** ***  **** if(s==1)
  *  **   **    *  ******* *  
** * ***   * *** *        *    *  * ***  * * *  *** ** ** ****** *  *** **   ****  *****  ** *  *
  * ***   *   * * *   **   **
 ***   *  * * **  * ** * * * * if(s==2)
*    * * ** *** ****       **   *
  *  *   *   *   *  *   *** *** * *    ** * *** * ***** *    **  *   * *     ***
*     * *  * ** ** **   * **
 ***   ** * ***        ***  *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   ** ****** * * ***
int main()
{
int M,D,S;
  * **  * * * * *** ***** * **  * **** *
scanf("%d ***  **  *  * *  *** 
S=(M*2+D)%3;
if(S==0)
***** * ***     **  ** *** ***  ****
* *  **** *     * **   *  if(S==1)
 **  *  ** **  **  *   **   *** * *  ** ** * **  * * ** * *   *   ** 
  **  **   *** *  ****   *** ** ***** * *  *  ***  **    
 **  * * ** *     ***     ** *  *   * *** *    *     **  *   * *  **  * ***  ** **** * * *    ***  **   ****



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* * *   *****  * *** * **   *  m,d,s;
   * ** **  *   *** * ***   ** * **     *  *  * * ** **    **        *
 * * * *      *  ***     **    = (m*2+d)%3;
******** * *** *     * ***  * (s == 0)
** **   * * * *  ** ** *** * * ****  ****** * *** **
 *****  * **  * *  **    ** if (s == 1)
**  **  ***   * ** *   * ** *  ** *    *** ** * * ***  *
  * **  **     *  **         *** ** * if (s == 2)
  ** * * *     * *** * **     *** *  *  *** * 
 * * ***** *** ***  *    * *  * 
  *  *** ****** *    *    0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  * *  * ** *  **  * * * * *  * M,D,S;
* *  * * *** * **    * *** ****  ** * * %d",&M,&D);
***** **  * *  *** * *     * * ********
*** * ** **  *  * ** *  * *
*      * *** * **   **  **    **      ****** * *    *  
*** **  ** ** * ***    * * **  *  *
*** * **** *  * *********** ** *   *  * **  **  * 
*     * * ** **    **  ***    * 
** **  *  **    * * **** **   ****  * ** ****
 *  ******* ** *   **  * **         0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  *  *   **        *     *  ** m,d,s;
* ********* ****  * * *   **    **** * **   *  *  *     *** *      *****
   *          * * * **     = (m*2+d)%3;
* * **    ** *  ******   * **  (s == 0)
  ****   * ***   * *  * **  ** ****   ** *   *  
   *          *  **  *** *     if (s == 1)
 **   *** *     *** *  *     *   ***    ****    
 *      **     * * *      * if (s == 2)
* *  **** *   ** * * *****  * ** *****   **  ** ** *  
  **  ** *  ** ** *  *   *
**  ***  ****  *   **   ***  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 ***  ****** *      *  * * *   ** *    ** * * %d",&m,&d)!=EOF)
    {
 **  ***   * * **  * ** *   *  **** **  ***  *     * ** *****
******       ***  * * *** **** **** *  *   *  * *       
 ** *****  ** ****  **   *** **  ** * *** ** * **   *     *** * * ***  ** * ** *   **** ****   * * ** *
  **  *  *  **   * *  *  * **    **  * * **   *      if(s==1)
*  *     *  ****** **   **  *  **  *     **  ***    *  * **    * **  *******    ** ** *** ** ** * **
 * *** * **   * * * *  ***    *     ***   ***  *  ** **  if(s==2)
 *** **  * * *  ***** *** * **** *  * *  ********  *  *  **       * *  *** *  **** ** *** ** **  **
 **  *     *     **  **   *  * *   ****** **** * *  
* ****** **  ** ***** * * ****** * * ****  ***   *** *  *  * *  *  ** *    
    }
  ** ****** *     *** **  ** ** *  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ** * ** * **         *

int main()
{
int M,D,S;

* *  *  * * **     * **  * **  ****  
 *  * 
* * * 
{
* * *  ***  *****  *  *
}
 **    *
{
** * * *  **  **** 
}
** 
{
**  ***    *  **** **
}
  ** *  * *****  *   * *  ***

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.62
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 795 views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 730 views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 767 views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 682 views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 611 views
12,783 questions
183,443 answers
172,219 comments
4,824 users