期末考題目-Question 3

1 like 0 dislike
12.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 12.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
    * *  ***  **   *   *  ** ****   *  *      ** ******   
 * *       ** * *  ****  **  * ** 
** ***  * *    *   ****  *
    * * ****** **     ***   ** *   ** **   * 
  ***   *  ******  * *      * 
 ****  **    * **** * *   ****  * * *** **  *
****        *** **** *  * 
* * **  * *   *****     **  * *  * *  ** *

 * ** *    *** *  *  ****** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 *** ****    ***  * ****  *    **     ** **** ** *   * *  **   
 ** **  *   * * **  **   *** ** * **   
***   *    *** * * **  ** ** *   ***
   ** * ** * *** *  *    **     ** *  * ****  *  **** ** **  **** *  **      
 *  * **** **** ** * * * *** if(s==1)
  * * ** **  ** * *  * ****    ****** **** **** *     * *   * * * * *
  ** **  *  ** ******* if(s==2)
 * *    **   ** ***  * *   **      ** *   ** *  ****** *** *    * * 
     * ** * ** *** ***  ** **  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
***  *   * * **  ***   *      M,D,S;
    
 *  **     ****           *  * **** *  %d",&M,&D);
    
* **  * **        *  *     **** 
 * * *    *   * **** ***  
  *** **  *  **  *   **      *   
* *  * * *** * **  * ** *   
*  ***  **  ****** **  *   *     *   **  *  **  ** *    *  * * * **** * **   *  **
 *   *** ** *       **     
*   *  * *    ***** *  **   if(S==1)
 * *     ****** *** ** ** 
*  *    ** * *** *    *   * * * *** *** *  * **   ** **    *  ****    ****  ***  * **  **
*  * *   **** **  *  * ***  
   *  ***** ***     **** **  * *** if(S==2)
 *  ** * ** *   *** *  
 **  **   * ** * * ** ** *  ****  ** **** *  *** *******     ***  * *  * * *
*       **  * **  *****    
**    **  ** * ****************   0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
** *   ***  ***      ** * m,d,s;
   * *****          * **
  * ***  * ****  *  * ****    * ****  * %d",&m,&d);
    
 *   **  **  *  ***** * ***  *  + d)%3;
***  *  ** *****  *   ***** *
*      *   * *   *  * *** *      
* ***** **   ***  ****   ****
*   * **  ** * * ** ** *** *         * ** *****    *  ***  * *  
** **** *  *  ** *  *** **  
*** **  **** ** *   * * *  * if(s==1)
     *** **     * *** * ********
***  *   ** * * ***     ***    **   *  **  ***  * ***    ** * *  **  * *   ** *    *
* ** ***    **** ** * **
 *****   *  ** ****  *******   ***   if(s==2)
 ***   * ****  * ***  * * *
 ** *  *  *  ** ** **    ****   *   ** ***     ***    *   * *   ** *  *** 
**** ** * * ****** * * *  ** 
*  ***** *  **   ***
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * ** * * *** *    * * 
int main()
{
int M,D,S;
 * ***   *** * * *** *        * *  
scanf("%d * **** *******     *** * 
S=(M*2+D)%3;
if(S==0)
** *  ******* *     * *** ** **    *    
*** *  * *  *****  ***      *** if(S==1)
*    * **  ****  *  ***  ****    ** * * * * * * * *** *****  * * **
**           * **  * ***     ***  * *   **** * **    **    
** **        * *  *** *  ***  ******  * * **** * * **         ** * *   * *** *   * * *    *   * *  * * *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   *** *     * **  *** *  m,d,s;
  **   * ******** **  * ***********   *** ** *  ** * *** ****** *****
     *   *** * *** ***   = (m*2+d)%3;
** **  ** *** * *  * *** *  ** (s == 0)
 *  *   *  * *      *   **  *    *  ** **** ***** ***
*         ***  *  if (s == 1)
*  * ***       * ****** * *   * *  * ** ***   *   * *
   * * * ** **   **    * ** * **  if (s == 2)
** ** * ** *   ***** ******** **  * *  * * *   ****  *  *** 
**  ***    **  **** *   **** 
     **    * ***  ** * *  * 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
** * ****    **   *   *     **  M,D,S;
 * *****  *  ****  **** *  *  ** ** *** ** **    %d",&M,&D);
   * *  * *  **     *** * * *  **
 *      ***  *       * * *  ***
*** * **** **  **  **  ***** * ***** * ****  ** * * 
 **   **  ***** * * *   ******  **  * 
***    *  *****     *  *** **  ****   ** **   **
**   * **  **   ****     * * * *****
      *** *   *  * * ** ** ** *  **     ** ***
** *  *** *  *    *      ****   0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* *  ***  ******  *** * m,d,s;
**  * *  * * ****    **  * *  * ****   *    *  *  *    *       *    **
*    ***  * * ***** **** * * = (m*2+d)%3;
 *  ****  **  * * ** ** ***   (s == 0)
 *** *    * *  *** ** *** ***** **   *  ***** ****
* *  *  ********    **    *   if (s == 1)
 * **  *    *** ***  *   ***    *   * *  ** ** *
  * *  **  * **  **   *** * ** if (s == 2)
 *  *** *  * * *  * *** **  *****   * **   *   *** *    
** ** **** *   ** *** *****
 * *  *** *  ** ***** ** **** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 * *** ****** * *******  * *  *** *     * **** %d",&m,&d)!=EOF)
    {
* *  ** * * * * *   *  ** **  * *  *  *  **  * ** *  ********** 
** **   *   ** *** *  * * ***   *** ** *  * ***** *   
**     *   *   ***  **** **  * * *****  *  **    **** * * **      ***  ***    *      *     **    
      * **   ** *  **  *  ******* ***** *       ***   ***** * ** * if(s==1)
    **  **    ****     *   * *   * *  *****  *   ****** *** ***** *   **** ****       *  *     *  *  *  
*  * * * **** ** ** **    *** * **** * ****    **** *   *   if(s==2)
** ***    *** * *  *  *   *   ** **     * **  ** *     ***** * * ***  ** ** *  ********* *** *    * * *  * * *  ** 
 ******  ** **  ** * *  *** *      * ** ****** *       * * *
**** *  **   * * **** ***  *  ***  * ** *   * *  * * * * * * ****  **   *       * *   
    }
 ** *** *  * *  ** **** * *  ** **    * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***   *     *       ** 

int main()
{
int M,D,S;

 **   * ***  ** ** *    *       **  **  ***
 * * * *
 ** * *
{
 ** ***  *    **    *** *
}
* ** 
{
*  ** ** ******* *   * *  
}
*    
{
 ** **** ** ** ****   *
}
 * *  **   **   *  *  *  * *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.38
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.3k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users