期末考題目-Question 3

1 like 0 dislike
10k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 10k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
***  **  ** * * *  ** *       ***  * *   *   * *   *  ***  **
*   *** *    * **   * *   * 
*  **      * *** *  *
  ***** *** * *    **    * ****** * ****  *  
****   *****  * * **** ***
 ** *** ****  * ** **   * *  * * *** *** * **
 *  ** *    * **** *    * * * 
* * ** *    * * **   ** ** *  * *  ** * * ***  *

* **     *  ********** *   0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 *  **  * *   ****    *  ****     *********  ** *  *   *    *** *     
* *  *  ****  ****  * *   *  * **  *
*** *  **  * *** *  ** * * ** 
    ***** **  * * *   *   * * ** *******    ** ***** **  ******* * *  **
*   **  * ** ***** ** * * ***  if(s==1)
    *     * * *  ** **** **  **  **** ** * ** *       *   *     * *   * *  
** *  *  **  *   *****   **  * if(s==2)
*  *   **  * ** ** * *    ** *  *******    ***  *  * * ***    *  * ** **
**   *** **   ****  *  * ** *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*  *   *     * *   *  *  * ***** M,D,S;
    
****    ****     **  ** * **  **   *    %d",&M,&D);
    
**      ****  ******* *   **  ** 
  *** ****         * ***
 * ***  ** ****  * * ***
* ******* ***  *** **** ****
  *    *    *  * ******   * *** *** * ** **  ***  * *  *** ** ** * * *  ***
**     *  ** *    * ******  *
 *** * **  * ** ***  *  **    *  * if(S==1)
* ** **   **  ***  *** ** *** *
* *** **    *** *     ***** *   * ***     *  ** *** ****** ** ** **  **** *  * ** **    *****
 *     * * **  ***** **  * ** 
 **  *   *    *********   if(S==2)
 * ** ** * * ***  ** ***
*   *   *   ***  * *  * *  **  *  ***   ** * * *  **   * * * *       *  ***
**   **  * *   *    * ****   * 
**   **  *  *      *  **    *** ** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
 **     **  * *** **   ** ** m,d,s;
 ** **   * *  * * ** * *  *
 *** *   **** * * * **   ********* *  %d",&m,&d);
    
 ***** *  *** * ***   * * **   + d)%3;
*   *** * *  * ** * ****  
     *     *   * ****  *    ****** *
* *  * * * * ** * **  * *   ***
  * ***    **   **  *  * *        *  **** *   * **   *** *  *   
* **    ****** ***** *   *    **
 *** *    * **** *  *  ** if(s==1)
 ** ***  * **** ****   * * * * 
**     **  ***  **** * * *  * *****  ** *  *  *  *   ** ** * ** ***  **** ****   **
 ******* **** *   * * *** 
***   * **   ** * **    ** if(s==2)
 ** *   ***  *  **   *   * 
  ***       *   *  ***  ****** * * *** *** ****  *******   ***  *   ***  ******  * *   
*** *     *  *      *  *   
    *    *****  ** ***   *  ****
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  *  * *  **  * *
int main()
{
int M,D,S;
******* * *    ******** *   **  ****
scanf("%d  **     *      
S=(M*2+D)%3;
if(S==0)
  * **    ** *  * ** ******        *   ** * * 
**** **  * **   * * * **   * if(S==1)
 *  **  *  * ***       * ****     * ****  ** *** ***    * * * ** * 
*** *   ****** ** **** *     * **  * * * *****     **** ***   **
 *   *  * ** *   **  * * * *  *  **  * *****  **  *          *    *** * *   **  * **       * *   *  * 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
    ******** **     * * **    m,d,s;
*  ****  *  **  ** ** **   * * *** * ****  ** ** *** ***  *  ***  ***
**   **       * * *** *** = (m*2+d)%3;
     * * *** *** * **  ** *   *   (s == 0)
 *   *****   * *** * **  * *    * *   *** * 
** ** *   * *  * *  *****  * *  * if (s == 1)
 **    ** * *    ***  ** * *  * *  *   *** ***     ****   *
*  * **  ***   *  *  ** if (s == 2)
 * *** ****  ***  **** *  * **  **   *  **  * 
*  **** *** *  *   ** 
  * ** **  *   **  *** *  ****  * 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
**   **  * *** ** * *** ** * *  *  M,D,S;
***  * *   ***** *  *   ** *   *    * ** * %d",&M,&D);
*  ***  * ** * ** *****  *    *    *  **
 * *  *  ****  **** ****  ** *  ***  
  *      *         ** *****  ***  * *   ****
* *****     ****  ****** **** * ** **
***  * ** * ** *   ***  *   ***** **  *  *   ** *  *
 ***  ** *  *  * *   * ****  **** ** **
 *  **  *   *    *** **  ** * ** *   ** **** 
****    *  *  *   ** ***   *  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 * ** *** ***  *  * * **** **  m,d,s;
* *  *** *** * ** * *  * **    * **     **  ** **    **  * **
  *** ***  *  *** * * *  * = (m*2+d)%3;
 * ** ****  * **  *  * * **     (s == 0)
 *  * *** *   **  *  *  **   *    **   **  * ** ***  * * ** 
**   *  *  **    * ***  * * if (s == 1)
*  *** *  * ***   * **  ** *** * *    **  
 **********    * ****   ***   *  if (s == 2)
***** * *****   * **** *******  ***      *  ****   
**** *  *     ***  ****** * 
*   ** **  ** * * * *  *    0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 ** *** ***  ***      ***   **   **  * ***  %d",&m,&d)!=EOF)
    {
*  * **  *  ******** *  *  ***   **      ******* *  * *  *   * * 
 ** **   *** *  ****  * ** * * **   *  ***** **   ** * **** * *  
* **  **** *     * * *  * *  **     *   *** ***   **  *********  *   **  *  *  ** **  ** **   *   **** ***  *
***     * **      ** ** *****    * * *   *** **  if(s==1)
**  *     *  ******* * * *****  **    ***   *** **  *******     * * ** ** *   ***  * ***   *    *  ******
*   *   *   ***  ***  ***        *  **  * ***  ******  * * if(s==2)
 ** *   **  ****** * * * ** *  ***   ***  ******** * ** ***  ** *   *   ***  *** **** **  ** *  ** *  **    ***** 
****  ** ***    *** * * **  *   ** **  *   **  *** 
* * *   *  **   *  **  *  *  ** **  ** * *** * ****   *   *     **    **** * ***  **  ***  *
    }
**   **  * **   *******        0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   *    ***   

int main()
{
int M,D,S;

        ***         * *   * *   *   ****
 ***  **
 **   
{
  **** *** **** **  *
}
 *   *
{
*  * *   *  *   *    **
}
    ** 
{
***    ** *** *  *** *
}
 ** *** * * *** *  ***  *    *  

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.40
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.7k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users