期末考題目-Question 3

1 like 0 dislike
18.8k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 18.8k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
** * *****  *  ** *   ** *   ** *   ****  * **  *   ** * *  
*     * ** * *    ******   *** *  
  ****  **  *****  * * ** 
  *     * *    ** * *   * *  **** ** * * 
  **    * ****           *
* *  **** ** **  ** *   * *     *       *  
 * ** * * ***    ***   *
*** *    *      **** * * *  *  * ** **  ** **

*      * * ***  * *   0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*  *** *** **  *  **   *  ** **  **  ** **   *  *****        ***  *  * 
**  ** *   * * *  * *  ** *** 
* ** *  ** *  *  *   *** ** **** **
  ** ** ** *  * * **      *     **   ** *    * *  **   ** * **  *  
** ******* * *  **  *  * *   * if(s==1)
* * ***   *** *  * ***     * *** * *  * ****** *   *  ***** * 
 * * * * ***  *    ***    ** ** if(s==2)
* * ** *** *      * *    *  **  *     * **   *    ****   *   **   * *** ***
 *   * ** *  *     *** *** ***** *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
   ** ***   * **** **  * M,D,S;
    
*  * ** *    **  *   ** * **  ** ***  %d",&M,&D);
    
 ****** *******  *   * *  ** * * *   * 
 *** * * **    * *    **    ** 
 ******      ********   ****   *
 * *** *** * **   *  **   *
*  **  ** * **  * *  **  ** *  * ****   *  * **** *******   ** *   * **** ***  *******   *
      ***  ***    **       ** *
  ***  **   **  *       *    *  * if(S==1)
  * *** **   *** ** * ** 
* * *     *   **  ** ***  * **  *** *  *****  ***** * **  ****  *  **  ****  ** ** *
* **  * * * *** ** * ***  
 *     ****   ***  **      **   *** if(S==2)
   *       *    ****    * **
   ****   * *** *   *   ** * **  **    ***  ** **    * **     *** *  ***** * *  ** *    * 
 ******  *   *   *** *  
 * *        **     *** * *    *  *     0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
**** **   * **  * *  *** *  * m,d,s;
**  *  * *     *   *  
   *  * **  *** **** * ** *  ****    * %d",&m,&d);
    
 *** * * *****   ** ** *  **  + d)%3;
  *  ** * *** * ****         *  * 
* *  ** *   *  ** ***** **  * *  *
** ***  **  ***** **** 
** * * * ***** **   * *  ** * * *  ***   **   **    **       *  * *
    **   **  *  *  *    *
   ******** *     **   *   * * if(s==1)
    *   *  * * *    *    **  *
**** *    * *  *  ** **    ***  ** **  *    ** * * **  ** * * *** * ***** *  * ***  * 
* * * *****  * *  **  *   
 ** **  * *    *  ***** * **    if(s==2)
 * *     ***** * *   *   *
  ** * * ** *   **   * *  * * *    * *  *****           **** ***  *****    **   *** * *
**      *   **   * * * *****  
   **  *   *  * *  ** ***
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   ** **  ** * * *  
int main()
{
int M,D,S;
*****   **   *  ** * *  *  **  *
scanf("%d   ***  * * *   ** *    *
S=(M*2+D)%3;
if(S==0)
*** * *  * *** **  *   **  ***   *** **   
*     *   *** **   ** **  **** if(S==1)
  * **   *   * ** *  **         * ** *  * **        * *** * * ****
   ** * ** * * * * *** * ** ** *   * *  **  **  
 * ** * ** * * * * ***** ****  *** ****   *       * ** ***** ** ****   **  ****     * *  * ** ** * * **



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*  *  * * *  **   **  *   m,d,s;
*     *  **    ***     * *     **  ***  ***  * * ** **     * * * 
*  ** *   ***  *  **  ** **   ** = (m*2+d)%3;
    *  **   ****** * ** ** *  (s == 0)
**** *  ***** **** *      * *     *** **    ***  
*   **  ** *  *  *****  *** *  **  if (s == 1)
**  * *    ***   * *     * * ***   *  * * *  * *   * *  
*** *     *****  *****      * *** if (s == 2)
 *      ** **  *** **   *  *  *  *** *  *  ** **** 
 * *  *** ****     *    *
*    * **  *    ** * ** ***   **  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
**     * * *  *  *      **  M,D,S;
*   *  ****   *   * *  ***  ** *    %d",&M,&D);
  * *        *  *  ***  *   ** 
*** ** ******* *    **  * *  * *  
*******       * * ***** *   *      *        * *** ****
**** * *  *** *  *  ***   * ** **  
 * ***    ** *  ** *** * *   *   *  ***  ** * * ***  
*   ***    *  * *  *  * * ** * *
**** * ***** **  * *******  *    ***  *  **
     ** * *  * ****** ***   0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 * **   * * **     *    ***    m,d,s;
 * ***  *   ***  *  *  * *   **        *** ***   * *   *   ** *   * *    *
********     **   * ****   = (m*2+d)%3;
  *    *  *  ***   *   ***    (s == 0)
  *** **   *  *   *** * ****  ** * *             * *** 
 **** **   **       ***  ** **  if (s == 1)
******  *    ****** *   * ** *** ****   *  *   * **    *
***** ********** * *****  * ** * *   * if (s == 2)
  ***  * ******** * **    *** **    ** **  *   *****
**  * *   *** *     **  ** *
***** **  * *** *        ** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
* *    ** *  *  ** *** *   *   ** ****   * **  * %d",&m,&d)!=EOF)
    {
* * *  *  ****   * * **   **  **** **** **  * * * *    *   ***   ** *** 
* *****  * **** *** * *********   *  **  *      * ****   *  
***  * * *    * * * * * *   *  ***** * * * **    ** **   *** ***  * * * **  *** * *  ** *****  ***  *
 *  ***  **** ** *  * *   ** **** *     *** * ** ** * **    ** if(s==1)
     ******    **   ** * *  * *  *** ** *  ***     *   *        *    * *   ** *  *  * * **  
*   * **    ** * ** *      ****    **** * ** ******* ****  *** if(s==2)
   *  **  *   * * ***  ** **   **    * * *   *** * *  *  ** * ** ** **  *  * ** * ****  * ***  ***      
** * *** *    * * ***********   * *   ** *   * ** 
***  * ***    ******** ******** *** **  **   ** *  ** ** **** *  **      *   *  *   *  ****  
    }
*   *  *** * ** * * ** ** * ** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ***  **  *  *    

int main()
{
int M,D,S;

**    * * *   ** *  * * **   *  * **     
**   *  *
****
{
* *  *    **  ** **    * 
}
   **  *
{
 *   * * *  *** **   *   
}
 *** **
{
 *** *  *   **** *** *
}
*** *   * ** **  ** * * 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.9k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.5k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 6.8k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.8k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users