期末考題目-Question 3

1 like 0 dislike
1.7k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 1.7k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 *   *  * ****  *  *  *       *      *  ***        *
* ***   ***  * * *   *   * * *  ***
*     * * * *   *  *   **
** * * *   **     **  *  *  *    ***** *****  
***** * *  **     * * * *
 *   ****  *    ****  * ********* * *  ***   * 
 *  ** ***  *  **  *   **  
  ** *   ** *    **  * ** **   * * ** * * * **

  *** ***** ** *  *  *** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
* * *   * ** *  *   *  **    *   * * * *  * * * * ***  ***** ** **   
* ***    **  * * *   ** ****   *  
 **  *  ****  **    ***** **  **     
*  *   *        *  ***   *******  * ** * ***  *      ******  *    **  **
  *** **   **   *  *** *   if(s==1)
  **** * * *   ** *    *   *  *    *  *  * *   ** **  * ***  * *     *  * *
 **   * ******   *      *** if(s==2)
*   ****** * ***** *** ***     ***  *    * ***  * ** ** **   *  * **
** ** *** ** *  **  ** * * **  ** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* * * * *    *  **** **** ** **    M,D,S;
    
**   * * **  *  **    **  *********  %d",&M,&D);
    
*  **  ** *** *   *   * **      **
* **   * *  ***  *******    
  * * *  *  ***   *       *   * *
* * ****   *** ******   **   *
 * **      ****   ***** **** *    **    ** ** *  **** * *  * *** ** **    **   *     * *
* ******* *******   *** ** **  
*   * * *  ***  *  *  * * * if(S==1)
* * * **   * *    ** *  
**  ** **  **      * ***  * ***  ** ***  *   ** **   **  **  *  ***  **    **  *  *  *  * * 
 **  * ***  *** * **    **
*   * * **  * ** * **  *  ** *  if(S==2)
* *  ** *  ** *   * ** * *** 
 ****** * *   * *  *** ** *** *****   **        * * * * *   *  ***** ***** ** ****
******* **  *   * **  * * * 
****** * *  ***  *     * *****     0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
***** **  *****  *** * **  m,d,s;
 ** * **    ***  ** *** * **
 *  * ** ***     *  *  * * * *  **   %d",&m,&d);
    
     *  * * * **   ** ****      * *  + d)%3;
**    * *   * **  *   ***
*  ***  **       ** ****   **  ** ** 
  *     *  ** * ** *****
  **  *  **  *** * **  * **** *** * * *  **** ****** *   *
** *    *** **   ** **      *
* **    *  *  ** *  **    ** ** if(s==1)
 **** **       *   *       
 *  ** * *  ** ** * *** ***  *  *****  ****  ***        * *  * ******* * *   ** * ** 
  ***** ** ** ** ****  **  * 
*   *    *** * * ***   * *** ****  if(s==2)
 ***** * ** *** ***  *   **   
****  ******  * ***** *  * ** *  ***    ****       **  * ***** **    * * ******* * *****  * *** 
***** *  * ****** **   *   
   *****  *    ** ***** * 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*** *    * *** *  *
int main()
{
int M,D,S;
****** ***  **   *  *     *****   **
scanf("%d   **   ** *** * 
S=(M*2+D)%3;
if(S==0)
* * ***   * * ** *******  *        *  * * 
****   *   ****    **  *  *    **    if(S==1)
*** ******   ** *     *  * *   *   *  * ** * *** *   *  ** * * ***** 
***  **    *** *  **** *** * * **    ** * ******** *   *
  ***   ***   **** **** ***  * * ** ** * *  ** ** ***   * *  *** **  **** *  ********     ** * *  * *  



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   ** * *  *** *****    *  m,d,s;
 *       **       *  **** *  **** * **  ******      ******** * ***
* *     *** **** ** ** **      * *   = (m*2+d)%3;
* *      ***    *    *   * *     (s == 0)
  * *  * **  **     * * *  *   ***  *** **  ***        *
  *  *   ** * * ****     * *   if (s == 1)
 **  ***  **  *  *  *** **  * **** * ****     **
* * * *    **** * ** **  **    ** if (s == 2)
*   * * *    *   **   ** *  * *** * *  ***   **     * 
** ***  * **       **   
** * * * ** *   **    **  *    0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
* ********      *** * *     **    M,D,S;
 * *****  ** *   *** ***** *  *** * %d",&M,&D);
*  *****   ** **  *    *** * * **** 
***    *   ** *   ** ***  ** 
 *    *   **   * ** *      ***  *   *    * ***** * **
  *  ***   ** ***** *   **   * *
*  * * * * **   **  *  *    * ***  **     * ** **
** * **  ********  *  * *   *  ** 
**    **   **   *          *   ******  *      
 *  ** * *****  **       *  *****  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* ** *     ** **   * **  *   * m,d,s;
 **     **     *  *   ** *   ***  *   * **   * *  *       **  * *
     * **      *** *** * **   = (m*2+d)%3;
  ** *  *  *  * ** * * * **** ** (s == 0)
  *      **     ** * ** ***  *  * *   *  *** ** 
* * *** **  *****   **      *   if (s == 1)
 * *  **       ***** *   ** ****  **  * * *  *  * 
*** ****** ****     * * ****    if (s == 2)
 *** **  ** ** * * **   ***** ** ****  *   * **  
 ** * **      ** * * ***
    * *      ** * *      ***  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
     **     ******* *  *   * **     **     * * * *  %d",&m,&d)!=EOF)
    {
  ****   *     * ** **   *      * *   * **** ** *  ** ***    * * *
    *  * * * *   * ***   ***   ** *  **** **   *     *   * ** 
**** ***      **  * ** * ********     *  *    *** * ** *  *******  **    *** ******   * * ** ** ***
 * *     **  ** *    *** ** *** *  * *** ****       if(s==1)
 ***   **      * *    **  *   * * ** * *  *  ******** ****    **  ** *   **  **    * * **** *   **   
* ***  *     *   ***  ***  *    ***  **  *   ***   *   if(s==2)
** * *  *  ***   **  * ** ** *     ** *     * * * * * ***  * *  *  *  ** * *    *** * *    ** *
* **   ** * **  *    * *   ** * *   * * * **  ** *  
*  ***** ****  * * * **    **   ** **   ** ***** * ***   * **  * *****    ** * *  *  **
    }
 **   * * * ** * **   * * ** *****   0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ** *** ****  *

int main()
{
int M,D,S;

* ***    ****  ***   *********  * * ****
****** 
*  **
{
*   *** ** **** ** * ** ****
}
 * *
{
  *  ***    *** *   **  
}
* ** **
{
 ***** *   *    *  ** 
}
***** *     ***  * * ** * ***

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.97
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 809 views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 738 views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 780 views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 692 views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 624 views
12,783 questions
183,443 answers
172,219 comments
4,824 users