期末考題目-Question 3

1 like 0 dislike
9.9k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 9.9k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*  * * **** **     *   **  **** ** *  ** * ****** * *****  
  * **     *  *    * * *   ***
 * **  * ****** ** 
* **** * *   * *  **  ** ** * **     
 **********   **    *    **   
** **  * ** ** ** *     *  * **   **  *  **
  * *** * *  * *  ** * *   
**     *  * *  *       * * * * *     ** **  *

 * *** *    ** **  *  * ** ***  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 **   **     ****   *     ** **    *   *    *  ** *   * * **   ** * **  
   *  *  **       ****  *    
***   **    *   *   ****    * ** *    
****  **** * * *  *  *     *** * ** * * *   *  *******  * *   
  ** * * * ***  * * ***  * *   *  if(s==1)
 ** **  * *        ** *   *** *  ****      *****  * **** **   * *** 
* * **    * **       ***  *  if(s==2)
* ***    ***  **  * *********** ****  * * *  * ** ** * * ****  * *** ***  
* ***       **    ** *** *  *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
** * *  ******   * **    *  *    *** M,D,S;
    
 * *** ***  * *       **  **** **** * %d",&M,&D);
    
*   *** *  *      * **** ***  * **
 * * * *** **  * *    ** ****
   * *** **  *  * ****** *** * *  **  
 *** *** **   ***   ***
*  *   **    * *  * * ** **  **** ***  **   **  * *****  ****      ***            * 
** ** **    * * *   ** *  
 * * ** **  *  ** * * if(S==1)
** * **    ****  ** *   *********
 *  **  * * * *       ** **** * *  ***   * *** ** * ** *      * ***  *  **       * 
* **  *** * * *** *   **   *
    ***  ** * ***  ******* * if(S==2)
*  **  ** * * ***** ** *   *   
 ***   *   *****   *****   *   **   *  ****   * *  **  ***** *** * ***   ** ** *****
  *** *** *  *    *** *  * **** 
        ***  * ***** *     0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
   ** *  *    *       * **        m,d,s;
  *   ** *  ****  ** * ** 
** *      *  **  *      ***  * *** %d",&m,&d);
    
** * *  **  ***** * *****   ** ** + d)%3;
 *    * ** *  **  **  * *  * *
  *    **  * *** ** *** * *  ** ***
  *   **  **** ** **** * ***
** ***** *    *   * * **   ** *    * ****  ***       ***  ** * 
 *  *  * *      ******  *    **
 *   ** * * **  ** ***** **  if(s==1)
 ********* ****  *  *   *****
  * ****** ****   **  *** ** * **    * *  ** *   *** *** * * * ** *** **  *  *   ** * 
 * * * **   ** *****   *** * **
**     ** **     ** * *** * * if(s==2)
**   * **    ** * *  ** *  
* * ** ****   ***** **   ***    ***   ***** * ** *  **  *    ******* **  *** *****
 *    ** * *  ** ******   
   **   ** *  * *  *  *    *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*      *****  * 
int main()
{
int M,D,S;
* **** * **  * * * ****  *    **  * 
scanf("%d  *   *** **** **  ***
S=(M*2+D)%3;
if(S==0)
  *** *****  *    * **    ** ***    **
 **** * *  * ** *****  ** * if(S==1)
** **** *  **    ** * *  *** *  *  ***   *  **** ***  ** *** 
*** * *    * ***    **    **      **** **   *     *   **
 **** ** * **  **    *   *    *  ** **  *  * * *  *    * * * ** **   ***  ***** * *  ** * **  * ***  * *   * 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
     *  *      *   *  *  **** m,d,s;
* * ***      * *  *   * *** * **  ***  ** * ** ** *** * * *  **  
** *  ******* ** *  *  ***     = (m*2+d)%3;
 *   * ** ************  (s == 0)
** *    * *      * ** **  * ** ** *** * *******  * 
  **  * **   ***   **** *   if (s == 1)
   * **  *   **  *  * *** ***** ** ****  * ** *     
** * ** * * ** ****        *  **  if (s == 2)
 **  ** ** * *****   ****    *****   ***   *  **  *
* * **      *** *  ** ***
  *   * *   *****  *  ***  **   *** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
* **   *  * *** *****    **   M,D,S;
*   ** ******** * **  *  *     **  *****  %d",&M,&D);
* *    ** ***    **   *   ** ** ** *   
 ***  ** * *   **   *      * 
 *  **     ***  **  * *** ** * *   *  * *****     *  
* * *  ** *  *  ****   **  *   *  
******* * ***   ** * *   *** * *****   * ** ***  
 *** ****  ****** *** *** **  * 
  *   *  **  ** *      *** *** * *** ***  *  **  * ***
* * **** * *  ***  *  * *  *** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  * ****  ** *** * ** * ** * *  m,d,s;
  ***   ** *  *** *  ****** * * ***   ** **  ** *  * *        *  ***
*  * * **  * ***   * **   * *  = (m*2+d)%3;
  *    * *   * **  *  *     (s == 0)
  * *   *  *  ***** *     ****** ** * ***  ********* 
 *  *** * ******* *     *  * * * if (s == 1)
 *** * * *          **   *  **   **   
* ** * * *     *****   *** * * if (s == 2)
**  ***   *  ** * *  * *  *  *  * * **      * ***  
***** *   ** *** * ****  
  *** *  ** *  **  *** * *     ***  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
*  *   *   **     ** *****  ** *  **   *  ** %d",&m,&d)!=EOF)
    {
*   *** ****  *    * ** **  ** * *  ***   * **  * * *  
  * *** ****  *     *** * ***    * **   * *    * ***  *    ****  
    **  ****** *  *  *  *** ** *  ***  *  *   * ** ***   ********   *     *     ****     ****  * ** ** 
 * ** *   *** ******* * * * ***     *    * ***   *  ****  if(s==1)
* **  * **   ** ** * **     *   * *   ** ** *  *      * * *   ***** *** ****  * ****** **** * ****   *   ** *** *
*  * ****    *  ** **** *****   **** ***   ***   *** if(s==2)
     ***   *** *   * **   **   ***** **   ***  **   * ***** ** * ****     *  ******   *  ** *
    * *  *** *    *    *  * *  * ****** **    * ** ** **  *
***   *   * * * * *       *  * *** * ***    ** ******  * ** *   ** ***  * ** *  *  ****
    }
  **  ****  * *     **       *  **   0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *  *** *    **  ****

int main()
{
int M,D,S;

** * *********    **** *  ** **** **** *** **
** * * 
* **  
{
**  *    *   *    ***   
}
 ** **
{
*  * * * * **  **  * * **** 
}
 **  *  *
{
****   ****** ** ** ***  ** *
}
**  * ****  **   *     *** *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.162
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.7k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users