期末考題目-Question 3

1 like 0 dislike
5.9k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 5.9k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
  *   ** ** **  * *** ** **  **  ** **  **** * **  *   *** *
*   *     **      * ** *** **
*  ** ***     * *****  **  * 
*** ** ** *   ***  *** *  *   * * **  **  **** *
 ***    *** * **  * ** **  ** **
**** *    ***** *  * ***** **    ** * ***    *
***  ****   * ******  *
 *   ****    *** * ** * ** *   ****  ** 

*    ** ** * ** ** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
  * **** * *****   *  *  * **   ** *  * *  * *  ** * **** 
 *      ** ****      *  * ** *  * ** *
  ****  * * **  * **    **  *   * **
 * *  ** *****  * * ** ***     * * **  ****  **   * ***   * * *  ** 
*  *  *  * ***  *** **  * if(s==1)
 **   **  ** *   **  **   ** * ***** ** *   ** *  ****** ****  *
   *  ***  *  ***  ***** * if(s==2)
   ***    * *  * *  * ***   *   ** ******* *     * * * **  *** ******   **
*  *** **  **  *      *****  * *   0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 **  *   *  ** ** **    **  M,D,S;
    
**  * ***** *  *** ** ***  * ** * ** %d",&M,&D);
    
**   **   * **     ** *    *  * *** 
***** * *  * * ** *  *** **
    * *****  **   **  *  * *
 *  **  ** **  ***     * *
* * **   * ***** *** **** **** *  *  **   ***  ***** **** * * * *****   * *   * * * *
    *      ** * * * ****  
 *** * ** * *  * **  **  *  * *** if(S==1)
 *  *  *** * **   * **  **  *  *
 ***    ** * **  ***  **  *  **** **  * * * * *  **  * *  * ** ** *  *  * ****** * * 
 * ** **   *    ***  *** 
*** * **    **  *   **      ** ** if(S==2)
*   *** ** *****    ** ** * **
***** *  * * *      ***** * *** **** **        * *  *   ** * * * * *  *  *  *   *   * 
**** ** *  * **   *   ** ** * * *
** ** *   ** ** * * ****    * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
* * **   *  * *    **************** m,d,s;
 *     *   **    ***  ***   
 * **   ********* * **** * *** *    ** %d",&m,&d);
    
*  ** *   *  **** *  **** *    *  + d)%3;
 ** * *  * **   *  *  * **  
**  *    **  * *   *   * *** * 
  * **** *   ** *    *
  ** * *    * *    *   **  * ***   * **   ***   * *  *****  *    ***  * 
    *   *  *  *   ** * ***     **
 *    * *          * ***** ** * if(s==1)
 *        **** ***  *   * *   
  * **** * *    * ******* *  ** ** ***     *****        *  *  ***  ******    ** * *
  **   *  ** **   *   **  *  
 *    **  **  **    * * *  **** if(s==2)
* * *  * *  **  * *  ****  ***  
* *  *  *** ** ** *  *  * * ***   ***  * * *  * *     **** ***   ******  ******* **** *  ** *
  ***  * **** *   * *  
  ****** * ***** ***   *  * ** *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * * ** ****  ***** **
int main()
{
int M,D,S;
 **    * * *   *   *     *   ***** *****
scanf("%d  ** * * * **      *  
S=(M*2+D)%3;
if(S==0)
* *  ******** * ****  * * *  *** **    *
 **    ** *  *    **  *** * **** **  if(S==1)
     * *****     *** ****   *     *** *  * * **  *  * *   * *
** ***  * * * *  * ***** *   ***  *  **    ****     
* **** **    * * ** ***  * *   **  ***  * * **  *   ***  **** ****  *   *   *  ** ** * ** * * * *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* * ****  **  ** *     m,d,s;
***** ** **** *  * **  *  *    ***  *    **  * *  **  ***** 
*  *  ***** *    *      = (m*2+d)%3;
    **** **  *  *** ****  ****  (s == 0)
*     *    * ** *     **   *   **  *     * **
*   * ** * * *  * * **    *   ** *  if (s == 1)
**  * ********** **     **     * * *   * ***  **  *** 
  *** ** ****** *  *  *    * * if (s == 2)
* ** ***  **  * **** *    ** ** ***  ** *    ** ** 
*     * ** *********  *   
* *****    ** *  ****  ** ***     0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
** ** *  ** * ***  **   * M,D,S;
 * ** **   *    ** **  ********   * *  %d",&M,&D);
***         ***     *  **   * *** * 
** **  ***  * * ***   **** ***   
***  *   * **     * * ***  * *****  *  ***  * *   *   * * 
 ** **  *** *   ** *     * **  
**     **   **       **  *  *********     *** ** ** * *  * 
***  ** *****  **   **    * **  *
*   ***** ***   ** ** ****     ** * * ** ***   ****  **
* *     *   * ** ***   *  * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  *   * ** * * *****  *      * **   m,d,s;
 *  *  *** *    ** * * *    ******* **    *     **  *** 
 *   *   * ***** * ** * * = (m*2+d)%3;
   ** **  *  ** **  *  (s == 0)
  ***  ** **  ******** ******  * *  **   * *** ** 
****   **  *** *      * if (s == 1)
 ** *     ** ***   ****  ** ** *  **** ** *  *** * *
 * **     *  *** ****  * ***    if (s == 2)
*  ** ******* *  ******  * * ***   **     *      * 
 * ****   * ****  **  **  * *
* * **   *   * **   * * *** ** *  * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 **   **  *******  *****   **** **    %d",&m,&d)!=EOF)
    {
*** **   * *** * ******  *  * ** ***  *      *** *********  *** 
   **** *****  ******* ***  * *****  * * ** * * *  *  *
  *     *  **  *   * *   *** **  * * *** *** * **** **  *        **  **** ** *   *    ***** ** ****    *  * * 
*  *  ***  *     ***    * *  ***** *    ** ** *   if(s==1)
   **  * * *   *  ** **  *      * * * **** * * ** **** *   ** **** ********         * *** *  * ***** *    
 ** ****  * * ** *  * ****    * ** ** ** *  *   * *    ** **  *   if(s==2)
****     * ***   *  *  ***  ** * ** * ** * *   *  *   *  * * * * ***** ***** * **  *  **** * *      
 **  *****   ***   * ** ** * ******     ***** **  *  ** ***
****** * **   * ***  *     *  *  *** * **   * * ***** ** *  ******  * *** ****** * 
    }
*   ******* * * * *** **  *  ** * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
****  *** *  *  

int main()
{
int M,D,S;

*  * *  * **  * * ** *    ******* ** ****
*  ** * **
**   
{
   **  *  *** *  *  *
}
 *** *
{
  ****  ** * * *   **  *
}
 ** *
{
 ********  *** *  *  *
}
  ***    ****   * ***** **    

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.158
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.8k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.7k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.6k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.6k views
12,783 questions
183,443 answers
172,219 comments
4,824 users