期末考題目-Question 3

1 like 0 dislike
10k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 10k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
* *  *   **** *  **   ** *  ***   * *   *** * **    **** *
  ** **  *** * **** * * *    * **
*  ***      *** ********** ****
*****  * *         * **     ********** ** ** *
***     *** ***** * * * **
* * ***   *** *** *  * ** * ****   **** *  ***   *    *  
*      *    *****
**  ** ** *****  *  *  **  * *******  * **

 *  *   ***  *   * *   **** ** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*** **    *** * *   ****** *   *      **  *  *****  ***    *   
 *   ** ** * ** * * ** * **   * **  ****
****  ***    **   **    *  **
 * ****  * *   * *  * ******   ****  *******  **    *****   *  *  ****
****  *****   ***   *   *  if(s==1)
  ** *   *** ** *****   ****       *   **  ***** * ** *** * *    ****  
*  * **  *** ** ** ***   *  *  if(s==2)
 ** ***** ***  *  *   ***  *    *** * *** **   ** *  ****    **   *   ***
****  **** *   * ** ***  ** * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
   * * ***  ***** * * *   M,D,S;
    
 * **  * **** *  * *  *    *** * *  ***   %d",&M,&D);
    
   *   *     ** *** *** * **     *
   * ** ***  ** * **   * 
* * * ***   **  * * **  * *****  *
**** ** *  *   * *    **   *  *
    *    ***   ** *** ** *** *  *** **  **** * ****  ** * *     ** ***   **  ** *** **   ** *  
*******    ***  * ***** ** 
   * ** ** * ***         * if(S==1)
  ****   *    **  ***  **  *
  * *      ***      * * *  * * ***     * *   **   **** * *** ***  *  * * ***   * * **
* **  *******   ***    *  *
 *       *  ** * *      * * **   if(S==2)
 * * * *        * **  *** * ***
** ***  * ** ** *  * ****** * ***  **  * ***   *** *   *      **  ****   *   ** ** * 
** ***** *   *      *  * *
* **  **   * * *****  *      *     0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
**********  ** *  *  **  m,d,s;
* *  **  ** *   * * ***
** *    ***    ****  * *** *  **  *  %d",&m,&d);
    
* *  *  *   * *  *  *  * **     + d)%3;
  *  * ******* ** **  **  
   * * **  *   ***    * *      
 * ** ** ** * *** *  * ** **
   *** * *  *  ** *  * **     * * ** ***  **  *   **  ** ** * **    * 
* *** *       ***** * *   ** 
 *** * ** *  * **  * **  **** if(s==1)
 **    * *   *****  *    **
  ** ** *** **   ***  * *   * *** *   * *   * * **** **  ** * ***** ** * **  ***  ****
  * * *  ***  * *   ** 
** *     *** ****** ** * **** if(s==2)
** **    *   ** * * *** 
**   * *  **  **  ** * *  *   ** ***  ***       * **  ***   *** **    * *    ** *   ** * * *
 **** *   *   ****   * *  * 
  **  ***** *  ** *  ** * *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 **   *   **  * ** 
int main()
{
int M,D,S;
       * *****  ** **  *   *     * 
scanf("%d    ** *** *  *** * * *** *
S=(M*2+D)%3;
if(S==0)
* **** **  *   *** **  **   *     * * * *    * * 
 * *  * ** * * *****     **    if(S==1)
* *** *   ***  * * *   *  *         **  ** *  **    *   * **
  ** ****  * * ****  **  **   **  * ** ***   ** ***  **    
***** **   ***  *  ***    *** *    *  * * * *  ** ** * ** **   ** ***      *   ** *  ** *** **** *  ***



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
***  * *  **   ** **   m,d,s;
   ***** * * ** **** *  * **** * ** * ***   * * *          * * * ** *
 ***  *  ** *** **  **  * *        = (m*2+d)%3;
**   * *  * ** ** *  ** *  ***** *  (s == 0)
 *     *     *** **  *** * * *  **   *** ****     * **
***   ** * *  *   *  ***  ** *  if (s == 1)
* **    **** ** ****** **  ** ** **       ****    
**    *** * * ***  * **    ***  if (s == 2)
 ** * *** *   *  *  ***  *  *  ***    * * *   
* **  * * **   ** *  *     *
**** **  * * ** *  *  **  *  **  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
** ****   *** * *  * ** *   * M,D,S;
 *  *   *** **   *  ****** *  ** ***  %d",&M,&D);
   *    * ****      **   *****   *
* ** ** **  * ***  ***** **   *  
***  **   ** **  * ***      *  ** **** *  *  * **
 * ** *    ***  *** *** ** **
  *                ** ** *** * * **   *  ***
 ******  **  * *    ** ***
*  **   *    * ***** * ****  ** ***  ***** ****   **** 
*  **       **    * *  *** *    * * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** *  **  * ** *** *  * ** m,d,s;
  *  ** * *          * *  *** ***  *  * *   *     **  * *     
** ***** *** * **  *** * **** = (m*2+d)%3;
* **  **  *    **     * **  **   (s == 0)
**      ***   ** * *  *    * ** * *******   ***** ** 
* ** *  * **    *    ** *     if (s == 1)
*    *   ** ** *  * * * *** * * ******* ***  *** ***  *   
  ***** *  *   *   ****   if (s == 2)
 * **   **   *   * **     *** *   *      * *    
*  *  ***    *   ** *     *
 ***  *** **  *  ****  ** ** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 **    *    **  * *  **   *   ***  ** *** %d",&m,&d)!=EOF)
    {
**** *   * *** **** *  * ********  **  * * * ** ** ***   * 
 **   * **  **   * **  * ***    **    * *        *****  *  ** 
   **** *  * **    **** ****** *    **    *   *  **** *** *** ** **  *   *   *** *** *    ***  
    *****  *  *    ** * ***  ** ***   *    * *        *   *  if(s==1)
**     ** *     * *  **** * * * **** *  **** *** *  *  ******  * **      **  * ** *   *  **** *  ** *** 
      *   *** ** **  *  ***    * ** ** * ** ****    ** *** if(s==2)
*** * *   ** *****   ***  *  ** ***  ****** *  ** *    * * ** *     ** * *  ***  ** **   * ***** ***     * ** ** 
     * *  **      **  *** *   ** ** *** *** * * * *   * ***
   **  ** * **  ** **** ** *   *  * **** ** *   * * **  *** * *  ** *   *     *  ** * *  ** ** *
    }
  **** **  *  ** *** * *** *** *    * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
****  *******   *

int main()
{
int M,D,S;

  ***** * * *      **** ***  * *    *   
**** *** *
****
{
*********     **   * * *   *
}
  * * *
{
*  ** *** *    ** *  *    **
}
 *******
{
   *****  ***   *  * 
}
 **  * *** ****** ***  *** *** 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.111
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.7k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users