期末考題目-Question 3

1 like 0 dislike
17.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 17.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
  ****  **** ** * **** ** *   *  **  *** ***  * *** ** 
 *  **  *  ** *  ** * **  * 
 ** *****  *  *  **    *** **
* *      ***     * ** **  **  *** ***
******  **  ** ** *   *
*    ***    **** ** *   *  * ** ** * ** *** *
**  * ***  * ** **  * ** *
  *  ** *** * *  *    * **    *   * * ** *    

**  ** **  * *   ** *   *** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
**** * ***    * *   ******   *       *** * *****  ** ***  * *   **     
**   *** **   * *    * * *   ** 
*** * ** ***  **  **  ** *  
* * *  *  * *     *   **** * *  **  *  * ****   * *** *     *    ** *
**** *** ** *** * * **   *****  if(s==1)
   ** **** * **  ***   * *** **** ** ****  * *    **       ****   ***  
***  * *** *  **  **     ** if(s==2)
**** * **   *  **   * **** *   * ****** ***  *** **** **   ***      * *  ** 
 *****  * **** *** **** * * *** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*  ***      * **  * ******    * M,D,S;
    
    **     * *** **    *    ****  ****  * %d",&M,&D);
    
  *   * *** * *  **      **** **
***** * *  *** **  ***     *
* * * *  **  ***  ***  * **  
* * *       ****  ****
* ***  * * *    ***     *** *****   *   *  ***    ** **        ***   **
  * *     *  **   **   **
*    ***    *** *   ** *    *  if(S==1)
*   *  ***   * **   * ****  *
 *  *  ****  **  ** * *  ******   * ***    *     *  **** *        *** *  ** ***
    **  *  ***** **  * **** * 
        **** *     * **  *** if(S==2)
 *** *  **********   **** ***
****  *  ********* * *      * *  **   ***  **  * ** ** *******   ***  *** ***   * ****  ******
 * *****  ** **  *   
 ** **  * ***** * *    *   * * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
* ***** *  *  **   * *****     m,d,s;
   ** *  *    **  * ***  ** * 
 **** ** ***  *** *** ** ***** *  ** %d",&m,&d);
    
* ***  ** * ** *     **** **  + d)%3;
* ******   ** ** *      *
***  *  ****  ** ***  *  ** **** *
 *     * *   * **  * *  *****
 *  * *     * ** * * * ** ** *** * ** ** ***   * ***   ** 
 *  *    ***    * * *** * *** 
*** * * **    **         *  * if(s==1)
**** ***    * *  * *    **
 ** *   *  **  *****   **** * * ****  * ***** *  * **  *****     * *    ** ** * * **
*    * * *  **** ********  **
 *  ** *  **** *  * **  * if(s==2)
**** *  * * ****** * * ***   
**** *   * * **  * *    * *   * *   **  * *  ** ** **  ******* *   *   
***    ** * ** *** * ** * 
  *     *   **** *****  **   
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
     *  * *** ** 
int main()
{
int M,D,S;
  **   * *** **  *  ***     ** * * 
scanf("%d    * *  * **  *  ***** 
S=(M*2+D)%3;
if(S==0)
 ** *  * * *  ****      * ** * **    *   * 
 * ** ***  **    **  *  **      *  if(S==1)
     ***    ** * ** *  *  ***  *  * *   * *   *  **     **      ****
 *       * *  ****    * ** ****   *  *  **      *  * 
******    * *   *   * * * ********   ***  *    ** *** ** *** *    *  *     ******  ** ***** * *  ** 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* **  * *******    * *  ** ***** **  m,d,s;
    * *       *  ***** *** *** ** ** *  ** ****   *** **    
*  * * ** **  * * * * ** * * *  = (m*2+d)%3;
**   * * *  **  * ***  **   (s == 0)
 *  *   *  *  * * ** ** **  ** *  *  *** * * * * 
  ** **   ********** ****    if (s == 1)
*      **  ** * * * **   *    * ****      * * *
**** ***    * *   ** * if (s == 2)
***  *  *** * **  ** ** *  *    **   **  *   ***** *
******     * ******    ***** *   
 ***   *   **  ** *      ***  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    *** * ** * *      * **  M,D,S;
  ******   ****  **** ***   * *  *   * * ****  %d",&M,&D);
 *  * *  * ***    * **** *   * *    
  * * *   * *    *    ***** * *  
** ***** ** *** *  * * ******* **  ** * * ****
* *  ** ***  * * ** * *  * *   * 
*  * * * * ***      *    *  *   *  * * ***    * *   *     *   * 
 ** *** * * ** * **   *** *** *****
 *  *  * ** **   * * *  * ** *******  *    ***      *
 * * *** ***** *   *   * **  *  * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 ** * **** *    ** ***   * * ****  m,d,s;
*  ***   ** *  ** *  *  * * *    * *** ** * **     ** * * *  **** 
***    *  * ********   *** = (m*2+d)%3;
    **    ****  * *  *  *   (s == 0)
 *  *** * *** ** ** *     ** *  **      * **** * 
   **** **   * *****  ** *    ** if (s == 1)
***  ** * *   ***   * *** *   *  **    *   **  *****    
     * * *******  * * * * **   if (s == 2)
   *  ** * *  ******** *    **   *** *   * * * * *  **
 *** *  ** * **  *   **** *
 *  * **   **   **  **   *** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
    ***  * *    * * *  ***  * *   *  ****   *    %d",&m,&d)!=EOF)
    {
*    * ****  ** *** ***  ** * *** ***  * **  ***    *  * * **
   * ****    ****  ***  *** *  *   *     *** ***  * * *** * *
  *  * * ** * **  * * ** **** ** **    *  *  ***    **      ** * * *   * ** *    *** **  **  * ** * *    **
* ***   ****    ***** *  *  * *****  *** ** *  * **      ** if(s==1)
 *  * *  ****** *** ***** ********  * **  ***   *** *  * *   *** * **  ** ** **       ***  *  * **** * * ** ***
 *   *** * ****  ***** ***  ***   **     *  **  ***  if(s==2)
******* * ** * *** ** ** * *  *****   **       **   **    ** * * *   * ****  * *** *  * * *   * *   *
   *   *   * *** * * *   *   * *  **            ***  * *
     **  **  *  ** *    ** * ** *   * *****  *****  ****     ****     **    * 
    }
 *   *  ** * **  *  **  *   0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  * * ***  **  ****

int main()
{
int M,D,S;

  * **    * * **   *** * ***  ***  * 
****   *
*    *
{
     * **   *  *  *  * **   * 
}
***
{
 **** *     ** *   * *   * ** 
}
 ***    
{
 ** **  ** *  * *   
}
** * ** ****** *  * * **** 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 6.1k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users