期末考題目-Question 3

1 like 0 dislike
7.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 7.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
      ***  *  **     ** ***  * ** * *  ****   *  ******
* *  ** ** *  *     ***  ** 
*******    **** * **  * *
*   ***** **   **** * ***  *      **   **   
* *** ** *  ***   *** * *
**     *** ****  *     ** * * *  *   *** * 
** * ***  * *** *   ** 
  *** * * **** *****   *  ** ****   *    * ** 

*****    * **   * *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*   ****   * ********  ***  **   * * **   **** * ***** *    * *      * 
      *  *  * *  *    * *********  
***    ***    *  ** ***** **  * * 
  ** ** ** ** * ** **** *  *  *** * * ** **   **  *  ** ** ** *     *  *** 
**** **  ** * *** ** *     if(s==1)
**  *    *  * ***  *  ******  *  *** *  * * * *    **** **   * ** ***  *** * ** 
*    **   * **  **     ** *  if(s==2)
 *  * ** *** *  ***  ** ***    *   *     *****    ***** * ** *** ** ****   
* *    ** ****    **    **   * *  * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 * ****  * * ****** ** * *  * M,D,S;
    
*  *****  ****  *  * *  ** * ****    *   **   %d",&M,&D);
    
  *  ** *** *  *  *   *   ***  *   * * 
* * * ***  ***   *  * ** 
  **  *   **   * *** *  **** *
 * *   *** **    * *  *** * 
** **** ** *     ** * **   ***   ** ****** *  * * * ***  * *   * **** **  *  *** ** ******
*   **  * *** *   * **  ** ***
  ** ** ***   * *  *  **  *  *  if(S==1)
   ***  *  *   * **  *   ***  *
  *    * * ** ** * *** ****  **   ** *   ****   **     *  *  **   * **  * * ** **** ****
** **  **   ** *   * **
** *******     * * ***     *   *  *  if(S==2)
   *    ** *  ******* *  * *  *
   ** *    **   **   * ** *** **    *  *** *     * *****  *****  ***  * *  ** ****** *  *   *
 **    * *     *** **  ** *
*   * ***  ****    * * **   0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
**   *** **   * *   **  * *** ***     m,d,s;
*  ** ** *  * ** * ******   *   
****** **  *** **     ** **     * * *   %d",&m,&d);
    
 **  ** ** ****  *   ***    ** **** + d)%3;
* * *  *   ****** * * ***  *  
*   *  * **  ***   ***** * * ** *
 *   * * ** **  **   *  ****  * *
 * * *   **   ** ***    *****   *** *     * ***     *     *     **** ** ***
   *   **    *  *   *  *  ** *
  ***** * * **   * * ** **  ** if(s==1)
**  * **   ****** * * ***
* ***   *   ** * * * * **    * ********** *  * * * ** *  * * * * **   ***  *** ***
 * *** *   *  **** **   *** 
 * * * ** * *    ******  ** *  * if(s==2)
** * * ** * **  *  ****
 **     *** ******** * * *  *   * *   *    **  *   *** ******  ** ********* ******  * *
   * ** ******** * *  *** * *  
 *  **       ** * *  *     
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** ***  ***   **   *
int main()
{
int M,D,S;
* *  *     *    ** ***      * **   **
scanf("%d  * * **** ***** *  *  *****
S=(M*2+D)%3;
if(S==0)
**  ** **** * * ** ***** *  *   **   * * * 
* *****   * ****   ** if(S==1)
 **   *   *        ** *  **    **   **  ** * ****  **  *  *  **
*** *******  ** * ***** * **  * **** * *  *  *** *** * *      
  * *   * * * ***    * *    * *  * *  ****  *   *****  ** **  **  *   *  *        *   *  ** * *   *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 **  **   * * ***    * ****** m,d,s;
   * ******  *  *   * **  ** ***  **      * *  *  **    *** ** * * ***
 **  * ** * *  * ** **** *    = (m*2+d)%3;
 *     ******  **  * *  * * (s == 0)
  *  * *   * **   ****  *   *****  *  ****    ** 
 * * * * * * *    ** *   *  ** if (s == 1)
 *  *** *** ***** *  ***** * * * **** *** *** *  *  * 
*    ** ***  ***     *  ***  ** * if (s == 2)
 ****  *  * ****      *  **** *** * ****  *    * 
*   * ***  ***  ** *   **  
**  *  * *  * **    ***** *****   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 ******  * *** * *  *** ** *  * M,D,S;
**    * **  **  ** *  **   *     *** %d",&M,&D);
  * ***   **   * **    *  *   *   ** *
****   * *   ****  *** ** * ** *
 * **  **  * * ** **  ** ** * **** ** 
****** ** *     **    ***** *  
*  *  ** *** *   ** *  ***  ** * *  **   **** 
 *    *    * * * **  * *** ** 
** **  *    *** *       ***       *  ****   
   * * **    **    **  **  **** * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
***  * **** * *****  * m,d,s;
   *****  *  * * *  *  *  **   *     *    **** ** * * *********     
  ***** *** *  *  ****** *     = (m*2+d)%3;
 * *  **  ****  *** ****  ** *   (s == 0)
*** ***   **** *** **** *   * *  * * *  **  *** *
   ** * ** * * * *****       * if (s == 1)
* ** ******** ***  * * *   **  *      **** *    *** *
  *       ** * * **  *  ** **   *  if (s == 2)
* *  * ***  *  **** *** * * * **** **   **  ******  
 *  * ******** *    ***  * 
** * **   * *** * * **   *  * *   0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
*  **    * *** *    **     * * ***  **  **  %d",&m,&d)!=EOF)
    {
 ** * ********   * * ** ** **  * * **  ** ** **  ** * *** * ** **
***** *  * *** * *    *       * ** * *  ** * *** ******
 ******  *  *   *     ** *** * **   *   *  ** * *      **  ***     *    ****  *  *   *    *   *  *** 
  * *  *   ** **    * * *   *** **  ** * ** ***  * * **   if(s==1)
 *** * *  ******** ***  *   *   * * *  *** ** ***  * * **  *    *     * * **  ******* **  **   **  * *** * *
  **  *     *  * *  *****   * *****     ******  ***** * if(s==2)
**   *   **  *  ** **   * *** **** *   ****** ***  *   * ** * * * *     *** **    *** *  *  **** *    ** * * 
* **  *  **  ** * *** ** **  * * ** * ** *  * *  *** ***
 **  ** ***   ***  *  * ****** **   *  * * ** * *   *** *  * * *     *   * **
    }
*   *  *  *******   * *   ** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *****    ** ** **** 

int main()
{
int M,D,S;

 *  *** ** ** *   *  *   **  * ****
 **** **  
*** 
{
* ***** *** *   ***  **  
}
 * ** 
{
  *** * * *** ** *****  * 
}
***    
{
***     *  * *  *  ***** 
}
         * *  ** *  ** * ** 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.71
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.2k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.9k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users