期末考題目-Question 3

1 like 0 dislike
10k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 10k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*** *  *  *  ***    ** *  ** * **  *    **   *    ***  *  * 
 **  ** *** *  * *   **  * * 
         **** **     *   * 
* **   **  *   *      * ****  ***    *   * **
 *** ***  ****   * * ***
  * ***  ***** ******** * *****  *** * ** *  *    
*  ***         **** ** *
   * ** *    *** *   *  ***  ** *  **  **  * *

**   ***** *  *****    *   0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
   *****  *  * * * * * *** *  ** *  ** ** **** ** ** *  ** ** *  *** ** 
  * ***  ** **** * ** *** **  **
 ***   *  * ** ****  ** ***** ** *
 * *  **** **  ** ****  ***   *  ** *  *    ***** * ** ** * *         * * 
 ** *** ** *     **  * * **     if(s==1)
  *  ** * ** *** *  * *     ******   *    ****   **  * *** ***** *  *
 * *   * * ***  **** *  * if(s==2)
* **  ** * **** * ** **  *** *  *     * ***  * * ****       **** *  * * *  * 
   * * *  * *  **    *  **  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
**     *   **    *    **  M,D,S;
    
 ** ** * **** *** **  *****  *  * ****    %d",&M,&D);
    
 ***  ** * * **** ** *     ***
*** **   *    ** *       
 *  ***  *   **  *    * *  **
* *  ** *****    *      * * ***
**   *   * ** * **    * *  * *  ***   ****** ** **  ** ****       ** **   *   *
* ***    *  * *  **
* **    * * * **  ***     * **    if(S==1)
** ** ** **  *****  * **  * *
 * *  * ** ***  *   *  ** *** *   *  *  ***   **** ***  *  *   *  ***** * * * ***    
    *  * **  ***     **** **  
 ** ** *    * *  ********* * if(S==2)
   **   * ** **  *   **
*   **      ** ** *   *******     * **  ****      ** *  * **  ** * *  * ** ***    ***
* **  *  **    **** ***  *
   * * ** *  *   **  ** *  ** * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
***  **  * * **   * ** *  *** m,d,s;
 * * ***  **    ** *  *  *   
* * * *     *** *  ** * * * *****   ** %d",&m,&d);
    
 * **    * *   * ** ***  + d)%3;
** ***   *     * *    ***  * ** 
 *** *****  * ** **   *    **** * **
*  *   * **  *  * **   **
* ** ** * * *    * ****   *    **  ****     *****  ** ***    ***    
***   **  *******   *     **
*  ***** * *   *  * ******** if(s==1)
**** *  **** ***  * * ** 
*  *** ** *      * **   *      * **     *  *  *  ** ***  **** **     * ***      * *** 
** * ****  * **  *****  
  ***   *******  ** *******   if(s==2)
 * *  **    * *  *** ****     *
***  ** ** * **  *  *  **  *** * ** **** *  ******  *** *****   ****  **** * ** ** ****  ****  
   ***  *   **   ** *   * 
* **** * ** *  **  ** ** **   **
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ***  *   * *  ***  
int main()
{
int M,D,S;
 ** ** * *  *  *  ** *     *
scanf("%d ** *   * *   *     * *  
S=(M*2+D)%3;
if(S==0)
*     * * * **  *** *  *     *   ** *     *
**  *  **** *  * * ** * *  ** **  *  if(S==1)
**** * *  * *  ** * *   *   * *  * *   ** ** ***  * * *** *****
   *** ****** *  **  ** ** *   ** *   ***  ** ** ***
   ****  **   ** ***   ** ****** ** *   ** **  **  ** **  * *        * ****   *  *   ***  *  * * *  *  *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  ***   ** **     **     ***  m,d,s;
 ****  **** *** *   * * *  ****** ** *   *    *  *  **** *****   ***
* **  *****   *  ** *  * = (m*2+d)%3;
**  *     **      **** *** *** ** * (s == 0)
   *    * * *  ** **** ******* *   *  *  *** * **  
 *  ***  * **    * * * ** * *  * if (s == 1)
*  * *  *  ***      *** * *  * ****  *    ** *   
* * * **  *  * * ****     **   if (s == 2)
* *   *  * * ** * *** *    **** *  * * ****  *
* *** **  ** *    **
 *   ***  * * *** *  **    ****  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 *   *     ***  *** **  *   M,D,S;
*   ** * *** *  *   * * *    *     %d",&M,&D);
*   * ***  * * * * *** *  ** **  * ** 
     *   *     ***    *    **  **
*   *  **   * *  **   **** *     **  * **** *******  *
 * *  *  *  ***  *       **  * * 
*** ** *   *  *  **    *    **   ****** * * * *****
*  ***** **    **     **** * * 
 * *   * ** * * *    ** * ** **** ** **   * **
*** ** *     ***       **** ***   0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*    **    * * *** **** **   *  m,d,s;
***    * * ** * *   ***  * *  ** * ** *  *    *** *   * *    
  * **  * *  **   **  ***   = (m*2+d)%3;
 *   *  ** *     * *** * * *  (s == 0)
* ****   * *  *    *** ** * *******   * ** **  * ***
   * *** ******  * *    * *   if (s == 1)
** * *** ****         *** * * * * *   * *** **** *  *    
**** * *  ** **    *  *****  *  if (s == 2)
* ***  *  ** ** **   *  *** **   *    * **** *     
 * *   * *  *   **** ****  *
  * ****   *****  *    **** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 *  ** *****     * *  * ** **   *  *  ** ** %d",&m,&d)!=EOF)
    {
 ** ** ***   * ****  **  * *      *** *    *  **      * *****
   **    *   * **  **  **** **  * **     *  * *   *  *** ***   
  ** * * *** * ** **   ************ ** ** ***** ** **   ** * * * **     ******* ** * *   *   * 
*****   ***   ***   * * ***   * ***    **  ** **     * if(s==1)
***  *    **      * * * ** * * **  *** **** **  * *  ***** **  ** * ****  ***   *       **  *  * * ***** *  
*   *   * *     ***** * **       * *** *   *   ***  *** * if(s==2)
*** **     *   **** **  ** ** *  ** **  * * ** *     *    *** *** *** **  **    * ***  *** * *  **  * * * 
     **** **   *  * *  * * **         **  *     *  ** * *
  ** ** *  ***    **   *** *** *** *  * ** *********** * * ** ** *  *    * *  **** **
    }
   **** ** * ** **  ** ***    0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*   * *       *     *

int main()
{
int M,D,S;

  *  ***   *** * ** * **** *** * *   ** **
***  * **  
**  *
{
 **** *** **  **  **   * * 
}
  * *
{
* * **   *   * * **    ***
}
 ****
{
** * *** ** ** ***** 
}
  ** * *  *    *  ** **  ***** *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.176
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.7k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users