期末考題目-Question 3

1 like 0 dislike
18.8k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 18.8k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
* * **  * *  * **  **** ******         ****   **  **  
 * ** * *** *   *       ** 
***   * * * *** * *** **
  * *  * * **  * **  ** *****  * ***   
** *         *  *  **  ****
 * * ***** *****  *    * **  **  ** **   ** * **   
 **   ** **** ***    ***  ** 
 ****   *   **  *  **   *****   *   **      * ****

 * ***** **** * ** * **** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
  **      ** ** **   **** * *  *** *   * ***  *    **** *** * 
***** * **   **  ***    ****  ***  *****
*** ***   *  * ** *  * ** 
***  * *** ** * * *  ** **    *  *** *  *    ****  *****   * ***  *    * * 
 *  *    * *  **   *  * **  *  * if(s==1)
 * * **   *  *  *   **     *   *  * *    **     *   * *  ** ***   *    
***  ** **   *  *** **** *  if(s==2)
  ***  * ****  ***      *** **    *  *   *   **   *  *    *   *** *
* ** **** * *** **    ** *  *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*    ** *  * * ***** **   M,D,S;
    
   **  * **** * **  *   **    *** %d",&M,&D);
    
 ***   **    * ** * *** * * **** 
   * **  **   **** *  *** *
   *   ***  *  ** * ****    * *  ** * 
* ****** *** ***  *  * ****   
 ** ** *****  * **   * *   ** ** *  **  **   ******  ***   * *  *  ***** *  ** * ***  
*** *** *  *** *   *   *  
* *   *  ***  *   **   *  ** ** *** if(S==1)
**** *      * * ** * * ***
** ** * **** * * *    *** *  ** * *****  * * ****** * *  * *** *** ****   *     *****
        ***  *  ****   **   
    *    ***         **   ***  if(S==2)
*     ** * *** *   ** ** * 
 ** **  *   * *   ****** ****  ** **  **** **   *   *    **** *    **
**   ** * **  *  *  *** * ***
**   * ** *     * *  * *   * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
**   * **  ****   **  *   * ** m,d,s;
   ** **  * ***  *  *   
  ** * *     **     ***   ** * * *  * ** **  %d",&m,&d);
    
**** * * * ** *  **   *  * *  + d)%3;
*    * *   ***  * ** ** * 
  ** *  *     ** **  ******** 
    * *  ****  ** *    ** 
  *   ***** * ***     *  *** * ****   *  * * *  * ** * * **  ** 
*   **  ***  * * * *   * *  *
*   ** * ** ** ** *** if(s==1)
*  **** *  *      * ***** **  
* **** *** *    **** *******  * * * *  ****     **** ***  * *  *  ** * ***  
*  *** **    *        ******* 
*   *   ** ** * *      **  **  if(s==2)
  *  *  *  * ** * * * ****** 
*   *** *** *   *   *  *   ***  ** *  *   *  ** *     ** * * *  ***  * ** ****  * * 
* * ** * * * *** ****  ***** * **
** *** *       * * *  * *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** * ** * ** * ***** ***
int main()
{
int M,D,S;
 ****** **    ** * ** ** * * 
scanf("%d **  * ****        * *****  
S=(M*2+D)%3;
if(S==0)
 **** * * *  * ***** *** *   *** * *** *    * 
* * *  *  * * * *       * ***** if(S==1)
*  ** ** *  *  * *    *** ***** **    ** * ** *        *  *   *   
**   ***** *      *  **    *   *** * * * * *  ** *  ******  *
* **  * *****    * *   ***  *  **** ** * * *  ***     * ***   **  * * **  * ** ** * ****  ***** *   



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *****    **   *  ******* *   m,d,s;
*    *  *  *    * **** *  ***     * *  **   *  *   *   ***  * ****   ***
 * *** *   **  ****    ****  * = (m*2+d)%3;
  *    *  * ** *   **    **  (s == 0)
 *** *  **      *    *  * * **  *    *** ****   **
 ** * ** *  * * * * * *** * if (s == 1)
*    ***   *  * ***  *** * **** **   *** * **  ** 
   * *  *    *****    *   if (s == 2)
*  * *      **  * * * ******  ***  *  *   ***** 
  ** * ****   **** ** ***   ****
       ** ** *** **    **  ** *  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 ***  * ** ** **** **  **   M,D,S;
** *** *** *  **  **   *  *  *   * *  %d",&M,&D);
  ***** **** ***  *  ***  ****
      **    **    * *    * ***  
***  *  ***  ** *   ***** **  **  *  * *   ** ****
** *  ***  *  *    **   *** *  *** 
   *** *   * **** *  *   ** *  ****    ** *** * *** 
 *  * *   * * ** **    *****  *** **
  *   * *  ******   **** *** *  *       **  **
 ****  ***  ** *    * *   * * *  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
****   **** ** *  ******* * *   m,d,s;
   * ** *   *  **      *****  * *  * **   *** ** ** **   ***  *    * *
**      *     * **     ** *** = (m*2+d)%3;
*  * * * *  ***  * **  ** (s == 0)
   *  **   *   * * *  *  ** **   *  *** * *  ***   ** *     *
*   ** ** * *    *  **** * * **** * if (s == 1)
    *** *      * * **     * * ***** **  ***** *  * ** ** 
**  * *  ** ****    ***    * if (s == 2)
**   * ****   * * ***  ***** **    * **  * ** **  *  
 * *  **   **  ** * ***
 * * *** * ** *   * * *  *    *  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
      *   *   ** ** ** * *   * ** * *    ** *  %d",&m,&d)!=EOF)
    {
 **  ** *       * * *   **  ** **     * * **  ** *** **** *
 ** ***   *     * *  *   * * * * *  *        ** ****  **   *
**   *  *   ***  **    ****    * *   *  **  *  ***     *   * *     ** * * *** **   **   ** *** *  * ** *  
** ****** ***    ** * *     *** **** *******  *   * if(s==1)
*    **** **  ** *  *  **  ****   ** * ** * * *  *  *****  **  ****   *  *     *   **  **  ***** * **
* * *   *** ** * ***   * *  ** *    **  *  * *  * * ********  *  if(s==2)
*     ***   *      ** * * * *  *** **   ****** *   *    * ****    * * ******* *  *  ****     ****   * *      * 
*    *  ***   **  * ****  *  **   **  *  *  ****  ** *
   *    *   ***  *  ** *** ******* *  ** * *   ** * **  *     ** * *  *   **  **
    }
 ****   ** *   *** ** * ** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*** ***** *  **

int main()
{
int M,D,S;

  * **** ** *** *  *** *  * ** *****
 * *   **  
  ****
{
*   ***   ****  **  **  * *  
}
*** * 
{
* **    ***  *  **  ****  
}
  *  
{
  *     ******* *  *  *
}
** ** ** ** ***   ** *  *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.9k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.5k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 6.8k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.8k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users