期末考題目-Question 3

1 like 0 dislike
12.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 12.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*    *   *** *   * *** ****   * ******* *     *** *   
* ** **    *  **   ****  *  ** * 
  **  ****    *  * 
 * ***  * **       ** *   ***** *  *      * 
  ** *  **** *  *   ** ***     
* ***   *     ** **  *  **  *  * * ***  * *
  *  ***    * *** *** *    ***
*    *** ***  **    *  *** ***  ** * **  * **

  ****  **    * *** * **** * 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
   **  * ***  *    * *     *  *     ** ** ****    * * **** 
   **     *   * ***  * ** **** **
*   *   *****       *  **  ***** *
*   ******** *  *** *  * *****   * **     **   *    * **  *  ** *** 
  * **   *   *   ********* *   if(s==1)
*      **  * **   *   **     **  * * * *     *******    *     *** *** 
******* *****  * *      **  * *  if(s==2)
 ** * *  **   *** **  ***** * * *  ***  *    * * *  **     ** ****   ** *  * 
**** * *    **    **  *** * * * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 *  *     *      * *** ** *  M,D,S;
    
   *** **   *   **********  ** *** %d",&M,&D);
    
*  ** *   *** **  * **  ** *
*  *** * * ** *   * ** *   **
 **  ***  *  ** * *  * * * *
  * ****    **** ** *  *  
** *   **    ** * *      * ** * ** **  ** **  *    *    **** ***  ***** ***  ****** ***
 *  * *****  *  ** **    * *  
* * ** ** **  * **  **   **   if(S==1)
**  *  **  ****   *****  *  
 ** * **** *    ****   ****   *  **     *  *  ** ** ***   **     * * *  **    *  ** *    ***
** * *** **  * *    **** ** *  
  **     * **** *** *  ** if(S==2)
  **  * *  **   **   ****    ** 
* *     * *  * *   * *  ** ***    ***  **  ** * ** **** ** * * *** * *****   ****** 
 ** **   **  * ** * * * 
  *  *      ****   * * *  *** *    * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
  *** *  * *  ** * *  * * **** ** m,d,s;
** * **  **** **** *  ** *
   ** *  ** **** * ***  * * ****** * * * %d",&m,&d);
    
  ** *****  **** * * *   ** + d)%3;
 ***  **  *  * * *  * ****   **
*** *   * *********    ***  ** * *
 * *  * **** * * *   *****    **
*      **  ** * *  * *****  * *  ******* * **  *     ***  **   *** ** * * 
  *  * *  *** **  **  * *** * 
 ** **  ** *** * * ** * * ***   if(s==1)
*  ***** ***** *  ** **** *
** ********  *    *   * *   ****** ****** *  *  ***  *  *** ****  ***** *  *** *  **
*** *  **** *  ***    *  ** * *
    **   **** * *  ***   ** if(s==2)
 ****** *   ****** ** **** 
*  * ** *   *  ** **  *   ** ****      *  *** *** ** *     * **  *  * **  * * **** ***
** ****  ****   * *** * ** *
 ** * * ** *      * **  *  
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  **  ** * * ** ******
int main()
{
int M,D,S;
  *    * * *** *   * **  * * **  * 
scanf("%d ***  ****  **  **     * 
S=(M*2+D)%3;
if(S==0)
***  *     ***   ***   * * * * ***   **    *   
 *     **  *  **   **** *** *  if(S==1)
   *    ** ***     * *** **  * **   *** *  *   * *****    *** *
*   ****** ***   **** * * **   *   *      ** *** *** *
**  * * * * **  *    * ****    *  **** *******  * ** * **   *** * * *** **** * ****     ** * ****  ** **



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*  *     *  ***  *   *  * ** m,d,s;
 *** *  **  *  * ***  *   *   * * * *     * ***   * ** * ** * *
**      *   * *   *** *  * = (m*2+d)%3;
 *    * ***  *  ****  ** * * (s == 0)
*  *  **  * ***** * ***       *    ********* *** * 
*  ***    ** ** * * *   *    if (s == 1)
  * *   ****  * * * * * *   *  *  *  * ** * ** **   ***
  *** *  ***  ** *** * **  * *  if (s == 2)
  *  *** ***   *** ******  *   *********     *  
  ** ** * *****   *   *     * *
 *****  *  **** *     0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
*  *****   * *    ** * *  ****   *  M,D,S;
 ***  *  ****** *   * *  **   * ***   * %d",&M,&D);
 * *    * **    * **  *    **  *
 *   ****      ****** **  * 
 ** **   * *******   * *** ***  ***  ** **   * *** 
** ***  *   * *     *  ***      
* *****    ***  **** **     **    **      **  ***  ** 
*      ***   ******    *  * **   *  
* ** * ***   *    ***** * **   * **   *  ***  * *  
**  ***   * ** **   *** *    0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 * ***     **    ***  ***  * m,d,s;
   *   *  **   *** * *   *  *  * **     *** * ***  * ***   *  * 
    ********  * ** *   *** **  = (m*2+d)%3;
 * * ** ***  * ***  * *  ******  (s == 0)
  * *** *    *** **** **   *  ** **  **** *  * * **
*  * *   ****** **      *    **  if (s == 1)
 *  ****    * * * *  *   *    *    ** *  ***   
* *    ***** **  ** ***    **  if (s == 2)
* * * ****     * * ** *** **   ***   * ****        * * 
  *   *** *  **  * *  ****   * **
** *    ***  ***** *         *   0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 **** *    ** *  *  * * *** *      **   ** %d",&m,&d)!=EOF)
    {
* * ****** *  **** *  * **  *** **  * * *****  * *** *** * 
**** *** * ***** ***   *    ** *  ***      ***   *  * ***  *     *  *
****   **  *   ** * * *   * ********  **  **** ** ***   *   *  *****  *  **  * ****   ***  * ** **  * *  * ******
      *  *  *  ** *    *  *  * * ***    *      if(s==1)
  * ****  **    * * ***   *    *********** * *  *   * * **** ***   ** ** **  ******  *   *  **  **** 
 **** * **   ** *   *** * **** ** *** *      * * ***   ** if(s==2)
*  **  * * **  *   * *****  ***** * *  *  * *  ***   * * *  *** ***  *    **  **  * * ** ** ****** ** *
    *  * * *  ***     *   ***   ******     ******      * * *
 ***  *  **  ** *** **  * *  *    **  **  *   ** * * ***  * ** *  *  * **     *     * 
    }
  **** *** *  *****   *** *    0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
****** *  **  *** **  *

int main()
{
int M,D,S;

   **  *  ***   **     *** * *  *  *
**   ** 
  * ****
{
 *       **        **
}
  ** 
{
** ** ** * *  **  ****    * 
}
 *  **
{
*  ** *    * **   ***  *  
}
*****  *  * *  ** * ***** 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.97
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.3k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users