期末考題目-Question 3

1 like 0 dislike
13.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 13.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 *** ***  **        ** *    *   *   ** *  ** * *** *** 
*  *** **  * * ** **  
    *  *    *  *** * 
**   ** ***** * * * ***    * ** * *  * **** * *
 *   ** ** * *    ***   *  *
   * ****** *** ** * ***   ** ******* * ******  
 ** ***  **  ** * * *    **
  * ***    * *  **  ** ***** *  * ** ****

  * * * * *     *  ** ** * 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 *      **** **    *  ** * * ****  ** **  ****     *    ********    
**    *      ***   ** * *****    *
***** * * ** ***** ***  **** ***
 **     *   **  ***      **  * * *   *** ***  *****   * *    ** * *  
 * *     ** *   *  ***** * if(s==1)
* ** *****    ** **  ** *** **       *   * * *   ** *** **  * ** *  * *  *  
** *   *   *   ** ** **  * * if(s==2)
* ** *  *        * ******* * *** **** * ******  *  *  * *** * ***  *
** *  ** *  ** *** *  ** ***  * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*  * **   * *     ***** *  ** M,D,S;
    
* **   *    *  *  ** ****      ***  ** %d",&M,&D);
    
* *  * * ** ** *****  **  *   ******  
  *  * ** *   *   *** **     *
** * ***    * **  **        *     ** 
 * * *   *****  *    * * 
 * ****     **   *** ** *  *****     *     *  *  **   *  *  * *  *   * **    
   **  * **   *  * ** *  ***
   *   ** ** *    * * *  *  ** if(S==1)
 * * **** *  ***  * **  * *
  *   *   ****   ***      *   ***** ***  **  ** *** * **  * *   * * ***   
    *  **** * * *  **   *  **
   * *     * ** ** ** *   *  *** if(S==2)
   *** ** *  * ** **  *** **
**  *   **   ****    *** *****  ******  *** ** * * *  * ** *       *** * **  **    *   
 *   * * *  * *   *  ** * *  
** * ****    **  ** *   * * *** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
* * **  **  * * ******     * * *  m,d,s;
* * *  *  *   ** *** * *
 **  **         ** *** *  *** ** **** **   %d",&m,&d);
    
* *      ** ** **  ** * *** *  + d)%3;
*** * ** *****  *  * *   ***
** ****  **  ******   * ****   *  *
 **  *  *** * ** *  ***  **   * 
** ***** * ** ***   **  *  **  * *****  ** ** **  * *  * *** 
 *** **  *  *  *******    *
***  *  * * *  *  *  *  if(s==1)
 ***    ******    * *** *** 
*   * *  *  *    *** **  * **  * *     **** * *  **** *** ** **** ***  * * *****  *    
* *   *  *  *  **  * * ****  
***  * *** *    * *       **     if(s==2)
* *** * *****  **      ***   
 **   *   *** * ***   * ** ***** **  * * * ****   ****** ** *  ****    **  *
** * * **  ****     *      
**** *   * ****** ** * ** *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***** **  * * ** * ** 
int main()
{
int M,D,S;
 *****     ***  ** *** ** ** 
scanf("%d  * * ****   *   *  *** 
S=(M*2+D)%3;
if(S==0)
    *** ***  *** * *  **  ** ***    *
   * *  * **  * *  * *       *** if(S==1)
  * *   * ** *  ***  ***   *   **  *   * ***** * *  * * 
   ** * * * *  ***  ***   ***  ** * * ** *  ** *     ** **
  * * * **    ** ** ***** *  **  **   **** ** ** ***  **   *  *** *  **** * *** * **   ***   ** * ***  *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  **  * **** ***  *   * * * m,d,s;
** * **   ** * **** ** ** ** *** * ***  *  * **    *   * *  *  * * **  **
 ** * * * *** **  **** **  = (m*2+d)%3;
****** *** * **      **  **  (s == 0)
  *  * *   *    **    **  * * * **  * *    * * *** 
**** *****  ***** *  *   * *  if (s == 1)
 **    **  * ** * *    ***  **   * ***     **** ** * ** 
****  *** * *      * **  **  * *  *  if (s == 2)
   **  ** *     * **** *** **  **  *   *  ****  
**      * * * ****  * 
 *  *** * **  *  ** **** *  * *    * 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 * ****  *  * *  * **  *  M,D,S;
** *  * *   *   **   *** *****   ** **  %d",&M,&D);
* * ** **** *  **  **  *     *    *
 *  **  * **** ****** * ****** ***
* ***  * * **  **   * **   ****   ** ****  * ** *  **
* *  * * ** *  * ***  **** **  
*** *****  ***** *   ****  ** **   *  * *** **
 ***      ** *    *   *  ** ** * 
    **  * * * *  **   *  * *** ****  ******  * *
* **   *   ******* * **  *  **  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 * ** ******  **** **   *  *  *** m,d,s;
* * *  * *  **        ** ***  **   *** *     *   **  ***   * * *  * 
 ** *  ***   *** * *** **  = (m*2+d)%3;
   * *  **** ***   ** *** * **** (s == 0)
   *   *   ***** *         * ******    ** ********   
    * * **  * *   * ** *** * *  * if (s == 1)
******  ***  * ***  ** **  * ** * ** ***       * 
**    **  ** **    ****** *** if (s == 2)
   **  ***    * * ****   ********   * **  *  * 
 ****  ** *** ****   *   *  
*  * *    ** * *    *  * *    ***  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
* *******  *  ****** **** **  ** *  **    * %d",&m,&d)!=EOF)
    {
   ** *   *  *** ****  *    *  * * ** * ***    *** **   *  *
** **   *  * **  * *     ** **   *  *****  *     ****  * * 
*** ** *    * * ** ***  *  * *** * *****  *   * * ***  *  **     * ** **  **     ****    * ** * * **   ** *
      *** * *  ** * *******   ** *****    * *** ** ****** if(s==1)
***   **     ***    **    ***** *** **** **    *   *    * **    *  ***  * *     *   * **  * *  *   * *  **
**   * **** **   *  *   *  ***    * ** **   *** * *    ***** if(s==2)
 **** ***   **    ** **    ****  * ** **** * **   *   * ** * ** *   **** *** *** *  ****** *  ** * *  **   *  
*  *   **** *   **  * ** ** ** *    ** * ***  **** 
 * **  * * *   *    **  ** * ** ** *    * ***** * *   ***    *  *** *****   *  *  ** *
    }
*  **  *  * *  * * * * *  *  *      0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 **  **     ***

int main()
{
int M,D,S;

***  *  ***   *    **  ***  ** ***
**    * ** 
* *  
{
**  *** ******* **  * ****  
}
** **
{
* *  *** *** *  * **   
}
* *  *
{
*** *  ** *  * ** * *  *  
}
  * ** * * **    * ****** ***

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.184
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.9k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.7k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.6k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users