期末考題目-Question 3

1 like 0 dislike
1.7k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 1.7k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
**** **   * ****** ** * *    **   ** **  ** ** *  
******* **  ****  ** * *   ***
***     *** * *  * * 
* *   *** **   * * **  *   *  ** *** ******* 
*** ****** * **  ** ***
  *  *   **  *** ****  *  *   * *****  *   *  *
  * *****  * ****  **   *
*   **    * *   *   * *** **   **   **  * 

  ****    ***     **    *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
  * * * **  ** * *  *  **    * ** * * * * **  *   *   ** 
*  ** ** * *   *  *    *  **   **
  *  *  *    *  *  * * *  * ** *   
***  **   ** ***** ** ** *** **  *   * *** * ** *    * ** * *** **  *     ***  
  * * ****** ***  *   * *** **   **  if(s==1)
 *   * ** **   *   * *   *     ********   ** * *     * ** ** *   ****  **  ****
 *  *  * *** * *    ***  *  *    * if(s==2)
*    ** *    * * * *  *   * ***    ** ** *   *   *   * *   * * *  ** *    *
**  *    ** * ***** * * *        0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
   ** *     ** ***   *   * M,D,S;
    
  *   * **** *** ** *  *** **  * * * %d",&M,&D);
    
 *    * * *** * ** *  * **    * *
** ****  ** ****  **** 
****** *   *** ***** *  *** *    
 ** * *  **   ** *  *  * 
  ** * * *** ** *** *   *** *  *** *** ******    *  *    **  *** * **    ** * * ***   
 *** **    *  * *** * ** ** 
 * ** *  *** * *  **    *** if(S==1)
* ****  ***  ** ** **  ***
 *  *****  **     **   * ******* ********    ** * **  *  ***** *  **** ** ***  *
*  ***   *  *  * * *  * * 
 *    * *** *   ** * * *** *  * if(S==2)
    *   * *  ** *** *   *  
*  *    *   **  *    ** * *    *  ***  * ** ***** ** **       * **   *  ****  * 
* ** ** ***** *** **  *
  *  * **  * ** **  *       0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
*** ** * ***** *  *  * ***  m,d,s;
   **     * **    *    ** ***   
*    *  *  *   **       **   ** ***   * %d",&m,&d);
    
**     *  *  **   ** ***** * ***  + d)%3;
 *  ****  *   ** * ***    *  * 
**  ***   *** * *  ** *    ** 
* *** *  * ****    **  
   **  *  *   *  *****  * * *     * ****       ********  ****  
*   * ***  ** **  **** ***
 * ***  * *****  *  * ** * if(s==1)
****  ******** ** ****** *  
   *** **  ** **   * * *  ** * ***   *   * * ***  *  ****    *    ** *** ** *  *  *
 *  * * * **** **  **    **    *   
   **    *  * * **     * * if(s==2)
**** ******* **        * 
  **   *  ** *      * **  ***  * * ** *  * ****** * *  * *  **** **   ****  **  * 
   ****   * * * ***  ** ** ** 
*  ***********    * **  *     *** 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
****  **    *   
int main()
{
int M,D,S;
** ***** *  *     ** ** **   ***    
scanf("%d  * *   * *** * *****   
S=(M*2+D)%3;
if(S==0)
 *    *  ** ***  ** ** ***  ****   ** **  *
  * ** *** * ****   ***  *  ** * if(S==1)
 *   **** *  * ** **     *** *    ** * **** ****  *** *
**  *  ****  ***    ****    *** **   *****   **  ** *** ***
  ** *   * *** *   * * *  *  * ** ***    *   *    ** *******  * *  **     * *  *   *  *   * *** 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*** * *** * *** * **    *   m,d,s;
 * *     ** * *     ***   **   **     * ***   **   ** **     
     **     * **   *  = (m*2+d)%3;
    *  ** *   * ** ***  **  (s == 0)
****  * ******* ** ****  **  **    *   *  * ** *  
* * * **  ** *  *** * ***   * if (s == 1)
**    ** **   *  * ** ** ****  *  **   ****       ** *  * 
*  *  *  *   ********** **  *****  if (s == 2)
*** ****  *  *        ***  *  * ** * * *   ** ** * 
 ** ** ********* * ***  **  *
  **  **   *  * * *  *** ***     0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 *    ****  ***  * *   * *** M,D,S;
 *  * ** * ****     ***   *******  ** %d",&M,&D);
** * ** **** ** ** * * * ******       
***********  *  *   **   ** *   *
*   **  * *  *** * *  * **  **  * *   **  ** ** ** * ** 
 **** * ***      **    ***     * 
*  **  **  ****  *  *** ** * * * * *  ** **   *
 *****  *   * ** ****  * *   *  * *  
* **  ** * * *  *     ** **  *    * ***    
**  * ** ** * *    **  ** * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 ****     * ******  *  ** ** * m,d,s;
* *  * *****      *  ** **       *** *  *** ***** ** **** ***  
 ****** **   **   * * **** = (m*2+d)%3;
* *   ** ** * ** ** *    * (s == 0)
* * * * * *  * **** *** *   *  * *  **** ** *   ***  * * *
*** * *  **   ** ****  ***   if (s == 1)
 ***  ** **  *** *  ***  ***   **  *    * * *      * * ** 
 ***  *** **   *  * * *   if (s == 2)
*   * *** ** ** * * ***  **   * * *  *  *  * * * **     
 ** * ** *  *  ***  *     
** ***  ** ****  *  *       **  * ** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 * *  ** * *   ** * * ** * ** **   ** %d",&m,&d)!=EOF)
    {
    *   * ***** * **  *** *   *** ****** ***** *  **    **** *** *
*  *** * *   * **** **    *      *** *** ** ***** * *
    * *** * * *  **    *** *   ********* * ** *  *  **  ** ***  ** **** * ** *  **  * ** ** **   *** * 
*  *  **  ** ***    **   **  *     *****    * ***    * ***** **  if(s==1)
* *   ** *        ** *  *  **        * * **    * *****  * *  *******   *   **** *          ** *  * ** 
 *   *  ***** *  *** *      * *  * *    * ***  ** * *      if(s==2)
***     * *   * *****   **** *  ***  *   *    ** *  **     ****   *  ** * *   ***   * *****  *****    *  *
*      *  ** *  *** * *** *  ***  ****    *     **      ** 
     **** **    * **  ** * ***** **  *       *    * *** * *  ** ** * * ** ***   * 
    }
*  * ** *****   * *** ****  ** * * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*   **    ** * ** **

int main()
{
int M,D,S;

 * * ** *** *  * *      * *   * *  * *
*   * *
 *  * 
{
   *   *  *        ** *  *
}
 *** 
{
*    * ** * *  ****  *** *
}
* **   
{
****** *  **** *     *  **** 
}
*  ** ** **** * ***  ** **  *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.151
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 807 views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 736 views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 777 views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 690 views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 623 views
12,783 questions
183,443 answers
172,219 comments
4,824 users