期末考題目-Question 3

1 like 0 dislike
5.9k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 5.9k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 **** **  **** *    * *  * **     **   *   * **  * * **  **   *
*  ******    ***** **** 
   ***  ***  *  * ******* 
* ******     **  * **  **  **** ** ***     ** 
* *** *  **  * * * ***   
** ** *** *  *** ***     ***   ***    * *  
**     * * * *  *  * **   *
 *     * * *  * ** * *****  ***  ****    *

   ***** *   **** *   0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
** ** * **** *      *  **  *  *** ** **  *** * * * *   * ** ******* 
* * *  ** ***  * *** ***************  *
   ** *  * * ** * ***   * *    
**   * *    **  * **   ** ****  *    ** *  ***    **   **  * * ***
 *  *  * *   * ** ****** *  * if(s==1)
  *  ***** *  ** **  **  * * *** * * *    **** ** * **     **    **
****** *  ******  *** *  *  *** if(s==2)
   * * ***   ** ** * ***  * *  ***** * * *  *  * *  * *  **  **    ** * * ** * 
  ** * *  **   *** ******   * ****   0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
** ****   * **** ** ******   * M,D,S;
    
*  ***** *** * *   * * * * **      *   ****  %d",&M,&D);
    
     ******** *  **** * * * **** ** 
 * ** * *  *****  ** * ** **  
***** * **  *   ******* *  **  * 
* * *    **   * * *    ** ** 
      *  * * *       *   ***   * *  *** *** *****    *****  ** ***  ** * **
*    ***    * *** *    **  *
**    ********* *  *****      *   if(S==1)
***** ** *  ** ** ***   *  
**  * * ** ** **  * *** *** **  ** **  ** * *** *   * ****   *    ******* * ***  * *  **
**  *** * *  *  **** ** ****
**   *******  * ** **    ** *  if(S==2)
 * * **   ***   ****
* *  ** ** *  **  * *    ****     *  *** ****  * ****   **** ** **     * * *  
* **** * *  * ** **  * * * *   *
 * * *    **   ********* *   *  *  0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
  *   * ***** *** ******   m,d,s;
  *  ***  **  *    * * ** *
 ** ** *   * ***** ** * ** *    **      * %d",&m,&d);
    
* **  *******  *** * **  * + d)%3;
 ** **  **  *** **  **** * 
******** *       *****     ** * ** 
  *  *** **** ****      *
*    ** ** **   ** **  ****    *    ** **  * * *****   
******  * **   *   **  **
    ** *     *   **   * if(s==1)
 *   * * ****   * * ** *     ***** *  
 *  * *  *  **  * *   ** *****   * * *   * * **  ***  **  **  ****  * * ****   
* * **  ***   **    ** **** 
  * * **** * * *        * if(s==2)
 ********  **    * **   **   
   ***  **    * **   ***   ***** * *  **** ** ** *** **      ***   * *  **  ** *   * 
  * * *    * **   ** *    
*   **  ****   *      **** ** 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  **  *** * *   * 
int main()
{
int M,D,S;
** * *  **  *** * ** **  *    *
scanf("%d **** ** * * *     * *** ****
S=(M*2+D)%3;
if(S==0)
 ** *    *****  * **   **       *** * *  ***
 * ********  **    * ***** if(S==1)
    *      *  * **  ****** *  *       **   * *   *   ***** *  
* **   ** * *  **** ** ** *  *  *  ** *  *  ***  ***    *
*****  **   * **  **   *    * ** * ** *** ***********     *    ***  *  **  *  * **  *******  ** * *  



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   * ** ***   ** ***    * m,d,s;
*  ** ** * *   ** ****     ** ***   * *   * * ** *** * **** *
 *  * **   **   ** ****  **  = (m*2+d)%3;
    ***  ****  *  ***  ***     (s == 0)
*  **   ** ** *  **** * * * *  * * *   *****  *
   *  ***  *     * **** * * * **** if (s == 1)
*       ** ** **  * **    ** **  *  * * * **      *  ***
*  * ** **** * ** *****  *    * if (s == 2)
***      ******  ** * *** * *** *****  *  *    * 
**  * ***  ** * * *    * *
 * *  ********** ** *  ***  ***  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 **   *  ** *      **  *     M,D,S;
 * * * ***  ** *      *  * ***  *  ** **  %d",&M,&D);
*  **  ** *   **  *     *****  *****
  * **  ** * * ***** *** *** **
 **** ***     *     *    *   * * *     *   * ** *  **
********  *  *        ** *  *  
*  *  * **   * ** ***   *   *     *  *   * * *   *   * 
*  *****    ** * ** * **  ***  
   * **  * ** **   **** **  *** *      *  *** *  
  *    * ***  * * *********** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
****  ** * *  * * ** * * *  ***  m,d,s;
  **  *** *   *   * ****** ***    * * *  ****  * **  * *****   
 * **  **  ** *   ** * * *  *  * = (m*2+d)%3;
   **    * * * * * ***** **    (s == 0)
 * ****  *** *  ***   **   ** **  *   ******  **
 *  * *  ***    * * * **     * if (s == 1)
    ** ** ** *   * ** ***** ** *  *** *****    **  * * *
*** *    *    ** * * ******   *  if (s == 2)
* *     ****  *     *   *  *   *   * ***    * * 
    ** **  ***  *  * ** ***  ** 
* *** *  ***** ****** ****** * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 *   *  *  **   * *** **  **    *   %d",&m,&d)!=EOF)
    {
** **** *  * *** ** * ** **   * *    *** *** ** *    ** ** **
* *  **  **  * *   **  ** ******* *   *  * *   ** ****** *   *
* ******  *** ** **** **** ** **       **  ***  * **    ** ** *  *** ** ** ** ****    * *  *   
 *       * *** *** * *** **** ***** *** ***       * ** if(s==1)
*** **  * * * *  ** **    * * ** ***  *  **    *  * *   *   ** * *   * ** ****** *  * *  * ***  **    ***  **
 ** ** **  * * * ** * *  * ******* * **** **  * ****  if(s==2)
**  *  *  * *  *  **  * *  *  *  ****   ** * *  *  *  *    **  * ***  * ** *** **  ** * ***   ****  * *
  ** * **     *  ****  *   ***   ** ** ***  *    ****
*  ******    ****       **  **       *  ***  ** ****    **  * **   * *  *******  
    }
** *   **   **  ***     *  **    *   0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *    ****  * * ***  **

int main()
{
int M,D,S;

    *  ***    **     **  **  **** *  ** 
 * ** * 
    * 
{
 * **** *  **** **   * *
}
 ** *
{
**  **      *   ** ** *   
}
**  ** 
{
   *   * ** *   *  **
}
 ***** *  ** **   * *** *   

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.238
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.8k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.7k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.6k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.6k views
12,783 questions
183,443 answers
172,219 comments
4,824 users