期末考題目-Question 3

1 like 0 dislike
1.8k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 1.8k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 * *  **     ********    *   **    * ***  *   **  *  * **
 *********  ** ** *  **     **
 *** * *   * **  *  * * *
* *     ** ** *** *** *  * ** ** **  *     
* * ** ***   ***        * 
 ** *  ** *** * ****  * * ** **  *  *  
  *    **   *   *    **   
***    *  ** ** *         ***  **   ****      

* **   **    * *  * **  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
******   *   *   *  ****  * *   *   ******* *   ** **    ***  *  * *  
*  ***   * *   *** ** * * ***** *
* ******     *  *     * ** * * 
 ****** *  * ** * **    *******  * * ** * ********  *    * * * * **
****    ** *  *  * ** **  *   if(s==1)
* * ***  *    *****    *   ** *** **** *    ***   *     **     *    *  ** * 
 *  * *** * ** **** **   * *   if(s==2)
**** * * * * * ***  * * *              ** *   * ** * * *    *  *   * 
**  ** *****  **   *   ***  *** *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
**  ****   * * * ** *** *  M,D,S;
    
**  * ***   *  **  *     * *  *** ** *** %d",&M,&D);
    
**** **  *** *  * * **      * *  ***
* ****  **      ***** * ** 
  ***   * * * ** *****  *  *    *
*  *** *** *  *  ***  ** * **
      *  **** ****   *  ***  *** **  ** *  *  *      ***    ****  **   **  **** ******  * * *  *   
**   * **   **   ** **  * ***  
 **  *** *  **** **** *** *   * if(S==1)
    ***** *  **   ** **** 
*     ****  *  **  *** **  *** *  *** ** ** *  ***** *   ** *  *  * *** **   
*** *   *    ***  * *  **** ** 
** ** * *** ****  ****  ** ** **  if(S==2)
 *    *  **   *******   * * * **
 **  * **  * ***** ***  * **** **** ** ** ** ***** **  **  *   **  *   * *  * * *    
  **    ****  ***** *  * **
**   **   ** *   ***** **  *  ****  0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
 ******* ***  *      * **** ****   m,d,s;
  ***    *  * * **  **** **
   ****  ** ****  * * ** ** * *** **** %d",&m,&d);
    
***  *    *  ** **  *  *   ** * *    + d)%3;
******* ***   * **     *   * * * 
**** *   **** **  *  **   **  *** 
** **  ***       ***   *   *** *
  ***   **** ***    **** * ***  ******** *  ** *    *  * *    ** * 
   *  **** * **      **** *
**** *  ** *  *  **   *   if(s==1)
* *     ***  **** * ** *  *  * 
     * *     *** ***  *  *** ***** **  *   *  *  *     *  *  *   *** ***  ***  ***   **  ***
* *  ***     **  *  * *** **  
   * *  ***  ***      *****   * if(s==2)
  ** ***   ** *** ***** * *
 * **  *   **** * ***** *  * **  **  *   *       *  *   *** * ******    **** **    *
*          * ********  *** 
   ** *** *    **   *   
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*****  *  *  * * * 
int main()
{
int M,D,S;
 ********  * **    *    **********
scanf("%d * *** ** *  **  *    
S=(M*2+D)%3;
if(S==0)
 * *   *     ***** *  *** *  *  * **    * 
 *  * ***** ** **  * * **     if(S==1)
 *  **** * *       ** ** ** **** * *  *** * *** *   ****** * * **  *  * 
 *******  ***    * * * *** * **  *  *** *****  *** *  * * *  
* *  *    * *  * * * *  ***  *  *  * * * ***********   *  * ***** ** *  **      ***  *  *   * *  **   ****



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* * ** *** ** **      *  m,d,s;
*** **  **  * *  *****    *  ** *** *   * *  **  *  ** *** ** *  * *
*** ** *   *  ** ** * **   * = (m*2+d)%3;
* *    * *    *****  *  ****** (s == 0)
*****  **   *   *   * *  ** * **  **  **   ***  
   **** ** * *  ** *****    **  if (s == 1)
* *** ** * ** ** *  * **** *    * ** **  **      
*****  *   *  * **  **  * *   if (s == 2)
 *  *** *     ******* *** ** **** *  ****   * ****** 
**    *  * **    ***   **   *
 ** * **   **   *  * *  **  *** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
* ***   ****** ***   *   * *  ** M,D,S;
***  **  * *  * *  ****  ***** **    %d",&M,&D);
 * ** *******  ** *  * ******  *  *
***  * * ***  * *** *** *  * 
 ** *   * * * ** * *****   * **** *      ** * **   *  
 * ***** * * *   *   **** **  * * * 
** *  *****  ** ** ***   *** *****  * ** * * ***   *   
  **  *** ***   ** ** * *   * *   *
  *   *  ****    *** *** * ** ***  **** **   * *   
  * * **    ** * *  *   *    *** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *  * *     ** **  *     * *** m,d,s;
 *  * * ** *  *   ****  **   ***   ****   * ***  **  * * * * ***     *
**   ** * ***  ****** *     *  = (m*2+d)%3;
* ** ** * * * * *** ** *         (s == 0)
 *** * *** **  ** **  ***  ******** *** *** **  * 
**************** ** ** * **** * * if (s == 1)
 **  *****  * *   ***** **  ******  ***     *    ***  * **
  *** **  ****  *   * ***  * if (s == 2)
 *   *** *** * **   *** * * * ** ** * * ** *   ***      * 
* **** **  *     **  *
**  ****** *** *  * *****   * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
  ******  **** **  ***** ***   *  * *   ** ***** %d",&m,&d)!=EOF)
    {
   * * * *  ** **    *   * * *  ***  ** * *  **   ** ** ** * **   
** * *****     ** ** *  * *****      ****  **   * **** 
   * *    *      **  ******     *****  * *** *  ***** *** **  * * * *  **** * * **           * ***   **
* ** **  **      * **** *******    **   * * * *  * * ** * if(s==1)
** ***  * *****        *  * **  *   *  ****  *  * **  **** * *  **   * *** ** *   **  * ** ***      * *
*** *** **   **   ** * ***   *   *****  **** *  **  *    if(s==2)
  **** * * **  ** * **  *   *** * *    **   * **  ** *****   ****   **    *  ****** ** **   *    * 
 *   *  *   * *  *  *  ****  *  *  **** **   *  * *   *  ** 
** ***    *   *  * **  * ** ** *** ****** *** ** *** *** **  * * * ** *** *
    }
*   * * * ***   ****   *  ** *** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * ** **   *   * *** * *  

int main()
{
int M,D,S;

     *** ** ** *  * ****     * ***    
    *  **
*  *  
{
*   *  *     **    * **  *
}
 ** ** 
{
* *    *  *    * * ***   **  
}
    
{
 * ****   *   ** **** ** *
}
 *** *     * * ***  * **  *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.42.167
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 835 views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 767 views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 812 views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 721 views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 653 views
12,783 questions
183,443 answers
172,219 comments
4,824 users