期末考題目-Question 3

1 like 0 dislike
10k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 10k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
  *  *** * *   * *  * *    *      **  * *****  * * *  ** 
 *  **  *    *  *  *    **  ** 
   *  *  * *** * **  ** **
** **** * **** *****     ***    * ** *  ** *  ** 
 * **   ** * * **** ** 
***** *  * ***   ***** ** ***  ** * **     
   *****  *  **  *  
   ****  ** * * *  *  *  *  ****   ***  ***

 ****** * ***     *** ***  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
** ******  * ***    ****** **** * *  ** *** **   *   *** ** * *  
 ** *        ***** ***   ** ***  
 *   * **    * ** * * * *   * *  *
***   *    * *****   **  **** *  ** * *    *  *** ** ***  ** ****  **
* * * * *  * *   * *** * *   if(s==1)
** * **  *    * * *** *** * ****     ***   ****   * **    *** *** *     
** *** *  ****** * ** ** ** *   if(s==2)
  ***   ***  *     ****    **    ** ***** **** * ** ** **  * *  *
  ***   **      **        ***  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 **   ****** *    ** ** * ***  M,D,S;
    
**  ** **      **  **  *   *  ** ** * *     %d",&M,&D);
    
*  * * **  * ***   ** * **    *******
*  ** ****  *** * **  *  * *
*    ***   *    *    ** **  **  
       * **  *  **   * ** 
    *    ** * *   * *           *      ** * ** **        ** * *  *  **  * *** * * *** *   
** ***  * ***       **      
   *      *** *** * *   ** if(S==1)
**    **  *  ***  * ** *
*  * * ** *** *  * ** **  ** * *     * **  ***  *    * ****   ***      *  ** * *  *
***  **  * * *  * * **   
* *     * *  *    * *     * *   if(S==2)
  ** **** *   * * *   *****
**  * ***   **    **     **  ** *  ***  **   **  *****     ** ***  *    **  *   *** * *
 ** * *       * ***        ****
***  * ** *        **     * ** ** * * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
  ***** *   *** *         m,d,s;
 *  ** * * *** *  **  * *  *
**  * ***** * * * *   **** * * *   * *  %d",&m,&d);
    
*  *      * *  ***     * * *  ** *  *   + d)%3;
 ***  ****  *  *  **  *       
 * *** *** ***        **  *  ** **  
   * ******   * *   **  * * 
  ***  ** ***  **** *    * * ** *  *  ** ********** ********* ** *    
 * *  *****  *** *  **** **** *  
 ** *   **  ** * **  *  ** if(s==1)
* ** * *  ** *    * **  *
*  *** ****  *    ** * **  ***    ***   *       **  * ** ** *  *  * **   ***    ** ** **   *
***  * ****  * * * ** * **   
****      *** * * *   **   if(s==2)
**  *  **  **  ** *   ** **   *  
 ** *  **  * *** ** ** ****           *   *** **  ***  *      **     * *  *      **    *** *
 *  **** ********* ***     * *
*  * *****  *****  ***** *****
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ** * *  *  **** **
int main()
{
int M,D,S;
 * * ** **** **     *** *     
scanf("%d *     *****    ** *  **   **
S=(M*2+D)%3;
if(S==0)
****   *  * **  *  *    ** * ****  * * *  **
   * *  *  *  * *    ***   if(S==1)
* *  *  ***     **   **     **** *** **** **  * *  * ** **  
****  **   * * *** * *****   ******** **** ** * * *** *  **** *
** **  * * *****         **  **    *   **  *   * ****** ** *** *   * ****** **   * *    **  * * * 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
***  *  ** *** **** *    ****   * *  m,d,s;
  * * * ******* **** ** * ** **   **    *   * *** * *****  * 
  *   *     **  ** * *  = (m*2+d)%3;
** *  *** *   * ****    (s == 0)
**  *  *  *       * * ***     **   *** ***  **
 *   ***  * **  *****    * * *   * *  if (s == 1)
*   * **        ** * *  ***  *   ** ***
     *  * ***  **          *  *   if (s == 2)
*** *    ***    * *  **  * *** *   * *   *  *   ***  *  
 * * * *** * **** ***   *  
 * **  ****  * **     ***   ***  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
*** *   *      *  ** * *   *     M,D,S;
  *   **** ** * *  ** *** *** *      * **   %d",&M,&D);
 ** ******  * * *  **  *   
*  * *** * *   *   *** * * ***
*   * * *    ** *     * *  *    ****  *  * **    ** 
 *    *   **** **   *  *** ***   * 
*****  *   * * * ** *           **** * ******      
** *** * ** ******  *   ** * * ** ***
   ***** **  ****  *   *  *      ** *  * * *** * 
 *    * * *** *   * **   * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
****   **** **  * * * * *  *** m,d,s;
  *  ** ** ***** ** *  *  *  * *****     * *  ***  *   ********** **
******       ** ** * * *  * = (m*2+d)%3;
 * *  *  * ******* *** *   (s == 0)
**   ****  ** *    ***  ********* ** ***  *  ****
** ** * **  *    * **   *** **** if (s == 1)
   ***  *   ***   *  *  ************   * * * * *  *  *
* *** **  *   *****   ** * if (s == 2)
     * * *** ****  *****  **  *   *    **** *     
* *  ***   *    ***   **   *  ** *
**    ***   ***   ** *  **     * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
*  *   *  **** *    *** *  ****  * *  *** %d",&m,&d)!=EOF)
    {
**** ***** * ** *   ** **   ***********  *  * ** ** *   * * *   *
**** *  * **  * *   * **** ****    *  * ** ***  * *  *     **
   * **** *   ** * ** ***** *  *     ******   * ****  ** *   **    *  **   * ** * *         * * * * ** 
 *  **  ***   **    *  ** *   **  ** *    * ***    **** **   *  if(s==1)
* *    * * *  *    ********  ** ****     ** ** ** *  * ****    ***        * *** **  * * * *   ** *** *** ** *
   **  *** *** *    **     **** *  * *    *  ***  if(s==2)
  ** ** ***    * * ***  ** **  ****     *** *  *** ***  **  * **    ***               * * *****  * * *  *    
***** *  **** *   *  ***  *** ** * ** * ** *   * ** *  
***    **    **  ** ** *  **     *   *  **  *  *    * *** ** **  **  **   ** *  *   *
    }
 * ** * ******** **  *** ** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**** ** **   **** *

int main()
{
int M,D,S;

***  *   **  *   * * *  *  ** ***
* *** **
 * * 
{
  * *     *  * ***  
}
*  
{
**  **** ** *** *** **** *  
}
*   *
{
   ***********  *** * *
}
 * **  **  * *   *   *  * 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.194.168
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.7k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users