期末考題目-Question 3

1 like 0 dislike
7.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 7.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
  *** *  **    *  *** ****     ** * ***** *  *    * *     *** ***
 *       *** ******* *
 *   * * **     ***   **  **
 * **    *   *** *   *******     * * * 
** *       *  * ***  * ***
* *****  *  * *** *  ***  ** * * *       ** *
* * * **      * * **  ***
*    * *  **     ***  * *  *  * *  *  *****

 *  *  * *  * * *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 * **  **** *  *   *** ** *** * **  * *   ** * *  ** *****   *  *    *     * 
***  *** * *** ** * * * *      **
 ***  **** * ***********  **  ***  *
*** ***    ** * * **    *******  * * * ***   ** * **   *  ***** *  *** * ***   **** 
* **  * ** ***  *** * * *** * if(s==1)
 ** **   ***  *   **** ** ***    ***  **  *  ** *  *** **  *** * *  * *     * 
* **  ** ** * *  * * * *   * if(s==2)
* *   ***   ***  **   ** *   *** ****  *  *   * * *     **   *    ** * * *
***   **     * ** * *     **  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*  *  * **  * *   * *** **** **  M,D,S;
    
**  *    * *** ** **  *  ************  %d",&M,&D);
    
 ***  ******   *  *  **  ** **  **  
*  ****   *  *  *   *** ** 
* ** ** *** * * ***  * * ***  *
 * *  *  * *    ******* * **
  **   *  ** ** * * ** * ***   ** **  *   ** * *  * **  *** *  * *      *  ** * *  
  * *      * **  ***    * * *  *
  *  *  ** ** *   **   *  *   ** if(S==1)
**  *      * ** *   * ***  ** **
**      * * ***   ****  *  *    ** **    *****   ***** * **   *  **  * ***      * ** * 
 * *  *    ** *** * **  ** * 
 *****   **  *  ** ***  ** if(S==2)
*   * * ***  **   **  ** 
 * ***  ****   *  *  ** *  **  * ** * *  *  **  *  *  **  *  ****     * **    *  * ***
      *****   *** *** ** 
* **  ******* **  *** * *** *** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
 *  **   *** **   ** *  ** * m,d,s;
  * ******  ********  *   *   
** **   **   * *** * *****       * *    * %d",&m,&d);
    
* *  * * *    * *** ***** * * + d)%3;
 ** * ** * ** * *   *  **
 **   *    *  *             
* *  * **   *    *  * *  **
  ****  ***  *  *  **     *  * * **** *** ***  *     * * 
*      *  *       * *   *  *
 * * *   ***  ***    * ** *  * **    if(s==1)
*  ******* ** ****  ** **
**  *    *** ****  * *   *   * * *** *  * ****   *** * **  ** ** **  **** *  **    **
*** ***   ***** **    * **
*  * ***** ***  ** **    ** *  if(s==2)
**  ** **  * * **     * ***  ***
***     *   **  *     *  **  **** * *  *  **      * **** *   **     **   ** *****  * *
** * ****  ***     * ***  * *  
**  * **    ****    *** *** *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * *  *  *   **  
int main()
{
int M,D,S;
   ******   *  ***    *  *  
scanf("%d ****          *   *  *
S=(M*2+D)%3;
if(S==0)
**   ****   ***** *     ***   * * **  
*    **      * *  *** **** *** * if(S==1)
** *  * * **  ****   * *    *  **** **   *  *  ** *  ***    
* **** * ***  ** *     *   *   * **** *** ******
 ****     * ** **** * * ** ** *** *  * *  *  * **  *  ** *     ***  **** **   *  *    **  ** *     



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* * *   * *     ****   *    ** m,d,s;
* ***** *       * *     ******  * * **  ** ***     **    **   *
 * * **     *  **  * ****    = (m*2+d)%3;
** ** ****   *    **   ***   **** ** (s == 0)
 * **     * ** ** *   ** *  ***    **** * *   *  ** 
** *  * *   *  * *       *  if (s == 1)
*  * * **   * * *  ** *** *  ** * * * * *   ** **
 ***    **  * *    **    ** if (s == 2)
 **  *  * *** ** ** ***** *     * ******* ** *** *
    ** *  *** *   * * ****
** *  **   * * * *  ** *****  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 * * *   * ** ***   * ** * * M,D,S;
***   **  ** **  **     **     ***** *** * %d",&M,&D);
 * *    * ****   * ***   * *  * * 
*  *   **        *       **  * ***
 *   ** *  ******   *    ** * ** **  **  ** *
*  **   * **  * *  **  ** *  **  *
   ** *  * * * **  * *   *  ***   * *  * *  * *  *****   
*  *    *  **** * * *** ** * *** 
*  ** ** *  *** *  *   *  ************* *    *** 
  *   * * *** * ***  **     * **  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   ***      ****  *    * * * m,d,s;
  *  *   ****   ** *****  ** *  * ** **          *  * * *  *
**** ** *   ** **  * **    = (m*2+d)%3;
*   *  *  ** *  ** ****   ** (s == 0)
* ***     *    *** *** *  ** *    *** * * *  *  * ** 
  ****  * *  *      *** *    if (s == 1)
* *   ****** * ***  *  * **** ** *****     * 
      **   *      *****   *   if (s == 2)
  *    * * *     **** *    * *      *       **  ***
***   **  ** ** *** **  *
* * ** *** * **    ***   * * * *** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
  *   *    * * * ****** **** * * * ****  %d",&m,&d)!=EOF)
    {
 * *    *** ** * *  **** * ** **  *  *  *    *** **   **   * * *  
* * * **   *****    *****  *  ***  *   * ****** *   **   *    
 *     **** *  * * *  **  ** ***  *  * *   * *    *   *  ***  *** *    *********    **   **    *  **  **** **
**** * **    * * *    ** * * **  * * *  **   * if(s==1)
**** *  ** **  *    * **  *   **   * ****  ***  *****  ******** ****   ** ******    **   **   *  * *   *  *  *
 ***  *     *   ** **   * *    ** *** *** ***  *    if(s==2)
*******  * ****** *  *   * **  **   ****      ** ***  **  *      *    ** *    ** *     *** **      ** 
  * * *****   ***   *   **  *    ** **  *      ****  
*  *  *** ** * ****** * **     * * ** * *      **** ***    **  *  *   * *  ***  ****** ** 
    }
 **** **** ****  *     * *   ** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *    *    *  **  **

int main()
{
int M,D,S;

** *   *  *    **   *    * *  * *     ** 
****** ***
** * * 
{
   * ******* *  * ** *  *
}
 *  ** 
{
  *  * ***** ****** *  **
}
******
{
** *  *  * ***** *  *****
}
   *** * * **    * *  ****  **

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.179
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.2k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.9k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users