期末考題目-Question 3

1 like 0 dislike
10.3k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 10.3k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
   * ***  ** *  ***  ** * *  *   ** *      * *   *  *    * *   *
* *  ** **   *  *     *  * * **
* **  *** ** *** **  * *****
  **** * *** * *  *** *** * * ***** *    * *  
**      ***  **  *   **  
 **   * **  ***  *  ** *    ****  **    **  * **
* *       *  *   * * *****
 *** ***** ***  **** * *  *   *   * **  * 

* **   *** **** ** ***** ***  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
    *** ***  ***** ** * *  ****      * * ***** *  * *  * *  **   
 *    * ** * ** * *** * *  *   
   *** ******  * *     * *   ***  
*    **  ** ***   *  *** *** ******    ***  * ***   *   *  *   * *  *****    *
** * ****** ****   ******* *** if(s==1)
** ** ** * *  ****  * ***  **** * **  * ** **  *  *****  *   **  * *     *
*   * * *** *   ****   *****   if(s==2)
 **    ***  ***** **  *    ***   *  *** *** **       ** *****    **  * 
* * * * * * **     ***   *** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 ****  *** ** * * ***** * **  *    M,D,S;
    
*   * * * * * **** **** ****   ** ** %d",&M,&D);
    
* * **   *****   ** *    * *****  * ***
     * ****** * * *    *   
 ** *** * * ** *  ** ** * *****
   **    **** **   **** * 
  * ******    *** ** **   **  *   * * **   ** *  ** *    **   *  *** * *   * **
*  ** **  **** **  * * **
***   * ****  ****   **** if(S==1)
        ** * ** ***    ** ** 
 * ***** *** * **   **       ****  ***** * *  *     **  **** *  * * *      ** *  **** *
       ** ** *  ** **  **  * 
*     * *** * *** **** * *  **  if(S==2)
*  ****** *    *** *  *   **   
*** *  * ** *  *** ** * * *** **   * * * *  ***  ** * *   ********** **    **   *** **
** * ****    *****  * *   **
    *  **  *  *** * *  *  **   0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
 **   ***   *** ***   * * * ** m,d,s;
* *   * *   * **  *      ** * * * * 
*  *****  *  ***   ** **  * **   ** *****  %d",&m,&d);
    
  **  *  ****    * **** **  *   + d)%3;
 *   ***  * * *   *   * *   *
 ****  ** ****     * *** ** * *  ** *
  * *    * *   *******  ** *
 ** * * * * * *  *  **** **  *    * * ** *******    *  *   *   * *
 ********  **** *  *  ****
 *** * *          *  * ** ** if(s==1)
*    *   ******  ***  * **   
**   **** **    * ***   * **  *  *      *    **  *  * ***********  *** *    ***
***  * *    **  *  ** * * *  
   *  *    * *      **    * if(s==2)
 * * * **** *    ***  * *     
***  * ********  * * ** * * *  **  *  **    * *   ** *   *  **  * * * **** * **
** ** * ***   ****   **    **  
***** ***   * *      *  * *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
    * *  *******  
int main()
{
int M,D,S;
********  ****     *   * * **  ******
scanf("%d *  *** *****    **  *  *  *  *
S=(M*2+D)%3;
if(S==0)
* *  *       **** *      **  **   * **    *
 *   ***    ***  * * * *   if(S==1)
* ** *** * *  *  ****  ** * * **** *** *   **  ** **  * **  *    * *
***        ****     **   *  * *** ** *   **  * **   *
** **         * ** ** ***  ********    ** *    * *  * **** *  *   * ******* *    ** * **  *   * * * **



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  **  ** **      *** * * *** m,d,s;
***  * **    * *  ** **** **   **  *  *   *   * * ** **   * **  *  
  * *     ** *  ** *       ***   = (m*2+d)%3;
** * * *   * *** ***   *  *  (s == 0)
  **   ***  *    **    *  *   *  ** * * *   *  ***
*  **    * ****    ***  * if (s == 1)
 *    *  **  *   **   *  *** **** ***  *  **  ** ** 
 * *     *  *** ******** * * if (s == 2)
 * ***  *  * *   * *   *     ***  * * * * *     *
 * **** *   * *   ******     
 **    *  **    * *  * * **  *    0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 * **** *    *  **    *     * M,D,S;
* *  *   ** * *  ***  ***   **  **  %d",&M,&D);
      * *    * *     * * **  ***   *
* * *    **   * * **    *   ***  **
* **    *   *  ** *  ** **  *      * * * * * * * * *
** * ***    * ***** **      
****   **  ***** ** **** * ** *******   *     ***   
**     ** ** * * *  *  * **** *    *
  ** ******  *** *   *   **   *  * ****     ******
** *** ** * *** ** ** * **** *** * *   0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
**   * ** * ** * **** ****    m,d,s;
*  *** **   *       * **** *    ** * ** * **   ***   *  *  *** *   
 *  *** *   * ********  * = (m*2+d)%3;
 *    *** **   *  *** * **   (s == 0)
** ** **** *  **** *  ** * *** *  * * *   **   *
**  **** *  * * **  * ** ***  if (s == 1)
**** * *** *  **    * *    * ***    **   * **  * * **
***   **   *  ****   *** * **** if (s == 2)
     **  **** * *       **    *  ******** * * **  
     *  *   *    ** *** *  
 ** *** ***    *   ** * ** **  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 **    ****** *** **   * **** *  *   * ***   ** * %d",&m,&d)!=EOF)
    {
 **   **** ***      * *  * ***** *   *       *** *  ** *
  * * **  ** *  ** * *   * *  **  *       * * ** *  * *** *
 *   * ****   ****   ** **  * *    *** ** *  ***   * *     ** * **  * *******    *   **** *** ** **  ***** *** 
*  * **   *  * ***   ** *  *** ** * *    **  ** ****   if(s==1)
    ** * *     ***    ***    * **   **  ***** * * ***   **  ***  *  ***  **     * *        ** * **    **  
     *    **  ****    *** ***  * *** ** *   **    *      if(s==2)
 **  * *  *** **  *   * ***   **  * ****  * * **** *  * *  * *    **  ***  *  **   * *  ***   *
   *  * * * ****  ** ****** ****   * *    *  **  ** *  ***
 * *****     *    * *  *** *****    ***  *  *  * ** ******   *   ***   *  * **    
    }
 ** * *  * ** *   *****   **     0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  *  * *  **** *    *

int main()
{
int M,D,S;

   ** *  **   **** *    * * *****  ** 
 ** *  
 * ** 
{
 **   *** *  **     **
}
* **
{
 * * **  *    ** * 
}
**
{
  *  *   **    **** *  **
}
 ******* ** *  *   **    *** 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.26
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.9k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.5k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users