期末考題目-Question 3

1 like 0 dislike
10k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 10k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 *      *   ***  ** *** * * * * *  ***     **  ** ** *   * *** *
* **  ** *  *   **    ** * **   *
 *   *    *   * **
* * ** ** ** ****   *** **  *   * **  * * *** *  * 
*  *** * *  * ** *   * **
*  **  ** ******* ********     **   * * ** ** 
* **  *******    *** *
*      *  *  **  *****   **** *      

*  * *  ** ****     *** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
     ***        *  * *****  * ******  * **  ** ** ****        * ** 
** * * * **  **** * **  ******* * **
*** **** ** * ***    * **  ** *** *
*  *  *   **     ****  * * ** ** *  * **  * * *  * * ** ***** *** * ****     
** **  ***  **  ******     * if(s==1)
* * ******* *  * * ***   *    * *  ** *  *  *   ***    *        * ** * *   
*    **   ***     *     * **  if(s==2)
 **  *** * *   *  * **   **       *** ** ****  ** *  *  * ** * * ********   
    * *     ***  * * ***   * **    0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
** *** * **        ***   *  ** **** M,D,S;
    
* ***** **    **   ****** *** *** **   %d",&M,&D);
    
  **** ** * ****   ** *  *  *** * *** * * 
 **** **  ** *  * *** **  
 * *  * ** *    *  *     * **    
******  **  ***   ***      **
 *     ** ** * *     * * *  *    *  *** **  ** ** ** **  ***  *   * *  **  * **
 ***    * *  **   *  *  **
  *    ** ****  **  * **** if(S==1)
  * **     ** * **  *     * *
**    *  ***    ** * *  **  ******   *         * *** ** *  *  * * ***    ****** ** ****
 ****   ***   **** *** *** *  
***  **  ** *   ** * *     if(S==2)
 *** **   *    * * *****
  **** **  ***      **  * *   * ***    *  ******* * *         *** *    **** * ** ****
**** *****  ** *  ****   ***   * 
     ***** ****  *  ****   *   0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
   ***** * ***  * *  ** **  *   *  m,d,s;
*  *** ** *   ***   *  ***  *
  *** *  **    * ** * ** *  **   *    %d",&m,&d);
    
* ** **  ** ** ** ** * * ** *  + d)%3;
*  ** *** **          **     
  *   **   **  *** ** *   **   
*  ****  * *   ** *  * ***  ** 
* *   **  *** ********** ***    * *   *** * *  **    *     ***  ** 
** **  ** **  * *    * * ***
****  **    * *****   ***  if(s==1)
* ** ****** **  **   ** ****
**    ** *      *    * ** * * ****   ***   ** ***    *  **    ****** ** ** ** *** 
* *** ***  *  **           * 
* **  **   * **   *** ** *** if(s==2)
* ****   ***       *****   ****
   *    * **     *  * * ** * * ****  *  *    *    *   *     * *****  *  *  * * ***** *
* * *   **  ***** * ******  
*  ** ********    * * ******
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*** ** *  **** *
int main()
{
int M,D,S;
   * * ** *  *  *  * * * *   ***
scanf("%d  *  *  * ******* ** ** 
S=(M*2+D)%3;
if(S==0)
     *** *   **   *    * *   ***  **** * **
 * * * ***     **   * * ** ** * if(S==1)
  *** ** **  **    ** *  **    ***** ***  **   ****   *** ** *** 
 * ** * ** *  * ** *  ** * * ***  *    *   * * ***  *
  ****     *  ***   **  * * **** *  * ** **** * *  * * ** * * * * *** ***  ****   *   **    * ** * ** * **



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  *   * *****   *  ** * **   m,d,s;
***  *** *   **    *  *  **** *   **    * * *** *    *  **      
 ** ** **** ****  **   **  = (m*2+d)%3;
* ** * * * *  ***** ***** * (s == 0)
*     **   * *** **  *  ****   * ** *    *  *
   * *****   * *   *  * *** *  *   if (s == 1)
 *  **  * **  * * * *    ****    ****** *****  **
  *** **  **    ** * * ***** if (s == 2)
 ****** ** ****    * **** **  ****  ***** **    **  
  **   ** *** *      * * ****
*    ** ***    *  ** **   **  *  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
** ***  **** *  ** **  ** * *  M,D,S;
** ** ****  * **** ***  *** * ******  *  *** %d",&M,&D);
****  **    **** *   **  * *   
* ** ** ***** ** *  *** * *****
 * * ***** * ** **    *** *    **  **    * * *  * ***  *
* * *****   *       ** *     
*** *  ** *** *  *     *** *** *  ** ** ** ** 
  ***** * *  ** **   *   **  *  **
 * **** * * *  **   * **        * **     * *** *   
** **     ****  *  **     ** **  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* ****** ***    ***    **    ** m,d,s;
 *    * * *    ***   *  ***  ***     * ***  **** **  * *  *
  *  **  **   **  **    **    = (m*2+d)%3;
* **** *     *  *   ****    **  * (s == 0)
*   * *  *****  * **** *  * **   ** * *** *     ****  
* ** ** * *  ** ***   * * * * if (s == 1)
* * * * ** ****  **   ***** ** **  ****  *  *  **   **** 
    *  ** *    *** * ** * ** *** *   * if (s == 2)
 *   *  *  ***    *** *  **     ** * * * ** ***
* *  *  *    ***** * *** * 
* *      ** **** ****   **** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
    * *   **  * * * ******** *****  ** %d",&m,&d)!=EOF)
    {
* ** *  *** * *  * *     **  **   ****** * ** *    *  **** *** *** 
**  ******   ** *  **  ***   * *** *** * *  *  *  ***       **
  ***  ** *** ** ** *  ** ** **** *****  ****   ***   *****    * *  * * **** **** * * *  ** **  ** * * **
   *   ** *  ***** * * * * **  * *  *  * ***    * **** ** if(s==1)
** *   *   *  **** **  * ***   * * *** *  ****** *  * *    *****     *** *  * * ** ********** * * **
**  **     *  **** **   *   *   * * *  **  * *    ** ***   if(s==2)
***     ** * * * *  **********    *** *      *      *     ****** ** **  **   ***  * * *  ** ** **** ***  ** **  *
**  *****    * *      *   **   **** **  * ******* ** * ** ** 
  * ** *      * **  ** * *  **   * *   *** * *** * *** ***       * * *  * ****    *** * *   ***  *
    }
  * *** ***** * **   ** * ****   0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  **  ** **  * **

int main()
{
int M,D,S;

** *    * ** ** **** **     * **   *** *
* *  *
 ** *
{
    *      ** * **  *
}
**   ** 
{
**   **    * **** **  *
}
**** **
{
      *** *     *    *
}
***  *****  * * * *  * * * 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.223
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.7k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users