期末考題目-Question 3

1 like 0 dislike
4.7k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 4.7k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
     * **        *  ** * *****  *   **** * * **  * *  * *
*   * * **   ***   * *  * **
   * **   *  *****  ** *  *
*     * * ** * *         *   ****  *   
     **** *** **   **** * *
* **   **       * * *  *  **  *  *  *       *  
  * * *  *  ** ***  *
 * *    * ** ****  **     * * *  * ** **  

     *** **   ** *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
* *        ** * *     ****** ** * **  * **   * * *     ****    
* ** **  *   *    * ** * * ** * * * 
***  ******* *       *  ***  
*** *  * ***   * ** * **    **     ****  * * * * ****  **  * ***  * ** * **
*  * *****   **** ***** **  * * * if(s==1)
*** *  *** *    ***    **** * *  *** **  *    * *   ** *  * *   * **   * * 
** * *   * *         ** * **  if(s==2)
 ****** *****   ** **  *  ***  * ** **   *  **  *   ***   *  *  *  
* * **** **   ***         *** * *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
**  *  *  ** ** * ***  ***  **  ** M,D,S;
    
*    *** *  * *** ****** * **** ***   *  * %d",&M,&D);
    
 *  * *     * * **** *       
* * ** * ** *****  ** * 
 * * *** *  **       *** *** *
*  *    *  *     *  *  
     * **  ** **      * **      ***         ****   * * **  * *  *** *   ***  *  *** 
 ***   * ** *** *** * ****
  ***  * **** *      **   *    *    if(S==1)
 **    ** *****  *** *     * 
 * ** *   *  **  * **  ****         ****   *  ** * * * *******  *   ******  ** ***  *
 *   * * * *  * *    *****  
  ** *** ****   * ** *  *   * **  if(S==2)
    **    * **  ** ****   
* *  *  *****   *     * ****  *****    * *    ** *    *** *  ** **** *  *   * * ** 
 *     *      ***    **     *
    ** * **     * ** * * *    *      0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
  ** *    *** **  ***     *** *   m,d,s;
  * *****    ** ***    * *  *
* ** ** ***     *  ** ** *   *     **   %d",&m,&d);
    
 * *** ****  ***** * ** * ***  *   ** + d)%3;
 *** *  * *** ** * *  **
**    ******  ***  **      ** ****  *
*  * *     ***    *         *
 *  *  *  *  * *** **  **** *  **** * * ** * ****  * * *  * * *  *
  **  *   *       **  * ** **  *
** * ***  **    * **  **   * *  if(s==1)
* * ** **   **     * * *  **
* *****   ** * *  ****  *** * * * * *  **  ***  *** *  **  ***   *    * *      
*      **    * **  * **     
**** *** * * *    * ***** * *  if(s==2)
* **   ** ****** ***     * ** *
 * **  ** * *** *** ***  ****** *  *** *  ***  **    *    *   * *** * * **** * *      
** *** *** ****    * *    *  * *
* *  *       ***  *  ** 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ** **  * **     * **
int main()
{
int M,D,S;
      **  ****   * * **  ***  * ** * *
scanf("%d     ** *  ** ***   * **  **
S=(M*2+D)%3;
if(S==0)
  **** ** *****   ** *  * *  **   ***** **  *
*  *  ***  *    *    * * if(S==1)
  ****** * * **  ** *** * *** *****  ***   **  ***   *  * 
* *    ******    ****** *      ***** **** **   * ** **
**** **** ***** *** *  * ** **  ***   ** ****    *   **  * ***  **   *    **  ** *** ** *      ****



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
    **  *   *** ***    ** * **** m,d,s;
   ******* * *  *  *  * ***      *** *   **   * ** * *  ** *
 ******* ** **  ** **   * ** * = (m*2+d)%3;
**  *  **     ** * * ****** *  (s == 0)
 **  *******   ** *   *     **    *   ****  * ** * *  **** 
*** * ****   *** *   * *  *  * ** if (s == 1)
  *     * *   ** *   ****** **  **** ***    * * *   **
***    ** *** ** *  *** *  *** if (s == 2)
 * **  **  ****  **  *** * *   ** ****       * * * *  *
    ****    * *   ***
  *** *  ***      *  ** *   **  *   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
* ** * * **    **  **  *   * M,D,S;
** **** *   *   *  ** **** ** * **  *    %d",&M,&D);
 ******  * *** *    **** ** * *
  * * ***** ***** *** *  ** * * *  
   ***   *   ** * * ***   *   ** * * *   ** *
*** ** **  ****  ****  * *** *  ****
****** **   **  * *****  ** *     * * ****** **  **
 *******  ******** *  *     *  * **** 
*   **  ** *  * *     ** *   * ****    * ** *
 *  ***   **** **  *  * ** ** *  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* ***** ****   *  * ***         m,d,s;
*  ** **   **** ***  *** *   ******    * * ** *  **   *      **
  **** * ** *****   * **   **   = (m*2+d)%3;
 ****  ** ******    ** **  * (s == 0)
 ***** *   * ** * **   ** *****   * *       *  
* **      **  * **        * ** * if (s == 1)
* *     ** *   ***     **** **   * ***** **  ** 
**  ** *** *  * **** *   *  **  if (s == 2)
 **** *****   ***   * ****  *       * **** * *  ** 
* *    *  *** ***** * *  ** *
*** *  ***     ***** *     0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
  *   *  ***** *   ****    ***  ****  *  *  **   *  %d",&m,&d)!=EOF)
    {
  * ***    * * *  *   **  *   ***   *  **** * ** * ** ***    *
     ** ***     ******  **   * ***      **    **   *** * ***** ** 
  ** *  *****   *  **  ** * * ** ***  * *** * * **  ** *  ****   * *** ** *** **    *    ***   *  * **
* ****  ********* **  *  **   ***   ***  * *  **    *   *  * if(s==1)
****  ** *** ******   *****    *** * *** ********  ***** ***  * ** * *  *   * *  *** ***  *   ** * ** **** 
    *  ***  *  * ***  **  * * * ** ******  **    *  if(s==2)
*  ****  * *    *    **** **  **  * * ******** * *  * ** *** * ** *  ***** ** *    ** **    ***    *
 ***   **    *   ****    *   *  *      ***** *  ***
**  **** *       *   **  *   *  * *  ** ** * **  * **   *  * ***   ***     * 
    }
  ** *   ***   **  *    *   *   *  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**   **  *  * **** *  

int main()
{
int M,D,S;

  * **** *     * **    *  **   ** **
** * ****
*   ***
{
 *******  ***  **  * ** *   
}
*****
{
   * ** *  *    *  * * *
}
***   * 
{
******   ** ** **  * *
}
**    **   * ** **  **** **

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.21
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users