期末考題目-Question 3

1 like 0 dislike
13.3k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 13.3k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 * * **** ***  * * *  *   *   ****   *   **  * **   * ***  ** 
* *  **  * ***  **  * 
**   *  * * **  * ** *   
**** ****  **   **    ***     **  **** *  *   *
  * *    * ** * * *  *** 
 *  *** * ** * ** *   **  ***  ***** * *
***     ***  * **  
    *   ***  **  **   ** **** *** *    **  *  

   ****     *   * **** * *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
* *  * **** *  * **  *  **  * * *          ***  *  * **  *   
*   ** * **  *    *****   ***  *
**   ***  * ** ****** ***   * * **
***  *     * **** *  *** ** * *  *    ***   * **  ****   **  * * *
** **** *   *   * *   **** *** if(s==1)
 **  ** *  *  *** ** *   *  * *         * ****  *** * **  * **  
* * **  * *     ** *  ****   if(s==2)
 *  *   **  *      ****  ***** * * **  **   *****    ** ****
 *     * ** *   * * * * * ** * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* *  *****  *     **** *** M,D,S;
    
          *    ** * * **   *****        %d",&M,&D);
    
*  ***** *      ****   ***  ***
  *    ******   *** ** *** 
   * * ***** * *  *  * *    *  *
 *   *    *       * *** ****  **
****  * *  **  *   ** * *   **     ** * ** * *****   * * * *  ****    *  * ***  ***  ****
* ***** *  * * *  **     * *
*   ** ** *      *** * * *****    if(S==1)
** *   * *** * ** * ** ** **** 
   *     *      ** ****  * *** * * *  *  **   **  ***** ***   *****  * * **   **    ***
** * * *   **        *    *  
*  * *  * *   *** *  *  * * * * *   if(S==2)
*  *  * * ***  *** ****  
  * ** **   * **  *** *   *******  *  *** * *      *    * *     * ** * * * *  * * ***
****      ** ***      ** **   
*    * *** ** *  *   ******  ** * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
** * ****** *** *      *   * *** m,d,s;
    * ** *** * * ** * *
   *** * *   * * ** * * *    ***  %d",&m,&d);
    
*      *****  **     *   ****  + d)%3;
 *   * * **  *   ** *  ** * 
** ***  * * **  * *** * *  *  *    **  
 *   ***** *****    **  *  **     
******** * ** * **   ****   * **     **  * ******   * *  
* *** * * *  * **** ** **      *
**  *   ***     *  *   *     * * if(s==1)
    * *   ** * ***      *   *  *
* *  *  *    ***** **** *  *      **  *   **     ***   ****      ** **** **  **   **    ***  ** 
* ** ** *  ** *   ***  *    * **
*****  ** **  * * **   * ** * *** if(s==2)
*  ** **     **** * * ****   
 ***** *  **** *** *** *   *   *   *   *   * *** **   ***  *    * * * *** ***  * *
** * ****   *  ***  ** **  *
*   **** * *** * ***** *** **
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*** *   ** ** **      **
int main()
{
int M,D,S;
   * * *  ***  *  ** ** **  ****
scanf("%d *   **  ** *   *** * * * *
S=(M*2+D)%3;
if(S==0)
**** **  *   **    * * *  *   * *** * *      * *  
* * **   *   *  ** ***  *   ** ** if(S==1)
*** * *  ** *    ****  *** * * ** *         * *  *** **  ***     * 
 * *         ****  ***  **  *  * ** *** ** *  **  * *   
*    **  * *  **   ** * *  ****   *  ** *****  *   ** **** * ** *   *       * * * ***** * *    * 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *   * **  ** *****    * **  *  * m,d,s;
* *   ***     *  * * *   ** ** ***    * * * *  * **** **
  **   ** *    ***    * = (m*2+d)%3;
   * *  ** *  *** * * *  *   ** (s == 0)
* * *      * * *  *   **    **  *    ** ***  *  *
****  * **  * *        *  * if (s == 1)
  ***** *** **   ****  ***   *   *** * *** ****   *
*   * **   * ******* * *    * if (s == 2)
 **  ******* *    *****  **** ** * *** *    * * 
* *   ** * * **  *** * **  **
   *     **       * *  *  *  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
* **** ** * * * *    * ***   *  ** M,D,S;
 ****** *    ** ****** **** *     *  *  %d",&M,&D);
** *** *  ******  ***  ***   *   *  
* *** ** *    **   * ***  * * * *
**  **** ** ** ** ****      *  **   ***   * **  
** ** **** **** ****** **  ** ***
     **  * * **   * *** *  ** ********** ** * **   
       *  *  *   *** ***** **  *
   **  * ** ***  ****** *   **  * ** *  * *** *   *  
** **     * * * *   * ***    0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
****** * *    *    ** ****  m,d,s;
*   *     ***  ***  * ***  *   *  *  * * *** ******* ** 
****  **  ** *    ***     **  = (m*2+d)%3;
 ****** * *       * * *** *   (s == 0)
  ** * ** **   * ***** ** *  ** *   *** * **  *  *
 * * **  *   * ** * *  *******    if (s == 1)
* *  * ****     **        **** ***  * *** * *   * * 
 *** * ** * * *** ** ***** *  if (s == 2)
 **   ***  **    *  * *   *  * * ** ** *   ** *  **  ****
****   * * ***    ** *  ** **
****    ** *  *****  *    **** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
***   * ** *  **  *   **** *   ** **   **** * %d",&m,&d)!=EOF)
    {
 * **** **** **   * * *  ** * **  * *   **    *    ***** * *
  ** **  * *** **  * ***    *** * *** **   ** *   **** * *
  ** **    **** *  * ******* ** **  * *   ** ** ** ** *  * **   ******** **   ** ***** *****  ****  
* **** * *  ** **  * **  *** **** *** ****  ** *  ** **    if(s==1)
 * *  ******  *** **** *  *  *    ***  *    * **  * *   **  ****  * *  * * * *** *** ** ****      **
 *      *********        ****  * *     **** **  **** * * if(s==2)
 *  ***      *   ***  *   ******* ******** *   **  *     **  * *  *  *  *   * *  * *** *   ** * *** 
 ** **     **    *   *** **  * * *     ****     *   **
*  ** *** **    **   ** * **  ****** ** **  *  *  *        * * *** ** * * *  *  **
    }
 ***    ***** * *** **    * * ** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ** *** ****  

int main()
{
int M,D,S;

   **    ** **     *    ****    ** * *  **
*** *  * *
**    
{
  *   *  * ****    * * *
}
* ** 
{
 ** **  *    ** * *   *  ** 
}
**   *
{
 *     * * * * **    *  
}
 *  * ** **  *** *  * *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.166
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.9k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.7k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.6k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users