期末考題目-Question 3

1 like 0 dislike
16.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 16.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 ** ** ****** *   ***  *  **     *  * * ** ***   **** *   *
   * *  ***     * ******  ** *
  *****  ****      *** ** * 
 *****  *   *  * ****    ***  **   * ****
***** *    ***  ** ** *** ** 
 *     ** *  * * * ** *   ** ***   ******
**     *  ***  ***      
**     *** ****** * * ** ** **  ** *** ** 

  *    *    *   * * 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*   ** ***     *** ** ** *  ******* ** * *  ***** * ** *  *     *** 
* *   ** *  *   * * **   ** * **  * *
* ** *** ** *   *  * *** *  * ** * 
 ** **** * * *     *      *** ******* ** *  *  * *    *        * *  ***  
*** * ****  ****    ***** if(s==1)
* ***  ** * * ** * **    *  * * *      *   ** *  ** *   *** * ****   ** **     *
    *  **** *****  * *** ***   ** if(s==2)
  *  ** **  * ** *    **** *  * * ** * * * **  ** * **   * **   **    
**     ** * * *   *      ** **  ** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* ** ** * ** ****  * *** *   M,D,S;
    
 ******  **  *** *** * ********* * *   %d",&M,&D);
    
   **  ***** *  **  * * * * 
    * ***** ******  ** 
* **  ***** **** * * * *    *** * 
****    *** * ******   *  **    
 *   ****       **    **     * *   *      * ** *  * ** *     * ** ***** *** *   *  * **
****  *  ** * *    * * **** 
** ****  * * ** *  ** ***** ***    if(S==1)
     ***     * **** ** ** ****
* ****  * * *    **  ** *  **   ***      ** **  ** **** * *****  *       ** **  *** *****
*   **  * ****** **** *  *
   *** * ** ******* *  * ***  if(S==2)
** ** *  *   ** * ** * *** 
*   *  ****  * *  ** *** *  **** *     ** ****   * ****   **  * *** * ***    * * *   * *
 ** *  *  * * ***   ***
** * * **** * *  *   ***    * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
      ***** *** *    * * * m,d,s;
**    *** ** ***  ***   *  *
***  ** ****    * **      *  ** * *   *  *** %d",&m,&d);
    
*    **  *  ** *  * *   * + d)%3;
****   * **** *   *****  
**  * **  *** **** *** ** ** * *** 
 **** *** ****** * ** *   **
 **  **  **** * ***** ***   *  ** ******  ****  **** **   * * * 
** ***   * *  ******** ** * ***
* * ** **  *  **   * *  * *** if(s==1)
*   * ** * * *** ** * * *  * * 
 *** **** *  *    *  ***** * * *******   ** ******* *   *** ***  * * * ** * ***** 
**  ****  *  * **     *     **
   *  *  * ****    ******* if(s==2)
 ** * ***  * **  * *    *
 *****  ** *  *** *  **    **  ** * * ** * ****** *  * * ********  *   *
  *  *   ** *  * *  ******** ***
*  * *******    * ** **     
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  *    **    *   ** ***
int main()
{
int M,D,S;
*** *  * *****  **** ***** ** *** 
scanf("%d ****  **    ** * *    *
S=(M*2+D)%3;
if(S==0)
  ** ** ** * *  * *   *****  **** **** * * 
**    ***   * * ***** *  *  *   if(S==1)
**   ** * *** *  **** *  ** **  *   * **  * * ** **       **   *
*     ** * *** *      *       ** **** ***  ****  *  
 ***   ** *****   ** ** *******     **  **** * ***   ***     *** * * ***   **** ****  * * * *  *  **  **



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
   * * *    *  *** ****  * *****   m,d,s;
** ****      *   * **    *  ** ******* * **  *  * ****** *  * **  * 
  * **  ***   *******  * **** = (m*2+d)%3;
  * *   **     *  *** **     * (s == 0)
 ** ** *** *** ***   ** * ***  *  * ***    *   **** * 
  **  ** **  *      **  *  * if (s == 1)
     **    * **    **  * * * * ** ********** *
** ***  *  *  * * *    ***   *  if (s == 2)
 ***  ** * **** *   ** ** **  ****   ****   
 * **  *  ** * ***** *** *** *    
*****      *****     **       * 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 *  *** *** * ***   ** * *  * **  M,D,S;
* * **  ** ****** * ** * * ***  *  %d",&M,&D);
 ***    * *** * *   **  **  *  * * **   
** **     * *     ***       **** *  
 * * * * * *   * **      *  ** ***  * * * *
 **  *  ***   *  * *    *    *** **
 **** *  *** *****    *  **     *** *** * *  *  *    *
  ** **  * *  * ** ***  **  **
*** **   ** ** *  * *** *****  ** ***  **   
*  *     *** *  ****  *  *    *  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*** ** *  * ****  * ****** * m,d,s;
* **** * ****  ***      *  ***** ***    *  ***  **    *  **  **
    * * ***** *   **  *** = (m*2+d)%3;
     ** * * *  *    *  ***** (s == 0)
** * ******  * **  * * *** ** ********* *   *** * *
  ** * *   *    * * * ** * *    if (s == 1)
  *    * ** *** **   *    *  *          *** ** *  **
** ***** ** ***  **  *  ***  if (s == 2)
 ****      ***  * **  * *** ***  **   ** *  
  * *  *   * *****  *  
 * **    * ***   *  *  **    **  **  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
**   ** ****  ***** ****  * ***** * ** %d",&m,&d)!=EOF)
    {
 *****  ****** *  *** ***   *  ** *  * *** * * *** *** ****
**  ****  *   **  *** *** *  **  **   ** *  * ***  
*    **       *  ***** *  ****  ***  ***   *** *****  *     **   *  **** *  ***      *  **    * **   *
**     *  ** ***   * ****   * *  ** ***   *  * **    ** if(s==1)
** ******  **  *  *   *   **    **  ****  *      *        * ***  ** ***  * *  * ** *  ** ***   * *  * *  *
******      * ***   **  **  * ** * *     ***  **  *  * if(s==2)
  * *     ****** ** *  **  **    **  **** *   * **    *** **** *  ***  ****** *    *** ****  ** *** **  ** 
* **** **   *  ***  * ** **  **  ** *** ** **   * *  * ***  *** 
***    ** *  * ******   **  *  ** *   *** ** * **    * **** *   ****  * 
    }
**    **** ** *   **   ** * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 **  *    **   *   

int main()
{
int M,D,S;

******** *  *   **  ** * * ****  
  **   ***
   *  * 
{
** ***** * ***** *  
}
  * *
{
     ** *  **  * **** **
}
 * **** 
{
   ***   ** ** * ** 
}
 *  *   ****   *  * *   * **  * *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.165
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.4k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 5.8k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users