期末考題目-Question 3

1 like 0 dislike
7k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 7k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*  ***  ** *  * * * *** ***  ******  ***  **   *  ******* * ***    
    * ** *    * ****    * 
 *** ***** * * ***  ** * ***
 ***  * **  * * *****   *  *   *  **  *  **  **  *
   *  ***   *  ***   
 * *  *** ** *    ** * * ** * * *  *  *** *  *** *
    ** * *         *  ** 
  **    ** *** ** *  *  ***    *  **   *

  *** ***   ***       *  ** **  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*  **   *****   **  * * *  * *     * **     ***  * * ** ** * ** * 
 *    **      **  ***** * *
 ****   *  ***     **  *       **
  ****  ****  **   ****  **  **   ****    ** **   * **** ****  * * *** * *   
*  *   ****  * *    *   *  ** * if(s==1)
****** ***  *  *   *  ******  * ** * ** ****   *****   * *** * ***   
*******   * ** *  * * ** *  *  if(s==2)
 *** ****   **** * *  ****   * ** * ** ***  **   ** *  * *   *
     * *********   *** ** *** * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 ** *  ** ***  ***** **   ****** M,D,S;
    
  ** * ***  * ***   *    *  * * %d",&M,&D);
    
   *  ** * ***   * ** *   **** ** ***
*  * ***** ** *  *  *** * 
  *** **** **   * *  * **  * *  *
* * *    ***   ** * ***  ****  
 *   **     * **    * *** * *** ** **    *  **   ***  *** *  * * **  *  *      *  *  * 
 *  **  * *   *  ****  * 
 *  *  ****   *   * *  *  if(S==1)
 *** ****  *  *  *** ***  *
** *** **  * *** * *  *** ***  **   * ***    **  *** ***  **  ** ****  ** ** *   
 * * ****  **  *    *
 ***  *     **        ****** **  **  if(S==2)
*** ****  * * * *   ***   ****** *
***  * **     * ****   * *  *******   *    ** ***** *    *  ** ** ** **** * ***    * 
  *    * *  *  *  * **   ***
**  ***  * ** ******  *  *   **  0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
**   *  *        *   ***  ** m,d,s;
**  *** ** ** * ** * **** * 
 *** * ** **   * *     ** * * **    %d",&m,&d);
    
*  *****    ** **  * * * *** * * * + d)%3;
*  *  * **** * *** * *   
*** * * *  * *****    *  ** ***
* ** * ****  **  *** *  *   ****
*   *   *** *** *  * * **    ***** **   *** **   *   ***   ******      *  
    ***** *** **  *   * ** 
   * **   *     **    **   *     if(s==1)
** * ** **    ** *  ** ** * *
****     *      *  *   **** ** ******  *  **  * ****     ** *****  ** ****  **   *** * * 
   * * **   * *********   **** *
**  **    ** ** ***    * * * if(s==2)
*   *** ** *****   **     
 *   ***   ***   ***  *    * *  * *   *    **   ***** **     *** ** *  * **    * **
  *  * *  *** * *** *  * **  
  * **  * * * ** ** *  * ** 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  * * **   * * *
int main()
{
int M,D,S;
* **  ** *   * * **   * ****     *
scanf("%d   ** *     ****  * *   * **   
S=(M*2+D)%3;
if(S==0)
  *  * ** ** * * ** *****      **  ****** *    
 * **     ***  *****  *  **  * if(S==1)
        ****** *     * *   * * *** ***   * ****   *    *  *  *
*   *    * * *     * ***    *  ** **********  *  ** *
***   ***   *  *       ******  * **   *   * *  * *   **  * ***   **   *****    ** *      *** ****** **



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
****   *    ***    * ** **  *  *  m,d,s;
 ***   *****    *****  *    ** * *   ** ***  ** ***** *  * 
  *    *  *   **** ***** * **   = (m*2+d)%3;
  ***  *   ***     **  *  * (s == 0)
  ***  **    * * *   *   * * ** *   *  * *  *   * **
** *  * *  *   **      * * if (s == 1)
*       ** * **** * **  ** ** **    * ****  **   
*** *  * *  * * *  **  *  *    if (s == 2)
******* *  *  ***    ***  ***        ***       *****
* ** *  *  * **    ****** * ***
**** **           * **** *  * **  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
**  *  * * * *  * * *  **   M,D,S;
  *  * * *  *  ****    * ** *      * %d",&M,&D);
**   *  **   **  *****  * ** *  **
** ***  ***  ** **  **     **
* *** * **  * ** ** * * **  **    ** **    *** 
         ** * * ***  *   * 
* *  *   *****    ***** *  *  ***     **   *  **** 
  * * * **** *      *  *   *   ** 
***  * ** * ** * *   *     *    * *  **  *** 
*** **    *  * *** **   ** ** * *** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
**   ** **  **** *   * ****  m,d,s;
*   * *   * ***    * **  ** *  **   ** ***  * *  * *  ** ** 
  *** * **  * *** * * **********  = (m*2+d)%3;
 ** ***        **  * **   * (s == 0)
 * **  * * **        **    ** * * * ***   * *  ** *
  * *    ** *       *  * **   if (s == 1)
  *  ** *****  ****** ****      * *    ** ** * * ** 
* *** * *   ***   **** *   **  if (s == 2)
  **   **  *** *** **  *  ** * ** * **** *  *** **** ** *
 * * *  *   * ** *   **** * 
* ** ***     *     **** *  *** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 **  ** ** *  **   * *   *   ***  **    *  %d",&m,&d)!=EOF)
    {
* ** ****    *  * *** * ** *** ** *     **** * * ** **  ** *
**  **  ***  *** ** *   *   * * * ** *  **   ***** ***   **  * *  
  *  *  *** * * * **  *     *** ****  ***  * * * *  ** * *   *  *  ** **      *   **  *   **  
   *  **   * * *  *  * * ** **  ** ***  *  **   ***   if(s==1)
*  * *  *      *     *     *  *        **   * * * * **  ***  **** * *   **  ******* ** **  * ***
 * ****** **  **** *    * ** *  *  * *    ***** * ** *** * if(s==2)
     **    * * ** ****    *    * ** ** ** **   * *    *   *  ***    *  ** ** * *  ***  *****  *  **** *   **
 **   * **  *  * ****      ** *****  *   ******  * **
**    ***** ** * * *  ***** ** ***  **  *   *  *  **   ** * ** * **  **  *** ** **  *
    }
   * * *******   *  ********   * *   * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * *   *  * *   ** * 

int main()
{
int M,D,S;

****  ** * **  *** ***  *   * ** * *
****   
* * * ***
{
** * *  *    ** ***** 
}
  * 
{
** **** **  ** ** * *  *
}
*** **
{
** *** ***** **  **  * *   *
}
  ******   *   * *  **

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.53
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.2k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.9k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users