期末考題目-Question 3

1 like 0 dislike
12.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 12.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 * ** **** *  *****  * *  **  * * * *    *********** * * * ***** 
***** ***  ** ** ** * * **  
*      **   *  *****  *** *
  **          *** *      **     * *** **   
 * * ***  **  *  ** 
       *** *    *  ****   * *     *  ******* 
**   *** ** **    *******
*   ** * ** *  * * * ** *   ********  ** ***

 **  * * * * ***  * **   0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 ** ** * **  * *  * * *  ***  *  ***** *******  * *     ** *****   
  *** *   **   ** * ***  ** * * **
  *  * * *  *     *** * *   
*   ******* *  * * *  ** * **   **  * *  * ***** **  * **** * ****   * *  *** 
***       *  * * *  ***   *  if(s==1)
***  ** ****    * **** * **  ***** ** *  *   ** ** *  **    *** *  * 
 *******        ***   **   *  if(s==2)
      *     *** **     ** ** * *   **  ** ******   * ****   **  *
*** ***  **  * ** * * *****  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* * * **** * *   *  *   *   *  * M,D,S;
    
*  ** ********       *  * **   ******  %d",&M,&D);
    
 ***  ** *  *    ***   **  *** **** 
    * ** ***         *    ***
* *    ****** * ** ** *  * * * *  * *
*********  ****  ******* *  
*  *   *    * *  ***  * *  *  *** *  *  *  ** * **  **  *   * * ****** *  * **** **  *
*** ** **     **  * * *   ***  
 **   ***  *****   ** ***** *   **  if(S==1)
  * * * *            * * * **
*  *  ***   *   *     *** *    **** *   **   * * * *    * *** **** *  *    *** * **** *  *
*****  ****   *  ***  ****  
   ** * *   ** ** **    *** * if(S==2)
 ****  *  * *   * *    * * **  **  
* * ** *     * *** ** **  * *  **  * * ****** ***   *  *   * ***   **  ***    **
****** * * * *   *** **  ** 
*  ***    * * *   **     *     * * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
* *   *         ****      m,d,s;
 **    ***    **** *   
*  ** ** * ******** * * * *  * **  ***   %d",&m,&d);
    
** **   ****  *  * ** *  * * *     + d)%3;
 **** * * ***   *  *  * ***
* *     **   * * *****  **** * *   
** ***        * * ***** ** 
**** **** *** *** *** * *** *   **********  **   * **  *  *  ** ** 
  ***** * ** *** ****  ** 
*  *  * *   **  ********  * *  if(s==1)
 *   *** *  *      **     **
*  **  * **    *****  *** **  ***** ****** ***** ***     *  ***   *    *******  *** *     
  ** *   *   *  ***    
  **   **** ***  **  ****   *  * * if(s==2)
***  ** *     *  *** *  **  *  *
*    ** *  *  *   *      * *  * *   * *       *  ** **  ******* *  * * * *  ** ** 
* **** *   **  *** * * * * 
*****    ***** *    **** * *   
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *      **   **   ***
int main()
{
int M,D,S;
 *** * *  ** ***  ***  *  *** * * 
scanf("%d  * * * *   ** ***  *
S=(M*2+D)%3;
if(S==0)
 * ** *****  **   ** * *** **  *****  ** ***
 **  * ***  *  ** *****  *  ***  if(S==1)
* ****  *** ** ** ***  *   * * *    *  ** * ***** * ** **
  *  * * *   *** ** *  ** *  *  * ** *   * **** *  **  *
***   *** *** * * *  **    * *  * * ***  *** * * *    ****       ***   ** * *   *  **



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*  *** * ****  * * ** ******  * * m,d,s;
  * * *  *  * **   * **   *   *** ** ** **  *** ***** * **    ** ** *
* **** ** ** * **  * * * ** = (m*2+d)%3;
  *      *    * * ** * *  *  (s == 0)
**********  *   * **     ******      *  *     *   
 * ***** * *  *****  * ****   if (s == 1)
  * *  **   *  ** *   *    *   * *****     *      *
 **  ***    **   *    *   * *** if (s == 2)
***** *****   ***    * ***** *  ** *      *  
* ***   * **     **** * ** *
**  ***  **** *     * *******  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
**  ****    * *** *   * **     M,D,S;
*     **** *  * *   *   **    *   ** * * %d",&M,&D);
*** * *   ** ****        ***   *  *   
** ** * * * ** *     *  *        
 *   **** *   * * ** * ****** **    ***  **  ** 
* ** * ***  **     *** * *   
  ** *  *   *  * ** * ** **** ****   * **  * *   *  **** 
** *    ******    * *** **  ***  ** *
 ** **  *** ** **** *  ***** *   * *   ****     *         
  * *    *   * * *  **  ** *  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* ***   ***  * *  ****  ** m,d,s;
  *  *  *  ** *** *       * ** *** **   * *  * **** **    ** * * ****
* ** *   **     * *  ***** *   = (m*2+d)%3;
     *    ***  * * * ****  (s == 0)
 ***  ** **  * *** ****  ** ***   * *  * ** * **  *  ** 
** * ***   ** * * **  ** *** if (s == 1)
 **  ** **    *  **  *  * ** * ** * *   ** * * ** ** *  *
** * *   * * *********  if (s == 2)
 *** ***  ****   ***  *      *  ** ***   *     
  **  **  *    * ****   ** *** ***
* **** ******   * *  **   ***  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 ****  ** * **     * * ** **  * *   **  %d",&m,&d)!=EOF)
    {
* *   *****      ***   ***   ****** * *  *  ****    * ***   
*   *  *  ** * * ****  *** **   * *     ****   *    *  * ** *
 * *   *  **** *  * *  ***    *       * ****   ***** *  ** ** **  ** ****  *  *********** * ** *   * *   *
** *  ***  **    *  **  *  * ** *  **     **** if(s==1)
**  * *      *  *     ************ ** *   ** *** *     *****    **** * * **  * *   ** ** ** *    ** * 
  *****  **   * ** * *      *** *  * ** * * ****      * ***** * if(s==2)
   * * *  *  **   *    ** *** * *   **** * ** * ***  * * *   *** **  **  ***    *  *   **   * *      *  **   *
*   *** *******  *** ******  * *   **  * * * ** * 
  *** **  *  ** **** ** *  *   **  **     **       **  ** *** *  *** *   *** ** 
    }
    *  * ***  ** *** * * *  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
    ** *   **  *  ** * 

int main()
{
int M,D,S;

*  * ** *** *  *    **    *  **  
**    ** 
**   
{
*** *  ** *  *  ** ***  
}
* * *
{
*** ***  *  * **   ** * *
}
   
{
   ** *    * * * * **    
}
*  ***  *   ** *    ***  *   * **

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.38
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.3k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users