期末考題目-Question 3

1 like 0 dislike
7.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 7.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 * *****  *****     ***  *    **  *   **    *   *   ** *  *  ***
  * *** *  *   **** ** * * ***
 ** ** *   * ** ** *  *  *  *
  * *  *   **  ** *****  *    ** * * * * ** * 
*  ***    **** ** **    **  * * 
  * * *  *  ** * **       *****  * *  **
 **   *  * *****  ** * **   
  ****  *  *** **   ***  * ** *   * *** 

***  * * ****   * *   0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
* **** ** **    * *    *        ***    ****** * ** *  *   *  * 
   *  * **      *  ** **  *    ** 
** * ***   * * ****** *  * ** *    
**   ** **     **    *****     *****   *   * **  *  *   **   ** ***** * 
  *  *    **   *****   * *      if(s==1)
**** * ** ** *** *   *  ***   *  * *   **  *   ***  *** * *  *  **** *   
*  *** * ***** ****** **   if(s==2)
  **   **  **   * *   *****      *   *  * *** **   *  *  **  ***    *
*    *     **  * ****  ** *** * *   0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* ** **   ****   ** **  * *  ** M,D,S;
    
* **** ** * *  * **     ** * *    ** *  *  %d",&M,&D);
    
**   * *** *****  ** ******   **** ****
* ** * *** **  *  ***  **
**  *** *   *  **** *** ** * 
** * ** *     **** **    * *
* * ***  *   *** *** ** *** ***** **** ** ** *  *    **   **** ** ******  *       *  ** 
 *    * ***** ***   ** * ** * *  
* *      **  *** *     **** *  **  if(S==1)
* ** * *  **  ** *    * *  *  
***  *     * *     *** * *  *****  *   ** * **  * *** ****     *  ***     *   ** *
****  ***    ***  * * *    
*  * *****  ** *** **  **      if(S==2)
 **** *   * *******
 ** ******* ** ***     **   *** * *    ****  * **   *    * *** * ** *******
*  *  **  * * ****    *****
* *** *** * *  *  **      *   **  0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
  ***  ** ****   * ** *  **** m,d,s;
* * **  *  *    * *     **
*  ****       * * **** **** *   ** ** * %d",&m,&d);
    
* *      *    ***       *** + d)%3;
 * ** *   * **       
******* *  **  *   **** ***  **  **
*** ***  * * **    **
*  * ** * * * ****** *** * ** ***** ***    *  * ***  **** **** * 
 * ***  *  *   * **** ** ****  *
 *** * *  * *  ***        ** ** if(s==1)
**   *** ** ** * *    ***
 * *** *   *** *  ** *  ***  *  *      *** ***** *  *    *  *  *** * * *   *** ** * 
   ****    *** *      * 
* *****  *  **** *   *  ****  *  if(s==2)
** ***  * ** *   **** ** **  
* ***  *   *    *  * *   ** * * *  *  * * ** *  * ****   *    * * ** *  *  *     ** *  *** 
    ****   ** *   **  *   *
**   *** * * * * *  *    **  *  
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * ***      *  * ** *  *
int main()
{
int M,D,S;
*   * *  ***   **  ** ***    * * * 
scanf("%d ****   ** * ****    * ** ** 
S=(M*2+D)%3;
if(S==0)
*      *  **   * ***  *   ****   * * *****   
  *   *** * * *  ***  **  ***  if(S==1)
   *  *    *  *  *  * *  * **** ***  * * * **   ** * ***  ** * *
 *****   **  **   *   *  ***** ** *   *  * *** **     ** ***  
 *     **** ***    *  ******* ** * *  * ** *    *  ***     *  ******  **** ******     **    *** ***   **



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *** * ****  ** *     **   ***** m,d,s;
**  *         ****** *    *  * *   *** ****  * **    *  ** *** ****  *
****  *** *******   *** *  *  = (m*2+d)%3;
*  *    *  ***  *  * ****  *     (s == 0)
**  ***  * *     * ***  **   *   ** ** *   *  *    
 * * **  * *  *****  ***   if (s == 1)
      ***** * ** *** ** * *  * ** * *  * *****
* *  * ** *    ***       if (s == 2)
  **  * **  **   ***   * * **  ***   **   **     * * ** * 
**** *    * **********     *  
 *   **   ***   * *    * * ****   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
********     *    *  * * * ****  ** M,D,S;
   **  * ** **  **     ***    * *** %d",&M,&D);
**  *** *    * * ***   *** * ***
 ******   ** ***  * * ** *** **** 
*  **  *****  *  * * * *  * ***  *  ***  ***  ***
*  *** * * * * **  ***  *   *      
 ** *     *      ***    ** *** ** *****   * * *** ***** *    
*********** * ** * ** * * * *
  * * ** *    * *** ****   *** **   **  ******** 
 * * ** ****  * * ** * *      0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 ***    *  **     * ** ***** * m,d,s;
* * * ** **  * * *   * *** ** ** **** **** * * *       *   *
***   *    **** ***** ****   = (m*2+d)%3;
  ****  * *  ***** * ***** *  * * (s == 0)
**      ******** * *  *  *   ** ***  * *   **  
 *  ******    ** **  *   *** if (s == 1)
 ***  **   ***  **   *  *    **  ** *** ***  * * 
 *          *    ***   **   ** * if (s == 2)
*   *** ** * ****   *   *****    *   **   * 
** ***    ****   *** ***  
* * *  ****** *         ** *   * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
   * *  *  *** *** **   ****** ****** *  *  * %d",&m,&d)!=EOF)
    {
* * **  *  ** *** * ***** * ** ****    * * **  **** *   ***** 
* * * * *** * ******    *  **  *****   *   **    *  *  * * ** 
 ** *  *  ***  **  *  ***** *     * *  ** ****  * ** ***** ****  *      * *  *   * *   *    *     ***  *****
***** **** * * ** *     * **** * *** **    * ** * ***  ***    if(s==1)
* * *****   **        ******* *  **** **  * *  **** **   * **     *   *  *  *** *  **  *** *  * * ***  *******
*  * * * ****   **** **  ** ** * *   *   ***** *** **   ** ** if(s==2)
***   ***** *  *  **  **   *** * * *** ** **** *** * ************* *   ***** **   ** * **  ** 
* ***  ** * *  * * ** **  **   * * **  *  * *   **  *   ** * 
 * ** * **          *** * * **  * ***** ** ** *** ** *    **   * ** *  *  *  ** **   * * ** 
    }
 **   * * ** ** *        * **   * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  *    *  **  **  ** *   *

int main()
{
int M,D,S;

 ***  * * ****  ** **  *    **  **
 **** **
  ** 
{
*****   * ***    *  * ******
}
 *    
{
*  **   **  **   *  ** 
}
 **   
{
 **** * *   **    *  *  ***
}
* * ** **** ********   **  *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.33
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.2k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.9k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users