期末考題目-Question 3

1 like 0 dislike
10.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 10.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
    **     **     *  *  *   ***  **** ****   ** 
**** *****         * *      *
* ****  * * * * ****   
       *** ** * ****  ** *** ** *    * * *   **** *
 **** * *  ******  * *     
 ***** *  *****   **     ** ******* *  ** ***
** *** *  **  ** *  ** ***
  *  ** *  **  ****  **  ** *     ****  **** 

  *** **  *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
**  **  ***   *   *** *  *   * * *** * * * ** * **   *     * * *  * 
 * **  * * ** * * *     **** ** ** ** 
 * * ****  ** *  ** * ** ** * ***
***    *  *** **      ****  **   ***     * * **** * ******    ***   ****
    ** * *   ****   **   *    if(s==1)
*  *  * * **  ** ***   *   * * **   * **     ***  ** **  ** ***  *  *    ***   
     * * ** *  **   ** **  **  ** if(s==2)
 ** *         * **** * ***    *  *  *  *     * *  *     * *    *   **
*  * ***  * * ***** **** ** * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*** *** ** *** ** ** ****  M,D,S;
    
* *      * **  ** *         *  ****    %d",&M,&D);
    
      * ******* **** * *   * * 
  *  * *** ** *   *** *** ** *
 * * *    **** **      *  * * 
   *  *  *  ***   * * *  **** **
  * * *   *  * *****    **       ** **   *** * * *   * *  *** *   ** ** * *  * **
  * ***** *    ***  *   *
 *  ** * *  **    **  **    if(S==1)
*****  **    *    * *** **  * 
**   * ***   * *  **   * * ** *        * *  *  ********* * *  ****  * * *  *    * *  * **     * 
***  * *** *  **** **   ** * * *
*  **  ***    * * * **** *    ***  if(S==2)
** ***  * **  ***   * 
  **   ******   * *  *     * * ******    **  **  *  **** *     **   
******* * *   * * *** **  * 
 * **  **********    * ** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
 *   *** ** *  *   *  **  * m,d,s;
 * * *  *** * ******  *  *
  ***  * *     ***  * ** ****  ********  %d",&m,&d);
    
 **** ** *  * **** *****  *  * + d)%3;
 * *** * ** *  **  *   * *  *
* *   *** * ****        **** * *
 * *   * * **  * * ** *   **
 * ******* *** *   *   **    ** **   *  *   ** * * *** *  * 
  * ****  ***  *  * *    * **
  * *    **  * * ****** * * *  ****  if(s==1)
*  * **  *  * ****** *  ** **
   * *   ***   **   *  *   *  * ** *  *   * * *** ***** **   * *  *       ** * **  *
**    ***  *   *   ***  **
 ** *   ** ** ** ******  * ****  if(s==2)
* * ***   *  *   ** * * 
   *    ***  * *** *   **  ** *  ****** ** **** **    ***    *  ** ** ** ** *  **
 * * *  * *  *  ***  ** *  *   
 *    **** *  ***  ***** 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  * ** *  ********* 
int main()
{
int M,D,S;
**** * ** *   *** *** *  *   ** * 
scanf("%d  * * **** * ** ** ***
S=(M*2+D)%3;
if(S==0)
* * ***** ** **** **    *    ***    *  **  
*   **********  **** * *    if(S==1)
 * *  * *  * **  **    ** * ** ***  ***     *    **     ** *
   * * *    ******** ** *  ****** * * *     * 
**   ** ** ***** **  * **     *   *** *  ***   * *   *** ***** ** ** *** **  **   ** *  *** * ****  * ** * 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  ****   ** **   * ***   *   ** m,d,s;
*** * **   * *    * * *  **  * ***   *  *   * * * ** *  ** **  
       * *** *      *** * *** = (m*2+d)%3;
 * **  ** * *  *       * (s == 0)
**   ** ***  * *  * *  * *  ***  *****   ** 
 * * * ***  ** ** *      *   if (s == 1)
  *    **         ** *** ** ***   **    *  ** *** * 
 ****  ** **** **  * ** *** * *  if (s == 2)
  * *** **    * ** * *      * *  * * * *  
 * ********  * *** ** *  **  *
**** *  * * * * *  *   **   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
* *   ** ******      * *  *  *  M,D,S;
** *  *  * *** * ** *     ***  ***  *   *  %d",&M,&D);
 **  *  *** **  **  ** *      *   **
* *   **     *****   **** ****       
** *  *  **  **    *  ****     ** *** *****    * * **  **
    * * **    * * *   * * * ***   
  *** *** * ***      *   **** **  * **  * **  * *  *****
** *       * ** ******* * *   
  *** ** * **   ** *      **    *****  ***  * *   
*********   *  *  *  * *    0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  ***   *  * *  **  ***  * *  m,d,s;
 **  * ** *** **     **** * ***  * *  **  * * ** ***   *   ***
 **** * *  **  ****** **  **  = (m*2+d)%3;
 * * ** ** *  * *      ** *      (s == 0)
  **  **  *  * **  **    *   * **  ** * **   **** *  *  *  **   *
**  **    * ***  ** **   *** if (s == 1)
* **  * ***   ** **   * *** * * *  *****  *  ** 
    *   *  * ***    * **  *   if (s == 2)
  ***  *       *   ** *** *   * ****  *** *****
**     *** **  **** *   ** 
  ** *  *  *  ****  ***   * **  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
  * ** *  *** **     * *** * *  * **** * ** %d",&m,&d)!=EOF)
    {
* *  * **** ****** **   **** ** ****    * *  * *   *      
 ** * *      * * **  **   *  ***** * * ***   *   * * **
*   *  ** ** **  *  **  *** ** **       *  ******* **    *******  * **    *  * * ****  ** * *    * *  * ****   * 
     *  * ** ** **   ****      * *    *    * *** ** *   *  if(s==1)
* * ***  *    *   ***  * * * *      ** * ******** * * * **  ** *  ****  *   ***   ** *    * *  **
 *   *    ** * *  *  ***** *  **   *  * *   *****  ** if(s==2)
  *****     *** * * *   * *     *   *  **    ** *    ** * *   **  **  ***     ** *    *** **  ****
* * *     *** **   * * * *  *   ***    *** *** ** * *** *  **
 *   *   * *      * **** ********  * **   * * *  *   *  **     **    ******  ** ** 
    }
 *      *** ** * * * **  * *    0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ** ** **   * *  * **

int main()
{
int M,D,S;

    ***  *  *   * *  ** * * * **   * *  ***
   *  
    * 
{
**  * ** ** **** * * 
}
 * ** 
{
** *      ** ** * * *
}
 **
{
 ** * *******     *** ****
}
 *** ***  **   * * *  *    

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.199
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.9k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.7k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users