期末考題目-Question 3

1 like 0 dislike
10.3k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 10.3k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*     ****    * * **  * *  *  ****** ***   ** ***  **  
 **   *** **** ***  * *   * **
* *   *  *   *** *   *
*   **     ** *  *     *** ** **  **   * *  
****  * *** * **  *   *
*   **  **     *  * *** * *    *  ** ***** ****    
**  *  *        *  * * *  *** 
       *   ****  **       ***   * *  ***

*  **  * *  ***  * *****   0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
** *  *   * *  *** **         **  ** * ***    *  *   *** * 
 **    ** **   *****  *   *   ** * * *
*     *     **  * **    *  
  ****  *****   ***    * *** *  **** **  **  *  ***  *  ** *  
 * *    **  * * *   * * *  * if(s==1)
    * ****  * ***   *    * *  ******      * *   * ****   * *
*   * * *   *   ** *** **  * * if(s==2)
*  ******* *** *         ** **    *  ****** ********  * *    *   **  ** *
   *   ** * * ** **   0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
***    **** *  **  **** ***  M,D,S;
    
 *  ** **  * *  ********   ** *   **** %d",&M,&D);
    
 *  ** **** * *  * * ** *     *  * * 
  ******   *   * * *   ** *****
** **      * *  **  ** * **  * *** 
***** ** ****   *  *     *** 
 ***        * ** ****  *  *** *  *     ** *  ***  ** ** *    ***  * ** *  **  ***  * *
 ** * ***  *   * *   * * 
 *  ** ** **  ** *** * *   * if(S==1)
     ** * ** * *  *   * *  ***
*  **  **   *  * **  ** *     ***   * *     ** **  *    **  ** *** ** *    ** *    *   *  
 *   * ***      *  **  **
  * ** **         *       ** *  ** if(S==2)
 * ** **** *   * *** ***  ***
   ** * *  *  * ***  ******** *     *** *****  * ***    **    ** *   ***   *** *** 
 ***      ****  **   *  * *
* **** **  **    *    **** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
*** * * ** *   *   * *  *  **    m,d,s;
 ** *  *  * *  * *** ** *** * **
 *  *  ****  ** **** *****    * *  *  * * %d",&m,&d);
    
*    *  **  *** * ** *   *** * + d)%3;
 ***  *   * ****    * **** *** 
* * *      *****  *** *    *** *** 
   *  ** ** * *  * ** * *  * *** * *
 **   *  ** *   * *    *   **  *** **********   * *   ***   ****
     * * * *   *  ** *  *  **
*****     *** **  ****   * if(s==1)
* *  * **     * *       *** *
*    * ** **** ** ***    * * **  * * *** **  * *  *  *  * **  *   ****  ****    **      *   *
*   ***  *  *   ** *
   *      *    ** *  ***  if(s==2)
*  *   **    *  ** **   **  **  * 
    ******   * * * *  ****** ***** ***  ** **  **  * ** *****  **  *   ***** * *
 *****     ****  ***** **  *
* * * ** *** *   *    * ** 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  **  * ** *   *  *
int main()
{
int M,D,S;
 * **  ***  *  * ***   * ***  
scanf("%d * * * **  *** * ** *  *   
S=(M*2+D)%3;
if(S==0)
  * ** ** *** *  * * ********  * **   *     **
* ***  **   * * ** *   *   *  if(S==1)
 * *      ***** ***   *****   * **    * **   *  * *   **   *** *   
   **   *    * ** * *  *** ** **  * ***  * * ***   *****
** * ** *   ** *  **   * **  ****   * *   *  ** *  ** *** * **  ***     * ** * * *** * *** ** *  *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 **   ***  *  *  * ****  *   m,d,s;
    ****  *     **       * *    ***** ** *   *** **  *   ** * * 
 **   *    * * ****** **** **  = (m*2+d)%3;
** *  ** * *  *   * *****  (s == 0)
  *  * *****  * *  *  *  * * * **** * *   ** ** *  **  
   ** * ****   * *****  if (s == 1)
 **  * *****     * *  **       **** *   ******
*            * *  *** ***   if (s == 2)
** *** *  * *       **** *     *   ** ****  *
* *   *  ***** *   **  *   
*  ***    ** **      ** * *   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 *** **** *  *    *   *  *    M,D,S;
   ** * ******  ********* *      *  %d",&M,&D);
 **   * * *    * **  ***** *    ** *
   ** ***   **     * *       ** *    ***
 * *    *  * *      **  * * **   * * **  *** *
    * * ***  *****    ** * **
   **  * * **    *  ** *  ** ** ** * ** * *   **    
   ** * ** *  * *    * *  **  *
 ***** **    * * ******  **   *      ** ****  *  *    
  * *  *  ** * *              ** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 **  ***** *  ** *   **  *  m,d,s;
 ***  * *   * *  *  ** ** *   *   * **  **      **  **     **
*   *   ** ***   ****** = (m*2+d)%3;
***     ****** *    ***   *******  (s == 0)
*  * * * ****** * *****     * *****  ****     * ** 
* * *  *   **  ***** *   ** if (s == 1)
  * **  * *******     *  ******** *  ** *   ** **    ** *   *
* *   *** ***** *** ****   ** * if (s == 2)
*   *** ****  ****   * * ** *   **** ** * *  *  *
 **** ** * **   *   * ***** *
  ** *** *    ** *** **   **   * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
   **** ***  ******* *     * ** * ***** %d",&m,&d)!=EOF)
    {
*  * * ***   ** *  *   *       * *   * **   * *       *  **  * *****  *
** ******  * * *  *** ****   ** ***    ***   *  **  * **
 *  * **  *    *  ** ***  *****   ** ******* * **   * ** ** *** *    **   *  *   *       *   ** * *** **      * 
  *  ***** *   **** * **** *  * ***  *   * *  *** * ** * if(s==1)
 ***** * * *** ***   **      * **  **  **  ***  * *     *** * ** * **  ** **  ****** ****  * * * *  * ** *   * **  
 ** **   * **  *  ** ******  ****  **** *  *  *      if(s==2)
   ***   *  * **         **    * ** *****     ****  ** **  *     * *  *  * *       * *******    ***
    *  *** *  * * **    * *    ***** * ** * **** *** ****** 
    ** *** * *     *  * **   ***   **  * ** **   ***** * *      *** **     ** ***    
    }
 ***    * ****  * *  **   * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * *  * ****   **  *  

int main()
{
int M,D,S;

 *** *** * **  ** **  *   *  ** ** *  
*   * **   
****   
{
********* * ******  *  **
}
 *   
{
*       *** * *  *** *** *  
}
**  **
{
*  * * ****  * ** **   *
}
 ***  ****  *    ** ** *   *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.91
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.9k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.5k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users