期末考題目-Question 3

1 like 0 dislike
4.7k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 4.7k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
     **  ** ** * *     * **  ******  * **  ****** * 
    ** * *   **** **  *
 *      * *   *      * *  ** 
      ********** *  **   **  * *** *** ** **
* ***  * * * * **  **
 **  **   * *  ****** *  *   * *  *    ****
            * ** *** *
****   * **  **** ****   * **  ** * *  ***   

  * **  ** * * **  ** *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 **  * *    **  *   ** *  ** *   * **  *** **** * ***  ** *  * * ****  
 **   * * * **    ** **** ** ***
 *  * **  *  **    * * ** ***  * **
 * **    * * ** * * * ** **  **  ***   * ****   **  *    * **** **   **  * 
 *  ***   ***  ** ** ***** *  **  if(s==1)
*****   **  *  * *** **** * * ***   ** *  *     *** *      *  *   * ***  *** * *
* *   ** *   ** *** ***** *   if(s==2)
 *** * **  * *    * **** *** ****** *** * * * *   *   **  *        *   **
*   *** **  **  *  ***  *  ****  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* **   *     **  * * ***** * M,D,S;
    
 * * * *  *   * **  **    **   *  * *** %d",&M,&D);
    
****** * * ***      *  ** *  **  
  ****** * *       * *   
 ** ***    *  **  * *     * **    ***
 ** * * ** **  *        *** 
*   * * ** **  *      * *  *** * *****       ** * ** **  ** ***   **  ***  *   *
 **  * **** **    *  ****    * 
* ** * **  **  ***      *  * if(S==1)
  * *******   * *      ***
*   ******** * *       ***      * *** ***  *    ** ** *    *  *    *       ** *  *
 * * *  ***** ***** * * *  * *
 **       ***  *  ****  *** if(S==2)
******** *  *  **  *  *****  
     **   **      *     * ***     *   *     *    **   * *  ** ****  * * 
 * * *****  *   **  ** * * **
* *   * * **  **  *  * **  * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
 *** **  *    ***       ** ***   m,d,s;
  **** ***  *   *    ** **
*      *     ***         * ***        *    %d",&m,&d);
    
*  *  *  ***  *  * *** ** ** **   * * + d)%3;
  ** **     **** *  *  **  
  *****  * **    **  *     * * 
*   *** **  * * ** *    *
 * **  *    **  *  *    *   * *          * * * ***  ** **  ** *** 
**  ***  ** ***    ****
 *** ****** **        * * * * if(s==1)
 * ****    * *  ******  **
   * *  * * * ** *    * *  * *   * ** * *****   ****     ***** *  * ***      * *  ***  
    *      *    ** *  *  
*       **    *  *** ******   * * *   if(s==2)
* *** ***  * *** ** **    **
* *** *  ** *  *   * * * *** ****     * * **  * * ** * ** **  *   ***  * **  ****   
* ****   **  **  *** *** **** *
*** ******* *  *   ******  * *   *
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   * ** ** ** * ** **
int main()
{
int M,D,S;
 *    *    ** **   ***   *** **    
scanf("%d      * *** ** *   *  *
S=(M*2+D)%3;
if(S==0)
***** * ****** ********** **   **   * ** * *** 
**** * * ** ******  *    **** if(S==1)
*     * ***  * * *       *    ****   **  * ***  *    ****    
*  ***** * ******  ***  * ** * *   * * ***  * *****    *
*     ** *** * *****  *    **   *  *  * **   *   * ** * **  *** *  *  *    ***  ****** * *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
**** **  * * *** ***  ******  * m,d,s;
  ***  ***  *   *** * *** *  *  ***  ** * *** * *   ** *
 ***  **    *  *   *  * **  ** = (m*2+d)%3;
****      * *   * ****** **  **    (s == 0)
* **  ******  *  * ** *  * ** *    *** * * ** *** **  *
    *****   *   *  *** *    * if (s == 1)
** **    ** **** *   **   ** * *   **     * * ******  **
   ** ** ** ******* * *        if (s == 2)
 *** ***    ***  ** ****  * * *  * *    ** * 
 *** ***** *  *** **   * * ** 
*   *****  * * **  *  * *** ** *   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 ** *    *       **  *     * ** M,D,S;
 ** ***** *   * **** *  * ****** *  %d",&M,&D);
 ******   * ** **  ******  ** ** 
 * **  *  **** * ****  *  *** *****
 ***  *** * ** **  *** ** *       * * * **        **
   ** *  *  ** **** *  ***** **  *   
 *** **** *   ** ****  *   *    * * *    * *   
****   * * ** * *  **** * **  *
   ******  **  * ****  ** *      ** ***   ***
 * * * **** *  *** ***** *  *   0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *    *  * ********* **  * ** * **  m,d,s;
 *  ***** *       * ***    **    *  *    *   *   * *  **  *  * * *   ***   
   **  *  ******  * * **  * *    = (m*2+d)%3;
* ** *** * *****  * **  ** * (s == 0)
 *  *** **  * *     * ****  * **   * ** *** * *** 
* *  * * *    ***** ** * ***  if (s == 1)
* *   *     *** *   *    *  *     **** * * ** ****  **
 *** * * * *   * *   ***    *  **  if (s == 2)
  ** **     *  *** *  ** *** **  ** *  *  ** 
**** * *   **  **  *    *
*  *     *  **   *** **  *     * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
*      ** *  ** **   * ** **     * ** %d",&m,&d)!=EOF)
    {
  ********* *   **** *     *     **   *** ***** **   ******  
*  *  *****  ** * *   ***  ** *** * *     ** *    **  **        * 
*** * **** * ** ***  *   **  ** *   **  * *  * *  *** * **   **    *** **** *****  *  *************** *
***   ****  ** ****** **  *  *   *** ** ** ****** **  * * *  if(s==1)
* **** **  ***     *** **** ****   *  ** **  *** **** **  * * *  ** * ****  ** *     *  * *  **  *  *  ***  **
 *  ****** *   **   *  * ** *** * ** * **  *  * if(s==2)
*   * * *** *  * *  ** ** ** * * **    ***  **    *   * ***         *      * ***  ***    *  * **  *   * *  
   *   **** *     * * **      * **     *** *    *  *   *
* * ***   *   *** * * * **** **    * ** ** * * *  * ****** * *   * * * *      *  ** 
    }
 *   * * ** * ** * *  ***** ****  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 **  **   * *****  ** 

int main()
{
int M,D,S;

 * *   * * **   *****  * **** *** * **
** **  * **
  ***
{
 * **** * ****  **  * * 
}
*     
{
     *  ****** * **** * *  
}
 **  *
{
*** * ***     *   *  *  ***
}
*  * *   ******   * ** ** ** *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.111
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 1.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users