期末考題目-Question 3

1 like 0 dislike
15.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 15.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
* *** ** ***     *****  *  *** *  ***    * *  **  ** * *
  * **** * *** * **   *  *
*** *  ** * *******   
  *  *  ****     *   * * **  ** * **    *   *
**** ** *  ** * * *** **    
  ***** *   * *     * * *  *  ** *   **** * **
   *****  *   *** *** * 
*   * ** **      ****  *  * ** * *      **  

*** ***   * *   * * ** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
* *** *    ** *   **** *  * * **  **   ********   **  *  * **  ** * 
 **  * *  *  *** *  ** *  **   
** *** *  ******* * * ***  *   
 * *** ***  * *   *** ** ***  ***    **** *** ** *** * ***** ***  ******    **
*  **  ******   *   * *  * * if(s==1)
*****   *** * *   **    * ***** ****  ** ** *** *    ** * * **** *  * *   
*** *** ***  **   * *  **  * * * if(s==2)
  * *  ** *   **   ** *** *** * **  * *   * * * ***** **  **  * 
*   * ***  *   *  ***  *     *** * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
     *   ** * ****  **  ** M,D,S;
    
* *   *  ** **  * *  * * *   * ** *  %d",&M,&D);
    
**  *   *      * *  * **  **  **
***   ****   ** *   ** ***     *
***  **** *  **  * *  *****  
         *  ** ***  *** **
**** * **     **    * * *    *** * *** ******  *    **  ***  ** **    ** *   *  **  *    
 ****    *   * * *  *** * * *
   ***  **      * ******   **** if(S==1)
  *  *  * **    *  *  ***  *    *****
     * * * ** **    *****    *    ** ** * * ** * * *    ** *    ******  * *   * **
*** ***  **** *   ***  *    
 *       **** ***  **   * *  *   ** if(S==2)
* * * **  ****  *** ***
 *    **   *** * *****  * ****  ** **  *     *****    *  **  *  **    ***     **
 *  ** *      ***** *   **
 *  ****   *     * *   * ****  * 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
   ***** ***   **  **  ** * m,d,s;
 *** * ** *  ** * *  
 * * *    * * * *   *  *** **  ***** * *   %d",&m,&d);
    
**  ** *  ** **   **   ***** ** **   + d)%3;
 ** **  *****    *** *  **
* * **    **** ******  *  ****     
*  ** **   **   ***  * * * ****
* ** ***  ** **    *** **      *  ****   *  * *  *   ** *    *   *** ** 
 *   **** **   ** *  ** * 
     **     * **  ****    ** *  if(s==1)
  * ***** *   *  *****  *
**  ***** * **** * **  ** *  * * **** *    * * **    *   ** *  * *    ** ****  * *  
 * * ** *  *  *    * * *     *
 **   * ** * *     ** *  *      if(s==2)
* **   **  *** *** **   ***** 
 **   ***  *  **    *  * *  ** *  ** ** *  **  **  * ** * * *    * ** ***** **   *
  * * * * *  *   **  **   *** 
* *     *   **    * *  *  
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  ** *      * * *** *
int main()
{
int M,D,S;
** ** *     *******  *   *    ** 
scanf("%d  * ***  *   ** ****** *  
S=(M*2+D)%3;
if(S==0)
*******     **   ** ** **********  *   ***
*** * *  **  **** *  *   ***  * * if(S==1)
***** *   * **      * * *** *   * * * *   *  *  * ** * *** *  *   *****
****   * ****   *   ***      *** ******** ** * ***** * *
 *  *    ** * **   * **   * *  * **  * **    ******** * * * ***** * **   **  ************ * * *** *  *   * 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** *  *  *** *   ** ***  * * * m,d,s;
* ** **   **  * * * ***********  *****    * * *** ***  * ***
 *  ** *  *** ***   ****  = (m*2+d)%3;
***  **** *  ***   **  * *  *  (s == 0)
  * ***   * * *    *** *  * *     ** **     *     * * 
 ** * * *** *  * * *    *** * if (s == 1)
*    * *****  *     *** **  * * *     *  * *   ** * * ** ** 
** * * *   **  *     if (s == 2)
   ***   *       *   **** ** *** *  *  ****   *
**   *  ** *  *   * * *   *
  ** ** *  *  ****   * * ***   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   ***   *  *** **   ****** M,D,S;
*    * **  **  ** * *  ** * *  * *  *** %d",&M,&D);
 * *** ** *    * **     * ***  
*******  *** *  *        ***    
** ** * *  * * *  ** ******* *** * * *** *  *    * 
*  **  **  ****** * ** ***  ** * * 
  **** * ****  * *** ** **  *  ***  *****  ********  
* *** *** **     ***  ** **** 
** *** *     *** ***       ** **  * **   **** *** 
*** *    * *  **  ** * **   *** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  *   **** ***  ****  *      ** m,d,s;
  * * *   *   *  * ** *  *     **  *      ****    *  
* ***** ***  * **** * = (m*2+d)%3;
 * * ****  *    * *  * * **** (s == 0)
 ***    *    *  ****   *** *   ** **** * *  
** *    *    **    **  *** *  *   if (s == 1)
** *     **** *       * ** *  *****     ** * *    * 
**  * ** ** ** *  * ******* *  if (s == 2)
 ***   **** **  ****      * *  *** * **  **  *
  ** *  **** * ******   **** 
*  **** ******* * * *      *   *** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
  ******    * * * **    **  *  **** *  ** %d",&m,&d)!=EOF)
    {
 * * **       * ******* * **   **  **** ** * ***   * *    ** ****
 *  ** *** * * *****  *  **    * * * *  ******* *  ** * 
  **    ******** ***   ****  *     ***** *** ***    * * *  *         ***     **   *  **    **  **    ** *  *
****  * *  ***  * ***  * *  **     ** ** * ** * *  * * ***  * if(s==1)
 *  *    **** *** ***     *   ** ** *    * **  *  **  **  *** *    ***  *     **     * * ** *  ***  * ****    
** ** *  * *** * **** ***  **** **   ** *   * ********   if(s==2)
***    *** * *   * *  *    **  * * * **   *  * ** ** ****   *  * * *    *  * * * ** *****      * * **
 *  *  * * **  * * ***   ***** ****** *   ** **   *
* **   *** *    * * * * * * * ** *      **** *  *** * ***   **** **    *     *  *   
    }
**** * * * *  *  **  *  * * **    0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * *** **** ***  ***  ***

int main()
{
int M,D,S;

** ** * ** * **** *     *  * ***   * * **
    **  
  ** 
{
**    * **** *    * ** ** 
}
   * * *
{
 *  **       *  *  * *****  
}
 * * **
{
   *   *  ****      **** ***
}
 **  * ********* *****    *  

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.151
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.8k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 5.4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users