期末考題目-Question 3

1 like 0 dislike
15.3k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 15.3k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*  **** *****       ****   *   ***** **  ***     **  * *** *  
 **  ***** *******    *  *  
****** * *  *  *    ** **  *
*** ** * ** *  * **     ***   * *** ***  *
***   *   *** ** * * ** ** 
** ** * *  * *   * * *****   * ** * *  *   * ***** 
   ** ** ** ***   *  * *
 **  * **  * *** * * * * *** ** *** *  *

    *  ***    ** **  ** * 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
* *** * ** *   * ** ******   *       ** **  *  * * *    * **  
  *   * **  ****  *   *** ** **
 **** *   * *     **   * *   * 
 **********        *     *** *  *  **     *  * *   * *** *     *  **  
 * ** **   * ***  ******  if(s==1)
***  * *  ****  *  ****   * *   ***  ** ** *  * *  *   * *   **  * *** * *
*  **      *       **   **  *  if(s==2)
**** *  ***  **   ****** ** * * * *   **  ** ** *     ***  ** * 
* ** *  *** ***   *  * * * * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 *     **  * * *** ****** * * * * M,D,S;
    
** **   ** * *  ** *** ***** * ***       %d",&M,&D);
    
** *** * ** *  **** ** **   * **** *
  * *  ** ***** * ** ***  *  
  **     ********      *  *   **  **
** ** * *** ******  *  *  **  ** 
* *  *   *  * * * * * * ****   ** *  * **    * *    * * * * ***** ** ****  ******
** **   ***********  **   * * ***
    ****** * * *****     *    *  if(S==1)
*  **** * * **  *  * *  
* *  ****** ** * ** *   ******  **    * ** ***  *** *    *** *    * **    * **
*  ** * *    *  *** *  * **  *
***** *   * ** * **  **  *   if(S==2)
   ****  *** ***** * *     ** 
***  * **  ***  **** **   *  ***    *   ****    * ***              * * **   *   **** 
* *   *  ** * **    *    *****  
** *** *   *    *** *** **    **    0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
****** *  * ** * *    *  m,d,s;
* **   **  ******  *       
*  *** * * ** *** ** **  * ******  **  %d",&m,&d);
    
 * ** * *    *** *  * **** ****** * + d)%3;
     *   *  *** *  * ** ** **
*    **  * *  ***  *   *   * ***  
   **   ** * * ** **   *  * 
 *  *  ** ***   **  *  ***  ** * ******       ******  *   * *
*  ***   ***  *** ***** ***  **
*  ** *** ***  *    *  * **    * if(s==1)
 *  *     *  ** **   *  *
* * ** ***** * *   ***  * ****  * ** * **    *   ******  *    *    ****  * ********* *
* * ** * * ** *    * *   ***  
 * * *   *  ** ** * **** * * *  * if(s==2)
 ***  *   *  ** * * *  
   ** **   * *    ******* * *   ** *** * ** * *****     *  *  **     *  *  *
** ***    ****  * * * **  * 
**    ***** **  * **** 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  **           *  
int main()
{
int M,D,S;
 * * **** *** *** ** *    *  * ** **  
scanf("%d  *  **** *   **   *    ***
S=(M*2+D)%3;
if(S==0)
    * *****  * *  **  * ****    ** * *****  
** **** * * * * * *** **  ** * if(S==1)
     *****   *** * * * *  ** * * *  ****  **** ** * *  *** *
*    **  ** *  **   * ** *  ***** * **  ** * **  ***  **
*** * ***** **   ***   ** *       **** ****** ****  *** * *      **     **  **  *   **  ** *  * ****



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
**  * ** ***      ** ****    ** *  m,d,s;
**    *  *** **  *  * **   *** ***  **   * ** *    *  * *  *   *** * 
 ***  * *  * *  * *  *   = (m*2+d)%3;
 **  **       **      *** (s == 0)
*** ***  * *   **********       * *  *  ***   ** 
*  *    ***   *** **  *   **      if (s == 1)
 * ********  *  ***** **     *** *  *  *  * ***** *
** **** **  * *  *   *  * ** * * if (s == 2)
  *  * * *  **  *    * *  **  **   ***   * *    * 
*  * ** * * *    **  ** *  * ***
 **** **   *  ****  * * ** *   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  ** * *  *   **  *  ***  *   M,D,S;
  ***   ***  * ** * ****  ****** ******   * %d",&M,&D);
 * ****  ** *** **    * * *   * **  **
* *  ** ****  *****   * **
*   * ****   *  **  * *** **  ***  *  *  **   
   *** ****  *   *  *     *  ** *
***  **** **  **   * ** * *** *    ** *  * *  * *      
*** ** * *  *      ** * ***  ** *   
 *** *  * * ** *  *  **  * * *   ****  **        
****    *** *** **  *** *   *** * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
***** ********  * *     * * m,d,s;
 ** *   *** *** *     *  * * *****    *    *   ****** * *  * 
** *** **  **  * * * **  *** * * = (m*2+d)%3;
 * *  *  **  *   * ****    (s == 0)
   ** ** * *  *  * *   ***  *** *****   **  **  
 ***     * *** *    * *  * if (s == 1)
*  * **   * **    * *  **   *   * ******* **** *   *  * *
* **      **   *  * ***  *   if (s == 2)
  *    **** * * ********  *   **  * * * ****  
  ****    * ** **   ** *    *
* * ***    * *   **    ****   * * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
*  * ***  ** * * *  ** * * *** * *** *   * * %d",&m,&d)!=EOF)
    {
 * * *** **** *     * *  *  ** **    *****  *  * * **   *
* * * **** *  ** ** *   ** **  **  * *   *** **  *** ** **  * *  *   
* *      ** *   ****** * ***  ***   **     ** **     ***    *** * *   **  * * ** *       ** **   **  *** ***  
        ****** *****  * ****    ***   *  *  *    *  **  if(s==1)
****     * ** *   * ***  ** *    ** *   *      **** *    * * * **  *    *  ***** **  ***** ** **** *  **
***  * ***** **** *****  **  * **    ** *  * **  * * * *   **  * if(s==2)
**  *   *  *  **  ** ***  ** * ***** *  *****  *  **    *  * *  *   *   ** * ****  *  * *  * *** ***     *
* *** ** **  *** ******** **   *   * ***** *    * * *  * 
**  ** **   ** ***  * **  *****  ******* *   * * *** *  ***** *     **  ** * * * *****
    }
 *  *  * **     *  ********    0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
    *  **********    

int main()
{
int M,D,S;

 **  *  ***   ***      *** *      *  * *
 * ** ***
* *** 
{
 *    *     *  ** ******  *
}
 * ** 
{
*    ****** *   *   ****   *
}
*  **  
{
   *** ** ** *****  *
}
*  * *  * **        * ***   **

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.90.26
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.8k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 5.5k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users