期末考題目-Question 3

1 like 0 dislike
12.4k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 12.4k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*   *** ***       *  **     *** * * ** **** *    ***  
  *  ****  *  *  **         ***
 *    ***  ***  **  * *     * *
 * **** ****  *     **  *  ***  ** *  ** *  *
*  * ** ****  ****  **  
 *  * * ***  * * * * **** *******  *  * ******   
**** *  ******  * *****
 ***  *** *     ** *   * * *  *     *  ** * *** **

**     ** *   *** *    0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 *  *   **** ** * *** *  *    *  *   *    **    **  **   ** * *  
**   * **    * *** ** * **  * **  ****  
  ***   ** * * *  *   * *  * * **
   *****  * * * **    ***         ***    ***** **  * *** *** * * *    ***
  * * *   ****** **   *  **    if(s==1)
 *  ** **    **  *  *    **  ***     *   ***  ** ** *   *  ***   ** *
***** ** *   **  *** ** * * if(s==2)
* *    * **** * ** *  ** *  **  ***  ******  **      ***** ****    **  **   * 
   **** * **   ** *  *  *  *    0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*   *  **** **** *    **   **   M,D,S;
    
***   ** * *****  ***** * *  **** **** %d",&M,&D);
    
 * * ** ** ** **** * ** *  ** **** * 
****  ****  *** **  *  ** 
*   *      * ****** ** ** ***
 *  **  **   * ** ** *    *
  *  * *  * * * * ****** * ***  **** **** **** **** * * *  **  **    ** * * * 
 * *   ** *   * * *** ****    
****  ***    **  * **  * * *  *   * if(S==1)
      * * * ***  **** *** *   * 
      **   ** **** *** ***  * **     **   *  **** ***    ** ***    **     ** **  
* * ** * ** **** ***     
 *** **  **** *   *  * **** if(S==2)
* * * * **  *****  *  **
  *   *     **** *   **   ***  **  *    * * **  *  *  * ***  * **  *   **   **** *   * 
  **     * * **** * 
  *****  **   * * **   ** **  *** *** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
 *     * *       **   ****  ** m,d,s;
  * *** *  *** *  **     **
** **** *     **** **** ***   ***  *   * %d",&m,&d);
    
***    *   * *  *    ** ** *      + d)%3;
* ****   ***  **  * *  
* *     **  * ***** * **  *  * *** 
   * *** *  * *  ** ** ***  *
* * **     ** ** **     * *  ****** * * *   * * ** *** 
**  ** **** **  *       **  
*        *  *   *** *  ** * **   if(s==1)
 ***       * *  ******  **  * *
  **** *  *   * * ***  ** *    ** **  ***   ***  * **   *    *****  *  *  ** * 
   *  * * * ***  **      * ** *
 *  ** **  *   * *    ***  * * if(s==2)
*** *  ****  **      ** * * 
* *  * ** **** ** *   * ** * **  *    ** *  ***    ** ***** *** ** *** ** *** ** **    ******  *
* *  **   ******   **  * *   
 * *** **    *  ** **** **** 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*    * **  * ***  **
int main()
{
int M,D,S;
*   **** * * *    ***  * *  * **  ****   *
scanf("%d   **  *   **** **   * * 
S=(M*2+D)%3;
if(S==0)
 * * ** **** ** ****  *     ***  ** * *    *** *
** *  * ** *    ******  *  *   if(S==1)
** ****  **** *** * *** * *** * **** ***** ***  ** *** * ***   * *   *
* *        ***  *  **** ** **  ****** *  * ** * ** *  *
*** * * ** ****   * *** * * *   *   ** *  * * * * *****     * ***  * **   * * ****** **   *** ***   ***  



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  *   *   * ** *  * ***   ** *  m,d,s;
****  *  ** **** **   *  * * ** ** * **   *** * * * *     *****  * 
** ** **** * * *** *  ***    = (m*2+d)%3;
   * *  ** *   **** *** * *  (s == 0)
**********     **   * *  **  ** **** *** **  ***  *******
** *  *  ** *   * *    *  ** if (s == 1)
** ***  * *** *  *  * **** *   *  *  *****   *** *  * 
* *** *** ***  * ** ** * * ** if (s == 2)
**  ***  *  **** *    ***   ** *** **  *** ** 
  * ** **  *  * ****   * *   * 
***    ** *  *** **  **  *  *  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
** ***  *    **  **   ** * M,D,S;
**** * ** * ** ***   ***  *     *    * %d",&M,&D);
  *    ***  *****  *  * *  * **  
*  **  ***  **    **     *   
*** **** *   *  ******* ** ** ****  ***  *  **  * *   
* *  ** *  ***    * *     *** *** 
*   *** *    *        *  **  *  *     ** *   *  * 
  ***   *    *  ** *   ****  *
   **    ***     *    * ***  ***         ** *    *
*   *   * * * **   *  ******  * 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  ****** * **     *  *  *    m,d,s;
  * *  *     ** **  **       *   **** *   ***  ****    *    **
**** ***   *  **** **** * *    = (m*2+d)%3;
 * * *    * ** * *****   * *****   (s == 0)
 **  * ** * *   * *    ****  *   * *** ******  * * 
 * **  * **   *** * **    **  if (s == 1)
** ** ***********   * **  *    **** ***  * *      *
 ****** *   * * ***** ** * * ** if (s == 2)
  *   *******  *      *  * ** *  *** *    * 
 ******* *  ***** *    ******* 
** *** * * ****** *  * * **     ** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
* * ** *  *   *** *   **  ****  * * *   %d",&m,&d)!=EOF)
    {
** ***   * ** ***  * ** * * * * ***** **  *  ** *  ** **** *   **
    * *  *  * * *****  * * ** *** * *   ***  *** *  * * *
   **    *     * * **  *  **  *  ** *  * *  * * ****** *******  * *  ****        **  * * ****  *   **** * ** * *
 *****    *** **** **  * *   *   *  ****  ****  **    if(s==1)
 ** ** **** * * * * *  ***   * ** *   ***  ****** *  *   * ****  * ***  ***   ***   **  ***  *   *****  
  **  ***        ** * * ****   ** ** *  *   * ***    *  if(s==2)
** **    *****  *   ** * * * ** *** * *    * *** *   * * ** * *****  * ** **    ***  * *  *****
* *   * * ***** * *   * * *      **  ***  ****  ** ******   
 *** * ** ****     *   *   * **  * ** ** ******  ***  * *   *   * *   **** *  * **    *
    }
    *  * * * * **   * * *** * ** *** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ** *   ****   ** 

int main()
{
int M,D,S;

*  * ******** ***  ***     ***   *** 
* ** *
* **
{
 * * ******  ** **     
}
*  ****
{
***  *  ******  * * * 
}
* *  
{
 *  ** ** * **   * * ** **
}
   ****   **  **   **** ***  *** 

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.38
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.5k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.1k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.2k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.3k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users