期末考題目-Question 3

1 like 0 dislike
10k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 10k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 ********* ***  *  *     *  **** * **  **** * *** ****** 
***   * **** **** * ****** *
 ** ****  *    * * * ***   *
 * *****    *  * ** *** * ** **   ***  *
*  ***** *  * *    **  
** ***  * ****  ****** *** * **  *****   *    ***  ****
  *      **** ** *  
       * * * ***** ***      *** * **** * * *  **  

** ** *    * *** ** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
  ***  **** **  ****  ** *   * **  **  * ***      *** *  ****   *  
 *******     **   ***   ** ***   
* *  **  *   *   ** * *****   
     * *** *  ** **  * * * ** * * **  ***    **** *  *    *** * * 
 * *     *  * *****  ****  * if(s==1)
*  ** ** *** *** ** ********   *   *    ***  * *  *  * ** ** * 
  *** * *  * * *    ****** *   if(s==2)
**  ***      ** **  ** **** *  **  * *  **** * **** *   *** * * *  * *** 
**  *  ** ***  *  ***** *     *   ** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 **  ****** *** *   *** * * M,D,S;
    
  *  *  *** *      *** * *  **** ** *     * %d",&M,&D);
    
 ****    **** *  ****  * * ***** **    
* * **  *  * * * *     * 
* **   ***   **   *  * **  * **   **
*  *   *   ** *  ******    
**     ** * * *** * ***  ***   **   *  * ***  **  * *******   *   **  * * ******* 
 * *  **    *  *** *** ****  **   
 *  * ** *     *    * *  * if(S==1)
* ***     * * *  * *****  * * 
*   *   *   ** * *   **  ** ***** * * ** ****  * **  *  *  *      *  * * *    *
  ** *  ** ** *   **  * ******
  * **   *** *** ***  *    * if(S==2)
*  * *   ** *    * ****  *  
*  * ***** ***** * * *  * *  *   * ** ** ***** **  **  *   * * *** * ****  *** 
  ***  *  * *   * *** * * * * *
  *****  *  ******  **  **  *  * *** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
**  *    ***** **  *   **  * m,d,s;
  ** **   * ****  * *    **
   * *   ** * ** ** * *****    *     ** *  %d",&m,&d);
    
* **      *  ****  ***   *** **  *  + d)%3;
 *  ****** * * *   *** * 
*  * **   ***** **  *  ** *  *     
 **** ***** *  ** *  ***
     ** *  ** * *  **** *  **   *      * *** ** * ****   **  *
 * *   **  * *** ****   * *** **
*** ** * *   *  *   * ** *** if(s==1)
* ** *  ***  *** *  *  ***    
* *     ****   *   *  *               * **  *** *   *** *  ** * *  ** *    *  * *** *   * *
   *  *   *   ***     * * 
*      **** * **   * *  *  **  *** ** if(s==2)
*  *  * *** **** ** ***  **  
 *** * *    * ** ** *  *  * **  **   *  *  * ** * ** *    * **  * * * *** ****** 
 *   * *    *   ***    * *  * *
  * ** *****   *** **** *   
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* *** * *   *  ***  **
int main()
{
int M,D,S;
 **     *  * ** *    ********
scanf("%d  *  **   *   ***    *
S=(M*2+D)%3;
if(S==0)
****  *  * ***   ***     ** * *    ****  *
*  *     ** ***  *****         *  if(S==1)
* *  **  *** * *  *  *** ******    * *  *********  * ** * *      * *
 *  *      ** * *   * ***** ** **** ****  ** *   *** ***  *  
 **   **    ******   *** ** * ****     *  **    ***  **     * *  ****     * * **   * * ** * * *****  *  *  *  *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
**  *     ** * * *  * ** *   m,d,s;
* **** *** * ** * * **** * ** **   ***  *   *  ***   **  
*   ***  ****  ** ****     * = (m*2+d)%3;
**** *  **** ** ***  *    (s == 0)
**  ** **  ***   **  * *****  *** *   * **   *** *  
***  * *   *** *     ***** if (s == 1)
     * *  ** **  *  *** ** ******* * **  ** *** ****** **  
*  ****  **     *    ******    *  if (s == 2)
* ***      * ******* *** *    ** * ***   *  * * *
 * * *   **  **  *****   
* * ** ** *   **  *** *     * ** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
** *  ****** * * * * *  *** * *  M,D,S;
    **  ***     **  *  * *     * *  ** %d",&M,&D);
  ** *  * ***  **  **** *   * ** * *
 *   *** **   **  * *  **** *** 
   ***  **  ****   * *****     ** * * * ******
* *** **   * ***  * * ***** *
 ** * * * ****   * **  **  * * ** ***    **   *   ** 
    * ***   * * *   *   * *       
   **    ****  *** ***  ** * **   **   * *  **
    *  ** *    ** ***  * **  **  *   0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
****  **  * *****  *  **     m,d,s;
   *** **** * * * * ** ** * *** *  * ** **  ** *** **  ****** * * * 
 * * ** * *** ** **** *  * *** = (m*2+d)%3;
* *  ***  *  *** *** *      *  * (s == 0)
*   * ** * *     *  **  * ** ** *  * * ***  * *  
 ** **    * *      *   * * * if (s == 1)
 *   *   ** **  * **  ** ** *** * ******  **     **** *   
****** ***** **  ** *   **** if (s == 2)
  ***     * * *      ******  ****** **  ***   * *  ****
*********   *  * * *  **** *
 *******  ***  *   * ******** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
******** ***     ***   *  * ** **   ** *   %d",&m,&d)!=EOF)
    {
* * * *** **   * * ** **   ***  *** ** **   *     ** ** * 
 * * * * ** **    **  * **  ******     ********  * ** *   * 
* ******    *  *** ***  ** ** * **** *   ** ****     ** * *  *** *    * * ** ** **  **  * *    * *   *  
 *  * * **** *   **  *    **  *****   * **** * ** ***     if(s==1)
* *** ******* * *** *  **** **** * *  *** **  ** * *  *  ** **   ** *** ***  **  *  ** ** *  * **     *  ** * *
 * ** ** **   *  *** ****    * * *** *** *   * * *** * *** **   * *  if(s==2)
***  ** * *  ***      ***  ****  * ***  *        *     **  *** * **** *  **** **   *    *  ** ***  *   * *    
* * **     *  ** ******** ** ** *   *  ***  ** *** **  **  
** * **      **  * *  * * ** * **     *  *   *** *  * *** ** * ***   ** *****
    }
**  *    *   *      ** 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 **  *    * ** * ****

int main()
{
int M,D,S;

*   ***** *** **   ***  **   * *  * ***
  *   **   
  ** *
{
 *    ***** *  *   **      *
}
 * * *
{
****   * * * **         
}
 * * **
{
 **** **  **   *** * * 
}
* *  * *     *      

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.233
©2016-2025

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.8k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.4k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 3.4k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.7k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users