0 like 0 dislike
4.9k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

Example input: 

12 28

Example output:

4

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited

edited by | 4.9k views

69 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{

* *** * * ** ******* * n,n2;
** * * ******** **** ** * i;
* * ** * **** * * * * **** min,gcd;

* * * ** ** ** * *** * * * ** * * * * * &n,&n2);

** * ** * ** * * *** * * * **
    {
***** ** ** *** ********* * * * * ** * ** * * *

* ***** *** * * * * * *** * ** * ** * * ** * **** ** ***
* * * ** ** ** * *** {
**** *** * * * ** * ** ** ** * * * * ** ** *******
* *** * * * *** ****** * ** ** *** *** ** ** * **** *** * *

* * ** ** ** * * **** ** i=1;i<=min;i++)
    {
* ** ** ** ****** ** ** * ***** *** ** ** ** * * * *** *
* * **** * **** ** ** * ** *
* * ** **** *** ***** * * ** **** * ** * * * * ** *
* ** **** * * ** ***** ****
** ** * * ** ** * * ***

* **** ** * * * ** * ** ****** * *** gcd);
return 0;
   }
answered by (-167 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ** *
int main()
{
* * * * ** ** n,j,i,gcd;
** * * ** ** * ** ** ****** ** ** *
* * ** ** * * * ** ** * * * * * ******* ** * **
  {
* * *** ** * ** **** *** ** ** * ** * ** *** ***** *
*** *** * * *** * * *** *** * ***
  }
**** *** * *** ** ** ** *
* * *** * **** * * ** ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
 int a,b;
 int m;
***** * **** * * **** * * ** * ** *
* ** * ** *** * * ********* * * ** ** ** * ** * **** **
* * * * ** * * * *** ******
    {
* *** * * ** * *** * ** *** *** *
** ******** **** **** **** **
* * * * ** ** ** * **** * ** *** * * ** **

******* *** *** * *
* * * ***** * % b == 0)
* * *** ** *** ** ** * * *** * * * ** ** * ** * ** * * ** **

* * ** ***** * * ** ** * * * * * * * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * **
#include * *** * **

int main()
{
***** ** * ** **** n1, n2, i, gcd;

** **** ******** * * * * * * *** * * &n1, &n2);

* * * * * * *** *** i <= n1 *** * i <= n2; ++i)
* ** * **** ******* * * **
* ** * * ** *** * *** * ** ****** * * ** * * **** * ** ****** * * * n2%i==0)
** * * *** ** * * * ** * * ** * * *** * ** * * ** * ** * * * = i;
* ** *** ** * ** *** **

* ** ** * * * ** ** * ** ** *** * * * gcd);
** ******* ** * *** ** ** 0;
}
answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *
#include *** ***** * * *

int main()
{
*** ** * *** * * * * * * n1, n2, i, gcd;

** *** ** * *** ** ***** * ** ** &n1, &n2);

* * * * * * * i <= n1 *** **** ** i <= n2; ++i)
* ** * *** ****** *
** ** * * ** ******* ** ***** ** ******* ********* ** *** ** * n2%i==0)
* *** * * ** ** * * **** * * ** * ** * * * * *** ***** * ** *** * * = i;
* * * * * * * *

* * * * * ****** ******* * **** * * * * gcd);
*** *** * * * *** * * 0;
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* *** ** ** **** ** *
* * * ** * *** * ***
int *
{
int * *
*** * ** * ** ** *** **
* *** **
{

a=b;
b=r;
}

* * ** * *
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** *** *** * **** ******** a,b,smaller,i;

* ** * ** * ** * **** * *** * * * *** * * ** * * * **

**** *** * *** * * *** * *** * *
* ***** *** * * ** * **** ** * * *** * ** * ** * * ******
* ** * * * ***** * * *
*** *** ******** *** ** ** * ** * ***

* ** **** ** * * **** * ***** * * * ***
* **** * ** * **** *** *** *** * ****** * * * * && b%i==0)
***** * * * ** * * * * *** * * * ** ** * ****

* ** ** * ****** ** * * * * *** ** *** *

** ** ** ** * * ** ** * * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ***** ** ***** * a,b,n;
* * **** * *** *** ** * * ** ** ** ** ******
* * * * * * * ** * * * (n=a-1;n>1;n--)
*** * * * ** **
*** ** * ** *** * ** ** * * * ** ** ** **** * && b%n==0)
******** * * **** * ** * * ******** * ****
* * * ** ** * *
*********** * ** *** * * *** ****** **
*** *** * * * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* ** ** * **** ** *** x,y,n,a,b;
** * **** ** * * ** ** ** * %2d",&x,&y);

    for (n=x-1;n<x;n--)
    {
* * ** * * ** *** ** ** * * ** * ** ** ***
******* ** * *** ** ** **** * ** ** * * ******* ** (a==0)
** * * ** * * * * * * * ** * ** * **** * *
* ** *** * ** ** ** *** * ** *** ***** *** * * * *** *********
** **** ** ***** * ** * * * * ***** * ** * * * ** *** * ** (b==0)
***** * * *** *** * * * ***** * ** ** *** ** * **** ***** * ** * ***** * **
* * *** ** * *** * *** **** * ** ** ** ** **** *** * ** *** * ** **** * * * * *
** ** * * * * * ** ******** * * ** * *** * *** ***** *
* * * * *** ***** ***** ** **** * ***** ****** ***
    }
* ** **** *** *** * ***** * * ******* ** **
* * ** ***** * ** * ** 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
int main()
{

*** ** *** * * n,n2;
* ** ***** * *** ** * * * * * * i;
* ** **** ** *** ** min,gcd;

** ******* **** * *** * **** * &n,&n2);

* * * * ****** * * * * * ** **** *
    {
*** *** **** * * *** * * ** * * **** ** *

* * ** ** *** * ** ** *** * * * * *** * *** * * * ***
* ** * * ** * ** ** * {
* ***** * ** ***** * * ** * * *** *
* **** * *** ** *** ***** ** * * ** ** * ***** * * ***

** *** ***** * ***** ** * ** i=1;i<=min;i++)
    {
*** * * *** * * * * ** * * * * **** * * * ** * * * ** * ******
***** *** * * * * * * **
** ** * * ** * ** * **** * *** * **** *** ***** *
* * ** * * * ** ** * ** * ****
    }

** * ** *** *** ** ** * *** ** * ** gcd);

* **** * ** *** ** * * ** * 0;
   }
answered by (-167 points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%d%d", &n,&n2);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:27:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%d", gcd);
     ^~~~~~
prog.c:27:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:27:5: note: include '<stdio.h>' or provide a declaration of 'printf'
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.4
©2016-2024

Related questions

1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 6.4k views
0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 1.1k views
1 like 1 dislike
36 answers
[Exam] asked Nov 15, 2017 in Midterm by thopd (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 2.6k views
12,783 questions
183,443 answers
172,219 comments
4,824 users