0 like 0 dislike
18.5k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

Example input: 

12 28

Example output:

4

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited

edited by | 18.5k views

69 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{

* ** ** *** * * ***** n,n2;
*** * ***** **** ** * * i;
* **** * * *** * ******* * ** min,gcd;

* * * * **** * ** *** * **** ** * &n,&n2);

* * * ** * ** * * * ** ** *
    {
***** * * * ** ********** *** ******* * * *

** **** *** ** ** * ** * ** ** * ******** * ** **** * **** * * * ******
* * * * * *** * * * {
**** *** * * * * *** * ** *** * ***** ** * **
** * * * * * ** ** * * ******** * * * * * * ** *

** **** * ** **** ** i=1;i<=min;i++)
    {
* ** ** ** **** ******* ** ** ** * ** * *** * * ******* * *
** * * * *** * ** * *
* * * ** *** * *** **** **** ** ** * **** ** *** *** *
* * *** ***** * ** **** *
* ** ***** ** ***** **

* * ** *** ** ** * ** ** * ** * * * gcd);
return 0;
   }
answered by (-167 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * **
int main()
{
* * * * n,j,i,gcd;
**** ** *** * ** ** * * * * * * ** * * *
** * *** * ** *** * * * * * * **
  {
* ** * * *** **** * * * * * * *** * ** * *** *
* * *** *** * ** **** * ** * * * * ** *
  }
**** * ********** ** * *
* ** * * * * ** *** ******* 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
 int a,b;
 int m;
** **** * * * * **** *** * * *** * *** **
** *** **** * ** * * ** * * ** * * ** **** ****
* * * * * *** * * ** *
    {
* * * * ** **** * * * ***** ** *** * **
**** ** ** **** **** ******* * ** * * ** ** *
** * ***** * * * * ******* * ** * ***

**** *** * **** ** **
* ** ** * ** **** * * * % b == 0)
* * ** *** **** * ***** ** * ** ** * *** ** * * * ** **

*** ** * ** * * *** * * * ** * * * * *** *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * * *
#include ****** ** * * * *

int main()
{
*** ***** * * *** **** *** n1, n2, i, gcd;

**** ** * ** ** * ** * * ** ** ** &n1, &n2);

* **** * *** * * * ** i <= n1 * **** i <= n2; ++i)
*** *** ** * * * *** **
**** * ** ** *** * * * * * * * * **** * ** * * * n2%i==0)
*** ** * *** *** * * * * * ** * ** * *** * * ** ****** ** ** *** = i;
* * * * *** ** * *****

* * * *** ** * ** * * * * *** gcd);
* *** * ****** ** *** 0;
}
answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * ** *** * *
#include ** * ***** *** *

int main()
{
* ** **** * * *** * *** * * n1, n2, i, gcd;

* * *** * * ** ** *** ***** * ** * *** * &n1, &n2);

* * * * ** *** * * * *** i <= n1 **** * *** ** i <= n2; ++i)
* *** * * ** ***** **
** ** * * * ******* ** * * **** * * **** ****** * * ** ****** n2%i==0)
* * ******* ***** * * * **** *** *** * *** * * * * = i;
* ** ** ** * * *

** *** ****** * * ** ** *** ** ** gcd);
** * * ** *** * ** * **** **** 0;
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
** * ***** * *
*** **** * ****
int ** *
{
int *
* ***** ** * * * * *** *
* * * **
{
*
a=b;
b=r;
}

** ** * ***** ** * ** *
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * * * * ** a,b,smaller,i;

** ***** *** ***** * *** ** * ** ** *** * ** **

* * ** * * * *** * * * * * ***
* ** *** **** *** * **** ** * ** * ** **
* * * * * **** * ** * **
* ****** * * * * * * ****** * * * *** ** ** * ** **

* ** ******* * * * * * ** * * * **
* * ***** * *** * * * ** * * * * * *** *** && b%i==0)
*** ** ***** * * * * ** **** ** **** * * *

* ** * * ***** * * *** * ** * * *

*** * ** * ** * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* **** * *** ** *** ** **** * a,b,n;
*** * **** * * ** **** * * **** **** * ** ***
*** * **** * *** * * (n=a-1;n>1;n--)
* ** * ** ****** * *
* * * * ** * * * * *** * * * *** * ** && b%n==0)
* * *** * ** ** *** ** *** *** * **** *
****** * ** **** ****
** ** * ** * * ** * * * *** * * ** ** ***
* * * *** * * **** * * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* * * ** * * ** ** * x,y,n,a,b;
** * * ** * ** * ** * * %2d",&x,&y);

    for (n=x-1;n<x;n--)
    {
*** * * *** * ***** * ** * *** * * * * ***** * *
** *** *** * * ** * *** ** *** * *** *** ** (a==0)
****** * * * * * ** ** ** * * * * ** *** * *
*** * ** * ** * * * ** * *** ** * * ** * ** *** * *** ** ***
*** * * **** * ** * ** *** * * * * **** *** *** * (b==0)
** * * * ** * ** * * * ** * ** ** *** * * * * * **** * ** *****
*** * * * *** * * ** * * ** * * * ** ** ** * ********* * * * * **** * ** * ***** ** *
* ********* ** * * * ** * ** ** * ***** ** ******* ** ** ** * ** **
*** ** ** * * * ** * ** * ****** **** ****** **
    }
* * * * ** * ** *** ***** ** ** ** *
* * **** * * * ** * ******* * 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
int main()
{

* * * * * * *** *** *** n,n2;
****** ** * **** * * ** i;
********** ** *** ** * *** min,gcd;

* *** ** *** * ***** * * * ** ** &n,&n2);

* * * *** * ** ** *** ** * *
    {
* * ***** *** *** ******* * * * ***** * * ***

* ** ** *** * * * * * ** *** * *** * * ** * ** * ** * *** ** ** *
** ** ***** * ** {
** * *** * * ** * * * * ** * ***** ** * **
*** ****** * * *** *** * * ** * ** * * *** ***** *** * * **

*** * *** * * ****** ** i=1;i<=min;i++)
    {
**** ** ** ** * ** *** * ** ** * **** ****** **
* ** ** **** *** ** ** *** * * *******
**** * *** ** * * * * ** * **** ** ****** * * * *
* ** *** **** * * * * ** * **
    }

** * *** * ** ** ** * *** **** ** ** gcd);

** * * * * *** * * ** * 0;
   }
answered by (-167 points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%d%d", &n,&n2);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:27:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%d", gcd);
     ^~~~~~
prog.c:27:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:27:5: note: include '<stdio.h>' or provide a declaration of 'printf'
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 24.4k views
0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 4.4k views
1 like 1 dislike
36 answers
[Exam] asked Nov 15, 2017 in Midterm by thopd (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 11.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users