1 like 1 dislike
5k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiplelowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(ab), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited

edited by | 5k views

36 Answers

0 like 0 dislike
Hidden content!
#include * ** *
//gcd and lcm
int main(void)
{
* ** *** *** * *** * n,m,i,gcd, j,k,lcm;
* ** ***** * * * * *** ** * * ***** &n, &m);
* ** * * **** * **** *** * i<=n ********* * * i<=m; i++)
** * ** * ******** ***
** * ** ** *** * ** * ** ** * * * * * *** ** * ** * * * * *** * m%i==0)
** * ** ** * **** ******** * * * ** ** ********** *** * ** ***** *
** ** ** * *
* * * ******* *** *** * ** ** ", gcd);

* **** * ** * ***** k>=n && k>=m; k--)
*** ** * * ** * ***
*** ** * * ** * * ** * ** * k%m==0)
** * ****** * *** ** ** **
** *** * ****

* * ** * * * * * * * * *


** * * * **** * *** * * ** * * 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
* * *** *** *** * ******** a,b,tmp,x,y;
***** ** * **** * * ** ** *** ** ** * * %d", &x ,&y);
** * *** * * * ** *
*** ** * *** ** * * ******
** * * * ** * * * ***** {
*** *** * * * * * * ** ** ** * ** **** *
* ** ** **** * * ** ******* ** **** * * * **
** *** ** ** **** * ** * ** ** * * ******
* *** * *** * ** ** ** ****
* * ** ** * * *** * *** * %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
* ** * * * * * a,b;
* * ** ****** ***** ** gcd,lcm;
** *** * * ** * *** * * %d",&a,&b);

********* *** ***** ***** ag=a,bg=b;
* * * * ** * ****** * * ** *
* *** ** * ** ** * ** ** ** * * ** **
*** * * *** **** * * * ***** * *** * ** * * temp;
* ** * * * * ******* ** * * * * * bg=ag, ag=temp;
* * * *** *** * *** ***

* ** * ** *** **** * i=1,al=a,bl=b;
** * * * *** ** ** * al%bl!=0 ) {
*** * * * * ** * * ** ****** **** ** ** * ****
** * * ** ** ** *** ** * ** * *** * * *** **
** ****** ** * **

* * ** * *** ** * * * ** ***** * %d",bg,al);
* * *** ** ** *** *** * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
** *** ***** * ****** * **** *** * *** * ****
* ** * * * * ** * * * * ** * * ****** *** * * * * * * * ***** *** ** ** ***
* *** *** ** **** * * ** * *** *** * *** ** * *** * * * * * * * * ** **** * *** ** ** ***** ** * * * * * *****
** * *** ** * *** ** * * ** * ** * ** * ** * ** ** ** * ** * * * * * ** *** *** ** * * * *** * * ** **
* ** * * ** **** ** * ** * * * * ***** * * * ***** **** * ** * *** ** ** ***** ** ** ** **** * **** ** * * *
** *** *********** ** ** ** ** * ***** * * * * ** ** * * ** * ** * ** ** *** ** ** ** * * ** * * * ** * * ** * * * * ",i);
** ** * ** * **** ** * ***** ** *** * * ***** ** ** * * ***** ** * * * **** * *** * ** ** ** * * * * ** ** ****
*** * *** * * * ** **** ** *** ***** ** ** * * ** **** * * * *** * * * *** **** * *** * **** * * * * ** *
** * **** * * * ** * ** ** ** *** ** ** *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
** *** * *** * * * * * * ** ***** * * *** * *
* * ** *** * * **** *** * * * ** * ***** * *
**** **** * * **** ** **** * * * ***** * *
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
***** * **** ***** *** * *** ** * %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
*** ** ***** * * **** ** * ***** * ** *
* ** * ** *** * *** ***** * ** ****** * ** ** (flagGCD1==0)
* ** ***** * * * *** * *** * ***
* * * * * * * * ** * *** * *** * * ** ** ** ** ** * *
* * * **** * * * **** * **** * * * * * * ******* ** * * *** (flagGCD2==0)
* * ** ** * *** ******* * * * ** * * * ** * ** ** ** ***** * ** *
***** ** ** * * ******* ** ** * * ** *** ** * * * * * ** *** ** * * ****** * *** ** * ** ",i);
*** * ** * *** **** * * * * ** * * * * **** ** ** *** ** * * * * * *
* **** *** *** *** * ** **** **** ** ***** * * *
* * **** ******* ** * * ** ** * * * * *** ** ***
    }

    //LCM
    for (j=1;j;j++)
    {
** *** **** * *** * * *** * ***** ** * ** ** * * * * * *
** * ** ** * * ** **** *** ** * * * ** (k=1;k;k++)
***** * * **** ***** *** ** * *
** ** *** ** ** ** * ** * ** * * * ** * ** * * *** ** *** * * **
* ** * ******** * * *** ** ** * * ** * * ** ** **** ** (flagLCM2==flagLCM1)
** **** ** * * * * * *** * ** * ** * * ******* * * ** * * ****
* * * * * *** ** *** * * * **** * *** * * * ** *** * * ** ** * * ** ** * *** ** * *
*** *** * * * * * **** * **** * * ****** * *** * ** *** *** * * * * *******
* **** * * * * **** * ** * *** * * * * *** * ** * * * ** * **
* * ** * * ** * **** * ** * * * *** *** * * * * * * ****** * (flagLCM2>flagLCM1)
* * * * * ** **** *** * * * *** * * * * ** ***** ** **
* * * ** ** ** * ** * * * * * ** ***** * * ** ** * *** * * * * * * * * ****
* * * ***** * ** ** * *** * * ******** * *** ***
*** * ** * ****** * ** * ** * * * * *
** *** * * * ** *** * * **** **** * ** ** * * ** * (flagLCM2==flagLCM1)
****** * **** ***** ** * ** ** * * **
* ** *** * *** * *** ** * * * ** ** ** * * ** **** * * * *
******** * * * **** * ** * * * **** ** **
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* *** ** * * * *** ** * ** *** *** ** ** *** ***
* ** * * * * * * ** * ** * *** ** ** * *** **** * * ** ** ** ** ** ** * *** * ******** **
** * * * * ** * * ***** * ** * ** **** ** ***** ** **** ***** * * * * * ** * ** * * ** ** * * * * **** * ** * * * * *
**** **** *** ***** * * ** *** ** * **** **** ****** *** * * **** * ** ***** ** * ** ** * ** ** ** * *
******* * * *** * * * * ** ** * ** ** ** *** ** * * * * *** *** ******* *** **** ** **** * ** ** * ****** * ******** ** ** * * ** **
* ** * ** ** * ** * ***** ****** ** **** *** * * ** * * * ** * * * *** * * * ***** ** ** *** * * ** ** ** * * ** * ** * * **** ** *** *
* ** *** ***** ** ** * ** * ** * * **** *** ** ** * * * **** * * * ** ** * ** * * ** * *** ** ** ***
*** **** * ** * * * * * * * * * * * * ** * * * ** * ** * * * **** * * * * * * **** * ** * * * * * ***
* * * **** * ***** * **** * **** **** ***** *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
*** ** * *** * * * ** **** * * ** * ** ****
** * * **** * *** * *** * * * * ***** * ** ** * *** ** * *
*** * * ** **** * **** * * ***** * * ** * * ** *
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** * * **** * * * ** * a,b,smaller,i;

* * ** * * * * * * * *** * ** * * *** * * *

**** * ** ** *** * * * * *** **
* * * ** ** ****** ** ** * * **** ****** * *** *** *
* *** * ** * * * *
**** *** * **** *** *** * * ** *** *** *** * *

* ** ** ** **** ** ***** *** * * **
* ** ******* ** * * * **** * *** * * ** *** * ** * && b%i==0)
* **** **** ** * * *** ** *** * ** * ******** * * * * *** * *

* ** * * * ** *** * *** ** ** *** ** * **** * ** ** * %d",i,(a/i)*b);

** * * *** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
* ** * * ** ** * **** * **** * ** i,n1,n2,a,gcd,lcd;
** * * * * * ** * * * ***
*** * *** ** ** * *** * ** ** * %d",&n1,&n2);
* *** * * * **** * * ** || i<=n2; i++)
* **** * * **** **** * *
* ** * ** *** * * * * *** * ** ** *** * * * **** **** && n2%i==0)
******* * *** ** ** * * * ***** * ******** * * * **
*** * ** * ** * **** ** * * **** * ***** * ****** * *** * * *
*** *** * ** ** **** *** * ** ** * * *
******* * ** * *
** ** **** ******* * * ** ** * *** && a>=n2;a--)
    {
* **** ** * ** *** * * * *** **** * ** **** ** && a%n2==0)
* ** ** ***** **** * * **** **** ** * * *
*** *** * * * ** * * **** * **** ** *** **** * ** ** ** *** ** ** *** **
** ** ** * ** * * **** * * *** * * ****
** ** * * *** * ***** *
**** ** * *** ** * * * * * ** * * %d",gcd,lcd);
* * * * * * * ** * * 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * **** **
int main (){
int i,j,k;
* *** * * ******* *** *
** * * *** ****** * * *
* * ******
* *** ** * ****** * * ** * * * ** ***
* ** * * ** ** *** *
* * * * * ** *


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

* *** * * * *** * * i;
** ** ***** ** * ***** result=1;
* * *** * * * *** * * * * ** *** * *
** * * ***** * * * * * ** ** * * **** * *** * && a2%i==0){
* ****** * ** * ****** ** *** * * * * * * *** ** * * ** **** = i;
** * * ****** * * * * * ***** * *** * ** *
*** **** ** *** **

* * * * ** * ** * * * * * result;
}
int Get_LCM(int a1,int a2){

*** ** **** * * * * i;
** * * ** ** ***** result=1;
* ** ** *** *** * ******* * **
** ** * * * *** *** * *** *** * * * ******* && i%a2==0){
** * * * ** ****** ** ****** * ** * * ****** * * *** * * * ** = i;
* * * ** * ** * * * * * ** * * **** *
** * *** * ** *** *** *

*** * ** **** ** **** * * ** result;
}


int main(){

** * *** * * * **** ** * ** ** ** ****** * * * * ***** *** *

*** *** * * *** * *** * * * **
*** *** ** * * * * * ** * * *



** ** * ** * ** * * * ** %d", GDC, LCM);
**** ** * ** *** *** 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.43
©2016-2025

Related questions

0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 2k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 8.8k views
0 like 0 dislike
21 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 3.4k views
0 like 0 dislike
22 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 3.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users