Midterm Question 3

1 like 1 dislike
6.8k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiple, lowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(a, b), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited
edited by | 6.8k views

36 Answers

0 like 0 dislike 
Hidden content!
#include  *** ** ****    
//gcd and lcm
int main(void)
{
**     *  *** *  * * **  ** **  *** n,m,i,gcd, j,k,lcm;
  *  *  ** *   *  *  *  **  * **** ** ***** **  * &n, &m);
* ****  ******* **  **   * * **  **   i<=n ** ****  *** i<=m; i++)
*  *** ** * **   * **  * * **  
         ********       *  ** *     *   * *   ** **     * *** *****  *  ** m%i==0)
 *       **      ** ** **  *        *  *** * ** **  **** * ****       **  * **   **** **
*** ***   * ** **     *   
   ** *   **   ** * ****   ** *** ***  * **  ", gcd);

 * ***    ****** ****     * * ***** k>=n && k>=m; k--)
    *   ****  ** **  * *  *** *   
**  * **   *** ** *     **** ** *    **   *    * k%m==0)
   ****  *  *     **   * * *  
    ** * ** *   * *     

**      * * *** **  * **  *  ****  *  * ** **  * *   


* **  **  * *  ***   * ** *  * 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
***  ** * *  ****   * * **  * a,b,tmp,x,y;
***    ***   *** *  * ** ** * *    *   * * %d", &x ,&y);
    **** * * *   *  ****** **
  * **   **    * ******  *** 
 * ****    ***  ** * *** *  * ***  ** {
    * * **     * **  * ***  ***** * * *** *   ** **   ** 
  ** * * ***    ** * **** *****   *  **    *    *
** *  ***  * *****   ** *****  * *    *** *** **  *** * **
****  * **  * * *** *   
  ** *  * *  ***   **    *    *  *   ** %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
** * **** *****  **** ********  a,b;
 *  * *    **  * **** *****  gcd,lcm;
     **  *  * ** ** * ** **  *** *** * %d",&a,&b);

***  *   **** ***   *    * ***  ag=a,bg=b;
    *  ** **      * ** *** *** * * 
  ** ****   *******  * * *   **** **** * *        *     **
***** *  *  *  * ***     * ***  * *** ****** * * *  ** *   * temp;
** *** *** * * ***  **** *  ***   ** * ******  *  **   bg=ag, ag=temp;
* * *   ** * * *  *  **** * 

*  * **  * *   *   * **  ** i=1,al=a,bl=b;
  *      ** * *  * * *  al%bl!=0 ) {
*     *  *   * ***** ***   * ****  ** **  *  **** *  * ****** 
*       *   * * *****  ** * *****   *****  **  *  *  * *  *    *
 *  * *** ***  * ****   

*   *    **** *** *** ** *  *   **     %d",bg,al);
   ****  ** * * **** *  *****  0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
     * ****** ***     *  * * *****   **** ** ** * ** **  
*  **   **    ***  ** *     ****      *  ** * ** ***   *****  ** *  ***    *      * * *  **  * ***  * ** **  **  
    *  *    * **  **           ***  **   **  *   **    * * *    *** *       * **  *  *      *** *  * *  *     * *** *  *        * * *****  * ** ***
  *    * *  ** **    **     **  *  ** ****** ** * **** ** *    *  *    ** **  ** * *** **   **  *   ** *** *       *    ****    **   *
     * **  ** ** *  *  *   **      *  *  * *    *  **  ***  **  ** *** *  ***    ** * *   *  * ** *   ** * * ***  *** * **     ***  ******    **** ***     * **** ** ** ***   
** ****   *  * *   ***  **** *   *  *  **  * * **  ******* *****  ** **    * * ** ***** **  * *  ******* *  *****     *****   *   * ** * * * ** ** **** *   ",i);
* ** *  * * * *     **   *     ***    *  * ****     ***** * ** ** * **  * *  *  ** ** * ** *       *  * *  **     ** **** *   ***   **** ** * **** **** **** * ** 
  ***     * **  * *  * * * *  * *    * ** *  * ** ** **   *  * *     *  *     *****   * **    * *       * ** ** *     * * **  *  * 
  **    ****  * ***    * * ** ***   * ******      * **
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
 * *   ****    ** **  *   *      ***  * *  **    * ***
  * ** ***    * ***   *** * *  **  ** * ** * *   *******  ** ** *    ** * **  * 
* *** **  * **   *  ***   *         *  *           * * *  * * 
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
** * *    **  * ** *  *  **  ** * *  ** * * %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
   *  * ***    *  **  *   * *  *  ** *  ** **  **** **  ***  ***** *   
 *   *  * * *   *  * ***** *  ***** * * **  *  **** * *  *  *   (flagGCD1==0)
*  *   *** ***  ***    **  *  **     ** ****  ** * ** * *
   ***   ****   **  ** *  **  *  * ** *  *  *  * *  * * *  **     * * **     *  **  
*******  **    *       * *******    *** ** *   * ** ****  **  *  ****   **   * *  (flagGCD2==0)
*  * * ** *  * *****  * **** *   ** ** * **  **   *** ***  *** *** ****  * *** *** * 
** *   *  * *  **   ****** * ***    ** *** * ***** ****  * * *  *****  * **      * * *   *** **  ***  ***  *****      * **  * *  *  ",i);
 *  ***   *   ******* ** ** ** ** *** * *** **  * *** *  * **  ** **  ** ** * * * ** * *   ***** *** ** *   ****** *
   * *** *  ** *   **  ***     * **** ** ** *  ******  ** *  ** *   *****  ***    
* * ** ****   *****  ******  ** * *   *  * * * *  *  
    }

    //LCM
    for (j=1;j;j++)
    {
* * * * **  * ** *  *    * ****    *  ** *     ***  *** *  
**   * * ***  *  *** *  **   *** ** *   *  *  **    (k=1;k;k++)
  *  * *   ** **** *   * *  ***   ***  ****       * *
    ** * ** *  * *   **** **  ** **** * *  *     * * *    **** ***** * *  ****    ****    ***
**    **   **  *  * **** ** **  *   ** ***  **   ***   *    * ***** ** *    **  * * * (flagLCM2==flagLCM1)
* * *  * ** * *  ** ** **   *   *  *  * **  ** *     *    **  * *  *  * * * ****  **
** **  * *  ** * ***    *** *  * **   * * * ** **      *****  * * ** * * ** *    *****  **** * **   *** *   **     ****     *  
*   **   * **    **   ** * * ****** * *   * * ** *   *****        * * *** **  * ** ***   *     ** *  *     *  
 ****    ***  ***    * * * ***     * ** ** *     *  ***   * **** *      ** *******
* *   * *** *  ***      *   * *  ****  **  * * ***      ** *  **   **   *   *  ** ***   *  **  (flagLCM2>flagLCM1)
*  *      ***************  **  *** *  *    *  ***** * **** *** ***     **  * * *
***  ** *       ****  ***** *  *  ***  *  * *   **   **  * ***    * ***** ** ** * ** ** *  **   * *   **    **    **
* ** * ** **  * *  * *  *         ******** *     ***  *  **    **   **   *  *   **
 ** **  *****  *  *** * *   * *   *** *** *  *****  **
 ** * *  * *    * **     * *  ** *  * *** *     *** *****   (flagLCM2==flagLCM1)
*  *   *  ** * ** ******* ** * *** *  **  **  ** * ** *
** ***  ** ***    *  *****  *  **  *   *  * *   *****   ***  ******     *  * * * *** *  * **
     ****  **** ****** *  *  ** *     ** ****  * * 
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
*   ***   ** *   *****   *        **   *    ****
  **  * * *   *  *** * *  * * *****    * *    ******* **   * *  *  *** * * *  * **  **  *     ** *****
***      * ** **  **   * *** ** * * *  **    *  **  * *  * **** * *  ******** **  *   *   ***  *******   ****     *****  *  * **  *     **** * **  * * *
* * ** ***  **  ** ***   **** * *  **** * **** * * * * * **** *  *  ***  * *  ** **  **  * * **  ****    ***  * *  *   **    ** * *  *** **  ***** * ** 
 * * **   **   *     * *****  *  * ***  * ***     *      **** *   ** * *** ** ****   **  * **** *  **** ** *   * ** *     ** *     * * **** **  **    *  * * **       ****   ***     
**  ** ** *  * **** * **   *** *** * * ** **   * * **    ***  *       ** *     *  *  *  ***  ** *** **   *      *  *   **    ** ** * *  *  * ****   *   ** * *  *   
  **   **   ** * ** **  *   **   ****   **      *  * *       *** * * ***** * ***  *   *   *    *     *** ****** * ** **** **  *** *  **  * ****
*     * **  ** **  *  **** ***    ** ** * ** ****  **       *  ** ** **   **** *****   *    ***   * *  ** ** * * **  **  *  *  *   * *  ** *** * **
  *** * **** *       **   *   *    *   ** *     *** *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
    *   **  *     *  *        ***  *  *  ** ** 
  * **     ****  *       *  ** *   ** *    ** *** **  **   **** ** *  *   ****
  * **   ** *     * * * ***** *  * ****  *        * *  ** 
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* **  ****  * ***    ** *   * ** a,b,smaller,i;

 *   * ** * *   *     *  ** * **   ***** ***  * ***  * *    *  ****  * * * 

              *  *   *     * *       * 
**  ***** *  *  **  *** **** ***** *      ***  ** **  *  ** ** ** 
*** *  * * **  ****  * *  * * ***
* **    *  ** **  ********* * **       ** ** * **  **  * *

  **  *******    *     ***  **** *     **   * **
* ** **    * * * * ** *  * *  ** *           * ***  * *** * * * && b%i==0)
 **** ***  *    ** *  *  *  *  *** ***  ***  * **** * * * ** * ** *   **** *** * ****   *  * 

** **** *****  ***   * **  * ** *  ***  *  *   * ***  * ** *  ** * * %d",i,(a/i)*b);

  **  *** **   *   *    **** **   0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 ** * ***   ** ** *   ** ** i,n1,n2,a,gcd,lcd;
 * ** ****   **     *  * *   ***  **   **
**   *  *     ** *** * *  **     **   %d",&n1,&n2);
  **  * ***   * *  ***     ********** *** || i<=n2; i++)
**  *** **   ** *****  
*  **  ***     ***    **  *      *    ***  *** **  *  **  && n2%i==0)
***  ***   * ****  * ***   *   *  *** ** ** * *** * ***
**  * ** *  *    *** * **    * ****     ****** ** *** *** * * **    * *  **  * **    * * *  * ** 
**********     ***   *  *  ***  * *******    **  *  ***   ****
 ***  *        ***  ** * *
 * *   *  *  ** **   * ** * *  ** ** *  ** && a>=n2;a--)
    {
** ******  *** ** * **  * ** *  ** ***   * *****  *** && a%n2==0)
  * *   ** * ** **    **     * *   * ** *  **  ** 
**    *        *    *     * *   *  ** * * ** * *    *  **   * ********* ** **  *   *
  **** **  ** ** **   *** *   **** *****     ** *    *** 
  *   ** ** *    **  *  ** 
** ** *      * *****   * **  * *****  *  %d",gcd,lcd);
  * **       *  * **** **   ** *  0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include      *    **** *
int main (){
int i,j,k;
 * *   ** *  ***   **  * **  ******
* ***  **   **   * ** **    ** ******* ** *
*  ***  ** *  *
   **  * ***      *  * *  *  *  **      ***  ****  *
*   *   ***  ***  ** *   *  * *   
*   ** * ** *  **    


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

* ** ** * **    **** *   *  *** i;
    * *  ***** *   ******* result=1;
* ****         ** *** ******  * **     * * 
**** ******   * **  ** ** **     *    ** ** ***    **  *   * && a2%i==0){
**   ****** *   *  * **  **   *   **    **  * * ** * *   *  *       *  * *  *  **  = i;
 ***  * **  *** * **   * * ***** ****  ***     * *** * *
*   * ***   * **** *   * *   

  ***   *    *  ******* * *  ** ***  result;
}
int Get_LCM(int a1,int a2){

 *****  * * ***  *** * * * i;
* * * *       *   *  **  **    * result=1;
  * * ***   * ***   * *  **** *  **  ***   **
 *   *  ** **     * **** **** *  * * ***      *** ** && i%a2==0){
 ***    *   ** *   * **   ******     * *  **  * *****   *      **   ** ** *** * ** = i;
 *  * *****  *  ** *** * ** **** ***  **** ** *    * 
 *   ** **        **** *****  

*******    *  **  * **  *    **  * ** result;
}


int main(){

 *  ***  ** *** * * ***   ***  *  * *       *** *******    *

**    ** * ** *   ***  **  * *** ** 
 * * *********      * ** * *  ** **  *  



 * *** *   *   *  ** *   ***** * ***      %d", GDC, LCM);
    * ****  * * * **  *  ** *  0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.158.158.163
©2016-2025

Related questions

0 like 0 dislike
10 answers
Midterm Question 3 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 2.7k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 11.9k views
0 like 0 dislike
21 answers
Midterm Question 5 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 4.7k views
0 like 0 dislike
22 answers
Midterm Question 4 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 4.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users