1 like 1 dislike
9.5k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiplelowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(ab), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited

edited by | 9.5k views

36 Answers

0 like 0 dislike
Hidden content!
#include * ** * ** * * * *
//gcd and lcm
int main(void)
{
* * ** * *** *** ** n,m,i,gcd, j,k,lcm;
* ** * ** * * * *** ** ** ** * ** * * * &n, &m);
** * ** ** **** * * ** i<=n ** * * i<=m; i++)
* **** * **** ***
** **** * **** * *** ** * ** * ** * * * * * * *** *** * ** ** m%i==0)
*** ** * ** * * * ** **** * * ** * * * *** *** * ****** *** **
* * ****** **** **
**** ** * ** ** ***** * * *** * ", gcd);

** ** **** * * * k>=n && k>=m; k--)
* * **** *** *** * *
** *** ** * * * * *** *** * * *** **** * k%m==0)
* ** ***** ** **** *
* ** *** ** *

* ****** *** * * * ******* ****** * ** *


* * * * ******** * *** * * 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
* *** * ***** ***** * * * ** a,b,tmp,x,y;
*** * ** * * *** * * * *** %d", &x ,&y);
* * * * * * ***** **** * * *
* * * * *** *** * ***
* ** ** *** * ** *** * * {
* * ***** * ** ** ** **** * **** ** *** ***
* * * *** ** * ** ** ** ***** ** ** ** ** *
** * ** ***** ** * * *** * ** * ** * ******
** ** ** ** ** * ***
**** * *** *** *** *** * * %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
** * * **** * * * a,b;
* * *** *** * * gcd,lcm;
** * ** *** *** * * **** ** ** %d",&a,&b);

*** * * * * ** * *** ag=a,bg=b;
* * * **** ** ** ** * * * * **
* **** * ** * ** **** * *** * * ****** *
*** * * ****** *** * ** ** * ** **** temp;
* * * * ** *** * ** *** *** ** * * ** ** * ***** ** bg=ag, ag=temp;
** ** ****** * **

**** *** * * * * *** i=1,al=a,bl=b;
*** ** * * * * ** * * ** * al%bl!=0 ) {
*** * * * ** * ***** * ** * * **** ****** **** *
* * * * * ** ** *** *** * * *** *** ***** * *
* ** * ** * * *

* * ** * * * *** *** * **** *** %d",bg,al);
**** ** * ** *** * * *** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
*** ******* * * * ** * * * ** * * *** * ***
* * *** **** * **** * ** *** ** **** *** ** **** * ** *** ** * * ** * * * *** *
******* *** * ** * ** * ** * *** *** * * *** *** * *** ****** *** *** ** ** ** * * * ** * * ** ** * ***** * * **
* * **** * *** * ** * ** **** *** ** *** ***** ** ** *** * *** ****** ** * * * ** * * * ***** * * ** *
* ** * ** *** **** * *** **** ** * * ** *** ** ** * * * * ** ** ** ** * ** ** * ** ** * **** * * ** * *** * ** ** * *** * *
**** * *** **** * ** *** *** *** * * * **** *** * * * * * * * * *** * ** * * * ** ** *** ** * ** * * *** ** ",i);
** * ** * * **** * *** ***** ***** * ** ** * **** * * * * ** * ** *** *** * * ** * ** * * * * ** *** ******** * * *
*** * ** * *** * * ** * *** ***** ** * ** ** *** * * *** **** * * * ** *** * * * * * *** * * * *** ** ** *
** * * * * ** * * * ** ***** ** **
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
** ** **** * * ** * * ** ** *** * ** ** **
* *** * * * ** * * * **** * ** *** *** * * ** * * ** **
* * *** * * ** * ** ** ** * ** * *** * * * *
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
********* * * ** ** * * %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
* *** ****** **** * * ***** * * * **** *** **** *** *
* * ** ** ** *** * ** * **** ***** ***** * * ** (flagGCD1==0)
* **** * ******* ** **** ** ***** * * * *** *
* *** * * *** ** **** * ** * * * * * ** ** *** ** **** * ** * * * * **
* * ** **** ** ** * * ** ** * * *** ** * ********* ** * ** * * * * * (flagGCD2==0)
** ** ***** * * ***** * **** * *** * * ** ** * ** ** *
* * * ** *** ** ** * *** * ** * * ***** * *** * ***** *** ** * * *** *** * ** * ** * * ",i);
* ** * * *** ** ** ** * * * *** * ** * ******* * * * * *** ** * **** * * ***
* **** * * *** ** ** * * *** * * * *** * * * ** * ** * *** ** *****
** ** * ** ** * * *** * ** * * *********** **
    }

    //LCM
    for (j=1;j;j++)
    {
* ** ******* * ***** *** * * ** *** * * * * ** ** *
***** ** ** ** * * ** * * ** * ***** * * * ** * * * (k=1;k;k++)
******** ** ** **** ***** ** * ***** * **
** *** * ** ** * * * *** ** * **** * ** **** ** * * *** * ***
** * **** * ** * * * *** ** **** * *** * ** ** ***** *** (flagLCM2==flagLCM1)
*** *** **** * ** ** ******* * ** * * * * * *** *** ** *
* **** *** * * ** **** *** * ****** * * *** *** ** ** **** * **** *** * *** * * * * ** ** * * ** * ** ** *
** ** ** ** * *** ** * ** * ** ** ** * * *** ** ** * * * ** * ** *** **** *** * ** * ** *** * *
** * * * * ** * * * * * * * * *** **** * * ** * * * * *****
****** ** * * ** ** ** * *** * * * * ******** ** * * * * * ** * * *** ** (flagLCM2>flagLCM1)
** *** * * ** * ***** ** * * ** **** * **** * ******* * *** ** * ******* ** *
* * ** ************ * * * * ** * **** * ** ** * ** * * ** * **** **** * * * *** *****
** * *** * * * * *** **** ** * * * ********** ******** * * **** *** *
** * *** *** ** ****** * ** ** ***
* * ****** * ** * * * *** * * * ***** *** * ***** (flagLCM2==flagLCM1)
* * ** * **** *** *** ** ** ** * * *
* *** ***** ***** ** * * ** * * *** ******* ** *** *** *** *** ***
* * * * * *** ***** *** * * * ** ** * *** * *
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
****** * **** ** ** *** * * * * * ** *** ** * **
* **** ********* * **** * ** * *** * *** ** *** ** * * ** * * ** **** *** * *** *
*** * **** ** *** ***** * **** * *** ** * * ** * * * * **** * * ***** **** * * ** * * * * *** *
* ** ****** ** * * ** **** *** ****** * ********* ** * * **** *** * * * * * * ** **** * * *** **** * **
* ***** ** * ** * ** * * * * ** * * *** * ** ** * * * ** **** ** * ***** * ** *** *** ***** ** ** * ** * * ** ** ** * **
* * *** * *** * * ** * * *** *** * * * ** **** **** * * ** * ** * ***** ****** ********* ** ** * * **** ** * ** * * **** *
**** * * * ** * * * * *** ****** * *** *** ** ** * ** ** * * ***** * * * *** **** ** *** * * * ** ****** ** ** * *** ***
** * * **** * ** ** * ** ** * ** * *** * ** ** * ** * * * ** * *** ** * ** ** **** * * ** ** ** ** **** * ** *** **
* * * ***** *** * **** *** ** * ***
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
* * ** * ***** * * * ****** ** * * **
* **** *** *** *** **** * * *** * ** ** **** * *** * ****
***** ** * * * * *** * * *** * * **
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ** ****** * ** ** ** ** a,b,smaller,i;

** ******* * * * ** *** * * * * * * * **** ***

** ** *** * * ** ********* * * *
* ***** ***** * ** * * * ** * * * * * * **
** * * * * * * *
*** * **** ** * * * *** * **** * ** *** * ** *

* * *** * ** ** * ******* **** *** *** * ***
* * * ****** * * ** * ** * ** * ** *** *** * * * && b%i==0)
* * ** * *** * ****** * ** ***** **** * * ** ** * ***** ** * ** *

** ** * * ***** * *** * ** * * ** * * **** ** * ** %d",i,(a/i)*b);

** ** * ** ** * * * *** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
**** ** * * ** *** * i,n1,n2,a,gcd,lcd;
***** ***** * ** * ** ** * *
* * * * * * **** * *** * %d",&n1,&n2);
**** * ** * ******** * * **** * * * * * || i<=n2; i++)
* * * ** ** * *** **
** *** **** * * ***** * ** **** *** ****** * && n2%i==0)
* * * *** * * * * ** * * **** **
*** * * * ** * * * ** * ** ** *** ** * ** *** * ** * * **** ***
*** *** ** * * * *** *** ** **** * * *** * *
** * * * * ** * *** *
* ** * *** *** ** * ** * * && a>=n2;a--)
    {
* **** * * * * *** *** * * * * **** ** * ** ** * *** * * && a%n2==0)
** * ** *** *** * ** **** ** * * **
*** **** ** ** * ** *** **** * ** **** * ** ***** * * * * * **
* *** * *** ** ** ** * ** ****** **** ***** * **
* ** * ***** **** * ***
* *** *** ** * * * * **** * *** ** %d",gcd,lcd);
*** *** ** ** ** * ** ** 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** **
int main (){
int i,j,k;
** * ***** ** * *** *
** * *** * * ** * ** * * * *
** * * *****
* * * * ** * ** ** * *** * * ** ** ****
* *** *** ** * *** *** **
**** * * ***** * * *


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

**** * * ** ** * i;
* * ** ** * * * *** * * * result=1;
** * ** *** * *** *** * ** **** *
* * * *** * ** * * **** * ** * *** * * && a2%i==0){
*** *** *** * ** * * **** ** * * ******* ** * * ** * * ***** * * ** = i;
** ********* ***** ** * ******* ** **** * **
* * * * **

* * * ** * **** * * ** **** result;
}
int Get_LCM(int a1,int a2){

**** * * ** * ****** * * i;
** ** ** *** * * *** * ** * result=1;
** * * ****** * ** * * ** * * * ** ***
** ** ** ***** ** * *** ** * ***** ** * *** * * *** && i%a2==0){
* ** * * **** * * * ** *** * * ** * ******** **** * * ** * * ** = i;
* * ** ** * ** ** * ** * ** ** **
* ** * ****** *** ** *** *

* ** **** * ***** ** *** ** * result;
}


int main(){

*** *** ** * ** * ** **** * * * ***** ** ** ******

* *** * * *** * * * ***
* **** *** ** * * * * * **



**** ** * * * *** ** * ** * ** * %d", GDC, LCM);
* **** ** * *** * * 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.64
©2016-2026

Related questions

0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 3.8k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 16.1k views
0 like 0 dislike
21 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 6.3k views
0 like 0 dislike
22 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 6.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users