Midterm Question 3

1 like 1 dislike
6.7k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiple, lowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(a, b), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited
edited by | 6.7k views

36 Answers

0 like 0 dislike 
Hidden content!
#include *  * * *** ** **
//gcd and lcm
int main(void)
{
 *   ** **    **   **  * * *  *  n,m,i,gcd, j,k,lcm;
*** *  ** *   ******  *  *    ***    **** **  * &n, &m);
* ****  ** ** ****   * **** *     i<=n *  *  *  *  i<=m; i++)
*   ** * *  *  *  *  *  *
 * * * *** * * * ***  ** **** *  * *  *  **    ****** ** **  **** ** * *   * *  m%i==0)
*  ** **  **  *** *** * *   **  * * *** * *   ** ***  *   * *   ***    * ***** *  ****
 ** *  * *** * * * *     
 ** **  * **   **  *  * *  ***    * * *   * ", gcd);

*   *  *   *** **** * *  **  k>=n && k>=m; k--)
*** **   *   * *   ** *  *
 ** ** *  **  * *     ** * * * * **  * * *  ** * k%m==0)
* *  * **     ****    ***   
 ** * ***  ** * ** **   

****    * ******           ** *  ** ****  ** * *    


 **    ** *** *  **   * ****  0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
   * * * *** **   **    ***    a,b,tmp,x,y;
** * *      *  *  * * ***       *   * * %d", &x ,&y);
*     *   *  **   ****   *
*  ***   ***  **** *  *** ***** *  
******  ****   *** **  *** *** **** **  {
* **  *    * *  ** **      * ****  ****    * *  * *  *  
 ****  ***   *  *   * *****   * *   **** **   ** * ** **** *
 **  **  ** **  ****    ** *   *  * ** ** * ** * ***  
 *  * ** **  ***  * *** *  *  
 *****       ** ***  *      ** *  *  **  %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
  **  **    *  *****  *  ** a,b;
**    *  *** *   ****** **** gcd,lcm;
   * **** * * *******  *   *  ****  %d",&a,&b);

* * ******   ** * **** * * ag=a,bg=b;
**** * *   ****   *   **  **** ***   ** *
 *  ** *****   *** *   * * * *    * ***** *       ***
***** * * ***     * * *    *   **   * *** ******      temp;
*  **** * **  *** *    ***  * *  * *     * **  *    *  ** bg=ag, ag=temp;
* * * * * * *   **  * *    * 

* *  *** *  ** *    * *  **** ** i=1,al=a,bl=b;
* ** ***  **  *   *  * ** **** al%bl!=0 ) {
** ***     *** *    ****** *** *   * *  ** ** * * * *** ***  
  **  *   * *  *   ** **  *   * *   ***    ** ***   ** * *
** ***  ***  ** * ***    ***  * 

**  *     * ** *  *    **    ** ** %d",bg,al);
      **  *  ** ****      *   *    0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
***   ** *  * ****  ********* **  * * **  * *    ****  *
 *  *       * *** *   * *  **  * *  *** *   ****    *   ***  *    *   *  *   **   *   *  **  * ** * *    **  
 * * ** *** ****  ** ** ***  *   ** * ***     *       ** * ***    * ***  *** * ** * ** *  * ****   *  ** **   ***  *  **          * ***   * ** *  *   *
*  *** *  * ** *  *   * ***  ** *** * *      **   ****** ** *      *   *   * *  ** *  * **   ********   * * * * **  ** ** *** ** ***    ****  *  ***
* * *   *    * *     ** ** *  ***  *  ** ** *  ***  *  *   **   **   *  *  * *  ***   * *  * ** *   ***  * ***     * ** *  **   ** *   *  **   ***     *  **    * *   ***  ** **  
**  *** ** * ********** *** ** **   *    ** * **     **  * * * ***  **  *    * ***** ****** **  ** **  * *  *      *   *  *    ** *    *  * * ** ****  **  ",i);
*  *** ** * *    ****** * **   ** * ***  * ***   ** * ***   * *    *   **   *  *   * *** ** *  *     **** ** * * *    **        **  *  *  ***
*  * *   **** * ******  * ****** *****  ** **   * * * *  * *   ** *  **** ****  * * **  ** * *        **** * **** *  ** ****    * **** *    **   
*  ****   *** ***  ** *  *     *** ** *  ** * **   
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
* *** *    * * *   *    ***     *   *  ** *****  ** *  * 
 * *   **  **** * ***   ***  ***   ** *  ** * *** **  *******  *****  * * 
* **   **** *   *  *** * *     * *  *  ***  * ***     ****   *  
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
* *    ** ** * *  * ***  ******* ***  %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
   * *** * **    ****    *** *** *  * **      **  * *    ***  
*** *  ****  ****** * *****  *   ****  * ***  *** ** ** * * (flagGCD1==0)
 **  ** * **   **    *** ********* *** *  *  *** *    * ** 
*  ** ** *** * *** ***   *   * *    *  *  ****  *   **    **  *     * * ***  ***    
 *   *** ** *    ***  ** ***     *** *    * ******   *   *   *** *  * * ****   * (flagGCD2==0)
********* *  * **** ******* **** **   * ** * * *** * **** *  * ***  *** * **    
***  * * * *   *******        ***   ***      **** *   *     **   **** * *   **     *** *  * ***     * ** * *****  *  * ",i);
*   *   ****  *** * *  *  *   ***       * * **    * *** *** *  * ** * ** **** *     *  *   *  **    * * * *      * *
   *** ****       **** * *      *    * * *   * * ** * * *    **** ** *   * ** 
   *** * *    **  ** *   **** *   *** * * *   *
    }

    //LCM
    for (j=1;j;j++)
    {
**    *  ****     *  *  * *   * * *  ***   * **   ***   *
*   * ****  * ** ****** * *  *    * *** *  *****   *   (k=1;k;k++)
*   *  **  ** * **  * ***  * ***      *** *    ****  *
* * **  * ** *  *   *    ** *    *  * *     *   ****  **    *** *  **** *** ** *     **  * *
   **    **   *   *      * ***      * *   ** ***   * *****   *   *** *   **** ** (flagLCM2==flagLCM1)
  * * *  * * **  * *  ****    ** **  * *  * *   * **   *   *      ***     ****  * 
  *** *******    *       **** *****     *  ** *   **       **** *** *** ****     ** **  **  ** ** * *   * **  ** * ***** **  *  
 **** * **    *  *** *  *** **   **  *  *   ***    *  ** ** ***  *  ***  *   ** **  ***   *   * **** * *   **** 
* ********    ***   * ***     ****    *    ** **  ** *  ** * * ** * * **   
**   *****    **     **  *  ** * **   *  * *** * **        *  *****   **  (flagLCM2>flagLCM1)
*** ** *  ****  * *  *   *  * ****  ** ** *      *   *******  * ***  * *** **   *** 
     *    *   *****  * ****   *  *****       * *  *    ***    ***** *   ***** **  **** *   *  *  *  *   ******  *
**   *** * **   * *  ** *  **          *  *   ***  ***** * * *  *   *  *  *
*  * ** ***   ** ******** *    * **** *   *  * **  * 
** *   * ***  *** ****  * **    ** **   * * ***  *  **      (flagLCM2==flagLCM1)
   *   ** **   *** * ** ***  * ** *   *   **  ** **  *  *   *
 * **   *  *    * **    **  **       ***    **  *  * **  * *****  *****  *    * * *** *   *
***   * * ** **    **      *  * **   **** **  * ***
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
***  **   * * *** *    ** *         ** **** *    **  * *
****   *   * ** ***  *  ** *   *  *** ****** * ***   *****     *** * *   ** * **  ***   *      * ** * **  
  * ** **  *   * ******** *   * ** **     **  * * * * ** * ***  *      * *** ** * ** **   *** * ****  *   ****** *  *   **   * *  ** *  ** ** *  * ** *** 
**    * ** *      ** * *  * *  ***  * **    *  * ****     *****  *** **    * * ** * *    * *       *** *   * *  *      *   * *  * **
** *    **  * * *  * **   *  *   ** *  *  ** *   *** * *     *     ***  **    **      *** *  * ****   **  **  *   *    *  ** *   * **** * *     *      **  ** *   
 ****      ** **  ** *****    *  * *** ***    * *** *      *     *** ***   * **  *** * * ** **   *  ***  * * * ** *  * ***** * **    ***  ** * *   *    * * **
* ** *  *** *****  ** * **   *   *   ***  *     *        *  **  *   **  ** *  *  ********  * *   * **  *   **  ***  *** **** * **      * ** * *
  ***  *  * **     *  * * *** **  ****** **** *   *     ** ** **      *** ****     *  * **  * * *     * * * * ***  *** **    *  *   * *   *******  *   
**  *   ***    **  *** ***    *      ** *   ** ** *** * ** * 
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
**   *** ***** ** *  * ** *  * *   ***  *  *** ***  ** 
** *    *    ** ** *** **   **    *  ** ****  ***  * * *   * * **  ** * 
* * **** *  * * * * * ****    **  *       *  **     **  * **
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
**      * **   * * * * * * *   a,b,smaller,i;

* ****** *  * *  *   *** ** **    *   * *** **     *** * *     *

  *  * *    * *  ***       * **   ** ***
  **     **  *** *  * *  ****    *    * *   **  ****   ***  *
   **   **  **** **** **** 
* *  *  ***** * ***  ******* ******* ** **   ***  *        *****

 * ***** *  ** *  *  * ***** *  ****** **    * ** ***
**   *   * ***** * *     ***  *     ** *****  * **  * ***   && b%i==0)
** **    **    ****    * **   ******    **  ****** *   *    *    ** ** ***** * * * ** * * 

* **  * ** ***  ***    **  *   ***  *****   * * ****** **  **  * %d",i,(a/i)*b);

***   *  ****    * *****  *** * ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
*** ** *  *     ***** * ** *  i,n1,n2,a,gcd,lcd;
  *    ***  *** *** *  * * * 
  *    *     *    * *     **  * ** *   *  %d",&n1,&n2);
  * *    * ** *****  *  **    * **  *   || i<=n2; i++)
  ********* *  *     *** **
 * *  *  ** *        * **        *  ***    ***  *     *** ***  * && n2%i==0)
   * ******* * * ** *   **  **  *** *  *  *  ****   *****
  ****  ** *****  **  * * ****  **  ***** * ****   *    **      * **   **  ** *  *    
*    * * ***    * * *** * * *    *****   * **    * ***
**  *** **  ** *  *******  *  
* *** ** ** *** ** ******  ***** * * *  ** && a>=n2;a--)
    {
 *  * ** *   *** * **    ** ******* *  *** *  *  ** **  *  && a%n2==0)
  ****  * * *  * * *  * *****  * **  ***  *   * *** 
****    **   *   ** ******    *  ***** *  * ** *  *   **** ****  *    * * ** **
*  * *******  *  *  *  ** **  ***** *  ** **   
         *  **  ***  *   
  * * ** ** ******   ****   ******  **    %d",gcd,lcd);
 *  ***    **  * *  * *  *  0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * ***   *   **
int main (){
int i,j,k;
 ***    ****   ***  ** ********
* *****   ** *  **** *  *  *** *   *   * * 
*  ** * * *  * *
*** *  *   *  **** *  ***** ** *   * ****       *** * *  
**** *** *** * **  ******** **
 ** *  ** ***  **   ** * 


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

***** * *   **    *  ****  ***  i;
*  * *** * ** *       *  **** result=1;
 * *** *** * *    **  ** ** ** * ****** * * ** 
* *  **  * ** ** ***  *    * **     *   **    *  *  *    && a2%i==0){
**     * **** ** *** *     **** * *   ****   **** *  *  *****  * * ***     *     *    *   = i;
*  ****  ** ** * ** *    ** **   **** * *     *  *   * *  *    
**       ****  * ** * *** 

 *   *     * ** *** *    ** ** **     result;
}
int Get_LCM(int a1,int a2){

 **   *   ** *  ** ** *** i;
   **  *** **** * *** * * *****  result=1;
      * **** **   *  * ** * **  ***  * ** *  **
*    ** **   *  *** *  *******  ** * ***     ***    * * * && i%a2==0){
 *    * **   *    **   ****    *  **** **     ***   ** *   * ** *** *** *     *  *** *   * = i;
 ** * *    * ***  *  ****  *  **  **** **    ** ******
**  *** *      *** ** **  * **

  * * **     * ** * * **    *   **   result;
}


int main(){

*  *   * ** **  *  * **** ****     * *  *** ***  ***  *** * 

  * *  *  **         ** ** *  * * *  **
   *  **** *** * **  ** ** ** ****  *  



*     ** ***   *  * *  ** ** ***   ** **  **  %d", GDC, LCM);
* *  **** *    ** ** ***   *     0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.58
©2016-2025

Related questions

0 like 0 dislike
10 answers
Midterm Question 3 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 2.6k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 11.8k views
0 like 0 dislike
21 answers
Midterm Question 5 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 4.6k views
0 like 0 dislike
22 answers
Midterm Question 4 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 4.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users