Midterm Question 3

1 like 1 dislike
10.3k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiple, lowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(a, b), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited
edited by | 10.3k views

36 Answers

0 like 0 dislike 
Hidden content!
#include *** ***** ***  
//gcd and lcm
int main(void)
{
  * **  **    *  ** * * **     n,m,i,gcd, j,k,lcm;
  * * * *   *   ***   ***   ** *** *   ***** ** * * &n, &m);
  *    * * *   *   ** *  ****   i<=n ** **  **   ** * i<=m; i++)
******  *** * **** * * ** * 
*** ** * ** ** *  ***   ****  *  * *  ***** * *   * *** * * *   *      *   m%i==0)
****  *   * *   *  **** ***** *    *    ***    * ** ****  ** ****   * **     ***** *
    * ***  *** ******  *  *
***  * *  **** * ** **   *** **  * * * ****  ", gcd);

***  *  ***         ***  * ****  k>=n && k>=m; k--)
**  **  **  *** * * *  *    ** *
 * ** *    ** * * *    * *** *   *  *  ***** *  * * k%m==0)
  *  *  * *   * **   * **  **   
*  * * ******  ***  

 ** **  *** ******      **      *** ****** **  ** **


* * ** * *   **   *** * *  **   0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
 * **** **** * * *  *   *    *  a,b,tmp,x,y;
*  * *  * *** **    ***  ** * **** **    %d", &x ,&y);
*     * * ** * **** ***  * *
 ***** ** * * * *   *** * *  * ** *
***  *  ** **  ** *   * **** * * * **    {
* *   *  ******      * *  * *  * ** *   *   *    * ** *   
**** * *  **   ***  *  *  * *** ** **   ****    * 
** ***    **  ** * ***   ** *** * ***   ** * * ****   * 
** ** ***  ***  * *** *  
   * *  * *   *   *** ** ** *   * *   ** %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
 * ****** *** **** *** *  *  a,b;
   ***  * ***  ** ****    *   gcd,lcm;
*     * **  * * **** ***  *  ** %d",&a,&b);

 * *  ** *  **   * * ***    *  ag=a,bg=b;
    ** *******  ***   ** * ** ***  **  **
****  **   * * * **** ****  *   ** *** ****   *     *  * 
**  * *              **** ****** ** *****  ***  ******   temp;
*   *    ****  * ** *  * * *** ******  ***   ** **  ***      *** bg=ag, ag=temp;
* ** *   ***  *  *     ******  

***  **  * ** *    *     **** i=1,al=a,bl=b;
* ******  *  ** **   **  *   **  al%bl!=0 ) {
*  *    **   * *** *    *** * **  **    ****     *** 
* **** * **   *   **   * *  * ** *  *** **  *****       ***
** *     * **  ** ******* ** * * 

*   * **  ***  ** **   * * *  *  * %d",bg,al);
       **** *   * ** ***  **    0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
 **  * **      **  *** * **   * * *      *** **  * ***  
    * * **       **    * * ** **  ***    *    * *  **  * *    * *  ****   ****  ******* *  *  *** *** * * *  
 **** ****   *  ***  ****   *  * * **    *    **  *  **      *** *********    ** * *** *  **   * **      ** *     ** ****       ***** ****
**    *  *   * * * ** *          **  * *     ***  ******* *  * ** * ***   *     *** *** *    * * * ** * *  *  *   * **** ***** *** ***** ** *  *
* ** * ***   * * * **   ** *  *    * **** * *   *     * ** *** * *** *** * ** * * **  **** **  **   *  *  *   ** * ** ********** * ** **** *  * * **  ********    * *
 **    ** **      ****   **  * **  ****    ***    * ** **** **** * **     *    **    *    * *****  ***  **** * * *  ***  *** * ***  *  *** ***  **** **  * *    ",i);
 **** **   *  * **  **    ********  * *  * **   *        *   * *  * **  ** *    *  *   * * ******** **  ** *  ** *  * *** ** *   * *  *  * * **   *  * * *  * ***
*    *** * ** *** ***** * ** *  ** *    * * * * **   *  ** **      *  *****   *  **   *  * ** *  *  *  *     ***  ***  **    ** *  *  ** * * * 
* * **   ***** ******   ** *    * *   *  * **** ** *     
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
******   *  **** * *  **   ***     * *  **    *  ** *** * 
 ** **   * ** * *   *  **  ** ** *** *  ***  ****  * * ***  *  ** **** ** *
       * *  *****     * **  * *  *** ***   **  ** **
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
  *   ** *  * **  * ** ****   *******  * %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
 *** *  * *  *   *   ** ** *    ***   *  * *  *  * **   *** *   
*  * **   ** ******* ***         * * *    * ****  ** (flagGCD1==0)
**** ******** *** ** ** *** * * *** ***   **           *
 *****   * *** **    ** ***   *   **   *  ****** *   ** **         *  ** *          ****** *
 *   * * ** * *** ** * ****** ** *   **    ****  ***** ***    ****  ****  * *   (flagGCD2==0)
 *** *  **   ******  ***** ** *  *  ** * ****** **  **    ** **      **** ***  * * **
** **** *  ** ***   ****  **   *    **** ****   ***  **  **   **  *  *  *   **** *  ****   ***  ** *     *** ** *  *  ** *       *  ",i);
 ***  *  * **  * *****  ** * * * **** *  * ***   **    * ** *  *   *** ***   ****   **    *     **
** ** *  * **  * ***  *   *  *   * **    * **    *       *    * ********* **  **
***    *   ***  * * ***  *** **  ** *   *   * ** * *** 
    }

    //LCM
    for (j=1;j;j++)
    {
*** **** * *** ***  *   * * **    ***   * * *   ***   * 
  ** * ***  ***  * *    *      **    ****  * ** * *** *   * * (k=1;k;k++)
** *     * ** *** ******   ***** * **  * * *   **** 
**    **         ** *  *   ****      **** ****** * * * ** *** ****    ** *****    **    
 *  * * *** * **  ***  ***   *  **   **** * *   * ** *   * * *** *  * ** * ***   (flagLCM2==flagLCM1)
  **  * * **  *   ****   **    *****  *  ***   *   *  **   *    ** ****  * **  **  ***
* *   * ** *  ******** *** * **   **  *   ****   ***   ** **** ***  **    ** * ** ** *  *** **** ** *   **   **** **** **** ** *         *  
** * ** *    *  *   **  *   *  *  **   * *     *   * ***  **   ** *   *  ** *  *     *   *    **  * * * *    
*  *** *  *** *  *   *****  *   * * *** *   **   **      * ** *** *** *  ***   **    
* * *** ***  * ** ** ** * *****    *  ** **   * ******* **   *** ** **  *   ** ****  (flagLCM2>flagLCM1)
 *  ** ** ******  * * **     **  ** * *******         *** * *  * *** ***  * *** ** 
     ******  *   ** **  ** ****   *  *  ****    * *  ** *  *  *    * *  ** **       *   **** * ****   * ** 
* *** * * **  *** ** ** *   *****   **** *** *  * *  ** * **   *   * *  **  ******* 
   *  ** ** *  *  ***** *  **  * *   * *  * *** ** * * *
  * ***** * ***    *    ****  **   * *  *  *  * *     * * ** *   (flagLCM2==flagLCM1)
  *    * *    *********   **   ** * *  *** **  *** *
 *  ***** * * * ** *** ********   *****  **      ***** *  * ***     ** * * ****  **   *
 ***  *   * * ***** * **             **** * *  
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* * *   * *    **   *  **     **  * ** *   *   *      
****    ***  **      * *  * ** *   ******   ****   * *  *  ***    *  **   *     * **  ** ****  ***  * *
*   *   ** ******  * ***    * ***** *******        *  * * **   *  **** ** *  ** **      *****   * *  * ** *   *****    ** *    *   *  *******  * *
 * * **  * * * *  ***   *  *****  *      **  ** *** * **      **** *  ***  *** *  ***    *****   * * ** ** *** ** *** * ***********     * * ***  * *
**  *    *    * * **  **   **  *******  *    ** ***** ***** **           **    ** *  * * *   **  * * * ** ** * *       **** * * * ***  *  * *****  * ***       
 *  * *****  ***  * *** *   * **   *** *  * ** **  *** ***  ** * *  **** * * *** *  ** *   **   * ***   * *   * * * **        * * * **  * * * ***       **   ***** *
     **   * ***   ***    * ****   *   *    ***  *** * *      ***** ***  *     * * ****** ***  **  *** *****  *  ***** ** *** ** *  *   * ******
**      * ****  **   ****  **  *****  ** *** ** *   **    ** ***  ** **        **  *     *  * * *        * * * *  *   *  *  *  * *
**  ********  ****** ***** ** *    *** ** * *  * ** **   *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
  * **   **** ***   **    ** ** ****  * * ** ** ** * * ***  
     **  * ***    **   *    * * **  *** *   ***  *   **    *  * *** ***  ***  * *
*** * ** ****  * *  *     * **     ** **    ***   ***** * 
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
  **  * ** **  ** *** **   a,b,smaller,i;

  * **** * ****   *   **  ** * *  *  **   *** *  *** *    *****  *

*  ***** * *  **  **  * * ******  * * ** **
** * ** *  **** * *         * * **    * * * **   *  ** ** **       
   ***  * *       ****  *  * 
  ** ***  * *     *  *****    *      *  *  * ***   ** **** 

* *** **  *  ** * * **   * *  * ** **** * *    * ***
  ****   * ***   *******  ***** * **     *   ***    *     ***     && b%i==0)
* * **  *   *** *         ** * ** *   *** *  * *   *    **   * *** * ** **  * *

   *  **     * * *  *   ** *         **** *   *   ** ***  ****** ** %d",i,(a/i)*b);

  *     *  **   * **  ******* 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
*  * ***  * * *** *  * **   **   i,n1,n2,a,gcd,lcd;
*   *** ****    *  * **  *** **
 *    * *    **    *   ***  *   **** *      **  %d",&n1,&n2);
*** *****  *     ** ***** **** *  **  *    || i<=n2; i++)
    *  ** *  **** ** *  ** 
*  *  *   ***  *  * *  ** **   *    *  *    **  ****  ***  && n2%i==0)
* *    *        **** ***** *   ****  *  * *** * *** *  **** 
 * *****   **** ** *   *  ****     **   * * * * **** **    * ** *  *** * * * ***
 *  ****** **           *  ** * ****    *  ** * **** *
*  **  *  ***   * **   * ******
 ** * * **** *  * *** ** **** * * ***     * **  * && a>=n2;a--)
    {
****          **  * ****   ** **  *   **   *    *  ** * * * && a%n2==0)
* * *** ** ****   * ****** * * ** *** **  *  * * * 
**   ****   **** *  *****  * *** **     **  *  ***  *** * **   *  *   ***     ***   * 
 *   * *** ***        *   ******   *  * *   *  ** ***    
    *  **  * ***  ** * *    
***   ***    ********      *    * *  %d",gcd,lcd);
      **** **       * * ** *** * ** 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ****  *  *** 
int main (){
int i,j,k;
*   * * * ***    * * *    
*   *   **   ** *** * * *  * *      * ** *
****      ****
** * * ** **  ** **   *** *** *** ***     * ** 
 **** **  ** ***** *****  *
*   ** * * **   *


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

 * ** **   **** *   ** *    * i;
*  * *****  *   **** *** ****  result=1;
*  * ** **   *** ** ** ******* **   **  * *  *  
***  ** *  ** * * **    * * *   * * * *****  * *  *** *  *** && a2%i==0){
  ** * * ****   ***      ***** ** ** **** **** ***      **  ** ** * **   *   **** * = i;
 ** *      * *  ***** * * * * * *  *   ****  ***
 *** **     *  ** *    *  *  

  *  * *    *** ***    **** ** * * result;
}
int Get_LCM(int a1,int a2){

* **** *    ** *  ***** i;
*** ** ** *   **** **     ** * result=1;
 ******  **     ***   *   * * * *** ** *   * 
* ***   ** **   ***   ** *  ** *** * ** **   * **   *** ** * *** && i%a2==0){
  **          ****   *** ***   **  * *******   * ** *  * *****  * * *   ****      ** = i;
 **   ** **  ** ** ***** ** * **** ****  **** 
  **       * *   ***** 

 *** * **** ** ****  *   *** **     result;
}


int main(){

* *** * **  *   **  *    *  *      *  * **    * * *  *    * *  * ** *

****** ***  *  * ***  ***** * ******  *** 
*    ** * ** * * **  **  * * *    ** **



  ***  ** *     **** * * *     *****    ** *  * %d", GDC, LCM);
*  ** **   ***** * **     ****    *  0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
10 answers
Midterm Question 3 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 4.1k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 17.1k views
0 like 0 dislike
21 answers
Midterm Question 5 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 6.7k views
0 like 0 dislike
22 answers
Midterm Question 4 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users