1 like 1 dislike
5k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiplelowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(ab), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited

edited by | 5k views

36 Answers

0 like 0 dislike
Hidden content!
#include * ** * ** **
//gcd and lcm
int main(void)
{
** * **** * **** * ** n,m,i,gcd, j,k,lcm;
* * ** * * *** **** *** * *** * * &n, &m);
* * * * **** ** * * ** i<=n * **** i<=m; i++)
** ** **** ***** *** * *
* * **** * * * ******* ***** ** * * ***** ** * ** * * m%i==0)
* ** *** * * ** * *** * * * *** * * *** **** *** ** * * *** ***** ** * **
* *** * * *** *** ** **
** ** * ****** ***** ** * * * ", gcd);

** * ** ** ****** k>=n && k>=m; k--)
** ******* * *** * ***
* *** * *** ****** **** * *** * * * k%m==0)
* *** * * ****** ***** * *
*** ****** ****

* *** * ** ** * *** * * * *** ****** * **


** * ** * * * *** * * ** 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
* ** ** ** * * *** * a,b,tmp,x,y;
** ** ** ** * ** ** * *** * * %d", &x ,&y);
* * *** ** *
* * * ** ** **** * * *
*** * * ** * * ** ***** ** {
** ** ** **** * ** * * ****** * ** * *** **
* ** * * **** * *** ** * ** ** * **** *** **
** * * * **** * *** * * ****** ** * *
*** * * * **** * ** *** **
* ** **** ** ***** *** ** *** ** *** * %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
* * ** *** ***** * a,b;
****** ** ** *** * ** ** ** * gcd,lcm;
** * * * ** ** * ** * *** * * %d",&a,&b);

** * * **** * ** *** ag=a,bg=b;
* * * ** * * ** *** * * *** *
* * *** * * * ****** * * * ** * * *** ** * * * *
*** *** *** * * * ** ** * * temp;
** ** * * * *********** *** * *** * *** * * * bg=ag, ag=temp;
**** **** * **

*** * *** * * *** ******* * i=1,al=a,bl=b;
****** *** * **** *** ** al%bl!=0 ) {
* **** * * * * ** * * ** ** * * * * * **
* * ***** * ** ** *** ********* * * *** ** ****
* * * ** * * * *

** ** * * * * ** ** ** * *** * * %d",bg,al);
* * **** ** ** ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
*** *** ** * * *** * ** * * ** * ** ***** **
* ** ** * * * ** ** *** * * * * *** **** ***** * * *** *** **** * * * ****
* ** *** ** * * *** * ** * ***** *** * * * ** *********** * ** *** * * * **** ** * ** * * ** * *** * * * **** *
* ** *** ** ** *** *** * * *** ** * ***** **** *** * ** *** * * ** * **** *** *** * *** * * ** * *** * ****** ***** **
* * * *** * **** ** **** * * * * * ***** ** ** * **** *** * ******* *** *** * **** ** * ** ** ** * *** * ** * ** * * ** ** ****
* * * *** * * ** ** * ** ** * * *** *** ******** * ** ** ** * * *** * ** ***** * * * **** * ** ******* * *** * ",i);
** * * * ** * * ** * * ** ** * ******** * * *** * * * **** * * * *** * ** ** * * ** **** ****** * * ******** ** *
* ** *** **** *** ***** * * *** * * *** * ** * * * * ** * ** ** * * * **** * * * ** * **** *** * * ** * * * ** * *******
*** * ** * * ** ** * ** ** * ***
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
* ** *** *** * *** ** *** ** * **** ** ** * *
**** * ****** ** * * ** *** *** * * ******** * ** * ** *
*** * * * * ** ** * ** * ****** * ** * ** *
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
*** * *** * * * * ** * * %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
** * * * ****** ***** * * ** *** * ****** ** * *** ** ** * ***
*** ** **** ** ** ** ** * * *** * * *** ** (flagGCD1==0)
** ** * ****** * * * ** * **
* ** ** *** **** ** *** * * ** *** * ** * ** **** *** * * ** *
* * * ** ** * * * *** * ** * * * ** * ** ******* * ** *** (flagGCD2==0)
* * * *** *** *** * ** *** ***** * * ** ** ** * * * ** *
* * *** * ** * * ** *** * ** * *** *** ** * **** * * * * * * * ** ** * *** * ",i);
* * * *** ***** *** * **** ** ** * ** * ** ** * ** *** * * * * * * * ** *** * *
* *** * * * * *** ** * *** * **** **** * * * * * * * * ** ** *
* * * **** ** * * * * * *
    }

    //LCM
    for (j=1;j;j++)
    {
** * * ** ** * * ** **** **** ***** * *
* * * * *** * **** * * *** * ****** * * ** ** (k=1;k;k++)
** * *** * ** *** ** * *** * *** *
** * * *** * * ** ***** * * *** * ** ** * *** ** * * * * ***** ** **
* * **** ** ** ********* **** ***** **** * * * * *** ** * * * * (flagLCM2==flagLCM1)
** * * * ** * * *** * **** * * * * * * * * * * * **
* ** * * ** *** ** *** * * * ** *** *** * *** ***** ***** * * * * * * * **** ** ** * ** ** ** * * * * ** **
* **** * ** * * * * * * ** * ** ** * ** ** * ** * ** *** * * * ** ***** * * **
******* * ** * ******** *** * *** *** ** * * * * ** * ***
** * * * * * ** * * * **** * ** * ** **** * *** **** *** (flagLCM2>flagLCM1)
* * ** **** *** * * * ** ** ** * ** * * ** * * **
******* ***** * ** **** ** * ** *** * * * ** *** **** **** *** * ****** * *** ** ****
** * * ** **** *** * ** * * *** * ** * ** ** * * ** * *
* **** * * * * *** * * ** * * ** * * **** * *
* ******* *** * * * **** ***** ** ****** * (flagLCM2==flagLCM1)
*** * * * ** ***** * * * *** ** ******* *
**** ** **** * * *** ****** ** *** * * *** **** ** **** ** ***** *
* *** ***** * * * * * ** *** * * * *****
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* ** * * ** ** *** **** ** * * *** ** ** ** ******
* *** * ** * * ** * **** ** ** * * ** * * * ** ** * * *** * * ** * ** * ***
* *** * *** * ** *** * * * **** ** ** **** * * * *** * ** * *** * * * * * ** * * ** * * * *** ** **
**** * *** * ** * * * **** ******* * ** * *** ***** ** *** ** *** * ** ** * ** * * * *********** * ** ** *** ** * *
*** ** *** * ** * * ** *** * * **** ****** ** *** * ** * *** ** ** * *** * * * ***** ****** * * * * * *** * **** * **** * **** * *** ** *
************ ** *** * ** *** ** ** * * * **** * * ** * ** *** *** *** * * ** ** * * * * *** ** * *** * * * ***** *** *
* * * ** *** ** * ** * * * *** ***** ** ** ** ** * **** * * * * * ** ****** * * * ** * ****
****** ** * * ** * ** * * * * ** * ****** * **** * * * ** * * ** * * * ** * * * * * ***** * * * * *** ** *
* * *** ** * ** * * **** * * * * ** * * ** *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
**** ** ** * * * ***** * * *** * * **** *
** ** ***** * ** ** * *** ***** ** ** * * ** ***
* *** **** ***** ** * * * * ** ***** *
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
**** * ** *** * **** ** * a,b,smaller,i;

**** * ******* *** *** * * * * * * * * ** ** *

* **** * ** * ** ** * *****
* * ***** ** * *** * ** * ** * *** *** * * *
*** * * ** *** *
*** * **** ** * * * **** *** * ****** *** **** ******

******* * * ** ****** *** ** * *** * * *
* * * ** * * * **** **** * ** * * *** ** * && b%i==0)
* *** ** *** * ** **** ** * ** ** * ******* **** * * *** **

** ** ** * ** ** * ** ***** ** ***** * * ** * *** * %d",i,(a/i)*b);

* * * ** **** * ** * * ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
* *** * **** ** ** *** i,n1,n2,a,gcd,lcd;
***** *** * * ** ****
** * * * * *** * * * *** %d",&n1,&n2);
* * ** **** * * * *** ** *** * ** * * || i<=n2; i++)
* * * * ***** **** * * *
*** * * *** *** ** * * ****** *** * ****** ** * && n2%i==0)
* * * ****** ***** ** **** * ** * * * *
*** * ** ** * ** * * * * * ** * ** ** ** * **** * * *
* * ** ** * ***** *** ** * ** * ** ** * * *
* * * *** ** * * * * *
* ** ** ** * * *** ****** * && a>=n2;a--)
    {
** ** ** * * * **** ** ***** ** *** && a%n2==0)
*** *** ** * *** ** * **** * *** * *** ** * **
**** * *** * * ** * * * * * ** * ***** ** * * * * * ****
**** * * ** * ** ** ** ** ** ** *** ****** *
** * * **** * * ** **
* **** **** ** * ***** * * %d",gcd,lcd);
* ** * * * * ** ** * 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * *
int main (){
int i,j,k;
* * * * * * * *** ** *** *
* * **** *** ** * * * ** ***
** * * ** **
**** *** * * * * ** * * ** ** * *
** ** ** ******* * ** * *
* * * ** * *


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

*** * ** **** * ***** i;
* ** * *** **** result=1;
* *** * * **** * * * * * ** ** *
** * * ****** * **** ** * * * * * ** * **** *** && a2%i==0){
**** ** * * * *** * * ***** * * * * ** * ** * * * ** * * * *** * * ** = i;
* ***** *** ** ****** ** ** *** *** ****
* * * * *** ** *** * *

* *** ** * ** * *** result;
}
int Get_LCM(int a1,int a2){

* * ** **** *** * **** * i;
* * * ** *** * *** * result=1;
* *** * * * * * ** *** ***** *
**** ** ** ** * *** * ***** ** * ** * * * && i%a2==0){
* * * **** * ** ** * * * ***** * * * *** * * ** * * * ** = i;
** * ** *** * ** * * * ** * ** * ****** * ***** ****
* * *** ** * ***** *

** ** *** * ** ***** * ** * result;
}


int main(){

** ** * ** * * **** * * * *** * * * * * * * ***** **

* ** * * * * * * * ** * * ****
** * * * ** *** ** ****** * **



* * * *** *** * *** * * ** * * * %d", GDC, LCM);
* **** * *** * * * * 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.32
©2016-2025

Related questions

0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 2k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 8.8k views
0 like 0 dislike
21 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 3.4k views
0 like 0 dislike
22 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 3.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users