1 like 1 dislike
7.5k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiplelowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(ab), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited

edited by | 7.5k views

36 Answers

0 like 0 dislike
Hidden content!
#include **** **** * *
//gcd and lcm
int main(void)
{
* * * * *** * * * *** n,m,i,gcd, j,k,lcm;
** *** ** * *** * * *** ** **** * ** &n, &m);
* * * * ***** * * * i<=n ** ***** ** i<=m; i++)
* * * ** **** * *
** *** ** * ** *** ** * *** **** ** * * * **** * ** ** *** m%i==0)
* ** ** ****** * * ** *** *** ** * * * * ** **** *** * * ** * *** * * *
******** * * * ***** ***** ***
* * *** ** * * * **** * *** **** ** * ", gcd);

* * *** **** * k>=n && k>=m; k--)
* ** * * * ** **
* * * * * * ** ******* k%m==0)
* * **** * ***** *** *
* * * * * * * * *

** * ** * * ** * * ** **** * ** * ** *


* * * * ** * * ** ** 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
* ** ** * * a,b,tmp,x,y;
* * ** * ** ** * *** ** ** ** * * %d", &x ,&y);
* * *** ****** ** * ** *
* *** ** * ** ** * * **
* ** ** * * ** ** ** ** * * {
* ** *** ** *** * ** * * *** ***** **** ** ** * *
**** *** *** ** ******* ** **** * * * *
****** ** ** ** *** * ** *** ** *** *** * ** *****
**** ***** ** * * ** * * *
** ** * ** * * **** ** ** **** %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
** * * ** * ** ** * a,b;
* * ***** *** ** gcd,lcm;
*** * * **** ***** * ** * %d",&a,&b);

*** *** **** ** **** ag=a,bg=b;
*** * *** ** *** ** ** *** ***
** *** * ***** ** *** ***** * **** ********* * *
*** *** * *** *** ****** * ** ***** ** temp;
******* * * *** ** **** *** * *** * * * bg=ag, ag=temp;
*** ** * ** *** *** **

*** * ** * ** * * i=1,al=a,bl=b;
* ** ** ** ** ** * * * * al%bl!=0 ) {
* *** *** * * ****** ** *** * * * *** ** ** ****
* ** ** ** * *** * * ***** * * *** **** **
* * ** * ** *** * *** * *

* * ***** * **** ** ****** * * %d",bg,al);
**** **** * ** * * ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
*** ****** * * ****** ** **** * * *** *** **
** *** * *** ** ** * ***** * *** * * ** ***** *** * *** * * * *** ** * * *** ** * * * * **** **
** * * * **** ** ** * ** * * * * *** ** * ** ****** * *** **** * **** * * * * ** * ** ** ** * ** * * * * ** * * * *** ****
**** * *** * * * * *** ** ** * * ** * * ** ** * ** *** * ** * ** ** *** ** * ** ** * **** ****** *
** * * * ***** *** * * **** * *** *** ** *** ** *** ** ***** * **** * * ** ** ** ** ** ** * *** * * ** ***** * *** *
* * ***** * * ** ** * ** * ********** ******* * ** * * ** * * ** **** * * ** * * *** * * * * ** * *** **** **** ** ",i);
* * ******** ** * * *** * ** * * ** * * *** * ** * **** * *** * * ** * * * * * ** **** * * * * * ** * * ** ** ** * *
*** ** **** ** * * ** * * * * ** **** ******** * * * ** * * * * **** * * **** * ** ** * **** **** *
* * * ** * ** ** * ** ** ** *** * *** *** ** *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
* **** * * ** * ** ** * ** ******** * * ***
***** * *** ** * * * * *** * * * * * * * ** * * * * ** ****
* ** ** *** ** **** ** * **** **** * **
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
* * ***** ** ** * ** * ******* %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
* ** * ********* **** ** *** *** * * **** ** * *
* **** * * ** ** * * * *** * * * ** ** **** (flagGCD1==0)
* *** ** ** * **** * **** ** *** ***
** * * ** *** * *** ** **** * * *** ** ** *** *** ** *** *** * * ** **
** * ** * * ** * ** * * ** *** ** ******** * (flagGCD2==0)
* * * * * ***** * * ** * * ** ** * ** ***** ** ** ***** * * * * * * **
** ** *** * * * ** * ** ***** * ** * * * ** * ** ** * * ** ****** ***** ** ** ** ",i);
***** * * **** * * ** * * * * ** *** * * * * * ** * * * * ** * ** ** * ** ** ** * * * * * *
** ** * ** * * **** * * ** ** **** * ** ** * * * ***** *** * *** *
* * *** ** * * * **** * *** * *** * ** ***** *
    }

    //LCM
    for (j=1;j;j++)
    {
***** * ** * ** * * ** **** * * * ** ****
* * ** ** ** **** *** *** * *** ** * * (k=1;k;k++)
**** *** * * ** * * * * **** *** *** *
** * ** * ***** ** ** * * * ** * ***** ******** *** * **** ** ***** * **
* * ** * ** * * ** * * * **** * * * * * *** * (flagLCM2==flagLCM1)
*** **** * *** ****** * ** * * * * ******* *** * ** * **
** * ** * * **** *** *** **** * ** * *** * **** * *** * ** * * * ** ********* * ** ** * * ** ** *** *
** ** *** * **** * *** ****** ** *** * *** ***** ** * *** ************ * * * * ***
* ** * * * * * * * ***** * * * * *** ** ** *** * ** * * ** ** * * * ** *
* ** ** * * *** *** ** **** * **** ** *** * * *** * * (flagLCM2>flagLCM1)
* * * * * * * * *** ** *** * ** *** * **** *** ** ** * * *
* ** ** ** * **** * ** * * * ** * * **** *** * * * * * ***** **** * ** ** *** * *
** ******* *** * * * * ****** * * *** **** * * * * * *** *
* * * ** * **** * ** ** ** * ** ** * * *
*** * ** * *** ** * ** * * ** ** * * ** (flagLCM2==flagLCM1)
* * ***** * * * * ** * * * **
** * *** ** * ** *** * ** * *** * * * * * * * * *** * ** *
* * ** * * ** ** * * * * ** * ** ** *****
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* ** * * ** * **** ** * * * * **** ** * * **** ** * *
** ** *** * * * * ** * * ** ** ** * * * *** ** ** * ** *** * ** * *** ** * * *
* *** * ****** * * *** * * ** * * *** * ****** * * * * * * ***** * ** * * * * * ** *** * **** *** ** * ** ** *
********* * ****** ** ** ** * ** ** * *** ** ********* *** ***** **** ********* * ** * * ** ***** *** * ** * * * **** ***
* ** * ** ** * * ** * * * * ** * **** * * * * ** **** * ** * ** * * ******** * * ** ** *** ** ****** **** * * *
** * ** * * * ** * * * * * * * * ** * ***** ****** **** ***** ** *** * * * * ** ** * ** *** * * ** *
* ** ** ******** * ** *** *** * ** ** * ** *** ***** ****** * ****** ** * * ** *** * * * * * * ** ****** * * * * ** *
* *** ** * * *** * * * **** * * * * **** * *** ****** * * * * * ** ** * **** ** * **** * * * * ****
******* * ** ** *** * * * * ** * ***** * *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
*** ** * **** * * * **** * ** * ** **
* * ** * * ********* ** ** ** ** *** ** *** ** *** * **
******* * *** * ** ** * **** ******* *
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ** *** ** ** * *** a,b,smaller,i;

*** * ** * **** **** ** * **** * * * * ** * ******

* * * * **** * ** * * * * ****
* * **** **** ** * *** * * * * * **** * ***
*** * ** * ****
** ** **** ** * * ** *** * ** ** * ** * ** ** ****

******** * *** * ** **** ** * *
* *** **** ** * * * * *** * * ** *** ** ** * ** && b%i==0)
* * ** * ** * * * * ******* *** ** *** * ** ********* * ** * ***** * **

** * *** ** ** * * * ** * * * ** * * * ** ** ******** * %d",i,(a/i)*b);

* ** **** ** *** ** *** * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
* *** * ** * * ** * ** i,n1,n2,a,gcd,lcd;
* * * **** * * *** **
****** * * ** *** *** ** %d",&n1,&n2);
* * * * * ******* ** * * * * *** || i<=n2; i++)
* *** * ** *** *
**** * ** ****** ** ** *** * *** * *** ** * * && n2%i==0)
* ***** * ** **** * * * *** * * ** *****
*** * *** * **** *** *** * ** ** ***** **** * *** * ** * * **** **
* ** * * * * * ** * *** *** *** ** ** * * *
*** * ****** *** * ****
* ***** * * ** *** ** * * * * * * && a>=n2;a--)
    {
** ***** * * * ******* * * **** * * * ** && a%n2==0)
* * ** ** * * * ** * * * ** * * *
* ** *** * * * * * * * * * ** * *** ** * **** ** *
** * * ** ******* * * * ** * * *** * ***
* * * **** *
* ** * *** *** ** *** ** *** ** %d",gcd,lcd);
* **** * * * ** *** * * 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * *
int main (){
int i,j,k;
******** * *** **** *
* **** ** ** ** * **** ** **
*** ** ** ** *
********* * * * * * * **** * ****** * ** *
**** ***** * * * * ** *
* * ****** * *


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

* **** * ***** *** * * * * i;
*** *** * * * * * ***** * result=1;
***** ** ** ***** * **** * ***
*** *** ** *** ** * * * *** ** * * * * * *** && a2%i==0){
**** *** * ** * *** ** * *** ** * *** * * *** *** *** * *** = i;
** *** * * * ** **** ***** * ***** ****
** * * ** ** * *

** * *** *** ** ** * *** * * result;
}
int Get_LCM(int a1,int a2){

**** * *** *** * * **** i;
* * *** * * * *** * * result=1;
**** ***** *** ** ** * ** ******* ****
**** ** * * ***** * **** *** ** * ** * *** * * ** && i%a2==0){
**** * * * * ** * * * ****** * * * ** *** * **** ****** * * * * ** *** = i;
* **** * * * ** **** *** *** * * ** * ***
** ** ** *** *** *

** *** * ****** *** * * * * result;
}


int main(){

* * ***** * ** * * * ** * * ** * * **

** ** ** **** ** * ***** **
* * * ** ** * *** * ** ***



* * *** ** **** ** * *** * *** %d", GDC, LCM);
** *** **** * ** * *** * 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.71
©2016-2025

Related questions

0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 3.2k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 13.5k views
0 like 0 dislike
21 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 5.3k views
0 like 0 dislike
22 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 5.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users