1 like 1 dislike
3.5k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiplelowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(ab), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited

edited by | 3.5k views

36 Answers

0 like 0 dislike
Hidden content!
#include * * * * *
//gcd and lcm
int main(void)
{
* * * ** *** * n,m,i,gcd, j,k,lcm;
* ** ** ** * * ** ** * * *** ** &n, &m);
* * *** * ** * * * i<=n *** * ** ** i<=m; i++)
* ** ****** * * * **** **
** * * * * * **** * ** ***** ******** * * **** *** * ** * * m%i==0)
**** * ** * * *** ****** ****** * * *** * *** * * *** ** *
* ** * * ** * ** ***
*** * * *** ** ** *** * ****** ", gcd);

** * * *** **** ** ** *** k>=n && k>=m; k--)
* ** ** *** ** * * *
** * * * ** ** ** * * * ** * *** * k%m==0)
**** * * ** *** * * * ** * * ** *
***** * * ****** **

* * ** * *** * ***** * **** * * * **


** * * ** ** * * **** **** * 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
** * **** ** * * * *** ** a,b,tmp,x,y;
* * *** *** **** * ** * ****** * * %d", &x ,&y);
* * **** ** * * **** **
*** * * * *** **** ** *** *
* * * ** ** ******* *** * *** {
**** ** *** ***** *** * * * * * ** * *** ** ** * *
** * * ** * ** * **** ** * * * * ****** **
*** *** * * *** **** ** *** *** **** * ***** *** * *
*** * ***** * ** * **
* **** ** **** * ** * * ** * %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
** * * * * ** * a,b;
* * * *** ** * * ** *** * gcd,lcm;
* ** ** **** * *** * %d",&a,&b);

*** ****** * *** ** ag=a,bg=b;
* ****** ** ** *** * * * *** *
* * * ****** **** * * ** *** * * ** *** * *** **
*** *** * ** * * *** ** ** * * ** * *** * * temp;
** * ** ** * ** **** * * * ** * ******* *** bg=ag, ag=temp;
* *** * * ** * *****

** ** **** * * * * * i=1,al=a,bl=b;
* ** * * * * * ** al%bl!=0 ) {
** ** ** * *** * * * ** ** * * * * * ** *** **
* * **** * * * ** **** ** ** * * * * * **** *** ** *
** ** ** *** ** * * ** **

* * * *** * ** *** * ** ** * * %d",bg,al);
***** ****** * * ** * *** ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* * * ** * * * **** * ** * * *** * * ** *
** * ****** ** * * ** * * * *** * * * * *** *** ** * * * *** * ** *** ** *
* * ** **** ** *** ** *** * ** ******* ** * *** * **** * * * * ** ****** ** *** **** *** * * ****** ** * ** * ** * *** * * * *
** ***** * * * * **** ** * * * *** **** *** * ** ** *** ** *** * * ***** * * *** * ** ** * * * * * * * * ** ***
**** ** ** *** ** * * ***** * *** ***** * ** ***** * * ** ** *** *** * ** **** **** ** * ** **** * ** *** ** *********** *** ***
**** ** * * *** * ** **** ****** ***** * * ***** * ** * * *** *** ** ****** ** ** ** *** *** *** * * * * * * ** ** ** * ",i);
* ** *** ** *** * * **** *** * ** * ** * *** * * * ** * * ** * * * **** * ** * **** * **** ******* * **** *
* * ** *** ** **** *** * * ** * ** * *** * ** ****** * * * * ***** ** * * * * * * *** * ** * ** ** * *
* * *** * **** * *** ******* ** * * ****
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
** ** * * * * *** * * ** * **** ********** * **
** ** *** * **** * * ** ** *** ********* * **** ** * ** **
* * * * * *** * * *** ** * ** ***** * ******* **
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
* *** * ** **** * *** * * %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
** ***** * ** * ** *** * * * ** ** ****
**** * * ** **** *** * * ** ** * * **** ** **** * (flagGCD1==0)
** ** * ** * * *** * ** * ** ****** * *
* * *** * ** ** * ** * ** ***** * * ** ***** ** ** **** * * * *
** ** * ** * * * * ** * * * ***** * ***** ** ** ** (flagGCD2==0)
** ** * ** * **** ** ***** * ** * *** * * **** * *** * * * **
* * * * * * * ** *** * ** ** ** * ****** ****** ** ****** * ** * *** * * * * * * ** ***** ",i);
* * *** * ** * ******* ***** * * * *** * ** * * * * * * * ** * ** *** *** * ****** *** *** *
** * * ***** * * ** * * * ** ** ** ** * * ** * *** *
* ** ** ** * * ** *** * *** ******** *
    }

    //LCM
    for (j=1;j;j++)
    {
* ****** * * * ** ** ** ** * **** ***
**** * * * ** ** ** ********* *** * (k=1;k;k++)
*** * *** **** * ** *** * **** ******
* * *** ** *** * ***** *** ** ***** ** *** *** ***** * * * * ** * **
** **** *** ** **** *** *** * ** * * *** ** *** * * * * (flagLCM2==flagLCM1)
* * **** ** **** *** * ** ** *** * ** ** * * * **** ** ** * * * *
*** * **** * ** * ** * * * ** * * * * * * * *** * *** * ** * * * * * ** ** ** **
* * ** *** *** * * * ** *** * * * *** **** * ** * * *** * ** ******* * * *** * *
* ** * ** * * *** ****** ** ****** * * * * ***** **** *
** * ** * * * * * ***** ** **** * *** * **** * *** * *** * * ** *** * ** (flagLCM2>flagLCM1)
** * ** * * * ** ** *** * ** * * * * ** * * * * ** *
* * * * * ** *** * ******* *** **** ****** * ** ********* *** * * **** * *** **** ** * *
*** * * * * * ** ** * ** ** * * ** * *** *** *** *
* *** * * ** *** **** * *** *** * *
* *** * * * **** *** ** ** ** * *** *** * ***** (flagLCM2==flagLCM1)
*** ** **** * ** * * ** ****** * * *** * *
** * * **** ** * ** **** * * * * **** * * ** * ** **** * * * * *** *
*** * ** ** ***** *** * *** *** *** ** ** * *
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* *** * * * * * * * ** * * *** **
*** *** * * * * * **** *** * **** ** * * *** ******** * ** **** ** * ****
** **** **** * ** * * ** * ** ** ** ** * * **** * * **** ** * *** *** * ** ** * * * ** * ** * ** ** * *
** * ********* ** * *** * ** **** ** * * ****** * * **** ** ** ** * * ** * ** **** * **** ** ***
*** ****** * ** ******* ** **** ** * * * * ** ** ** ** *** * ** * ****** * ** ** ** * * ****** ** **** *** ** **** *** ****** ** * * * ***
* ** *** * * * * ****** * * ** ** *** **** ** * ** * ******** * * * * ** * * **** * **** * *** ** ********* ***** **** *** *****
* **** ** *** ** ***** ** * ** ** * * ** * **** * ** * ** ** * * ** ********* * *** * ** * ** * * * ** *** * *
** * * ** * ***** *** * ** ***** * * * *** * *** * * * * ***** * * * * * ** ** * ** * * ** * ***
* ** * * * * ** ** * * ** *** * * ***
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
*** * * * * * ** * * *** ** * * * *
** * ** *** *** ** ***** *** ** * ****** * * * * ** * * * *
* ** * **** *** ** ** ** *** * * **** * * ***
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * * ** ****** * ** * a,b,smaller,i;

***** * ** ** * **** * * **** *** * *********

** *** * ** * ** ** * * *
**** * * * ***** ***** * * * * ** * * * ****** * *
** *** ** * * ** *
*** * *** * * ** * ** * * * ** *** *****

***** *** ****** * ** *** *** * *** * * * * ** *
* ** * * * *** * * * * * ** * *** * *** * ***** * && b%i==0)
** ** * ** ****** * **** *** * *** * * ***** * *** * * ** * * * *** *

** * ***** * ** *** ** * **** *** * ** ** ** * * * * %d",i,(a/i)*b);

**** *** ** ** * ** ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
* * * * ** * * * * i,n1,n2,a,gcd,lcd;
* ** * * ** * * * * * ** ***
**** ** *** * ** **** ** ** %d",&n1,&n2);
*** ** * * *** ** *** ** * *** || i<=n2; i++)
* * * * *** **
* ** * *** * *** ** * * * * *** ** *** * ** * *** && n2%i==0)
***** * * * * * ** * ** * * *
* ** * * ** ** * * * * * ** * ** *** * *** ** *** * **** * * ** * * ** **
** *** * ** ** * * *** ** * ** * **
*** * ** **** * * ** ** **
* * * ** * * * * * * *** * ** && a>=n2;a--)
    {
* ***** * *** * *** * *** *** **** * * * ** * && a%n2==0)
* * **** ** * * **** *** ******* * ** * **
* * * *********** ** * ** * * *** ** * * * ** ** ***** * * ***** ** **
*** *** *** * * ** **** * **** ***** ** * *** * * **
* * * * * ****** **** *
**** *** ****** ** * ** * * %d",gcd,lcd);
** ************* *** *** 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ***
int main (){
int i,j,k;
* ** ** * * ** ** ****** * **
* * *** *** * **** * ***
* ** * ***
* ** * * * * * **** ** * * ** * * ** *
* * * *** * * ** **
** * ** * ***


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

* * ******** *** * i;
** **** * * * * ** * * result=1;
** ** ** * * * ** ** ***
* * *** ** * **** * * * * **** ** * * *** ** && a2%i==0){
* **** *** * *** * * ** * * *** * * ** * * ******* ** ***** *** ** = i;
* ** * * * * ** * **** * ** * *******
* * ***** *** ** *

* ** ****** ***** * ** result;
}
int Get_LCM(int a1,int a2){

**** ** ** * * * * i;
** *** * * *** * ** result=1;
***** * * * *** *** * * * * ****
* * * ** * * * * ** ***** * *** * ** **** *** *** ** && i%a2==0){
** * **** * ***** * **** * * ** ** *** * * * * * *** *** * *** = i;
* * * ** ** ****** * * ** * * ** **** *
**** ** ** ** ** *

* * * * ** *** * ** ** *** result;
}


int main(){

** * **** ** *** * ** * ***** *** ***** * * *** * *

*** ** ** * **** * ** ** *****
** ** ** ** * *** ** ** ** * ***



**** * *** * * * ** **** %d", GDC, LCM);
* ** *** * * ** 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.148
©2016-2025

Related questions

0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 1.4k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 6.4k views
0 like 0 dislike
21 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 2.5k views
0 like 0 dislike
22 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 2.6k views
12,783 questions
183,443 answers
172,219 comments
4,824 users