1 like 1 dislike
6.5k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiplelowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(ab), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited

edited by | 6.5k views

36 Answers

0 like 0 dislike
Hidden content!
#include * *** *
//gcd and lcm
int main(void)
{
* ** ** *** * * n,m,i,gcd, j,k,lcm;
* * *** ********* ****** * ** ** * * * ** * &n, &m);
*** ** * * * ** ** * ** ** ** i<=n * i<=m; i++)
* * * ** ** * *** * *
* *** * * * ****** * **** ** ** * **** * ** ** ** * *** ** * ** m%i==0)
** * * * * *** ** * * * ** * ** * * * *** * * * * * * ** ** ***
* **** * * **
* * * * ** * * * * ** ** ", gcd);

** ***** ** * * * * * k>=n && k>=m; k--)
* ** * *******
* *** *** * * * *** * * *** * * * * * * *** k%m==0)
* ** * *** ******* * * *
* * * * **

* ** ** * * * * *** *** * * * * * * *


**** * ** ** * * * * 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
**** * * * * *** * a,b,tmp,x,y;
** * ** * * * **** ** ** ** ***** %d", &x ,&y);
* ******** ** ***** * *
* ** *** * * *** *** *
* * * * * *** * ** * * **** {
*** * * ** ** * ** ***** * ** *** ** ** ** * ** * * *
** ******* * * * *** * * * * ***** ** ** ** ***
***** * * ** * * * ****** ** ** * *** * * ****
** * * * ** *** *
* ** * ****** ********* * *** %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
*** *** ** ** *** * * * a,b;
* *** *** * ** ** *** * *** *** gcd,lcm;
* * ** ** * * * * * ** * ** ** * * %d",&a,&b);

* ** ** * ** *** * ag=a,bg=b;
** ** * *** * ** * ** * *******
** * ** * ** * ****** ****** * * ** * ***** ****** * *
* ** ** ** * * * * * ** * ** * ***** * ** * * temp;
** * ** **** ** *** * ** *** ** ** bg=ag, ag=temp;
* * ** * ***** * *

** * ** ** * * *** *** i=1,al=a,bl=b;
* *** *** * ** * ** * ** al%bl!=0 ) {
* * ** * **** * * * ** *** * ** * *** * * *** **
* * * ** * ** * * *** * ** *** * *
* ** * ** * * * **

* * * * * *** ** **** * ** * %d",bg,al);
* ** * **** ** ********* * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
**** ** *** ** ********* ** *** ** * * **
* * * * ** * * * * ** * ** **** * ** *** * ** * * **** * * * * **
* * * * * * *** *** * *** * * *** *** * * * * * * * * * ** **** * * * ** * * * * * ** ** * * *** * *
** **** * * * * * ***** *** ** * * ** * * * * * * * * ***** * * **** *** * **** ** *** * **
* ** *** * * * * * * ***** **** *** ** * * ** ** *** ** ***** *** ** * ** **** *** *** * * *** * * **** * * * **** *** * ****
* * * ** * *** * * * * * * * * ** * * * *** ** *** * ******* ** * ** *** *** ***** ***** * * * * * ** * ** * ** ** * * * ",i);
** ** * ***** * * * ** * ** * * ** * ** ** * * * **** ** ***** **** *** * * * * * * *******
* ** *** ** ** * ** ** * *** ***** **** * * * *** **** **** * * ** * * * * ** *** * * ** ** * ** ***** **** * ***
** **** * ** ***** * ** ** * * * * *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
* * ** * * * **** *** ** ** ** ***** ** ** **
* *** ** *** **** ** **** * * * * * ** **** * * * **
** * *** ****** * * * *** **** ** *
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
*** * * ** * * **** * ** *** * * * %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
* * * ****** *** *** **** * **** **** ** * * ** * ** *
* * * ** * * *** ** * * ***** * ** (flagGCD1==0)
** * ** ** * ** * * * ** **** * *
* ** ** ******* * ** * *** * ***** *** * ******* ** ** ** *
* * *** ** ** * * ** * * * * * * * * * *** ** * *** * **** * * ** (flagGCD2==0)
* * * * *** *** * * ** ****** * * * * ** * * *** *** ****
** *** * ** * * ** *** ** ** * * ** ** * ** * ** * ** * **** * * ** * * * * * * * * * * ",i);
* * * * * ** ** ** * * ** * * * ** * ***** * * ** * * ** ** *** *** * *** *
***** * * * ** ** * * ** ** * * **** ** ** * ** * *** **
* *** * ** * ***** ** ** *** ** ** ** *** * *
    }

    //LCM
    for (j=1;j;j++)
    {
*** ** *** * ** * ** ** * ** * * ** * *** *** * *
*** * * * ** * * * ** * * (k=1;k;k++)
***** ** * * * * * * ** *** * ** * **
* * * * ***** *** * ** ** * * ** *** ** ** ** ** * ****** *** ** ** * **
* * *** **** *** *** ** * * * * * **** **** *** * * * * *** * ** * (flagLCM2==flagLCM1)
* * * ** ** *** ***** *** ** * ** **** ** ***** * * * * *** * ** *
* *** * * * *** * ** * *** * * * * ****** *** ** * ** ** ** * * * ** * *** ** *** * ** * * *
* * ** * * ** *** * * ***** *** *** *** * * ** **** * ***** ** * ** *** ** ******** *
* * ** * ** * ** **** *** * * * **** *** *** * * ****** ** *** * *** *
*** * *** ** **** *** * * * ***** ** * ** * ** * *** * *** * (flagLCM2>flagLCM1)
* ** ** * *** *** * * * * ** ***** * *** * * * *
*** * * ** * ** ** ** * ******** * *** * * * * * * **** * ** * ** * *** ******** ***** *** * *
* ** * ******* * * * ** * * **** ** * ***** * ** * ** * ** * * ***** **
* * *** ** ****** * *** ** ** ** *** *****
* ** * * * ******** * * * * **** * (flagLCM2==flagLCM1)
* * * *** ** ** *** ** * ****** * *** *** ******
* ***** * * ** ** **** * * * * * * **** * * ** ** * *** * *********
** * * **** * ** ** * *** * ** ***** * **
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
** * * **** * ** * * * **** * * * ** * *****
*** *** * * * ** ***** ** * **** *** * *** * * * ** * * * *** * ** * * *
*** ** ** * ** * ** ***** * **** ** ** ** * * ***** * ********** * **** * * * * * * * * ** * *** ** *** * ** **
* * * * * * * ** *** ** ******* * ** * *** ** * *** * *** ****** ** * * * ** * * * *** * ** *** * * * * * ** * *
* * * * **** ** * *** ** * * ***** ** *** ** ** * ** * ** * **** * ** ** * * ****** *** * ** * * * * ******* ** *** ** **** * * ** **** * * *
****** ** * * * ** * **** ** * * ** * ** * **** * ** * * * * ** * *** ** * * * ** * ** **** * * ** * * ** ** * * * *
* * ** * *** ** * *** *** * **** * ** *** * * * ** * *** **** ****** * * *** *** * ** * * * * * *** ** ** * * * * *
**** * ***** * * ** *** ** *** ** * * ** ** * * * * * * **** ** *** * * * * *** ******* * **** **** ** * ** **
** * * ** ***** ** **** * **** * ****
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
** * ** * * ** *** * ** **** * * * ** *** *****
******* * * * * * * *** *** * * * * ** ***** * *** *******
* ** **** * * * * *** * ** * ****** *
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** **** ** ** * *** ******** a,b,smaller,i;

* * * **** * *** *** * * ** ** ** * **** * ** *

**** *** *** * **** * * ** * **
* ** **** ** ** *** * * * * ***** ** ** ** * ***
*** ** *** ** * * * ** *** **
* * * **** * **** ***** * * ** * * ** * * * *

* * * ***** * **** * ** * ** * *
* * * ** * ***** * * * *** * * * *** * *** * && b%i==0)
**** ** ***** *** *** * ** ***** * ** * ** * ** * **** *** ***

** * *** ****** ** **** ** * * *** * * * * * *** ** *** * * %d",i,(a/i)*b);

** * ** ** * * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
* * ** ** * * * *** ** i,n1,n2,a,gcd,lcd;
* ****** * ** * **** * **** **
* **** * *** ***** * ** * %d",&n1,&n2);
* * *** * * * * ** * ** || i<=n2; i++)
* * *** ** ** * *
* * ** * * * * * * ** *** * * ******* ** && n2%i==0)
** * * * ** * * *** * **** **** ** ** * * * **
** * ***** * * * *** * * * * * * * ***** ** ** * ** *** ***** ** * ****
** ** ** * * * * * * ** * *** * * * * *** *
* * *** * * * ** ***
*** ******* * * ** * *** ** * * && a>=n2;a--)
    {
* * * *** *** ** * *** * ** * * *** **** * * *** * * && a%n2==0)
** * * **** *** ******* * * ** ** * * **
* ** *** ** * * ****** ** ** ***** * ***** *** *** * *** * * *** ****** ***
*** * **** * ** * *** ******** * * * ** ** * * *
* * * * * * *
* ** * ** * ** * **** %d",gcd,lcd);
* *** ** * * ** * * * 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** **** * ***** *
int main (){
int i,j,k;
** * * ** * **
*** **** ** *** **** **
** ****** ***
* * ** ** * * ***** * ** * * ****
* ** * * * * ***** * *
* * * * *****


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

* * ** * * * * * i;
** ** **** *** * ** * ** * result=1;
* * * * ***** ** * * * ** ** * **
*** ** * * * **** ******* * * * * ** *** * *** && a2%i==0){
* * **** * ** * * ** *** *** * * **** * * * * ** ** * * = i;
** * * * * ***** ** * * **** ** *
* * * * *** * *

*** ** *** * **** * result;
}
int Get_LCM(int a1,int a2){

* *** * * ***** * i;
* * * * * ** * * * ** result=1;
** * * * ***** * * * * ** **
******* * *** **** *** *** * ** ** ** * ** ** * ** && i%a2==0){
** * * * *** ** ** * * * ** * * ** ** * * * * ** **** *** * * * * = i;
**** ***** * * * ** * * *** * * * * * **** * * *
* ** * ** ** * ** *

* * ** * *** * * * ** result;
}


int main(){

** **** * * * * * * **** *** * * * * ** *** ** * **

** * ** * *** ** *** * *
** ** ** * * **** ** * *



* * * * ** * * ** %d", GDC, LCM);
* ** * * **** **** ** 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.190.141
©2016-2025

Related questions

0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 2.6k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 11.7k views
0 like 0 dislike
21 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 4.5k views
0 like 0 dislike
22 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 4.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users