Midterm Question 3

1 like 1 dislike
5k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiple, lowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(a, b), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited
edited by | 5k views

36 Answers

0 like 0 dislike 
Hidden content!
#include **  *     * *   
//gcd and lcm
int main(void)
{
* * * **** * *  *   * * * n,m,i,gcd, j,k,lcm;
 * ***   ** *   **** *** *   **  *   * *  &n, &m);
 *    *  ***  *   * * *** **   * * i<=n **  ****    i<=m; i++)
 *  ***   *****  ** **
 * ***    *** * **** *****  * **   **  ** **  ** * *  *  * ** *  **   m%i==0)
***  **  **      *  * *      *     ******  *  * *    *   *  *** ***  ****
*   * ****** *   ***    *
**   * * * **** * *  * *   *  *  *** ", gcd);

** *** * **  * * *   *****   k>=n && k>=m; k--)
     *****     *   ** * ** *
  ** *     ****  *       *** *  *   **** *     k%m==0)
*   * **  **** ***   *** *
 *   **** **   * * * 

 ** * *  ** *** ****  *** ***  ** *** *  **     * 


    ** **   **  *       *****  * * 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
****  *    * **      **  *  a,b,tmp,x,y;
 * * *** * ****    * *       * *  ***  *    %d", &x ,&y);
  *** **  ***** **  *   ** * 
 *** *** *  ***    *   ***** *  
 *    * *  * *   *  *** ***    **** {
 * *****  * *    ** * * * * **  * ***** **   *  *  * ***  **  
**    *  **  *** * **  ********   **  * *   *  * ***   *  * * *   ** 
* *** * * **  *** **   *     *****  ** * *   *** * *  *   *
* **** **  *  * *  * ** * 
*  * ********  *      **  ***  *     %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
** * * ** ** **    * **** a,b;
 ****  *  *    * *   **     ** gcd,lcm;
  * ****** ****  * **** ** * ****** ** * %d",&a,&b);

*** *  ** *** *   *****   *   * ag=a,bg=b;
  *   **    ******  **   *  * *   ** **   * 
** * *    ** *    ** *** ****** ** * *  * ** **** **   *** **
 **  * ******     * *** ***** **** * **    *  ** * * *  * * temp;
  *   * ** **** ***  * *    *  * *  ** *  ** ****   **   * bg=ag, ag=temp;
******* *  *  ***  ** * * 

**  * *  ****    * ****  *    * i=1,al=a,bl=b;
 *      *       *  * *  *  **** * al%bl!=0 ) {
  *** ** ***   ***   ***  *  **   * * **  *   *  ** **       ***
**  *  *** *   * *   ******* ** **** * ** *** ***  ** *** 
    **    ********    ** *   

*     ***   * *    * *     *   **** ** %d",bg,al);
     ** ** *   *  * **  *   0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
     * * **  *    * *  * *     ***  *** ** *  ** *    
 ***** ** *  *    * *   ** ** *** ** ***  * *****     * *  * ***   *   * * ** *   *     * *** *******    * **  *
*   ******  *    **          *  ** *   *   * * **    * ***  ***** * ***** ** ***   * ** ***** **     * *  ****       **  * ***  *  * * ***
* * *** * *** * * *    *   *   * **    * * *** * ***  **** * *   *  * * **    * *  *        *  ** **    * * *   **** ** ***  **  **   * *  *****
****  *** *** *    ** *** *  *** *  *  **  ****      * *****    * *****     * ***   ****  *** ********** *  * * **   ***    * * *   *   ****   ** ** **
** *      * *** *   **** * * * * ** ** ** ** **   **   *      *  **  * ** *  * ***  * ***   **   * **    *** **    *  *   *  **    *  * * * **   ** *****       ",i);
  *********  ****     ****   ** ****     * **     * *    * *   ****   ** * * * **   *   *    ** ***  * ** *   ** *  *  * *  *   *  ***** ****
* *   *  *  *  **     *  *  * ** *** **** * *    *  ** *     *** *    *  ******   * ** *   **  * *  *     *  * *  * *  **  *  ***   * **** 
**  *    *  * **** ****    * **  ***     * *** *  
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
** **   ***   * **  **      *****    *       * * ** 
 ****          * **** * ** ** *    *  ** ***   *  ** *  *   *** ***    *** *    * *
   ** *   **   **** ** ******      ***  ***  *  *  *      * 
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
 ** **  * **  **   ** ****  **  *   %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
* *** *  *  *    * *  **   ** * ***  **     *   *********
***  *   * * *  * **  *  ** * ***    * **  *     * *  (flagGCD1==0)
**  * ***  **** *   *****     ** **  **   *  ** **** 
***   ** ***** ** ** * ****    * * *****  * ** * **** *  *** ***  ** **   *   * *
  *  * *   **  *  * *    *  **   **   *    *  * *   * *   *   * ** * **     (flagGCD2==0)
 * *** ** *  **  *     ***********        * *** *  **** ** *****   **   ****  *
****  * **** **  ***    ****    **   *   *    * * * * **  ** *   *    * *   ***** *** *** *   * ***  *  ****    **   ",i);
 ** ** **** ***   *  *   *  ***  * ** *  * *     * * **   *****  **    *       * *** *   *  *  *** * **   **    *  **
* ****  *  ** ** * *  * *  *  * ** **** *  **  *** *  **  **  **  *** * * 
*  ****  ** ** *  * * * **  ** * ***** * * ***** ****   ** 
    }

    //LCM
    for (j=1;j;j++)
    {
***** * * *  *  * * * *  **  *   **         *** * *  * * *  ** ***
****    * **    * **** * * ***  *** *      **  ** **  * * *** **  (k=1;k;k++)
**** **   **       *    *     **** ****     **   ***    ****
   ***     * ******** * *  * ** ** *   ** ** *  ** **   *  *  *  *    * *  *  ***** 
**   **     ** * *** *   ***  * ***   ***    **   **    *****    ** **    *   **** * (flagLCM2==flagLCM1)
  *  * * **      *   * ** ** *** *      **** ***  * * **       *   *  **
** *****  *****     ***    **    * ** *   *  * *** *  ****** *  ** * *  **** *  ** *** ***  *  * * ***   **   **   **  **** * *  * * *** *  ***   
 **   **** * **  *** **  ** **    *****   **   *  *** * * *    * *  **    * *  *  ** *  ***    ***** **
*******   *    * ***  * **** ** * **  * ** **** *   * *  * *   ***  ** ***  ***
 *  ****   * * * ****   *  *    * * *****   ***  * *  * * *** *   *   * **  ** ** (flagLCM2>flagLCM1)
** ** *  * *  *  **** **  **    ***  *     **     ** ***  ** * ***  ** **** ** * *** *
 * **  *  ** ** * ****   * * * * * * * * * *  *  * **   * *  * * *   * **   ***  **    **  ** ** ** *   * *   *  
 *  ** *   ** *******        **   * ******  *    *   * ***  ****   * **   *   *
     ********  **** ******  *    **** ** *  ***** *
  **     *** ****        **** ***  **     * *** *  (flagLCM2==flagLCM1)
* **    ***** *  ****  *** *  * * * * * *  *   **
* * *****  ** **   * * *  * *  *  *****  *    *  *** *  *     *   *  *** *    **  ****    
*** * * * ** ** **** **   *** ***    *   *      *****
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
*** *** * *****  * ** *   *** *  ***   * * *******
**  ***  *** ** **  * **  ********    *   *** ** *      **  ** *   **    *    **   ***   ***  ** **   * *******    
* *    * *  ******   * *   * * ****** ** ***** * * **  ** * *      * *    *    **  *    ** ******* * ** ** ** *   *   * ****     **   * *  *  *** **   **    * 
**       *   *  *** * ** *   ***** * *  ** * **** ** * *  * **** ** * **  ***  * ** ** ******  *  **  *** *  **    * *** *** **    **
** **  * *** ** * ****** * * * * *  **  ** * ***  *** *    *    ** ***** * *   * ****  *  *  * *  ***   ****** *   **** ***      ** *   ** *  *   *** * * * *   **    *
  * * **     ** *   *  * **      ******  *  *    * *     ** *     * * ** **   **  **** *** **  **   *       * **     *   ** *  **  * **  * ***     * ** 
   * *  *    * *  *  *  **  *  ** **     *    ** ** ***   *** *  * ** *   **  ***    *   *  * ***  * * * * * * ***   *    ****  **  **  *** * *  
* ***    **  * * *** **   **   ***  *** * *** **  ** *  * ** ***  * **    * ****  *   *** **    *    ** **   * ***    *  ***    *  *  
* *      * *  *** **  **  * * * **    *** * 
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
**  ** *  *     * ** ***   *** *  ** *****      ** * *
** * **   * ** * ***  **  * *   ** ***  **** *  ** *  * * ** *** ******** *  **   
** **  *    **   *  *    ******   * ** *    ******* **  **
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
  *** ** ** * **   *    *** a,b,smaller,i;

 * *    *  ** * *  *    ** **      **   *  ** * **** *   * ****** * *

 ** * * ***   ****  * ** ** ** *   *  *  **
 ** ** **** **  * *  * * *  *    *  * ******* * *  ** * * 
    *   * * *** ***** ****  * *  *
*      ****   ****    *  **** *   ** **  ***    * ** * *  *

* **  **      * ****        *** **** ***** ***   
*******       *     **  * *  *******  ** ** *** ***  *  *  && b%i==0)
****  *  ** *  * * **  **        **  *** **     *       * * *  * ********** * ****  

***     **    * * * **     *** * * ****  **** ****** **   **  *  ** **  *** %d",i,(a/i)*b);

 *  ** *   * * ** *    **** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
***    * *    ***  **  ** ** * i,n1,n2,a,gcd,lcd;
*** **  *** *     ** * *****      * 
  * *    *    ***    * * * **   *     * ** %d",&n1,&n2);
** * ****   **   *** *  **  ** *   *   || i<=n2; i++)
 ** *****  * *** ** * *  *   
   ***    *****  ******   ******** ** *    **   *  *** ** **  ***  * && n2%i==0)
  * *  ** **  **** **** **  **  * *   *  * *    ** 
**** ** ***   *** ** ** *  ** ***   *  * ******** *     *     ****    *****  ** ******* ****
*   **  *  **        ***** **  * *** * *  *  **** ** *  
*    ** * * ** *** ** *
 *  ** *  **  *  *   *     * * ** **** * * * && a>=n2;a--)
    {
** ******    ****  * * *  * ** *  ***   **   **   *   **  ****   && a%n2==0)
 *  *   ***** **    **** *  * ***   *** * *  * ***
**    *  *  ***    * * ***  * *      *   * * **    ***   *  * **  *** ***  ** 
 ***     * * *   *** *  * * **    *** ******** **   
* **  ***     ** ** ** ****
* * ***   *   * ** *  ** ***    * *      %d",gcd,lcd);
 *** **  ********* *  ** *  *  0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  **   *  * *
int main (){
int i,j,k;
 **  * ** **   ***  *  ***
** * **  **   * * ***  *  ** *    **  
**   * ***  *     
 *** * **  ****  **  * **** ***  **   *  *** * * *  *  *  
*  *** ***   ** ** * * *    * 
**       * *  **      *


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

  * *  *  * *  *       *      i;
  ******     *  *   **  * * *    * result=1;
*   **   **   * *     * *** ****   ***** ** 
 *  ** * *   *   * *******    * * *  **  * ***** * ** ** && a2%i==0){
 ***  **  * * ***** *  *   *  *       *  ** ** **  **     * ****     *  ***  ** **   * = i;
 **   ** **   * *     * * *** ** ***   ***  **  *** *
**** ***  *** *  * *  * ** * ** 

*** *   ** ** *     ** **   **   result;
}
int Get_LCM(int a1,int a2){

    **** *** ***    **   **  * i;
**      *  ****** *   *   result=1;
 * ** *** ********** * ** * *    ** ** *** 
  ****     *** ** * * **  **** *   *** *     * ** * * *** * * && i%a2==0){
**** **     *********** **** **  * **  **  * *   * ** ** ** *   **  *   * ****    * = i;
   ***   *    **  * *  *  ********  *  ** *    ** 
**  * *    *       **   ****

 * * * **   **   **  *  * result;
}


int main(){

* * ** ** ***   *****  ***   ****** **   ** ** * ** ** *  * **

  ** *    * * * * *   *    ***   ** * 
***  *** *** *  *** ***  **   ** * *  



***     *  * *** ***    *   ** * *****  %d", GDC, LCM);
**   ** ** ** * ***  ***    ** 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.39
©2016-2025

Related questions

0 like 0 dislike
10 answers
Midterm Question 3 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 2k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 8.8k views
0 like 0 dislike
21 answers
Midterm Question 5 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 3.4k views
0 like 0 dislike
22 answers
Midterm Question 4 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 3.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users