1 like 1 dislike
9.3k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiplelowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(ab), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited

edited by | 9.3k views

36 Answers

0 like 0 dislike
Hidden content!
#include * * ** ** **
//gcd and lcm
int main(void)
{
** ***** *** **** * n,m,i,gcd, j,k,lcm;
***** ** *** * ** * * * * &n, &m);
** ** ** ** * * ** * ** * i<=n ***** i<=m; i++)
* * **** * * **** * ** *
* * ** **** *** * *** * ******** * ** * **** ****** *** m%i==0)
** *** ** *** ** * * ** * ** * **** * ** ** * * ** **
* * * * ** * * ** * **
****** ** ****** ** * ****** ", gcd);

* * * * ** ** ** ** * k>=n && k>=m; k--)
* * ** ** * * ** * * **
* ***** * * ** * * **** * * * * * * * k%m==0)
* ** ** ** **
* * ** ** ** * **

** * ** **** * ****** * *** *** ******


* * * * ** **** ** * * 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
* * ** * * * * **** **** *** a,b,tmp,x,y;
* * * ** ** ** * * **** * %d", &x ,&y);
**** ** * * * * * * * * ***
* ** **** *** ** * *
* * * ** ** *** ** ** ** {
* * * ********* * * ***** ** * *** ** * *
* ** * * ***** * *** * * *** * * *
* *** * * ** ****** * **** ***** * * * ** * **
* ** ** * * ** * **
* * *** * * ** * ** * * * ** **** ** * %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
* * * * **** * * * * a,b;
** ** ** ******* *** gcd,lcm;
******* * ** ** ** ***** * ** %d",&a,&b);

**** ** **** * * * * * ag=a,bg=b;
** ******* * * *
* ** * * *** *** * * ***** * * ***** * * *** ****
** * * ** * ****** ***** ******* * * ** temp;
*** *** **** *** *** * ********* ** ******* * ******* **** ** bg=ag, ag=temp;
* ** ** * ** ** * *

** ** ** ****** ** ** * i=1,al=a,bl=b;
* ** * *** * ** * * * * al%bl!=0 ) {
** *** * ** * * * ** ** ***** ** * * * * * *
** ***** * ***** ** ** *** ** ** *** * *
** * ** * ** * *

* ** ** * * * ** * **** ** ** * %d",bg,al);
* * **** ** * ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* * * ** *** * * ** * ** * * * * ** * *
*** * * * ** *** ** * * ******* * * * *** *** * * * *** *** ** **
* *** ***** * *** *** ** * * * *** ***** * ** ** ** * * ******** ** ***** * *** *** * * * * * * * * * * **** **** *
* *** **** * * * * ** * * * ** * ** * ** ***** ** * * * * * *** *** * * * * * * *
** **** * * ** * * * * ** * ** **** ** * *** * * * * ** * ** * * * ****** * ** **** *** ***** * ***** * *** *** * **** ** *** * ***
* ** * * ******* * * **** **** **** ** * * **** ** * * *** * * * * ** * * ***** ** ***** * * *** * * * * **** **** * ",i);
** **** ** *** * ******** *** ** ** * * * * * *** ***** * * ** ** ** ** ** * * * ** ** * * ** * * * * ** *** *
** * * ** ** * **** *** *** **** * * * * * * * * * * * * ** ** ** *** **** * * *** ***** ******* * * ** * * * *
** * *** * * **** **** * ***** * * * **
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
* ** ** * ** ** * *** * * ** *** *
** * **** **** * * * * * *** ** * ** * ***** *
***** *** * *** * * * * * * * * ** * ** *
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
** ** * ** * * **** * ** %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
* *** * * * * * ********* ** ** * ** * **
* ** * * * * ** * ****** ******* (flagGCD1==0)
*** * * *** **** * * ** ** * * * * **
* * ** * ** * * * * * * * * * * * * *** * * *** ** ** * ** * * ** * *
* ** ** * ** * * * * *** **** * ** * * * ***** ** * ** * ** * **** * * (flagGCD2==0)
* * ** ** * * * ** * *** * **** * * * * *** ** *** **** ** * **
* * *** **** * * *** ******* * ** * * *** * * ** * ** ** * ** * * ** ** * ** ** * ** ** * * ",i);
**** ** *** ** *** *** ** * * * * **** ** * * * ** * ** * ** *** * * *** *
* * ** ** ******** * * * **** * * * * * * * ** * ****** ****
** *** *** * ** ****** * ***** * * ** * * * ** * *
    }

    //LCM
    for (j=1;j;j++)
    {
**** ** * * * * ** * ** * * *** * * * ****** ***
* **** ** ***** * * * * *** * * * **** * *** (k=1;k;k++)
*** *** * ** * ***** * * ** * ****** ** ** ****
** ***** *** ********* * ***** * ** * ***** * * ****** *****
* ** * ** ******* ***** ** * * *** *** **** ***** *** * * (flagLCM2==flagLCM1)
* ** * **** ** * ****** * *** *** * ** **** ** * *** * **** * *
* ** * **** * ***** ***** *** * **** ** * *** * **** ** ** ******* ** * **** ** * * **** * * ** **
* * * ***** * ** * * ** * ** ****** ****** * * * ** * ** * * *** *** ** ****** *
***** * * **** * * *** ** * ** ** * * * ** *** * * * * * ** * *
* * * *** * ** * ** * ** **** * * * ** *** **** * * ** * ** * **** (flagLCM2>flagLCM1)
* ** * **** * * ** ** *** ** * * * * ** * * ** * * *** * ** * **
** ** ** ** * **** *** *** ** * * * *** * ***** * * ** * * ***** * ** **
**** * *** * * * ** * * *** * * ** ** ** ** * *
* * * ****** * ***** * * *** ** *
** * * **** ** * **** * ** ********* * * ** **** * (flagLCM2==flagLCM1)
* * * * ** *** ** ** * *** *
**** **** * ****** ** * *** ** ******* * * ** *** *** * * * ** ** *
*** ****** * * ** ** * ** * * * * *** * *
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
******** * *** * * * ** *** *** * ****
** **** ***** ** * ** * ****** * ** * * * *** ** ** ** ** *** ** ** **** *** * * ** ** *
* * * ** ** * * **** ** * * ** * **** ** ** * *** *** * ** ******** * ** ** * ** ** ** ** *** **** *** ** * ** * **
* * * *** * * *** ***** ** * * * * *** * ***** ** * * * * * ** ** * ** * *** *** ** * ** ***** ** **** ***
*** *** * * ******** ** **** * * * ** * * ** * * ** ****** **** * *** *** * *** * ***** * ** *** * *** *** * * *** ** * ** * *** ******
***** * **** * ** ** * *** ******* ** * * * * ** ****** * ** * ** *** * ** * * *** * * * * *** * ** ** * * ** * ** * * * ** *
**** *** * ** * * *** **** * ****** *** * ** ** **** * * * ** * *** * * **** ** *** * ***** * *****
* *** ** * * * ** * * * * * * ****** ** * * *** * * * * ******** * *** ** ** * * ** *** ** * ** ** **
* **** * * *** * ** * **** * ** * *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
***** *** ** *** *** * * * * ******* *
***** ** ** * ** * * *** * *** ***** ** ** ** ** ** *********
* * * *** * ** * * *** ** * ** * * ** ** *****
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** *** * ** **** * * a,b,smaller,i;

****** * * * * **** * ** ***** ** ** * ****** *** * *

* ** **** *** *** ** **** ** ** ** **
** * * * * ** *** *** ** ***** ** ** **
*** * * * * *
** ****** *** ** ** ***** ** ** ***** ******** *** **

* * ***** * * ** * * * **** *
** * * **** * * * **** ** *** * * * ** **** * && b%i==0)
* ** * * * * ** * * * * * * * *** * *** **** * * * * * *

* * ** * * ** * * * **** * **** *** * ** ** ** ** * ** * %d",i,(a/i)*b);

* * * ****** * * ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
**** * * ****** * * * ** * i,n1,n2,a,gcd,lcd;
** *** **** **** *** * *******
* *** * ** *** ** ** * * * %d",&n1,&n2);
* *** *** * * **** * ** || i<=n2; i++)
* ** *** * * * *** *
** * * ** *** * * ** ** ** * ** * ** * ** && n2%i==0)
******* ** ****** ** * * * * * ** ** * *** **
****** * ** **** * ** ** ** * * * ** * * ***** * ** * **** **
* ** * * * * *** ** * ** * * * * * ** *** * *
** *** * * ** * **
* * * ** ** * **** **** ** && a>=n2;a--)
    {
* ** * * *** ** * * *** ** * ** *** * *** && a%n2==0)
**** **** * ** **** * ** * * * *** ** * *
* ***** ** *** ** * * * * * * ***** * ** **** ** ** ** * * * ***
* * * ** * ** ** * *** ** ******* * * ** **
** ** ** *** *
* * **** * ** * * * * ** * ** * %d",gcd,lcd);
* ** * *** * ***** ** * 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * ***
int main (){
int i,j,k;
* *** * **** * *
* ** ** ** ** * *** *
* * ** ** ** *
* * * ** ***** ** * ** ******* * ** *
** * * * ** * * ** * * **
*** ** * *


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

* ****** ** * * ** i;
* ** * * * * ** * ** result=1;
* *** * *** * * ** **** ** * * * *
***** ** * * * **** * ** * * * * * * * **** * && a2%i==0){
** * ****** * *** * * ** ** * ** *** * ** * * *** ** ** * = i;
*** * **** ** *** ** ** * * * * * ** * *
**** * * * ** *** **** *

* * *** * * * * ** * ** *** result;
}
int Get_LCM(int a1,int a2){

* * * ** *** ** ** *** *** i;
*** * * * * * * ** * * result=1;
********* * * * ** * * ** * * *
* * * * ** * * * * *** * *** *** * ** * ** * && i%a2==0){
* *** ** * ** *** * * *** ** * * * ** * * ****** ** ** *** ** ** = i;
* **** **** **** * ** ******** * ** *** ** * *
*** * ****** * **** *

* * ** *** * ****** * * ** result;
}


int main(){

* ** ** * *** ** * * * *** * * * * * *

***** ** * * **** ** * * *
* **** ***** *** * * *** * ***



* * ** * * ** * * * * * * * *** %d", GDC, LCM);
*** * *** * *** * * ** * * 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.164
©2016-2026

Related questions

0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 3.8k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 15.6k views
0 like 0 dislike
21 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 6.3k views
0 like 0 dislike
22 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 6.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users