1 like 1 dislike
7.3k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiplelowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(ab), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited

edited by | 7.3k views

36 Answers

0 like 0 dislike
Hidden content!
#include * *****
//gcd and lcm
int main(void)
{
*** *** ** *** ** n,m,i,gcd, j,k,lcm;
****** **** ** *** ** ** ****** **** &n, &m);
* *** * * * * **** *** *** * i<=n * * * ** ** i<=m; i++)
* * ** ** * * * ** *
* ** *** *** * * * ** * * * * **** *** * * * * * * * ** * ** m%i==0)
*** * *** **** **** * *** ** ** ** * ** * * * ** * * *** * * * **
** * ** *** *** * ** ** *
*** * ** ***** * ** ** ** ** **** * * * ", gcd);

*** * *** **** * k>=n && k>=m; k--)
* * * * ****** * ******
* * * ** ** **** ** ***** *** ***** k%m==0)
* ** * ** *** **** *** *
** ******* ******

** * ** * * ** ** ** ** * * * * * * ***


* ** * ** ** * **** 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
***** *** * * *** a,b,tmp,x,y;
*** **** *** * ** * ** ***** %d", &x ,&y);
*** ***** * * * *
**** * ** *** ** **
** **** ** ****** ** * * {
*** * * ** *** *** * * * ******* * **** * ****
** *** * *** ** ** * *** * *** * * ** * * * **
* ** ** * * * * ****** * ********* *** *** * * ** *
*** ** * * * **** *
* * **** * ** ** ***** ** * * *** %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
* * * * * **** a,b;
* * **** * *** *** ***** gcd,lcm;
* * ** **** *** ** ** * %d",&a,&b);

* * * ** ** * **** *** * ag=a,bg=b;
* * **** ** *** * ***** * ** ** *
** *** ** **** * ** *** * * ** *******
*** *** ****** ** ** **** ** **** ***** * ** *** ** *** temp;
* ** *** * ******* * * * * * ***** *** ****** ** bg=ag, ag=temp;
** *** ***** **** ***

** ** * **** ** *** * ** i=1,al=a,bl=b;
**** * **** * * ** * al%bl!=0 ) {
**** * ** * ** ** * ** ** ** ***** *** ****
* **** * ** * * *** ******* ** * * * **** ***
* * * * * * ** **

* * *** * * * **** %d",bg,al);
** *** *** ** * * * ** * * * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* * * * * ***** * ** * **** * * ** ** * * ** **
* * ** * * * * ** * ** *** ** * *** * *** ** ** ** ** ** * * *** ** *** ******* * ** ****
*** *** * ** ** ** **** * * * ** * * * **** * * * ** ** *** * * ****** * * *** *** * * * ** * ** * *
* ****** * * ****** * ** * *** *** * ****************** ***** * * * *** ** ** * *** ***** * * * * * ***** * *** **
* * * ** ** * * * * * ** *** * * ** * ** * ** * ** * * * * * ** ** * * *** * * ** * * ***** * * * ** * *
** ***** ** * ****** *** * * **** * * * * * * * ** ** ** ***** * * ** ** ** * * **** ** *** * *** ***** ",i);
****** * * ** *** * *** *** * * **** * *** ** * * *** ***** * * * * ** ** ** **** * ** ****** * * ** *******
** * * ** * * * ***** *** * * * * ** *** ** ** * ** ** *** * ** * * ** ***** * **** * * * * * * ****
* ** * * * *** * ** **** *** * * ** * **
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
** * ** * ** ** * ** ** *** * ****
* * ** ** * * * * ** ** **** ** **** *** * * ** **** ** *
* ******* ** *********** * * *** * * * *
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
* ** *** * *** *** * * ** %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
*** ** * * * * * *** * **** * * ** ** *
** ** *** * **** ** ** ** * * * * * * (flagGCD1==0)
* ** * *** * *** ** * *** ** * ** ** *** * * ****
*** ** * * * ** * * ** **** ** **** * ** * * ** * *** ** *
* *** * * *** *** * ** ** * * *** * * *** ** ** ** ** * (flagGCD2==0)
* ** * **** *** **** * ** * ** * ******* ****** ** *
**** ** *** * ***** ** * * * **** * ******* * * ** * * ***** **** ** * * * *** **** * * ",i);
* ** **** **** *** ***** * * *** ** * **** * ** * ** * * ** * * ** * *** * ** * ** ** **
* * * * ** ** * * * * * ** * *** * * * * ** * ****** ****
*** * * * ***** * * ** * * **** **** * * *
    }

    //LCM
    for (j=1;j;j++)
    {
* ** ** * * * ***** ** *** * * * * * **** ** * **
* * *** ** * * * **** * * ** * ** ** * **** (k=1;k;k++)
* * * ** * * ** ** * ******* ** * ** *
*** *** **** *** * * **** * ** * * ** * ** * ** **** * * * * ** ***** ****
**** * * **** * ** * * * * ****** * ** * *** * * * * ** * * * * (flagLCM2==flagLCM1)
* ** * * **** * *** *** * ****** * ** * * *** **** * * **
** **** ******* ** ***** ** ** * ** **** * *** * * * * ** ******* * * * ** **** * * * ** * * ** * ** * * **
* * *** ** * ***** ** *** * * * * ***** * ** * ** * ***** ** ** * ***** * *** * * * *** **
* * * ***** *** * ***** ****** *** * ** *** **** * *** *
* * * ** * ***** * **** *** **** *** * *** * * *** * **** *** **** (flagLCM2>flagLCM1)
** ** ** ***** * * * ** * * **** ** * ** * *** * * * *
**** * * ** * ** * * ** * ******* *** * * *** ** * *** * * **** * *** * * ** * * * *
* * * ** * ** ** ** *** *** * * *** * **** * *** *** **** * * *
* * *** * ** ***** ** * * ** * ****** * *
* * * * * ** *** *** *** * ***** *** ** * (flagLCM2==flagLCM1)
**** * * * * ** *** ***** *** * ***** * *
* **** * *** ** ** **** *** * * * * ** * * ***** ** ***
*** * * ** *** * ** ** *** * * ***** * ******* **
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
** * ** ***** * * * * * * *** ** * * * **
** ** * * ** * * ****** ***** * **** ** *** *** * *** **** **** *** *** **** ****
* * ** ** **** *** ** ** * *** ** ** *** ** * ***** *** * *** * * * ** * ******* ** * *** * * ** ** ** ***
** * ** * ** * *** ** **** *** * ** ** * * * ** * **** * * *** ** * * * *** * **** ** * ** ***** * ** * **** * * *
*** * * * ** * **** * * * ** ****** * * * * ** * * * ** ******* ** ** ** * ** * * ** *** * **** * *** * * ** *** * ** * * *
** ***** * ** * ** * * ** * ** * * * *** ** ***** * ** * **** * ** ***** ** *** * * ** * * * **** * * * *** ** * *** * *** * ****
** * *** * * * * * *** * ** ** ** ** ** ***** ** * ** *** *** *** * * * * ** * * ** * **** * ** ** *
** ** * * * * * **** ** * ** ** ** * * * ** ** * * * *** ***** ** * * * * ** *** * ** * *** *** * *******
***** * **** * ** * *** ** **** ** *** * *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
** * ******** * * ** *** * ** * * * * *
**** **** * ** ** * ***** * * ***** * **** * * * ** * * *
** * **** *** * * * * * *** * *** ****
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
**** * ** *** ** ** * a,b,smaller,i;

****** * *** * ** * * * * * ** **** * *

* * ****** * ** *** ** * **
** ** * * * * * * * *** * * * * * * ** **** * * * ***
** * * * ** * ** * ** *
*** * ***** ** * * * * * * *** ** ** * * * *

* * ** * ** ** *** * * * * *** * *
** * ** * * ***** ** ** * ** ** ***** ** * * && b%i==0)
* * * * ** ** ***** * *** **** * ** *** *** * * * **** *** *

* * *** * *** **** * * ***** **** * * %d",i,(a/i)*b);

* * * ***** ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
*** * * * ** * * ** i,n1,n2,a,gcd,lcd;
***** **** * **** ** * **
** ** * * ** ** ** ** ** %d",&n1,&n2);
** *** * ** * * * ** * * ** || i<=n2; i++)
* *** ** **** * ***
* * * *** *** * *** *** * **** *** * * && n2%i==0)
** ** ** * * * **** * * * * ** *** * * * **** *
* ** *** *** * **** ** ******* * * *** ** * * * * * * * **
** * ** **** * **** * ** *** **** * ** * *
* * * ***** ****
** *** ** * **** * *** ******** *** && a>=n2;a--)
    {
* ** ** * * *** * ** * * ** *** *** *** * * ** ***** && a%n2==0)
* **** *** ** ** * * ** * * ** ****
* * * * ** * * ** * ** * * ** * * * * * * *** * * ** ** *** * ** *** * * *
* ** * * ** ** * **** * * * * **
***** * *** *** * *** *
*** * ** ** * *** ** ** * *** ** %d",gcd,lcd);
* ** **** * *** *** * 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * ****
int main (){
int i,j,k;
* ** *** * *****
* * ** ** * * * ******* ** * * * *
**** ***** *** *
*** ** * ** * **** * ****** * **** ** *** **
** * * * *
***** * * ** ** **


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

* * *** ** *** ****** i;
* * ** *** **** * * * result=1;
* *** ** **** * ** * ** **
* * * * ** * * *** * *** ** * * ** * * * * && a2%i==0){
* ** * ** * * ****** ** * ** ** * *** * * ** * **** * * = i;
* *** * *** * ** * ** * * * ** **
** * * *** ** * *******

** * ** * *** * * ** ** result;
}
int Get_LCM(int a1,int a2){

** * **** * **** i;
*** *** * * * ** ***** result=1;
**** ** * *** * * * * * **** ** ** * **
* ** * * * * * * ** * ** * * * ** ** * ** ** && i%a2==0){
* **** *** * * *** *** *** *** * * ** **** **** **** ** * *** * ** ** * ** = i;
* * * ** ** * * * * **** * ** * * **
*** ** *** * *** ** ** *

* * * ** * * result;
}


int main(){

* *** *** * ** * * * * *** ** * ** **** * * **** *

* ****** ** * ** * * * ** *
**** * * ****** ****



*** ** **** ** **** **** **** %d", GDC, LCM);
** * ** * *** * * ** * ** 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.8
©2016-2025

Related questions

0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 3.1k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 13k views
0 like 0 dislike
21 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 5.2k views
0 like 0 dislike
22 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 5.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users