[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.9k views

22 Answers

0 like 0 dislike 
Hidden content!
     *  *  **   *  ***

int  *    argc, char **** * {
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** ***   *   return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  * * ** * * * *
#include  * * * ** **   **

/* run this program using the console pauser or add your own getch, ***   * *** *       *  or input loop */

int main(int argc, char *argv[]) {
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*   **  ** * *** * * ***  * *
* *   * *     *  * *     **** *     *  * the words you want to  * *   *   *
* *  ***    ****   ***   
**** ** ***    ****** **   *  = getchar();
  * ** *  * *  **   * * *    *** = a+3;
  **** ***** ** *   *****  *** *
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 * ** *** ****  **   ** * * = b+3;
*   **  *****  ** **** * *** * * *  
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* * *  * ***      **   * ** * * * = c+3;
**** **      **  *******    ** 
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  ***   * ** *  ***    ** *  = d+3;
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 * * *  * ** *** * * ** * = getchar();
  *  **  ** * *  * *   * *   = e+3;
*    * * ****  *  * ** * *** * ** *  ***
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 * *   ** *  *      ***    
    * * **  * * * **** *** *  *  * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**  ** ** ** **   *** 
*** *   **   ** ******* *

int * *  * char ***** {
/*
 **  *** */

**   **** *

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a = a+3;
b = *** 
c = **
d = d+3;
e = ****

*  ** the ***   ***
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* **  * **  ***    *  * * ***

**** *     * *   *** 
 ****  *   * **** ** * **  ****    0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
***  *  * * *** 
        ** ****    ***** * 

/* run this ***   *    the     *      or add your own  *** *  ** *** ** * *** * or ** * */

int  **  *      char   *  {
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** *   **  *  
**** * *            *   **** ** * *   *   
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{
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** *   *    **  if ** ** *  **
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*  **     **   ******* **  
}
*  ** * *    *  **   *   *     ** * *  *  
* *    ***   * ****    * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * *  * ***    *  **  
 
* *     **    *  *

* ** *    ***** **  *   *   **   **    *  *  * *       **  * * * *    *  * ** *   * *
 
** * * * ***  * **   *   
*
** * ** *  *  * 

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*
* = * *  
 
 * b + * 

*  = c + * 

*  = d + **

         *
 
** *   * ***  ****** *    *  *   *    *  
 
***    
*
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
***          * * **
 * *   * **** * ** *** 

int     ** argc, char *** {
* ***  * *  *** char  *  *   
  ***   * **  ** char  *  
   *    *  **** char **   
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*         *  *   char     
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** *  ** *  ** ****     *   input the letter to * *****  **
** *        ***  
 * *      ** ** ***** *  ***** **   ** *    *******      * ***** **   **   **    *  ***      **   * ** 
**      ** *   *  **  =   ** + 3;
 * **    * * **    * *  = *  + 3;
   *** ** ** * * *** =    + 3;
 **** ** **  * letterc =   ****  + 3;
         * **  **  * =  *** + 3;
    *   * *  ** * 
  **  ***   *   *          * **  *** ** *     ****         *   ** *    ***
****      *** ** 
   * *     **  **  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * * * * *  * **  ****
 **    ** *        ** 

int **  ** argc, char *argv[]) {
* *   * * *    * char *   *
*     ** *  *  char letteri;
 * ***   ** *** char * **** 
*** ****   *  * char  **  
  *  *   * ** * * char  * **  
 *  *  **  ** 
******     **  * ** * * ** input the letter to encode:     *  ** * *
*  ****     *  
 ***    ** * * ***         * *  *  ***** ***** ** *** *** ***    * *  * ***  ** **   *****  *   * **
*  ****** ****       * *    ** +3;
* *   *  ***    **** **  *** +3;
* * * ***   **** *  * +3;
* *  *  *  ** ******* +3;
*  * * * * *  * *   * * +3;
***    ** ***    
** *   *** *    
* *   * *  *  * ** **  * **    * * *  * ** ***  *  ***  ** 
*    *   * **   
*** ** *  ** * *   return 0;
}


INPUT
* ****      ****
  *  ** **
OUTPUT
*****  ** *      **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  * **    **    
** * * * * *  *  * ** *  

int  ***  argc, char ** *** {
***  *  *****  char *****
*  *    * **  char *  * *
**  * *   ** *   * char  ***  *
 * * * **      *  char *** *
*   **  * * char ** ** 
**   * * ** ** 
** *  *   * *    *   ***  *   * input the  **  to *   * *** **    ** 
*   *   **  * 
** *  * *   **     *  ** **     * ****  * * **  **  *** *   **   * **  **     ***  **  *** **  * *
*    ******** 
 *  **** * * *   letter = letter + 3;
*    ** *  ***    * = **  + 3;
    ***  * ** ***  = **   + 3;
** *  *     *** ****  * =   *** + 3;
* ****     *  *  = **    + 3;
 * **  *     * **   
 ****         *   ***  *   *  * * * **** letter is   ****    ** ***  * **   *****      * * * **
   ***        
****     ** ** *  return 0;
}

INPUT
** *  *    ******* 
 ** *** **  ** 
 ***
   * *         *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  * * ****** ** **

int main(int argc, char *argv[]) {
*  ***** *   ** * *  * * ****   ** lettera;
* *     *     *** ******  letterb;
 ****  * *   *  ***    * *  letterc;
   *  **    * **  **** ***     * ** letterd;
** * * *      **     *** ***** lettere;
*    ** ** *  *   *  **  **
* * *   *   *****   *   *** ** ** ** * %c %c %c **  *      ** **   *  ***** *  **  * *    ***       * *  *    ***** *  
* *   *  ** ** *** ** *    ** *  = lettera + 3;
  *   * **  *  * * ***    = letterb + 3;
  **** ** *   * *** ****  ** * = letterc + 3;
* * *  * **    * ** *   *    = letterd + 3;
 ** **  ******* ** *******  *  ** = lettere + 3;
** * *   ***    ** ** **    *  * *  *****  *   * ***  * * 
*  ****** ** ** *** *   *     **** **  *** %c %c %c  *   *  *    **  letterb,    *  *     ** *** 
****   ** ****  * *  *
      **   * ***  *  *  ***  *  * 0;
}

** * 
*  ** 
***    
 *  *  *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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