[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 10.3k views

22 Answers

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Hidden content!
* * *   *** * ***       

int  **   argc, char *     * {
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * *****  **  
#include *  **    ** *  * 

/* run this program using the console pauser or add your own getch, **   **** * * ** **** **** or input loop */

int main(int argc, char *argv[]) {
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** *  ******* **        *    * *     0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   **** ** * ***    * *  
*** *  *     *  ****** *****

int * * *      * char  * *** {
/*
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a = a+3;
b = **
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*  *    * * * ***
** **     *** *   * ****  *  *    0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 ** *  *   * *  *  ** *  
  * *  *** * *  * **

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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* ***  *   ** *** **** 

 **    * *** *    *** *   

  * *   *     *  * ** *  * ***  *    **  *     *  *    * *    ***  **  **** *  * ** ** * 
 
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* * = c +   

* * = d + 
 
***    * 

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* **   **
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** *  * * **   * ****  
  ***  **  ** ****    

int *   *   argc, char ** ** ** {
* * * ** *  * **  char **  **
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**   * ****     *  =    *  + 3;
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**** *** * * *  letterc =    + 3;
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 *** *      ***   
**** * * **** *   *    ** ** **      ***  * * * *    * ** * ** *     ***  * *  *
**  **  ***  
 ***      **    return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**  *  *    *   * * 
*   ***       ** **  *

int ** ** argc, char *argv[]) {
   * * * ** char  *** * 
 ** *  *       * char letteri;
  * *  * ** * * char *  **  
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*   **  *    * char *  ***
**** **      *** 
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* * ** * *** * 
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*  * *  * * * ** **  * ***   +3;
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  *  *** ***  
 * ** ** *  * **     return 0;
}


INPUT
* * **   * *  ****
   * ***   
OUTPUT
 ** ****    *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *** * ** * *** **** 
 ***    *  ****    ******

int  ***  argc, char     {
*  * * ** * * char ****  
  ****  *   ***** char ******
*   *   **** char *    
****   *  ** *  char *   * 
 ***     **  char * ** 
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*  * *    ** *** 
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 ***** *  ** *     **** = * ** + 3;
    * *  **     *   = *** + 3;
  **    *  *** * *  *    = *  ** + 3;
  * **   * *** ***  *  =      + 3;
  ** ***    
  *** ***  *  * *  ** **  **    * * *   * letter is      *  * ***   **   * *  *   *  * ** *    * * 
* * ****  ***    
**** *  * * * * return 0;
}

INPUT
 ** *  *  ***   
       *   ****
 **  
 * ** * ***  * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include **  **   *** *  

int main(int argc, char *argv[]) {
 *  *   *** *  *  * **** lettera;
 * ***  ***     *      **   ** letterb;
  **** **    *      *   * *** letterc;
    ****   *          * *** ***   * letterd;
  **  **      ***  * *   *     lettere;
**   ***      **** * *****   
**  *******      **   **   ***      ** ** * %c %c %c *     **  *  ***       *    *    *** ***     ***  *    *** ***  
*  ****** ** *   * ** ** ** = lettera + 3;
*    * * * ** ***  **  **      = letterb + 3;
* *     *** ****   *  ****** ** ** *   ** = letterc + 3;
  * * ** *  ** *** ****    ** **  = letterd + 3;
*  ** *****  *** *** ** * * ***  = lettere + 3;
* *     * * ** ***  *      ****  *** *  ***    
* *   *  ** *  **  ****   *  *     %c %c %c *  ****    *  letterb,        ****      *****
****   ***   **    *  * ***
**   ***   **  ** *  * * **    * 0;
}

 ** 
 *  
  ***   *  ** 
   * * 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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