3 like 0 dislike
5.6k views

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited

edited by | 5.6k views

22 Answers

0 like 0 dislike
Hidden content!
* *** ** * *

int * argc, char ** * {
* ** ** ** * * * *** */

* ** * * * int number;
* ** * * char a;
*** * * ** *** * b;
**** * * ** * * * *** * * c;
*** * * ** **** d;
* * ** ** *** ** * e;
* * * * ** *** ** **
** ** * * *** forgert how to shift word *** * * * * * *
* * * * ** * * ** * ** *** * ** ** ** * *** * ** * ** **
* * *** * * **
** * * ** * * * the message how??
***** * *
* ** * *** ** ** ** * ** * * **** *** * *
** **** ** * *
* * *** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
* ** * **

* **** * ****** {

** * * *
* = * ****
* ***
* = ** * *
= ** ***
* = * * *

* = *
* = *
= *
= *

*** *
* * ** **
* * * *
**
***** **
*
* * * * **
*
100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
#include **** * **
#include * * ** * *** *

/* run this program using the console pauser or add your own getch, * * * *** *** * or input loop */

int main(int argc, char *argv[]) {
* ** * * **** *** ** ** * a;
* *** * * * ** * * ** ** b;
* * *** ***** ** *** * ***** c;
****** *** * ** * **** d;
* * ** **** *** * **** * e;
* ** * **** * * *****
* * * *** * * ** ** * * * **** ** *** the words you want to * *
* *** ** * * * *
** * ** ** * * * * * ** ** *** = getchar();
** **** ***** ***** * = a+3;
* ** ** ** * * * **
******** * ***** * **** = getchar();
** ** * * ***** * * ** ** = b+3;
* * * * * * ****** * **** *** *
* ** * ********* * **** = getchar();
* ** * ** * * *** * = c+3;
** ****** * ****** ****
* * * * * ** ** * * = getchar();
* **** * *** ** = d+3;
** * ****** ** *** ** * ** *
* * ***** ****** * * * = getchar();
***** ** * *** ****** = e+3;
*** * ** * * * ***
* **** *** * ** ** * ** **** ** *** * ** *
* * * * * * * * * * **** ** *** *** &a, &b, &c, &d, ** * *
*** * * *** ** *
* * ******** * ** * the message how??
* **** * * ** * * * *** * *
* * * * **** * * * ** * *** ****** ** * *** a, b, c, d, e);
* * *** *** *
* *** * **** * * ** ** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
1 like 0 dislike
Hidden content!
**** ** * * ***
*** * * * * * ***

int **** **** char * * {
/*
* * ** */

* *** **

** ** * * * * *** * * ** * * * * * ** **
a = a+3;
b = *
c = * *
d = d+3;
e = *

* the * *** * *
* * ** * *
* ** ** **** * * **** ** *

***** *** **** *****
* * ** * ** * * **** * * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
* ** ** ****
* * * * ******* ***

/* run this ** * the * * or add your own * ** ** ** * ** *** * ** or * */

int * * * ** char * ** {
*** * ** * int num, ** *
* * ** * * ** *
* ** ***
* ** * * * * * ** * * **** **
*** *** * for = ** ** * *** *
{
* * ** * ** ** * = ***
* * * *** if ** * * ****
** ****** * **** = ** ** * *
** * ** ** * *** ** **
}
*** ** * * * ** **** ** * * **
*** ** *** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
1 like 0 dislike
Hidden content!
* ** ****
*
* ** ** * * ** ***** *

* * * * ** ** ** ** ** * ** ** * * * ** * ** ** ** * *

*** ** ** * **** *
*
* * ** *

* ** * * *

*** *** * * ** * * * * ** *** ** ** ** * ** * *****

** = *
*
* b + *

*** = c + **

* = d +
*
* *

** **** ** * * ***** * * ** *

* *

*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
0 0
That's correct.
1 like 0 dislike
Hidden content!
* * **
* *** * ** ** ***

int * ** argc, char * ** {
* * **** char **
* ** * **** char * *
** * * * char **
* *** ** * char * *
* * * * ** char ****
*** ** ** * *
* *** **** * **** * ****** ** input the letter to * * * ****
* *** * ** *
* * ** * * * ****** * **** * * * * *** * ** ** * *** * ** * ** * * *** * * * *
* *** ** *** * *** * = * * + 3;
* * * * * = *** + 3;
* * ** ** ** = * + 3;
*** ***** letterc = ***** + 3;
** * ** *** = * + 3;
* * * *
*** ** * ** *** * *** **** ** * * * * ** * *
****** * **
** ** * * *** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
1 like 0 dislike
Hidden content!
**** * ***
* * ** * * **

int ** ** argc, char *argv[]) {
** * *** * char * **
* * * * ** * ** char letteri;
* * * char **
* **** * char
* ** * ** char * *
* ****** * ***
******* ** * * ** * input the letter to encode: ** * **
** ** * **
*** **** * *** *** * ** * ** * * **** * ** ** ** * **** ** * * ** *** * ** **
* * * ** ** ** **** +3;
* * * *** ** * +3;
**** * * ** * ** * * * +3;
** **** *** ** * ** * * * +3;
** * * * **** ** ** +3;
* * *
** *****
** * * ** ** ** ** ** ** ** * * ** *
* ** * **
** * ** ** ** return 0;
}


INPUT
* * * *** ** ** * *
* * ** ***
OUTPUT
* * * * ** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
* * * *** * * *
*** * ** * *

int * * argc, char **** {
** * * ** ** * char * **
* ** ** char * ***
*** * * * * char ***
* * * * char * **
* * * * char * ***
** * * *** *
** ** * * * * *** * * input the ** to *** * * * * * *
* * * * *****
*** **** * ** *** * * **** * * ** * *** *** * ** ***** * **** * * **** * **
* * * **
** * ** * **** letter = letter + 3;
* ** * ** * ** = *** + 3;
******* * **** * ** = * *** + 3;
** * ** * ** ** ** = **** + 3;
** * ** = * *** + 3;
* ** *** **
* ** * * *** ** * letter is ** ** ** * * * *** * * * * *
*** ** * **
** * ** * return 0;
}

INPUT
** ***** * * *
* *** *
* *
** ** * ** *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
#include ** ** * ***

int main(int argc, char *argv[]) {
* ** ** ***** ** * **** ** lettera;
* **** * *** * *** * * ** letterb;
***** ** ** ****** *** * ** letterc;
** *** ** ** * *** ** *** letterd;
* * * *** * * **** * ** lettere;
* ** ** ** * *
* ** ****** ** * * * ** ** *** ** %c %c %c * * *** ** *** *** * * *** * * ** * ** * * *
* * * ** **** ** * * = lettera + 3;
* * * * * *** ** * *** ** = letterb + 3;
* * ***** ***** * * ******* = letterc + 3;
** * *** *** ** * *** ** **** = letterd + 3;
* * **** *** ** ** = lettere + 3;
** ** *** ** * * * ** *** *** * *** *
* * * * ** * * * ** ** * %c %c %c ** * letterb, * *
*** ** * ** * ** ***
* * * ** ** *** ** 0;
}

* ***
* *
** * *
*** *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.203.112
©2016-2025

Related questions

0 like 0 dislike
2 answers
[Normal] Essay (Open question) - asked Dec 12, 2017 in Chapter 2: Syntax structure of the C language by 許哲瑋 (449 points)
ID: 37081 - Available when: Unlimited - Due to: Unlimited
| 855 views
12,783 questions
183,442 answers
172,219 comments
4,824 users