[Exercise 03] Caesar Cipher Decoder

Question

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

Answer 1

Hidden content!
 *     *** ***  ** *  

int  *   *  argc, char **** * {
  ** ** * * * **  * **** * *   *  */

 **    *  *  *    int number;
    *  **    char a;
****  ***  ****  *   ** *  *** b;
*** * * ****   *  **  * **  * c;
 **  * *  * *  **** *    d;
   ** *   * * *   ***  ****  *  e;
* *    * * *  *  * * *
 *  *** * **      *  * forgert how to shift word  * * *   * * *   ***     
 * *  **   *   * ****   *    * *   * *  *  **  ** * * *   ***     * **  * *   *** *   
     **  *  *   
* **  * *  * * *  * the message how??
* ***  *  *      
**  ** * * ***       * * *      ** ***  **   ** **   ***
*  ****   ** ** 
 *  **     * **  return 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output

---

Case 0: Correct output
Case 1: Wrong output

Answer 2

Hidden content!
  *    ** ** *** ** *   

 **  * * *    *    ** {

  **   **  
** =  ***  *  *
**   * *  ***
   =  * **** 
* = * ***
 = ** ** * 

  =     
 =  *
* =  * 
  = * *

 **     *
***  
*   **    
 *  ***
** ** **  

 **    **   **    **    
*

Comments

Case 0: Correct output
Case 1: Wrong output

Answer 3

Hidden content!
#include  ** * *  * *    
#include      *  ****   **  

/* run this program using the console pauser or add your own getch, * * *  *** *** *    or input loop */

int main(int argc, char *argv[]) {
********  * *** * *         *  a;
*   **  *   ** *        * ** * b;
*** * **** * ** ***       * * * c;
    **       *    * * *  **  *  * d;
***  **   **     ******   * e;
* *  * *   * ********      *
   * *  *  *  * *  * * ** ** *  **    the words you want to ***  * * * *****
 **   **   ** * * 
 **** **   *   **  * * *  ** *  = getchar();
* *  *  **  **  * * **    ****   = a+3;
**** *   **  * *** *   **  ***
  *  * *** **  ****  * = getchar();
*  ****   *  * *  * *  **** = b+3;
 * ****  * *** * **   ** ** * 
    * **    **  * * *  *   = getchar();
*** **    **** * * * ** ***   = c+3;
   ****      * ******* ***    *
** *  ***  *  *** *  ** *  ** * = getchar();
*   ***   *** *  * * *  ** **   ** = d+3;
* *  ** *** **  *    ***   * 
**    *     ** *****  * ***   = getchar();
* **** **** *  * *  ** **    * = e+3;
  ****   ** *   ** **  *  * ****** 
* *   * **     ** ** **  ** * ** *    *  *   *   **   ** * *
  ** *     *   * *** ******** * ***      * **  * ***  &a, &b, &c, &d, * *    ***
** * *******  **   *  * ** *   
**   *   * **      **    ****** the message how??
** **   ** ** ***   * * ***
* * *   * ******* *   *** ** ***  *** * ** *  * **  * * *  *       a, b, c, d, e);
** ***  ******    **** *   
 *  * *  * *  ** *     *   **   0;
}

Comments

Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.

---

This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)

Answer 4

Hidden content!
*** **** *      * * 
 ** **    ****      *  

int  * **  **  char * * * {
/*
***     **  * */

      **   

** ***  * * *    * * **  ** * *  *   * * ** **  *  *  **   **  
a = a+3;
b = * 
c =   
d = d+3;
e = *  

*  ** the  **** ***
** **  ****   ** ***  *
* *   * * *  *  *  * **  ***** 

  * * * *  **  *   *  
     ****  *   *     **   *    * 0;
}

Comments

prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'

---

Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello

---

Case 0: Correct output
Case 1: Wrong output

Answer 5

Hidden content!
** * *   * **  **  **    
**  *  * *  ** **       *

/* run this **    * the **   *** or add your own * ***    ** * *  ** ***  or   *   * */

int ***   ***   char   *  {
***      ** **  int num, *   
*    *    * ** **       **  
*  ***  ******* 
  ***  *** **     ***         * * 
  **    *  * * for *   = ** **    **  *
{
*** *   * *  **** =  ** *** *
  *     *** *   if **    *    
 ** **  *   *     ** = **   * *  *  
  * * **  * ** *** * **** **
}
 ** *  **   ****    **  *    **** *
******  *      ***   * 0;

Comments

prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~

---

Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.

Answer 6

Hidden content!
 ** *   ** *  *  *    * 
*
**   ** *     ** * 
 
 * * *   *    *      *  * ****   **       *** *       *  ***  *** *  *    *    *  * * *
*
      * ** *  **   **   

* * * **    *  *

**   *   * ** ** ** 
 
*   *  **  *     *    ***     **     **  *    * ******  *       * ** **** 
 
** = * * **

   b +  

  = c +  

   = d + *
*
* *      

*****  *  ** **** * ** * **   * *   * * *

 * **  *
*
  

Comments

It's correct lol you can't judge me

---

Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.

---

printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?

---

That's correct.

Answer 7

Hidden content!
 **** * * *  * * *   
** *   *  *  ***** ***

int * *   argc, char  *     {
    *    ** * * char * *****
** ** *  * *  char      
* ***    * **** char    *    
 *   **      **** *  char * * 
  ***** *** *** char  *  *
 **  ***     ** * 
 *  *     ***    ** **   * ** *  input the letter to * * **   * *  **
*   *  ** ***** 
*     *  ** *  ** * ***** *  * ***  **       *** *       ***  * ***** ** ** ** *  *** *  *   **  *  ** 
   *     ** *  * **  = *** + 3;
  ***  * *  **  * =    + 3;
* *    *   * *  **** * *   =   *   + 3;
     * **  * *  *  letterc = * ** + 3;
**  ** *    **   *   = *  **  + 3;
**     * ** * 
 *  * * ** **    *   ** ** *   *** **  *   * ***    ** ***      ** **
  *****  *     
** ****  *  *   return 0;
}

Comments

-----------Re-judge-----------
Case 0: Wrong output

---

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.

Answer 8

Hidden content!
   *   ** *  ** ****   *
*  *      **  *     * 

int * *    argc, char *argv[]) {
 *  * *   **   char  * *  
 ** **    *  * char letteri;
*  **   ** *    char     *
***** *   **   char ** *  *
* **  * * *   *   char *  
  *****     ** 
* * *           ***   *  *    * input the letter to encode:  * **    ***
*** * *** *** *  * 
** * *  *   *  ** *** **    ** ** ** *      * **  *   ***   *   ** *   *  **   * ** **       *** ***     * *
**** * *  *  *  *    ** *  *  +3;
 * *   ***** * *   ** * +3;
**    **  ** *  **  *** * +3;
  **    ** ** *** ** * +3;
 * *  * ** *  *     * +3;
 *    * ***  *   
* *  *    
* *  *   **  * * ***  *  **** **** * ** * * * *  *  *     *   *****
*  *  *   *** *** 
*****     * *  return 0;
}


INPUT
*****   ***** 
** *  ***   *  *
OUTPUT
   ** *  **  

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'

Answer 9

Hidden content!
*   ***  *   *** ***   * 
 **  **   ***  *******  

int * * argc, char  *  *   {
 * *** * *   * * char  * 
 **** ** *     char ** * 
* * *     ** **  * char *** * 
 * ** *   **    char   * *  
*  *    **  * char  * 
*****  ** ****  ** 
*   *   * * * *   * **  *  **  input the **** to    ***    *   *   *  
 **  ** *  ** *  * 
    * *   ** *  * *****  * *   ** **  *  *****  ****   ** *  *** ** *   *    *   ***   ***       ***
   ***  * * * *  
**  *   * *** letter = letter + 3;
*   * **     *   **   * = *** + 3;
 * *  ** *  ****   **  * = ***  + 3;
    * * **      * = *    + 3;
 **       *    *** =     + 3;
*     *  **   
 *****    *** *  * *   *** **  ***  letter is  *  * * ** *  ***  * ***  *  * *   *  *  *   
  * *** * *** 
******   *** **   return 0;
}

INPUT
  * *  * * *  
 *  *  *  
  *
** **  **      

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'

Answer 10

Hidden content!
#include  *  *       **  ***

int main(int argc, char *argv[]) {
  * *** **** ***  * **  *  lettera;
* * *****  *****   *   *   letterb;
  *  ** ***** *  *    *** letterc;
**    *  ** ******** *  **    letterd;
 * *    *   *      * *** * * * lettere;
*   * *  **  **  *  * ** ** *
  **   *  **  **   **   ***  *** *  * * * * * *** %c %c %c    * *  * **   *   *    *  * *     *  * *        **  * * *   ***  
*****    **    **** * *** ** * *        = lettera + 3;
  **         ***  *** ******* * = letterb + 3;
 *  * ** **  *   **  * *   *  = letterc + 3;
     *****       *** *  **    ** *  = letterd + 3;
 ** *********  *   ******** *** *  = lettere + 3;
***  *    *  * *     ** **  *** **    * **  ***  *  
** * * *  ****  *** ****          *   %c %c %c   ***   * * * letterb,  * * * *   *  *  
*** **      * *    ** **** ***   
** ***  ****** *  **  **** ** **  ** 0;
}

**** 
* * 
    *     **
    
//hello

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'

---

prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'