[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 6.7k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  *  * **  *  * **
#include     *   *** *   

/* run this program using the console pauser or add your own getch, **  *** * **   *   ** *   or input loop */

int main(int argc, char *argv[]) {
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**  ***  * **     *** *  ** ** = a+3;
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*     ***    *  ******* **   = getchar();
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**  ** ** ******      **    = d+3;
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* ** * ***** **** ** * ***  ** * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *     * *  *****  *
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int * *  *  **  char * ** {
/*
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a = a+3;
b = *  *
c =  *
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
     ** * *** *  * *
****   * *      *    **   

/* run this *    **   the  * *** ***  or add your own     * *   *  *  *  * **** or  * * * */

int *  **     *  char ***   {
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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *   *     * * * *  *
*
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*  = *  * 

**  b + **

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**  = d +   
*
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***   **  ****  **   ** * ***** ** *  **  *   
 
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*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** * * * *  *  **     
**** *  * * ***  * 

int  ***   argc, char   *  {
*** *      * **** char  **    
 * * * *     char  *    *
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 ***  *   * *   ** * *  ***  **** *** input the letter to   * ***           
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****  * *    *  * * =  ** *  + 3;
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   * ****   ***   ** *    =      + 3;
 * ** *  **  *  letterc =   * + 3;
*    * * *  ** * *   =  *** + 3;
  ** *   * * ** 
*  * ****     * ** *** *    *  * ***  ****         ***    **   *** **
       **  * 
* **  *  * *   ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** *  ** *    * **
 * *  *   * * * ***

int    *** argc, char *argv[]) {
***  *  * ****    char *  **
** ***   * * * char letteri;
 **   * * ***  char *      
****  * *    char  * **  
***   *  **** char **  
   *** ** **  * * 
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***  **  ****    **  * * ****  ***  ****   *  ** * *  *    * ***    **   **   ****  * *  * * **  *   
**     ** **   *  * +3;
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***           *  *  **  ** +3;
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**  *  **      *    * **    * * +3;
*****       *  
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**  ** *  * ***   ***** *  *** ***** *   ***       * *   **  *  *  * ** 
 ** ***   **** * ** 
 * * *  * * *  return 0;
}


INPUT
 ** * ***** *****
*  **   * *** 
OUTPUT
* *         * ***
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   **   *  * **  *   * 
  **  ** * **  * **  * 

int  **  **  argc, char ***   {
* *  **      *    char   *  
 * * *    ***  char *  * 
     *** *  ***** * char * * *
   *  ** **     *  char ** **
*   **      * ** *  char  ****
*       **    *     
* **    *   *   ** **   *     *  input the   ***  to **  * *  ** * ** ** * 
*     * *** 
*  * ** *   **       ** **  * ***    **    *  *    ***    * * *     **  ***  ****    *   * *   *  ** ***** 
* **   *      * 
*  **  **  * *  letter = letter + 3;
 * *****  ***** * *    = * *    + 3;
 * *  * * **  *  *  ** * =  *  + 3;
 ****   ** ** ** * =    *** + 3;
  *  * * **   *   ***  =  ***  + 3;
      *       **** 
* * ** *  **     *   ***  *      *  letter is ** *     *** *   *       *   ***   *  *  *  **
 * *  *     **   
 **  * *   * * return 0;
}

INPUT
 ****  ** *  **  
* ** ** * *  
 *  
*   **   *  ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  * *   ** * ** *

int main(int argc, char *argv[]) {
***  * **** ***** *   * ***** lettera;
** *** ****  *** ****  **    letterb;
 *   **   * ******  ***  * ** letterc;
* ***** *   * **** ****  * *** letterd;
* * ** **  *  * * *  * ** *  lettere;
  **    ***   *** *    *
   ** *    * *  ******* ** *   *  ***  ** %c %c %c  * *  * * *      *          *** * * *     * ** ** ** ** * ***   *  * **** 
* *****   ****  *  *   * * * **    * = lettera + 3;
 **   **  * ** ** * * *** **     = letterb + 3;
 **  ******** *      ***  ** ** = letterc + 3;
** ** *****  ****   **  ** * = letterd + 3;
  *****    ***** **  *  **** **** = lettere + 3;
  ** * * * ***  *  * *              *  ** **  ***** *
 * *    *     **   *     *           %c %c %c ***** *  * *   *  letterb, * **** * *        * 
* ****** ***  ** *  ***  **   
     *   ** * ***        *    0;
}

 ** 
  * **
   ** *   **
 *  *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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