[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3.5k views

22 Answers

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Hidden content!
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int ** *  argc, char * * {
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* *  ***** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   *   ******* 
#include    *  * * **   **** *

/* run this program using the console pauser or add your own getch, * ***  ** ** *  * *  or input loop */

int main(int argc, char *argv[]) {
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* *       **** * * *   **** ***    * ***  ****   * *     * *   * *
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*  *  *     * ***   *** * 
       * *   **** **  *    0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   ***  *********** **   *
*    *  *  *       ** *

int    **   * * char **   * {
/*
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*** * * *  

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a = a+3;
b = **
c = **
d = d+3;
e = ****

*   ** *  the ***    ** 
*** **  ** *****  * ** 
***   *  *  * **   *   * * * *

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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**  *   *****      
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/* run this *  *   ** the  **  * *** or add your own * *   * * * *  * ****   **    or     ** */

int * ***  ** char  *  * * {
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}
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 *  ****    *** **  * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**  * * **      *   ** 
*
  *** * ******     

    *    * *** ***                   **     ****         *  * *   * *       * *  *     * ** **
 
*      * ** *   *          

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*  b + 

*** = c +   

   = d +  *
 
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**  **  **  *   *  *   **** *  *   *  *       
 
* ***   *

*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
***   *     ****** ** *
 * *** * *  *  **    

int *** * argc, char ** *  {
   **   * *  * char *     
** ** * ***  char *   
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****  * * * * 
** *    **    * ** *** *    input the letter to ** * ** ***
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**   *** * *  * **   ** =    *  + 3;
**  **        * * ***** * = ****  + 3;
* **  ** *****  *****  = ** **  + 3;
* *  *   ** letterc = **    + 3;
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     *****  *   *   * 
 ***    * **  * **    **  ** *    **  **   *     ** ***   ***     ** * * *  
   * **    
* *  *  ** *  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
***  *  **** * * *  *
* *** *  ****  ***    

int      argc, char *argv[]) {
*  *   **  char  * *
*** * * ** *   char letteri;
*  ** **     **  * char   * 
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 * * * *   * * char  ** 
**        ** 
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 *  *   **    ** 
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* ** *  *  **      *** *  +3;
** ** **    *** **  **    +3;
* **  **   * ***   ***** **  +3;
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******  ***   
**  **        
* *  ** * ***** * ** ** *  *  ****** * *   * *   ** * * ** ***  *      *** *
  **  *** *  * * 
*  *      *   return 0;
}


INPUT
* ** * *****  *
********** **
OUTPUT
  ***  *   **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *** * *   *   ** *** 
   **    * * *  *   * ***

int **  argc, char **  *** {
     *   ***  char *   **
* * *    **       char      
*       *** char **  **
*** **  ***  char   ** * 
  **** *   * ****  char **  **
 **     * ** 
* ***   * *   *   *  * ** **  input the    * to  * * * *  * **** * 
  * ** *  * * 
* **   ***  *  ** ****  *  *** *** *  *   *   *** * *   **  * **    ***  **  *   * ****      * *** 
*  **  ** *  
 **  *   ** ** letter = letter + 3;
     ***  ** **  ***  =     * + 3;
 *  ****  * *    **  =  *  *  + 3;
  *  * *    * ***  *  *** = *     + 3;
**** * *  * **   * *  * = ** * * + 3;
 ** **    * **  
   *   *  **  *   *****   * * ** letter is   ** ** *  * * *  *   *      *     * *    *  
*   *  **  * 
** ******   *  * * return 0;
}

INPUT
 ***** **        *
 ** ***    ** *
**
  ******** * *   *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ***** ** *** ** 

int main(int argc, char *argv[]) {
 * ** * *  * **   ** * *  * * **  lettera;
*  * * *  *** ***  ** *   **    letterb;
*  *   *  **  **   ***** * *** letterc;
***   ***   *   *****  *  **** letterd;
 * * * ** **      *   * * ** lettere;
*** ** ***   **  *  * ** ** * 
* ****** **    * *   * ** *** ** * **  %c %c %c * * ***   **  ***  *    *** *  *   *   *   *    ****  * *   * 
*  ****   ** ** * * ******    *  = lettera + 3;
* *****  **  **  *     * * *   * = letterb + 3;
*  ******  ** * *** ** ****  **   = letterc + 3;
****  ** ** * *** *  * ******    * = letterd + 3;
**** ****** * ***   * ** **** ***   = lettere + 3;
*   *   *   ***** *** *** **  *  *** *   *** *    ** *** *  ** *
  ** *   **   *  *  ***   *** * ***  *  %c %c %c  * * ***   *   letterb, *   * * *    *** *
 *    * * **    *       * *
  * ****** *      *** ** * 0;
}

  **
 * ***
** * *       
** **
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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