[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 9.2k views

22 Answers

0 like 0 dislike 
Hidden content!
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int  ***  argc, char    ** {
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *  **     * ****
#include *   **  ** * *

/* run this program using the console pauser or add your own getch, **** *** * ** *****  or input loop */

int main(int argc, char *argv[]) {
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* ** *** ***  *   * **   * * = a+3;
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* * * * *    * **   *   *    * = c+3;
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* * *** *   **   *   **  = d+3;
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  ** **     **  * * ***   *  
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
    *  **** **  **
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int ** *  * * *   char       {
/*
* *  *    *   */

* ***    

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a = a+3;
b = **
c =  *
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
******  ** ***       *
**   * * *****

/* run this *  *** *  ** the  ***  *     or add your own       ***  *** * **  **  *** or **  *  *  */

int * **    char *  * * {
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
****    * ** * *   ** *
*
* * * *   ** ** *  * ***   
*
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*  ** *  *  **   * ** *  ***  **       **    *  **  *     *     * *** *  *
 
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**     *  
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*******  **   ****  *     * * * *   *   *  *
 
*  ** *
*
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *   ***  * ** *   **      
         *****  **     **  

int *    argc, char   *  {
**   ** *    ** char   * *
****** * *** char * * ***
*   **   **    ** char * * *
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***      ***** char    * 
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*     **  * *****    *  = * **  + 3;
* *       ***   * *  =    *  + 3;
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*    * *    *    
     *  *** * *  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *** *   **    *  *   
       **  ****     *  

int * *   argc, char *argv[]) {
*** ** * * ** char   *  
***      *  *  char letteri;
   *          char *    * 
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*  *** **   *  *      *** +3;
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**  **  ***    ****    +3;
** **  ***  ** *** ** +3;
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* *    *  *** 
   *  *  * *     return 0;
}


INPUT
  *     *   
* *  **** 
OUTPUT
  * **  * **  *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 **   * **  *  *   * *  *  *
*****   ** ** **   *   

int *       argc, char *** * {
 ** * *   ******* char *    
**     * *  ***   ** char *    *
 ***  *  * **   char *  * **
* * *    * * *  *   char    * 
** **    ***** *  char  * **
** *    *     ** 
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** *   *  * **   
   **     *   **** *  **   *****  **        **  *    *    * *  **  ** **  *  **     ** *** 
**  ***  * * ** *  
***** *  **  *  letter = letter + 3;
** ***   * **  * *** * =  *  + 3;
*  * **  ***  *  *     = ** * + 3;
*  *** *  *** *   *     =       + 3;
 * * **  *  * *  =  * **  + 3;
*   **  * *  * 
 **  * *     * ** ** *     *  * *** letter is  **  *  **** ** *  * * *   *** **  **   * ** *
**   ** * * ** * 
***   *  * **  return 0;
}

INPUT
**   ***      ***
 **** **** 
*  * 
 *  ****  **** *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * **  **   ** *  

int main(int argc, char *argv[]) {
 *** * *  *     *  *** *  lettera;
* * **  ** ** **        letterb;
* **** ***** **  *** *  letterc;
*   **   * ***   * **  * *  letterd;
*  ****       * ** **   *  lettere;
***** ***     ** **  ***** *
  *  * ***   * *** *      ** ******** * **   %c %c %c * *** * *  *** ****         *  *     * * *  * **   *  *** * *  * * 
  **** * *   *      *  **   *  *  * = lettera + 3;
 *** * ***  **  **** * ** **    = letterb + 3;
 ** * * *   * *** **   ****  * = letterc + 3;
 * *  ****    * ***   * **  = letterd + 3;
*** * * ** ***  ***** * **    * * = lettere + 3;
 *     **  * ** *   * * * * *****  * ** ** ** * **   *   
** ****** ***   **** * *** * *    **   * %c %c %c  * * *  *   ** * ** letterb, *  *   **** *  *****
 **  **  *   ****** ****   *
 ***** * **** * ****  *** *  * 0;
}

  *   
*  * **
 ** *   **    *  
 **  
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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