[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 6.3k views

22 Answers

0 like 0 dislike 
Hidden content!
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int      argc, char ***   {
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* ** **     * * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  **   *   *** *
#include  * **  **    ** 

/* run this program using the console pauser or add your own getch,  * *  * **   ****   * * * or input loop */

int main(int argc, char *argv[]) {
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*  *   *** **       ** **    *    0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** * * *   *    *     
* **    * * ** *  *    *

int  * * *** * * char *  ** {
/*
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b = 
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*  *   ***         **
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
  *    **     ** *  **** *
* ******  * * ******** *

/* run this  **     the  * * **  or add your own     *    **  ** *** * *     *   ** or ** *  * ** */

int *  * ** char   * {
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}
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**     * ** * **     0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** * *   *** **   *
*
****   ***    *** ***** 
 
 **     * * ****   **  **   * *   ** * *    * * *  *    *     ***   *   *   
 
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*
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**  **  *  *  *** *   * **  ** ** ** * 

***
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
     *   *  * ***  * * 
 **   *    *   ***   **

int  *** ** argc, char  * *  {
 * *    ***** char    *
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**** **   
*  ** ** * **   **      *** input the letter to  *  ** ** 
** **  *  *   
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    * **  * * **  * *    = * *** + 3;
* * **    *   * *    = * *  + 3;
**  *    *     *** ** =  ** ** + 3;
*** *         letterc =  *   + 3;
***      *  *     **  = *** * + 3;
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   **** * **  *    *** * ** *** *  *    **  ** * **   **   ** *    * * 
 *** **     *  *    
*     *       return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * **  **  *   * **    
* **        * * *     **

int  *    argc, char *argv[]) {
 **   **   **   char   ****
 **   ***     char letteri;
     *    *** char * *  *
**   * *  *** char ****
    **  *  * * char       
**     ** * *****  
   * **** **  *    ** * * *    **  input the letter to encode: *   ** * * *   * 
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** **  * * *     **  *    +3;
*  ** ** ** *  *****  *  +3;
  **  *** **  **** ** **   ** +3;
 *   *    * **       ***** +3;
 * *   **  *     *  *        +3;
 *  *  *  **     
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*** *    *****   ****** * * ***** **   ******  *  **     *** ** **** 
 ****  *    
**   *   * return 0;
}


INPUT
***  ** *** ** 
** **     *
OUTPUT
 ***** ********
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *  *   *  *    *  
**  *  * * *  *      * 

int  *   * argc, char   * * {
***     * *  char  * *
 ** *      ** *   char    * 
   *    **   char *  *
  * * *  ** * char * **   
    * * * * *  char * *  
* ****    * *** 
****** *** *   *  *** ** **** ***  input the *** ** to  ***  **  *    *** 
* **    * ****   *  
****  **   ****  ***  * *   **  * ** *  *** * **   *  *   ** **   *       ***  *  ** ** ****      * * ** 
*  **     **     
 * **     ** * letter = letter + 3;
 *** * *    ***   =  ***** + 3;
* ** *  * * * **    = **   + 3;
***     ***  *** *  =  ** + 3;
*   ***  **  *** *    = *   *  + 3;
**  *  ** * * ** 
    *   * ****  ** ** ** ** * * * letter is  * ***  *  ***  * *   *    **   ** *  *    *   
 *  * * **   
****   *  ** return 0;
}

INPUT
**   *  **  ***   
*** **  * *
  * 
** *   ****  ***  *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * ** * ***  * * 

int main(int argc, char *argv[]) {
****    * ** *** **   **  * ** ** lettera;
      **    ** ***** ****  letterb;
********  * **  ** * * ** letterc;
  **   * ***  **  ** **** ** * * * ** letterd;
** ***      ***    ** ** ***   lettere;
**  *  * ****** *   *****
***    ** *  * *  ***   * ******  %c %c %c   * **        *   **  ** **   *   * *** **  * **** ****   *     ** ** 
 *   * * * ***  *** ***    ** **    = lettera + 3;
 * *    *  ***   **   **   *  ***  = letterb + 3;
******** *  * * **  * ** *** = letterc + 3;
  **** ***** ** *   *** ** *  *    = letterd + 3;
 * *   *  *****        * *  **  ***  = lettere + 3;
 ** *  *** **** **  ** * **    * ***  *  *  **  ** 
   ***    * * * *   * * **   *  ******  *   * %c %c %c *  *   ** *  *  letterb,   * * **    **
* * *** *** ** **** **
    * *** *** ****   *  ***** ** **  0;
}

* *  * 
 * *
* ** * ***   **
**  *  *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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